Explanation:
velocity - the speed with a direction. Thus, inertia could be redefined as follows: Inertia: tendency of an object to resist changes in its velocity. ... Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.
You slide a 325-N trunk up a 20.0° inclined
plane with a constant velocity by exerting a
force of 211 N parallel to the inclined plane.
a. What is the component of the trunk's
weight parallel to the plane?
b. What is the sum of your applied force, fric-
tion, and the parallel component of the
trunk's weight? Why?
C. What is the size and direction of the friction
force?
d. What is the coefficient of friction?
Answer:
A) 111 N
B) F_net = 0 N
C) 100 N, in the opposite direction of the motion.
D) μ = 0.3274
Explanation:
A) The component of the trunks weight acts parallel to the plane but in the vertical direction and so;
W = Fsin θ
W = 325 sin 20
W = 325 × 0.3420
W ≈ 111 N
B) We are told the trunk is moving with a constant velocity and for this reason the sun of the forces will equal to zero.
Thus; F_net = 0 N
C) Since the kinetic friction force needs to balance the component of the weight, the magnitude is;
F_f = 211 - 111 = 100 N
The direction will be in the opposite direction since it's against the motion.
D) From friction formula, we know that;
F_f = μW cos θ
100 = μ × 325 × cos 20
μ = 100/(325 × cos 20)
μ = 0.3274
Calculate the mass in grams of a toy car if a force of 2 N causes it to accelerate by 10 m/s2
Answer:
m=0.2kg=200g
Explanation:
F=2N, a=10m/s²
F=ma⇒ m=F/a=2/10=0.2kg=200g
Answer:
[tex]\boxed {\boxed {\sf 200 \ grams}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=m*a[/tex]
The force is 2 Newtons and the acceleration is 10 meters per square second. First, we should convert the units of Newtons to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared. The force of 2 N equals 2 kg*m/s²
Substitute the known values into the formula.
F= 2 kg*m/s²a= 10 m/s²[tex]2 \ kg*m/s^2 = m * 10 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 10 meters were second squared. The inverse of multiplication is division. Divide both sides by 10 m/s².
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}=\frac{ m* 10 m/s^2}{10 \ m/s^2}[/tex]
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}= m[/tex]
The units of meters per second squared cancel.
[tex]\frac { 2 \ kg}{10}= m[/tex]
[tex]0.2 \ kg =m[/tex]
Now, we must convert the mass to grams. There are 1000 grams in 1 kilogram. We can multiply the mass by 1000 or set up a ratio.
[tex]0.2 \ kg * \frac{1000 \ g}{1 \ kg}= 0.2 * 1000 \ g = 200 \ g[/tex]
The toy car's mass is 200 grams.
If the electric force between two charges is 4.2 × 10-2 N, what would the new force be if the distance between the charges is doubled and the charge on one of the charges is tripled?
Answer:
New force = 0.063 N
Explanation:
Given that,
The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]
The formula for the electric force is:
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂
Put all the values,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]
So, the new force is 0.063 N.
Answer:
The force becomes 0.0315 N.
Explanation:
Force, F = 4.2 x 10^-2 N
When the distance is doubled, a charge is tripled, Let the force is F'.
The force between the two charges is
[tex]F = \frac{K qq'}{r^2}\\[/tex]
when, q' = 3 q' and r is 2 r so
[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]
A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the school is _________ m? The direction of the student's displacement, relative to the school is ______?
Answer:
1. 7.5 m
2. towards west side
explanation:
I hope it will help you
79. A skater glides along a circular path of radius 5.00 m in clockwise direction. When he coasts around one-half of the circle, starting from the west point, find (a) the magnitude of his displacement vector and (b) how far he actually skated. (c) What is the magnitude of his displacement vector when he skates all the way around the circle and comes back to the west point
The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4 Pa. While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?
when you get the answer please tell me
The potential difference across a resistor increases by a factor of 4. How
does the current change? (Ohm's law: V = IR)
A it increases by a factor of 4
B it decreases by a factor of 4
C it increases by a factor of 2
D it decreases by a factor of 2
Answer:
Correct option is C it decreases by a factor of 2
Answer: A - it increases by a factor of 4
Explanation:
Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.
"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.
You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.
If we plug in 4V for V, we now have:
4V = I*R
Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.
Determine the force that the block of metal would exert when resting on a flat surface in Newtons
Answer:
normal force
tension force
and other example of force
Hai vận động viên chạy trên cùng 1 đoạn đường, vận động
viên A chạy với vận tốc 12 m/s vận động viên B chạy với vận tốc 36
km/h. Hỏi vận động viên nào chạy nhanh hơn?
Answer:
Pemain A
Explanation:
Mengingat data berikut;
Kecepatan pemain A = 12 m/s
Kecepatan pemain B = 36 km/h
Untuk menentukan siapa pelari tercepat di antara dua pemain;
Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.
Jadi, mari kita gunakan pengukuran umum meter per detik.
Konversi:
36 km/h = (36 * 1000)/(60 * 60)
36 km/h = 36000/3600
36 km/h = 10 m/s
Kecepatan pemain B = 10 m/s
Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.
Question 12 of 15
If nitrogen, which has an electronegativity of 2.0, bonds with hydrogen, which
has an electronegativity of 2.1, the bond between the two atoms will be
classified as a(n)
covalent bond.
Answer here
SUBMIT
Answer:
Covalent bond.
Explanation:
There are 4 main types of bonds:
Covalent, ionic, metallic, and hydrogen.
Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.
Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities
Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.
Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.
Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)
So we can see that:
The elements are not metals, so we can discard metallic bond.
For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.
Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.
we can conclude that the bond will be a covalent bond.
True or false: Ultimate tensile strength increases as the thickness of a solid material sample increases.
True
False
Answer:
False.
Explanation:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.
Answer:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE
Compare the MKS, CGS & FPS system of units. which system of units are convenient to use? Justify your answer.
Answer: The system of unit which is most convenient for use is the MKS unit.
Explanation:
System of units is defined as the complete set of units which comprises of both the fundamental units and the derived units. The mass, length and time are considered to be the fundamental quantities and their units are called the fundamental units. The systems of unit which are in common use can be compared through their description below:
--> MKS system of unit: In this system of unit, the unit of length is in meter (m). The unit if mass is in kilogram (k). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
--> CGS system of unit: In this system of unit, the unit of length is in centimeter (cm). The unit if mass is in grams (g). The unit of time is in seconds (s). Hence the name c.g.s. system of unit.
--> FPS system of unit: In this system of unit, the unit of length is in foot (Ft). The unit if mass is in pound (Lb). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
The system of unit which is most CONVENIENT for use is the MKS unit. This is because of the introduction of the international system of units (S.I unit). This unit was endorsed by the International Standard Organisation (ISO) to form a logical and interconnected framework for all measurements in science and technology. The MKS system of unit was made the SI units enabling physical quantities to be represented by only one unit.
what means 10² what we call this
we call it as well as 100 . so easey
Answer:
10 squared
Explanation:
10 squared
In Depth:
Let have a square that has a side length of 10.
A square four sides are equal and if we find the area of a squared, our formula is
[tex] {s}^{2} [/tex]
Our in this instance,
[tex] {10}^{2} [/tex]
or we call it
[tex]10 \: \: squared[/tex]
Using your Periodic Table, which of the following elements below has the largest atomic radius? A.) Aluminum B.) Sodium C.) Sulfur, D.) Fluorine
Answer:
sodium
Explanation:
it is highly reactive metal.
Answer:
aluminium
Explanation:
In a period , as we go from left to right in a periodic table, atomic number increases .
Differentiating electrons enters into same shell hence the effective nuclear charge decreases .
Hence atomic radius decreases along period.
Conculsion:
Aluminium is the element which has greater atomic radius and sulphur has smaller atomic radius.
PLS HELP ME I DONT HAVE MUCH TIME LEFT
The Euler buckling load of a 160-cm-long column will be _____ times the Euler buckling load of an equivalent 120-cm-long column.
1.78
0.56
0.75
2.37
1.33
0.42
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 3 cm and 8 cm.
201 cm4
18 cm4
128 cm4
4 cm4
24 cm4
Answer:
A certain source of 12V with an internal resistance 1colomb is connected to 5colomb external resistance what is the current
Two planetoids with radii R1 and R2 and local accelerations g1 and g2 are separated by a centre-to-centre distance D, and are members of a simple two-body system. A rocket is located on planetoid 1 and is scheduled to launch from this planetoid to a point between the planetoids where the net gravitational force on the rocket by the two planetoids is zero. At what distance from the centre of planetoid 1 is the zero gravitational point? Choose R1 = 1400m, R2 = 1000m, g1 = 7.5m/s2, g2 = 5.3m/s2 and D = 4800m. [5 points]
Answer:
Therefore, the gravitational zero points between two planetoids lie at a distance of 3000 m from the center of planetoid 1.
Explanation:
From Newton’s gravitation formula, the expression of the mass (M) of the planet of radius R is given as,
[tex]F_{G} = mg_{1}\\ \left ( \frac{GMm}{{R_{1}}^{2}} \right )=mg_{1}\\\\M= \frac{gR^{2}}{G}\rightarrow \left ( 1 \right )[/tex]
Let's take x to be the distance of the zero gravitational points from the center of the planetoid 1.
Thus, the distance of the zero gravitational points from the center of the planetoid 2 is (D-x).
At zero gravitational point, the gravitational force between the planets and the rocket must be equal.
how to find work done by load
Why gases are easily compressed?
Answer:
photosynthesis is the process by which green leaves prepare their food in the presence of sunlight,air and water
A sound wave traveling at 340 m/s is generated by a 480 Hz tuning fork.
How long is the sound wave?
Answer:
Wavelength = 0.7083 meters
Explanation:
Given the following data;
Speed of wave = 340 m/s
Frequency = 480 Hz
To find how long is the sound wave, we would determine its wavelength;
Mathematically, the wavelength of a waveform is given by the formula;
Wavelength = velocity/frequency
Wavelength = 340/480
Wavelength = 0.7083 meters
A 3.00 kg box sliding west at 2.00 m/s makes an inelastic collision with a second box sliding 1.50 m/s east. Afterwards, they both come to a stop. What was the mass of the second box?
Let west be the negative direction, and east be positive. Then the total momentum of the system is conserved such that
(3.00 kg) (-2.00 m/s) + m (1.50 m/s) = 0
Solve for m :
m = (3.00 kg) (2.00 m/s) / (1.50 m/s) = 4.00 kg
Water, H2O ,and methane ,CH4, are both covalent substances . why is water a liquid at room temperature while methane is a gas ? A. Carbon compounds tend to be gases . B. Water has a stronger intermolecular forces
write some uses of magnetic force
Answer:
television,radios, microwave ovens, telephone system and computer
How much Voltage is required to run 0.025 A of current through a 24 resistor?
Use AV = IR.
A. 960 V
B. 0.60 V
C. 1.7 V
D. 0.0010 V
OPTIONS:-
A. 960 V
B. 0.60 V
C. 1.7 V
D. 0.0010 V
FORMULA :- V= I× R
WHERE
I -> CURRENT
R -> RESISTANCE
so your answer:-
V= IR
[tex]V = 0.025 \times 24 \\ V = \frac{ \cancel{25}}{ \cancel{1000} {}^{ \: \: \: 40} } \times 24 \\ V = \frac{ \cancel4 \times 6}{ \cancel4 \times 10} \\ V = 0.60Volts[/tex]
so your ANSWER is OPTION B.
V = 0.60 Volts (V)
How do human activities lead to change in the weather?
Answer:
There is overwhelming evidence that human activities, especially burning fossil fuels, are leading to increased levels of carbon dioxide and other greenhouse gases in the atmosphere, which in turn amplify the natural greenhouse effect, causing the temperature of the Earth's atmosphere, ocean, and land surface to ...
Which model of the universe is the most widely accepted, and what does it
predict?
what changes must be done to the wire to increase its conductance.
Answer:
- Decreasing the resistance
- Using a shorter length
- Using a smaller area wire
Explanation:
Formula for conductance in wires is;
G = 1/R
Where;
G is conductance
R is resistance
This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.
Thus, to increase the conductance, we have to decrease the resistance.
Resistance here has a formula of;
R = ρL/A
Where;
ρ is resistivity
L is length of wire
A is area
Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.
the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is 40 kg, calculate the mass of another body. (And:119.9 kg)
Answer:
0.8 x 10^-9 kg
Explanation:
Given,
Distance ( R ) = 10 m
Force ( F ) = 3.2 x 10^-9 N
Mass ( m1 ) = 40 kg
To find : Mass ( m2 ) = ?
Formula : -
F = m1.m2 / R^2
m2 = FR^2 / m1
= 3.2 x 10^-9 x 10 / 40
= 3.2 x 10^-9 / 4
= ( 3.2 / 4 ) x 10^-9
m2 = 0.8 x 10^-9 kg
In the image below, a free-body diagram represents the forces of several vehicles driving across a bridge. Assume that the bridge is in statio equilibrium and that it has zero weight, and solve for the unknown reaction force
A. 10,800 N
B. 65,200 N
C. 120,200 N
D. 53,400 N
Answer:
The answer is "57,400 N".
Explanation:
[tex]\Sigma F_y=0 \ \ \ \ \ \ \text{static equilibrium}\\\\\to 121,200+R=17800+150,000+10800\\\\R=57,400\ N[/tex]
The answer is 57,400 N because the choices are wrong.
the mass of piece of granite is 15.6g when it is suspended can a mass of 5.5g of water is displaced find the dencity of granite
Answer:
2836.36 kg/m³
Explanation:
Applying,
Densty of granite(D')/Density of water(D) = weight of granite(W')/weight of water displaced(W)
D'/D = W'/W................... Equation 1
Make D' the subject of the equation
D' = W'D/W............... Equation 2.
From the question,
Given: W' = mg = 9.8(15.6/1000) = 0.15288 N, W = 9.8(5.5/1000) = 0.0539 N, Constant: D = 1000 kg/m³
Substitute these values into equation 2
D' = 1000(0.15288)/0.0539
D' = 2836.36 kg/m³
Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough is commonly used with transverse waves!
Answer:
yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!
Explanation:
