Answer:
a) reactant
b) product
Explanation:
During a chemical reaction, the reactants interact among themselves in a specific temperature, pressure, pH, enzyme etc. Due to various intra and inter molecular and atomic interactions, the chemical bonds in the reactants break down. Formation of new chemical product is governed by the formation of new bond (ionic, covalent, hydrogen vander waal etc. )
Romeo traveled by a 900 kg horse from Manitua to Verona accelerating at the rate of 20 km/hr. With what force is Romeo moving at?
Answer:
Force(Romeo moving) = 5,000 N
Explanation:
Given:
Mass of horse = 900 kg
Acceleration = 20 km/hr
Find:
Force(Romeo moving)
Computation:
Acceleration = 20 km/hr
Acceleration in m/s = 20 / 3.6 = 5.555556 m/s²
Force = m x a
Force(Romeo moving) = 900 x 5.555556
Force(Romeo moving) = 5,000 N
How much work is done on a small car if a 1000 N force is exerted to move it 75
Answer:
75000J
Explanation:
Given parameters:
Force applied on the car = 1000N
Distance moved = 75m
Unknown:
Work done = ?
Solution:
The work done by a body is the force applied to move it through a particular distance.
So;
Work done = Force x distance
Therefore;
Work done = 1000 x 75 = 75000J
HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN
A train moved at a constant speed of 63 m/s. How far will it travel in 120 seconds?
1.90 m
0.50 m
57 m
7.560 m
Answer:
It will travel 7,560 m
Explanation:
63 x 120 = 7,560 m
Answer:
A. 1.90
I divided 63 by 60 and got 1.05
I multiplied 1.05 by 2 (120 seconds = 2 minutes) and I got 2.1
1.90 is the closest answer.
Please help thanks
Most wind erosion is caused by _____.
1. saltation
2. abrasion
3. traction
4. plucking
Which of the following is not necessary for the creation of fossil fuels?
A. Organic matter
B Heat
C Pressure
D. Wind
Based on the figure shown, about how far can sound travel in water in 2.5 s if the water temperature is 25°?
O a. 3,750 m
Oc. 600 m
Ob. 375 m
O d. 875 m
Answer:
A
Explanation:
A roller coaster, traveling with an initial speed of 23 m/s, decelerates
uniformly at -4 m/s2 to a full stop. How far does the roller coaster travel
during its deceleration?
I NEED STEP BY STEP EXPLANATION
Answer:
5 and 3/4 meters
Explanation:
This is because if it is slowing down by 4 meters and it was moving at 23, then you would figure out how many times 4 can go into 23 and you'd get 5 and 3/4 meters.
The speed of the wooden bar is changed so that the bar hits the water fewer times each second.
What happens to the frequency of the waves produced?
A. Increases
B. Does not change
C. Decreases
Answer:
c - the frequency of the waves decreases
Use the motion map to describe the motion of the object.
A motion map. The position line is a long black arrow pointing right, labeled x. Above the line are five dots with a vector pointing away from x that start at x, each one shorter ending in the last dot with no vector. Above that are two yellow vectors pointing toward x between the second and third and third and fourth black dot. Above that are three black dots with vectors pointing toward the origin, x, each with a larger vector. There are three yellow vectors with no black dots pointed toward x starting just above the vertical column of three dots.
Which statements describe what is occurring at
t = 5 seconds? Check all that apply.
The object sped up.
The object slowed down.
The object continued in the same direction.
The object changed direction.
The object came to a complete stop.
Answer:
The object sped up.
The object changed directions.
Explanation:
Just got the question correct.
Answer:
A & D
The object sped up
The object changed direction
Explanation:
:)
I need help ASAPP
Thanks+ BRAINLIST only for correct answer for these questions.
Which among the following forms of electromagnetic waves has the highest frequency range?
O Microwave
O Radio waves
O X-ray
O Ultraviolet
Radio waves carry information from a broadcasting station to your radio or television.
-visible light
- sound
-X -ray
- gamma ray
Answer:
First) X-ray
Second) I think sound waves
Explanation:
3,000ml of an unknown liquid has a mass of 3 kg. What is its density?
Answer:
Ro = 1000 [kg/m³]
Explanation:
We must remember that density is defined as the relationship between mass and volume.
[tex]Ro=m/V\\[/tex]
where:
Ro = density [kg/m³]
m = mass = 3 [kg]
V = volume = 3000 [ml]
We must convert the volume of milliliters to cubic meters
[tex]3000[ml]*\frac{0.001Lt}{1ml}*\frac{1m^{3} }{1000Lt} = 0.003m^{3}[/tex]
Now replacing:
[tex]Ro=3/0.003\\Ro=1000[kg/m^{3} ][/tex]
A badminton player hits a 0.010 kg shuttlecock that is initially at rest in his hand. The net force on the shuitlecock over time is shown below. What is the shuttlecock's speed at t = 30ms ?
Answer: 10 m/s
Explanation: I got the answer wrong, then it showed it to me
a girl pushes her little brother down a snowy hill on a sled and he rides quickly to the bottom of the hill
which one of Newton's Laws is this
Answer:
Newton's First Law of Motion.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's First Law of Motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
In this scenario, a girl pushes her little brother down a snowy hill on a sled and he rides quickly to the bottom of the hill. The push from the little boy's sister is the external force acting on him and consequently, causing him to be in motion down the snowy hill.
A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before impact, the lineman is moving north at 6.0 m/s and the the quarterback is moving north at 1.0 m/s. Determine the speed and direction of the two players immediately after the tackle.
Answer:
Explanation:
We shall apply law of conservation of momentum .
Momentum before impact = momentum after impact
Since they are moving towards the same direction , their momentum will add up .
Total momentum before impact
= 136 x 6 + 100 x 1 = 916 kg m/s .
Total mass of lineman and quarterback = 236 kg , if their velocity after impact be v
their momentum = 236 v
According to law of conservation of momentum
236 v = 916
v = 3.88 m /s
Both of them will move with velocity of 3.88 towards the north .
Go to your backyard or to your high school’s basketball court or tennis court and try out this experiment to see if you can predict motion and inertia accurately. Bring a friend or classmate. Take along a ball.
Select two spots roughly 10 meters apart. Mark each of them clearly. The first spot will be the starting point and the second will be the target.
Ask a friend to run as fast as possible (sprint) carrying the ball from the starting point to the target. Have your friend release the ball when he or she is immediately over the target trying NOT to swing arms when dropping the ball.
Record the results in the table below.
Repeat the sprint at least five times. Record where the ball lands each time.
Next, ask your friend to jog to the target with the ball and drop it. In the table, again record where the ball lands. Do two trials.
For the final test, ask your friend to walk to the target and drop the ball. Also record these results in the table. Do two trials
Answer:1 Sprint 54 cm Beyond
2 Sprint 41 cm Beyond
3 Sprint 68 cm Beyond
4 Sprint 32 cm Beyond
5 Sprint 44 cm Beyond
6 Jog 31 cm Beyond
7 Jog 22 cm Beyond
8 Walk 17 cm Beyond and left
9 Walk 6 cm Beyond
Explanation:
Answer:
1 Sprint 54 cm Beyond
2 Sprint 41 cm Beyond
3 Sprint 68 cm Beyond
4 Sprint 32 cm Beyond
5 Sprint 44 cm Beyond
6 Jog 31 cm Beyond
7 Jog 22 cm Beyond
8 Walk 17 cm Beyond and left
9 Walk 6 cm Beyond
Explanation: edmentum sample answer
A car has a mass of 1500 kg and accelerates at a rate of 15 m/s^. What was the force applied?
Answer:
22500N
Explanation:
Given parameters:
Mass of the car = 1500kg
Acceleration = 15m/s²
Unknown:
Force applied = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
So
Force = 1500 x 15 = 22500N
most of the energy we use on earth comes from the sun—how does that energy(light and thermal)end up?
As ____energy in our food
As ____energy of wind or moving water
As ____energy that was our lights
As ____energy when we move around
An object of mass m is placed on Spring A, which is compressed by distance x. The spring is released and the velocity of the pushed object as it leaves the spring is measured. The experiment is repeated with the same object on Spring B, which is compressed by the same distance x. The object travels faster when pushed by Spring B. What can be concluded?
A .Spring A had a higher elastic potential energy than Spring B.
B. Spring A's spring constant is higher than Spring B's.
C. Spring A's spring constant is lower than Spring B's.
D. Spring A has more mass than Spring B.
Answer:
C
Explanation:
the gravitational force produced between any two
objects kept at 2.5*10^km apart is 580N. at what distance
should they be kept so that the gravitational force becomes
half?
Answer:
The two objects should be kept at a distance of [tex]3.535\times 10^{4}[/tex] kilometers.
Explanation:
From Newton's Law of Gravitation, gravitational force ([tex]F[/tex]), measured in newtons, between two objects is inversely proportional to the square of distance ([tex]r[/tex]), measured in meters. That is:
[tex]F \propto \frac{1}{r^{2}}[/tex] (1)
[tex]F = \frac{k}{r^{2}}[/tex] (2)
Where [tex]k[/tex] is the proportionality ratio, measured in newtons-square meter.
Now we eliminate the proportionality by constructing the following relationship:
[tex]\frac{F_{2}}{F_{1}} = \left(\frac{r_{1}}{r_{2}}\right)^{2}[/tex] (3)
If we know that [tex]\frac{F_{2}}{F_{1}} = \frac{1}{2}[/tex] and [tex]r_{1} = 2.5\times 10^{7}\,m[/tex], then the distance between the two objects so that gravitational force becomes half is:
[tex]\frac{1}{2} = \frac{(2.5\times 10^{7}\,m)^{2}}{r_{2}^{2}}[/tex]
[tex]r_{2}^{2} = 1.25\times 10^{15}\,m^{2}[/tex]
[tex]r_{2} = 3.535\times 10^{7}\,m[/tex]
[tex]r_{2} = 3.535\times 10^{4}\,km[/tex]
The two objects should be kept at a distance of [tex]3.535\times 10^{4}[/tex] kilometers.
10)A car is moving from rest and attained a velocity of 80 m/s. Calculate the
acceleration of the car after 5 s?
Explanation:
the velocity graph of a ball mass 20mg moving along a straight line
16m/s^2
Explanation:
initial velocity (u) =0
final velocity (v) =80
acceleration =?
Now,
acceleration = (v-u)/t
=(80-0)/5
= 80/5
= 16m /s^2
Write 4,007,500,000 in scientific notation.
4.0075 x 10 -9 (-9 is an exponent)
4.075 x 10 9 (9 is an exponent)
4007.5 x 10 6 (6 is an exponent)
4.0075 x 10 9 (9 is an exponent)
please help! you are amazing! brainliest too!
NASA helps fund science education.
Which statement about scientific knowledge is false?
A. Understanding science can help people make wiser purchases.
B. People with more knowledge of science are always healthier.
C. People with college degrees in science often earn high salaries.
D. Science education can help people understand the universe.
Answer:
I think its B and I don't know why my words are like this
Explanation:
What did the Dakota believe about Bdote?
Answer Bdote means “where two waters come together.” While bdote can refer to any place where waters converge, many Dakota people consider this location as a sacred place of creation, identifying themselves as the Wicahpi Oyate (Star Nation) who originated in the sky and came into being on this land.
I hope it helpful
While driving his sports car at 20.0 m/s through a residential neighborhood, Royston
comes up behind a slow-moving grandma and decides to pass her on the left. If
Royston can accelerate at 6.00 m/s2, how long will it take for him to reach a velocity of
30.0 m/s?
Answer:
1.67s
Explanation:
Given parameters:
Initial velocity = 20m/s
Acceleration = 6m/s²
Final velocity = 30m/s
Unknown:
Time taken = ?
Solution:
Acceleration is the rate of change of velocity with time. It is mathematically expressed as;
Acceleration = [tex]\frac{v - u }{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
6 =[tex]\frac{30 - 20}{t}[/tex]
6 = [tex]\frac{10}{t}[/tex]
10 = 6t
t = 1.67s
Explain how are position time, velocity, and acceleration related to each
other?
Wavelength in one full standing wave
Answer: one complete wave in a standing wave pattern consists of two loops. Thus, one loop is equivalent to one-half of a wavelength
Explanation: I hope that helped- Please mark me as brainliest!
Answer:
the standing wave within =1 oscillates at the fundamental frequency and has a wavelength that is twice the length of the string . Higher integer value of n correspond to mode of oscillation called harmonics or overtones . Any standing waves on the string will have n +1 node including the fixed end and n anti-nodes.
I hope that helped.Plzz mark me as brainliest
A highway speed limit is posted as 90 km/hr. Is this average speed or instantaneous speed? Explain your answer.
HELP PLS MARKING BRANLIST 100 PTS TAKING TEST RN
How long will your trip take if you travel 890 km at an average speed of 92 km/hr?
81,880 hrs
9.67 s
9.67 hrs
81,880 s
The primary job of a(n) ____
is to increase the power of a modified radio wave.
The primary job of a(n) ____
is to increase the power of a modified radio wave.
Answer:
amplifierExplanation:
Hope it helps:)
#CarryOnLearning
Answer: Amplifier
Explanation: Edge 2021
Have a great day :D
When power and current are known use R = P/I^2 to calculate the resistance.
P = 300 watts
C = 30amps
R = ?
R = resistance, P = Power, 1 = Current
[tex] \sf• \: Power \:( P) = 300 \: watts[/tex]
[tex] \sf• \: Current \: (I) = 30 \: amps[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find:- }}[/tex][tex] \sf• \: The \: Resistance [/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution :-:- }}[/tex]
[tex] \bf \red {\bigstar{ Formula \: of \: Power \: (P) = \frac{ {I}^{2} }{R}}}[/tex]
[tex] \sf \rightarrow 300= \frac{ {30}^{2} }{ R} [/tex]
[tex] \sf \rightarrow 300 = \frac{900}{ R} [/tex]
[tex] \rightarrow \sf R = \frac{300}{900} [/tex]
[tex] \rightarrow \sf R = \frac{1}{3} [/tex]
[tex] \rightarrow \sf R = 0.33[/tex]
[tex] \bf \purple{Hence, \: the \: resistance \: is \: 0.33 \: Ω \: . }[/tex]
