Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:
[tex]Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3[/tex]
Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:
[tex]0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2[/tex]
Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:
[tex]0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2[/tex]
And the resulting percent yield:
[tex]Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%[/tex]
Regards!
HELPPPPPPPPPPPPMEEEEEEEEEE
Answer:
25%
Explanation:
Cystic fibrosis is a recessive allele, meaning that the child must be aa to suffer the symptoms. Only 1/4 of the paired alleles is aa, so the probability of getting cystic fibrosis would be 25%.
How much energy is used when 14.3 moles of hydrosulfuric acid reacts with 17.1 moles
of oxygen?
2 H2S + 3 02 + 175 KJ
—->2 SO2 + 2 H20
Which substance is the limiting reactant?
Answer:
O2 is the limiting reactant.
Explanation:
Hello there!
In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:
[tex]14.3molH_2S*\frac{2molSO_2}{2molH_2S}=14.3molSO_2 \\\\17.1molO_2*\frac{2molSO_2}{3molO_2}=11.4molSO_2[/tex]
Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.
Regards!
Is benzene a solute or solvent
Identify each of the following as endothermic or exothermic.
a. Water in a pond evaporates.
b. Methane gas burns on a stove top.
c. Water freezes to form ice.
d. Energy flows from the system to the surroundings.
e. Energy flows from the surroundings to the system.
Answer:
Identify each of the following as endothermic or exothermic.
a. Water in a pond evaporates.
b. Methane gas burns on a stovetop.
c. Water freezes to form ice.
d. Energy flows from the system to the surroundings.
e. Energy flows from the surroundings to the system.
Explanation:
An exothermic reaction is the one in which heat energy is released.
An endothermic reaction is one in which heat energy is absorbed.
a. Water in a pond evaporates.
This process absorbs heat energy.
Hence, this is an example of an endothermic process.
b. Methane gas burns on a stovetop and release heat energy and hence this is an example of an exothermic reaction.
c. Water freezes to form ice.
In this process heat energy is released.So this is an example of exothermic reaction.
d. Energy flows from the system to the surroundings.
That means heat energy is released into the surroundings.
So, this is an example of exothermic process.
e. Energy flows from the surroundings to the system.
That means energy is absorbed by the system.
So, it is an endothermic process.
The value of ΔH° for the reaction below is -6535 kJ. ________ kJ of heat are released in the combustion of 16.0 g of C6H6 (l)?
2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l)
Answer:
the value of H° is below -6535 kj. +6H2O
Explanation:
6H2O answer solved
For the given reaction, 2 moles of C₆H₆ the heat energy released is - 6535 KJ. Then, for 16 g of the compound or 0.205 moles needs 669.83 KJ of heat released in combustion.
What is combustion ?Combustion is a chemical reaction that occurs between a fuel and an oxidizing agent, typically oxygen, resulting in the release of heat, light, and various combustion products, such as carbon dioxide and water vapor.
The process of combustion involves a rapid and exothermic (heat-releasing) oxidation reaction that produces a flame, which is visible in many cases.
Here, 2 moles of the hydrocarbon releases - 6535 KJ of energy.
molar mass of C₆H₆ = 78 g/mol
then no.of moles in 16 g = 16 /78 = 0.205 moles.
then energy released by 0.205 moles = 0.205 moles × 6535 KJ /2 moles = 669.83 kJ
Therefore, the heat energy released by 16 g of the compound in combustion is 669.83 kJ.
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True or false? All producers are at the top of the food web
Answer:
false all producers are at the top of food web
Plutonium-238 is a radioactive element that decays over time into a less harmful element at a rate of 0.8 % per year. A power plant has 50 pounds of plutonium-238 to dispose of. How much plutonium-238 will be left after 10 years
Answer:
46 pounds
Explanation:
Let the amount of Plutonium-238 left after 10 years be P
Let the initial mass of Plutonium-238 be Po
Let the rate of decay be r
Let the time taken be t
Hence;
P = Poe^-rt
P= 50e^-0.008×10
P= 46 pounds
Calculate the energy of the orange light emitted, per photon, by a neon sign with a frequency of 4.78 × 1014 Hz.
Answer:
Explanation:
[tex]E=h\nu=6.62606957 *10^{-34}\frac{Kg~m^2}{s}4.78*10^{14}\frac{1}{s}=316.7261*10^{-21}J[/tex]
Which hydrocarbon is saturated?
A)
heptyne
B)
butane
C)
propene
D)
ethyne
what is the molality of a solution that has 4 mol of KCI in 0.800 kg of water?
help me pleaseeee
The molality of a solution that has 4 mol of KCI in 0.800 kg of water is 4 mol/ 0.800 kg.
Therefore option B is correct.
What is molality?b is described as a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.
In order to calculate molality, we need to divide the number of moles of solute by the mass of the solvent in kilograms.
Molality = Number of moles of solute / Mass of solvent in kilograms
Molality = 4 mol / 0.800 kg
In conclusion, the molality is described as a measure of the concentration of a solution expressed in terms of the number of moles of solute per kilogram of solvent.
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Hexane, C6H14, is a(n)
hydrocarbon.
Saturated or Unsaturated
Answer:
Like any compound ending in '-ane', hexane is an alkane. It is commonly referred to as n-hexane and classified as a saturated hydrocarbon
Answer:
its saturated
cus its like
CnH2n+2
Cual es la nomenclatura stock/tradicional/sistematica del oxigeno????
Answer:
english pls so i can answer
g Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 1.84 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 27.30 mL. What volume, in mL, of base was required for the titration?
Answer:
25.46 mL
Explanation:
In a titration we use the volume and concentration of a solution to determine the previously unknown concentration of other solution. Let's consider the titration of an acid of unknown concentration with a standardized base (a base whose concentration we know). The generic neutralization reaction is:
HA + BOH ⇒ BA + H₂O
The base is in the buret and we will add it to the acid until the equivalence point is reached. The volume of base used is equal to the difference between the final reading of the buret and the initial reading of the buret.
V = 27.30 mL - 1.84 mL = 25.46 mL
Compound X has the formula C8H14.
X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?
Answer:
Compound X has the formula C8H14.
X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?
Explanation:
The degree of unsaturation in the given molecule C8H14 is:
DU=(Cn+1)-Hn/2-Xn/2+Nn/2
where,
Cn=number of carbon atoms
Hn=number of hydrogen atoms
Xn=number of halogen atoms
Nn=number of nitrogen atoms
C8H14:
DU=(8+1)-14/2
=>DU=9-7 =2
Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.
X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.
This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.
Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).
So, the molecule has a ring and double bond CH2.
Based on the given data the structure of compound X is shown below:
The reaction sequence is shown below:
An alkyl groyp has a formula of CxH6, determine the value of x
Answer:
i didnt understand
Explanation:
Answer:
x = 2 (C₂H₆)
Explanation:
The general formula for alkanes is CₓH₂ₓ₊₂
2x + 2 = 6
Simply solve for n:
2x = 4
x = 2
Which is most likely the reason the U.S government made such an investment
Answer:
The U.S government made such an investment because they're most likely to reduce harmful emissions.
A mixture of gases at 2.99 atm can You have two gases, and , at the same temperature. Determine the ratio of effusion rates of and .ists of 13.2 moles of hydrogen gas and 19.1 moles of helium gas. Determine the partial pressure of the helium gas.
Answer:
Given total pressure of the gas mixture(hydrogen and helium) is 2.99 atm
Number of moles of hydrogen is ---- 13.2 mol
Number of moles of helium is ---- 19.1 mol
Determine the partial pressure of the helium gas.
Ratio of effusion rates of the two gases.
Explanation:
According to Dalton's law of partial pressures,
partial pressure of a component gas in a mixture is:
partial pressure of a gas = total pressure x mole fraction
mole fraction of helium gas is:
[tex]mole fraction of helium gas = \frac{number of moles of helium gas}{total number of mioles} \\=>mole fraction of He= \frac{19.1mol}{(19.1+13.2)mol} \\=>mole fraction of He = 0.591\\[/tex]
Partial pressure of He gas is:
[tex]Partial pressure of He =mole fraction of He * total pressure\\ =0.591 x 2.99atm\\ =1.77atm[/tex]
Effusion rate of a gas is inversely proportional to its square root of its molecular mass.
[tex]\frac{rate of effusion of H2 gas}{rate of effusion of He gas} =\sqrt{\frac{molar mass of He gas}{molar mass of H2 gas} } \\=> \frac{rate of effusion of H2 gas}{rate of effusion of He gas}=\sqrt{\frac{4g.}{2g} } \\=>\frac{rate of effusion of H2 gas}{rate of effusion of He gas}=1.414:1[/tex]
Hence, rates of effusion of H2:He is 1.414:1.
all first level consumers are carnivore: True or false?
Doc. No.
QMS
Rev. Date
1. In the reaction
P
> M + N
a) The reactants are:
b) The products are:
Answer: In the reaction:
a) The reactants are: P
b) The products are: M and N
Explanation:
The given reaction equation is as follows.
[tex]P \rightarrow M + N[/tex]
Reactants are the species present on the left side on an arrow in a chemical reaction equation.
On the other hand, products are the species which are present on the right side of an arrow in a chemical reaction equation.
Hence, in the given reaction equation P is the reactant. Whereas M and N are the products.
Thus, we can conclude that in the reaction:
a) The reactants are: P
b) The products are: M and N
Learning Task 1. Read each item carefully. Choose the letter of your answer.
1. Which type of soil is characterized as having the finest particles holding greater amount of water?
A. Loam
B. Clay
C. Sand
2. Which type of soil is best for planting?
A. Loam
B. Clay
C. Sand
3. How does each soil types differ?
A. Texture
B. Color
C. Both A & B
4. Which type of soil do you usually expect if the community is along the seashore?
A. Loam
B. Clay
C. Sand
5. Why is soil important to living things?
A. Forms part of the earth where animals live
B. Provides the necessary nutrients needed by plants
C. Serves as a place where people live
D. All of the above
Answer:
1. B
2. A
3. C
4. C
5. D
Explanation:
Soil is regarded as the solid unconsolidated material of the earth crust. Soil is of three different types namely: Sandy soil, clay soil and loamy soil. These three different soil types possess different properties that distinguish them. Some of them are:
- CLAY soil is characterized as having the finest particles and can hold greater amount of water i.e. have a high water holding capacity.
- LOAMY SOIL is the best soil type for planting agricultural crops because it has the highest concentration of nutrients that suited for plant growth.
- loamy, Sandy and clay differ in how we feel when touched i.e. texture, and colour.
- SANDY soils are the kind of soils that are found in Sea shores and beaches.
- Soil is important to living things as it forms part of the earth where animals live, provides the necessary nutrients needed by plants, serves as a place where people live.
describe how you would test your indicator to check that it works
Answer:
If the colour of the indicator changes blue when a base is there and when it changes to red or pink or scarlet when it is acid. Then we can say that the indicator is working
iodide (KI). Identify the correct products of this
reaction. (Note that NO3? is the nitrate ion, a
polyatomic ion.)
AgNO3 + KI – ?
AgK + INO3
✓
Agl + KNO3
Ag + K + I + NO3
COMPLETE
What type of reaction is this?
Answer:
AgNO3 + KI → Agl + KNO3. Double-replacement reaction
Explanation:
Based on solubility rules, Silver, Ag produce an insoluble salt in presence of halides (Fluorides F-, Chlorides Cl-, Iodides, I-, and bromides Br-). That means the mixture of AgNO3 (Ag⁺ ions) with KI (I- ions) produce AgI as insoluble salt.
The reaction is:
AgNO3 + KI → Agl + KNO3And this is a double-replacement reaction where the cations exchange of anion to produce 2 new compounds.
Answer:
AgI + KNO3
Explanation:
double replacement
7.A sample of oxygen gas, O2 weighs 28.4 grams. How many molecules of O2 and how
many atoms of O are present in this sample?
Answer:
5.34275*10²³
Explanation:
Molar mass of O2 is 32g/mol
mass of the sample is 28.4g
number of moles = (mass of the sample) / (molar mass of O2)
=28.5g / 32g/mol
=0.8875mol
number of molecules = number of moles * Avogadro's Constant
= 0.8875 * (6.02*10²³)
= 5.34275 molecules
anuvia, the trade name for sitagliptin, was introduced in 2006 for the treatment of type 2 diabetes. In what type of orbital does the lone pair on each N atom reside.
Answer: hello your question is poorly written below is the complete question
answer:
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
Explanation:
Determining the type of orbital in which the lone pair on each N atom will reside.
From the configuration attached below we can determine the type of orbital and they are ;
For N1 : sp³ orbital
For N2: p orbital
For N3 : p orbital
For N4 : sp² orbital
For N5 : sp² orbital
2. Energy cycles through ecosystems because it returns to the sun.
True or false
Please help I will give 50 points
Answer:
false
Explanation:
energy does not return to the sun, it returns to the plants or producers. if energy were to return to the sun, it would have to travel though space.
How much water, in grams, can be made from
2.44 × 10^24 hydrogen molecules?
Answer in units of g.
Answer:
[tex]m_{H_2O}=73.0gH_2O[/tex]
Explanation:
Hello there!
In this case, since the formation of water from hydrogen and oxygen is:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
Whereas we find a 2:2 mole ratio of hydrogen to water. In such a way, by using the Avogadro's number, the aforementioned mole ratio and the molar mass of water (18.02 g/mol), we obtain the following grams of water product:
[tex]m_{H_2O}=2.44x10^{24}molec*\frac{1molH_2}{6.022x10^{23}molec}*\frac{2molH_2O}{2molH_2}*\frac{18.02gH_2O}{1molH_2O}\\\\ m_{H_2O}=73.0gH_2O[/tex]
Regards!
All forms of energy can exist as either ________ or ________ energy.
Answer:
potentiol or kenetic
Explanation:
What element provides strength to the exoskeleton of Clams and oysters
The combination of isotopes of hydrogen characterized by emmision of radiation is believed to take place in the
a. sun
b. galaxy
c. moon
d. star
Draw a Lewis structure for SF4 that has minimized formal charges. Include all nonbonding electrons and any nonzero formal charges.
Answer:
See explanation and image attached
Explanation:
The compound SF4 is sulphur tetraflouride. It has a zero formal charge and has a total of 34 valence electrons.
The central atom in the molecule is sulphur in an sp3d hybridization state hence the molecule has a trigonal bipyramidal electron geometry. Since it is a molecule of the sort AX4E; it gives a see-saw molecular shape.
The structure of the molecule is shown in the image attached to this answer.
In the Lewis structure of SF₄ , sulfur (S) is the central atom bonded to four fluorine (F) atoms. Lewis structure for SF₄ is attached to the image below.
Each bond is represented by a line, indicating a pair of shared electrons between the bonded atoms. The fluorine atoms are placed around the sulfur atom, and each fluorine atom has a lone pair of electrons that are not involved in bonding.
Sulfur (S) is in Group 16 of the periodic table, so it has 6 valence electrons. Fluorine (F) is in Group 17 and has 7 valence electrons each.
Since we have 4 fluorine atoms, add 4 times the number of valence electrons for fluorine (4 × 7 = 28). The total number of valence electrons in SF₄ is 6 + 28 = 34.
Since each fluorine atom requires 8 electrons (octet rule), each F atom will have 6 lone pairs (12 electrons) around it.
The sulfur atom (S) has a formal charge of +2 (6 valence electrons - 4 bonds - 0 lone pairs), while the fluorine atoms (F) have a formal charge of -1 (7 valence electrons - 0 bonds - 6 lone pairs).
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