what's this problem please

Answer:

The vertical line test can be used to determine whether a graph represents a function.

If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

Answer:

[tex]f(x)=-2x(x+4)[/tex]

Step-by-step explanation:

We want to find the equation of a quadratic function in factored form with zeros at x = -4 and x = 0 that passes through the point (-3, 6).

The factored form of a quadratic is given by:

[tex]f(x)=a(x-p)(x-q)[/tex]

Where p and q are the zeros and a is the leading coefficient.

Since we have zeros at x = -4 and x = 0, let p = -4 and q = 0. Substitute:

[tex]f(x)=a(x-(-4))(x-0)[/tex]

Simplify:

[tex]f(x)=ax(x+4)[/tex]

And since we know that the function passes through the point (-3, 6), f(x) = 6 when x = -3. Thus:

[tex](6)=a(-3)(-3+4)[/tex]

Simplify:

[tex]6=a(-3)(1)[/tex]

Thus:

[tex]-3a=6\Rightarrow a=-2[/tex]

So, our quadratic function is:

[tex]f(x)=-2x(x+4)[/tex]

Answer:

x = 44° and 74°: x cannot be less than 44°, x cannot be greater than 74°.

Step-by-step explanation:

Obtuse angles are greater than 90° but less than 180°.

We can first solve for the lower bound of x.

Thus the lower bound restriction of x is 44°

We can now solve for the upper bound of x.

Thus the upper bound restriction of x is 74°

Hi there!

We know that the angles ∠B and ∠A are supplementary because they are both interior angles. Therefore:

180 = ∠A + ∠B

Rewrite:

180 = (6x - 48) + (4x + 38)

Combine like terms:

180 = 10x - 10

Solve for x:

190 = 10x

x = 19

Solve for ∠B by plugging in this value of x:

∠B = 4(19) + 38

∠B = 76 + 38

∠B = 114

Answer:

SOH-CAH-TOA

tan = opposite/adjacent

tan J = 15/20 = 3/4

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

A = [tex]\frac{base1 + base2}{2}[/tex] x h     Formula

[tex]\frac{base1 + 5}{2}[/tex] x 20 = 80      Substitution

[tex]\frac{base1 + 5}{2}[/tex] = 4                 Work  (divide by 20, multiply by 2, subtract 5)

base1 + 5 = 8

base1 = 3                  Solution

[tex]\displaystyle\bf 1\frac{1}{3} -3\frac{5}{6} +5\frac{1}{9} =5+1-3+\frac{1^{/6}}{3} +\frac{1^{/2}}{9} -\frac{5^{/3}}{6}\\\\\\\ =3+\frac{6+2-15}{18} =3-\frac{7}{18}=\boxed{2\frac{11}{18} }[/tex]

Answer:

9x - 9

Step-by-step explanation:

4(2x + x - 3) - 3x + 3

Simplify the expression, combine like terms in the parenthesis,

4(3x - 3) - 3x + 3

Distribute, multiply every term inside the parenthesis by the number outside of it;

(4)(3x) + (4)(-3) - 3x + 3

Simplify,

12x - 12 - 3x + 3

Combine like terms,

12x - 12 - 3x + 3

9x - 12 + 3

9x - 9

Step-by-step explanation:

I solved it in the diagram

a) y=4.9x

b)y=63.7

c)x=13

9514 1404 393

Explanation:

The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.

t will not be negative because time moves forward. Here, we're only counting time after Riko leaves the house. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*

_____

* One might argue that Riko is behind Yuto for all values of time after Yuto leaves the house, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.

Answer:

again again again hello or merhaba(hello)

speed = path / time

so we can say this;

speed × time = path

note;

two speeds in different directions add up

and

two speeds in the same direction subtract

our speeds are in the same direction so we subtract

0.35 - 0.25 = 0.10 speed

and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico

when will they be in the same place now?

speed × time = path

0.10 × time = 5.25 miles

in this equation we find the time 52.5 minutes

After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind Yuto

0≤ t ≤ 52,5 ( this is our equation of time)

because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative value

GOOD LUCK :D

Step-by-step explanation:

greetings from Turkey (≧▽≦)

Answer:

{2,3,4}

Step-by-step explanation:

The range are simply the f(x) values

The range are the x values

To get the x values, we simply get x from each f(x)

So we have;

1-2x = -3

1+ 3 = 2x

2x = 4

x = 4/2

x = 2

Secondly;

1-2x = -5

1 + 5 = 2x

2x = 6

x = 6/2

x = 3

lastly;

1-2x = -7

1 + 7 = 2x

2x = 8

x = 8/2

x = 4

So the domain values are;

{2,3,4}

Answer:

A) 27

Step-by-step explanation:

[tex]9^{x}[/tex] = 81

x = 2

3([tex]3^{2}[/tex]) = 3(9) = 27

Answer:

115°

Step-by-step explanation:

in a parallelogram vertically opposite angles are equal.

m∠MNK=m∠KLM=115°

Answer:

Why your question is not visible

Your photo is black screen

Step-by-step explanation:

Please Mark me brainliest

Answer:

The positive correlation between the number of socks and the number of shoes in home

Step-by-step explanation:

Nah i just get an example so that i can get clue,if my answer is wrong sorry in advanced

Answer:

80 ;

10

Step-by-step explanation:

Given :

Total number of students = μ = 140

Let :

Number of students who passed in English = E

Number of students who passed in Nepali = N

n(NnE) = 20

n(E) only = n(E) - n(NnE) = 50 - 20 = 30

Students who passed English only = 30

Number of students who passed in Nepali is twice the number who passed in English

n(N) = 2 * n(E) = 2 * 50 = 100

Number of students who passed in Nepali only

n(N) only = n(N) - n(NnE) = 100 - 20 = 80

Students who passed Nepali only = 80

The number who didn't pass both subjects :

μ - (English only + Nepali only + English and Nepali)

140 - (30 + 80 + 20)

140 - 130

= 10

Answer:

Following are the solution to the given point:

Step-by-step explanation:

The formulated null hypothesis would be that the reported average do not differ significantly

[tex]H_o : \mu = \$3262\\\\H_a : \mu < \$3262 \ \text{(One tailed test)}[/tex]

what's the whole question??

Answer:

11.2

Step-by-step explanation:

[tex]p =\frac{160.16}{14.3}=\frac{160.16*10}{14.3*10}\\\\p = \frac{1601.6}{143}\\\\[/tex]

p = 11.2

Answer:

The person above me is correct I just did the work and I got the same answer as them :)

Step-by-step explanation:

Answer:

1/10, 0.9, 3/10

Step-by-step explanation:

#carryonlearning

Answer:

2000

Step-by-step explanation:

Since the number must be odd, it can have either 1, 3, 5, 7 or 9 in its one's place.

With a 4-digit number starting with 6, any of these digits can be in the one's place and it will still be greater than 6,000.

For the one's place, since we can choose from 5 digits, we have ⁵P₁. In the thousands place, we have one digit which is 6. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively.

So, the total number of 4 digit odd numbers greater than 6000 starting with 6 are 1 × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 1 × 10 × 10 × 5 = 500 numbers.

For the thousands place, we are left with the digits 7, 8 and 9. So, to arrange these 3 digits in the thousands place, we have ³P₁. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively. For the one's place, since we can choose from 5 digits, we have ⁵P₁.

So, the total number of 4 digit odd numbers greater than 6000 starting with 7, 8 or 9 are  ³P₁ × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 3 × 10 × 10 × 5 = 1500 numbers.

So, the total number of 4-digit numbers greater than 6000 that can be constructed is 500 + 1500 = 2000 numbers.

Answer:

[tex]y=a(x-h)^{2} +k[/tex]

[tex](x,y)=(-3,14)[/tex]

[tex](h,k)=(-4,6)[/tex]

[tex]14=a(-3-(-4))^{2})+6[/tex]

[tex]14=a(-3+4)^{2} +6[/tex]

[tex]14=a(1)^{2} +6,-6[/tex]

[tex]8=a[/tex]

[tex]ANSWER:8[/tex]

--------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

Answer:

y = 3

Step-by-step explanation:

2y - 3 = [tex]\sqrt{3y^2-10y+12}[/tex]

square both sides to remove sqrt bracket

(2y - 3)^2 = ( [tex]\sqrt{3y^2-10y+12}[/tex] )^2

simplify both sides

(2y - 3)(2y - 3) = [tex]3y^2[/tex] - 10y + 12

[tex]4y^2[/tex] - 12y + 9 = [tex]3y^2[/tex] - 10y + 12

bring all value to left side

[tex]y^2[/tex] - 2y - 3 = 0

factor

(y - 3)(y + 1)

solve for y

y = 3, y = -1

When plugged back into the equation, only y = 3 is true

Answer:

y = 3

Step-by-step explanation :

[tex]2y - 3 = \sqrt{ 3y² - 10y + 12} [/tex]

Swap the sides both of the equation.

[tex]\sqrt{ 3y² - 10y + 12} = 2y - 3 [/tex]

To remove the brackets of equations square both side and simplify .

3y² - 10y + 12 = 4y² - 12y + 9

Move the expression to left-hand side and change its sign.

3y² - 10y + 12 - 4y² + 12y - 9 = 0

collect like terms

3y² - 4y² - 10y + 12y + 12 - 9 = 0

-y² + 2y + 3 = 0

Change the sign of expression. because it helps to solve.

y² - 2y - 3 = 0

Splits the term -2y

y² + y -3y - 3 = 0

Factor out y from the first pair and -3 from second pair of expression.

y ( y + 1 ) - 3 ( y + 1) = 0

Factor out y + 1 from the expression.

( y + 1 ) ( y - 3 ). = 0

When product and factors equals 0. at least one factor is 0.

y + 1 =0

y - 3 = 0

Solve for y

y = -1 and y = 3

If we plug the 3 as y in the expression we find that y = 3 is the true solution of this expression.

This equation has one solution which is y = 3.

Incomplete question: we assume figures to explain further

Answer and explanation:

Given that client pays $0.15/kwh

If old fridge is inefficient and consumes 120kwh/month

And new fridge is efficient and therefore consumes 50kwh/month

For the old fridge, client will be paying

120×0.15= $18 per month on electricity charges

For the new fridge, client will be paying

50×0.15= $7.5 per month on electricity charges

Answer:

The sphere

[tex]v=\frac{4}{3} \pi r^{3}=\frac{4}{3}*3.14 *2^{3}=\frac{4*3.14*8}{3}=\frac{100.48}{3}=33.493[/tex]

The cylinder

[tex]v=\pi r^{2} h=3.14*(\frac{4}{2} )^{2}*3=3.14*2^{2}*3=9.42*4=37.68[/tex]

Add those two volumes together:

[tex]33.493 + 37.68 = 71.173 in^{3}[/tex]

Answer:

Step-by-step explanation:

This is a sideways cubic translated down 2 units. The graph shown is the sideways cubic translated up 2. So locate the graph that looks like this but has its "squiggly part" at -2 instead of 2.

Answer:

B.

Step-by-step explanation:

Since the numbers in the root is all the same, lets say [tex]\sqrt{2}[/tex] is a variable.

7x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex]

Group with like terms:

7x[tex]\sqrt{2}[/tex] + x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

Combine like terms:

8x[tex]\sqrt{2}[/tex] - 4[tex]\sqrt{2}[/tex]

There you have it! Since all the square roots are the same thing, we can treat them like variables.

the answer is B..................