Answer: 3.73 grams
Explanation:
[tex]Q=I\times t[/tex]
where Q= quantity of electricity in coloumbs
I = current in amperes = 96.0 A
t= time in seconds = 37.0 sec
[tex]Q=96.0A\times 37.0s=3552C[/tex]
The reaction at cathode is:
[tex]Pb^{2+}+2e^-\rightarrow Pb[/tex]
[tex]96500\times 2=193000Coloumb[/tex] of electricity deposits 1 mole of
3552 C of electricity deposits =[tex]\frac{1}{193000}\times 3552=0.018moles[/tex] of Pb
[tex]\text {mass of Pb}={\text{moles}\times {\text{Molar mass}}[/tex]
[tex]\text {mass of Pb}={0.018}\times {207.2g/mol}=3.73g[/tex]
Thus mass of lead deposited is 3.73 g
Calculate the molarity of a solution that contains 3.00x10-2 mol NH4Cl in exactly 450 cm3 of solution.
Answer:
0.06moles/litres
Explanation:
molarity = no of moles / volume in litres = 3.00*10^-2/(450/1000)=0.06 moles/litres
Answer:
0.07mol/dm^3
Explanation:
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Explain what method you would use to obtain
Petrol (boiling point 20
60 C) from a mature of petrol and kerosene (boiling point 180 220 C)
Answer:
Fractional distillation of crude oil in laboratory
Explanation:
In general, we can sort them according to their boiling point.
We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.
Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.
Heat flows from hotter objects to colder objects until it reaches a state where heat is no longer flowing.What have the objects reached when heat is not longer flowing?
Consider the following equilibrium
N204(9) - 2NO2(9) Keq = 5.85 x 10-3
Which statement about this system is true?
If the equilibrium concentration of NO2 is 1.78 x 10-2 M, the equilibrium concentration of N2O4 is
The equilibrium concentration of N₂O₄, given that the concentration of NO₂ is 1.78×10⁻² is 5.42×10⁻²
Data obtained from the question N₂O₄ <=> 2NO₂Equilibrium constant (Keq) = 5.85×10⁻³ Equilibrium concentration of NO₂ = 1.78×10⁻²Equilibrium concentration of N₂O₄ =?How to determine the equilibrium concentration of N₂O₄Keq = [Product] / [Reactant]
Keq = [NO₂]² / [N₂O₄]
5.85×10⁻³ = [1.78×10⁻²]² / [N₂O₄]
Cross multiply
5.85×10⁻³ × [N₂O₄] = [1.78×10⁻²]²
Divide both sides by 5.85×10⁻³
[N₂O₄] = [1.78×10⁻²]² / 5.85×10⁻³
[N₂O₄] = 5.42×10⁻²
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Answer:
First answer is "The equilibrium lies to the left", and the second one is 5.42 x 10^-2 M.
Explanation:
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How many moles is equal 82.4 grams of CO,?
Answer:
1 mole = 28.0101
Hence,
82.4 = around 2.8 mole
Have a great day <3
The half-life of 226Ra is 1.60x103 years. How long until only 12.5% of the original sample of 226Ra remains?
Answer:
4.80×10³ years
Explanation:
Let the original amount (N₀) of ²²⁶Rn = 1 g
Therefore,
12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Original amount (N₀) = 1
Amount remaining (N) = 0.125 g
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
0.125 = 1/2ⁿ × 1
0.125 = 1/2ⁿ
Cross multiply
0.125 × 2ⁿ = 1
Divide both side by 0.125
2ⁿ = 1/0.125
2ⁿ = 8
Express 8 in index form with 2 as the base
2ⁿ = 2³
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.
This can be obtained as follow:
Half-life (t½) = 1.60×10³ years
Number of half-lives (n) = 3
Time (t) =?
t = n × t½
t = 3 × 1.60×10³
t = 4.80×10³ years.
Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.
Which is a saturated solution?
A）40g NH4Cl in 100g water at 50°C
B）2g SOz in 100g water at 10°C
C）52g KCl in 100g water at 80°C
D）120g KI in 100g water at 20°C
Answer:
C）52g KCl in 100g water at 80°C
Explanation:
A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.
A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.
From the solubility curve in the attachment below:
A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.
B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.
C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.
D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.
how many atoms are in 0.5 mole of aluminum
According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.
Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
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Given that C = n/V. And you have n=2 and C=4 what does V= ??
1...0.5
2...2
3...4
4...8
or5...Dont know
Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.
Answer: An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.
Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.
Help bestie pls help ASAP thank you
Explanation:
heyyyyyyyyy how are you sure
A chemical reaction causes the chemical compositions of substances to change.
a. True
b. False
Answer:
True
Explanation:
A chemical change is otherwise known as a chemical reaction. A chemical change is characterized by the formation of new substances, evolution of heat and change in chemical composition of substances. The change in the composition of substances during a chemical change is the result of the making and breaking of chemical bonds during a chemical change.
A chemical change is not easily reversible because it involves changes in chemical composition of substances.
An example of a chemical change is the combination of sodium hydroxide and hydrochloric acid according to the reaction equation;
HCl(aq) + NaOH (aq) -----> NaCl(aq) + H2O (l)
We easily notice the change in the chemical composition of each of the substances involved in the reaction.
During a hurricane, what effect can the ocean have on the beach?
A.
Only the wind from a hurricane affects the land.
B.
Only the rain from a hurricane affects the land.
C.
The ocean can wash away much of the beach in a short time.
D.
The ocean always cleans litter from the beach during a hurricane.
A chemistry student is given 4.00 L of a clear aqueous solution at 22°C. He is told an unknown amount of a certain compound X is dissolved in the solution. The student allows the solution to cool to 22 C. The solution remains clear. He then evaporates all of the water under vacuum. A precipitate remains. The student washes, dries and weighs the precipitate. It weighs 0.56 kg.
Required:
Using only the information above, Calculate the solubility of X in water at 22° C. If you said yes, calculate it Be sure your answer has a unit symbol and 2 no .0 it. significant digits.
Answer:
The responses to the given points can be defined as follows:
Explanation:
In point 1:
The answer is "No".
In point 2:
The mass of solute = The mass of precipitate [tex]= 0.56\ kg =0.56\ \times 1000 = 560 \ g[/tex]
Calculating the solubility:
[tex]= \frac{\text{mass of solute in g}}{\text{volume of solution in ml}}\\\\ = \frac{560}{ 4000} \\\\ = 0.14 \ \frac{g}{ml}[/tex]
What features did you use to classify igneous rocks as extrusive or intrusive ?
Answer: Igneous rocks may be simply classified according to their chemical/mineral composition as felsic, intermediate, mafic, and ultramafic, and by texture or grain size: intrusive rocks are course grained (all crystals are visible to the naked eye) while extrusive rocks may be fine-grained (microscopic crystals) or glass.
Explanation: Hope this helped! :)
Answer:
Igneous rocks may be simply classified according to their chemical/mineral composition as felsic, intermediate, mafic, and ultramafic, and by texture or grain size: intrusive rocks are course grained (all crystals are visible to the naked eye) while extrusive rocks may be fine-grained (microscopic crystals) or glass ( ...
As student used a pen to draw a line across a piece of chromatography paper. he then placed a sample of dye on the drawn line for analysis . is the student doing the right thing? why?
Answer is in the photo. I can only upload it to a file hosting service. link below!
tinyurl.com/wpazsebu
8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has the capacity to hold 0.100 kg water/kg dry zeolite. Once the zeolite becomes saturated with moisture, it must be regenerated by heating. The inlet moisture content of the methane is 7.00% (by mass) and the outlet moisture content is 0.05% (by mass). How much methane (kg) will be produced before the zeolite must be regenerated
Answer:
Follows are the solution to this question:
Explanation:
Methane inlet humidity content of [tex]=7.00\%[/tex]
Methane moisture outlet content [tex]=0.05\%[/tex]
Zeolite absorption humidity [tex]= 6.95\%[/tex]
Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]
One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]
The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]
Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]
That's why it will be producing 1439 kg of methane.
The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.
What is zeolite?
Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.
In the question, it is given that:
Capacity of 1kg of zeolite to hold water = 0.100kg
Capacity of 1000kg of zeolite to hold water = 100kg
Inlet moisture content of the methane = 7.00 % (by mass)
Outlet moisture content of the methane = 0.05% (by mass)
Capacity of zeolite to absorb methane content = 6.95 %
Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg
Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.
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how many grams of hcl would be produced if 54 grams of water were used
Answer:
i dont know
Explanation:
its simple i dont know
Answer:
Explanation:Red
Do molecules move in all phases? (yes/no)
Answer: sorta
Explanation:
In fact, they do not flow at all: they simply vibrate back and forth. Because the atoms in a solid are so tightly packed, solid matter holds its shape and cannot be easily compressed
what career field/job would utilize ppm units
A environmental jobs
B Medical fields
C Jobs at the brewery
D Jobs in analytical chemistry
Based on the graph, which statement about human use of natural resources is most likely false?
Hey love! <3
Answer:
C. Resource use by humans has gone up and down over the years is a false statement
Explanation:
In the graph you can make an observation on how the increase of human population is directly positive.
The resource use either has a positive or negative correlation, making it impossible for the usage to fluctuate over the years.
Hope this brightens up your day a little! ❀‿❀ Sincerely, Kelsey from Brainly.
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A sample of gas has an initial volume of 30.8L AND an initial temperature of -67 degree Celcius. What will be the temperature of the gas if the volume is 21.0L?
Answer:
–132.55 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 30.8 L
Initial temperature (T₁) = –67 °C
Final volume (V₂) = 21.0 L
Final temperature (T₂) =?
Next, we shall convert –67 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = –67 °C
Initial temperature (T₁) = –67 °C + 273
Initial temperature (T₁) = 206 K
Next, we shall determine the final temperature of the gas. This can be obtained as follow:
Initial volume (V₁) = 30.8 L
Initial temperature (T₁) = 206 K
Final volume (V₂) = 21.0 L
Final temperature (T₂) =?
V₁/T₁ = V₂/T₂
30.8 / 206 = 21 / T₂
Cross multiply
30.8 × T₂ = 206 × 21
30.8 × T₂ = 4326
Divide both side by 30.8
T₂ = 4326 / 30.8
T₂ = 140.45 K
Finally, we shall convert 140.45 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T₂ = 140.45 K
T₂ = 140.45 K – 273
T₂ = –132.55 °C
Thus, the new temperature of the gas is –132.55 °C
How to balance NaOH+CO2=Na2CO3+H2O by algebraic method?
A certain metal M forms a soluble nitrate salt M NO Suppose the left half cell of a galvanic cell apparatus is filled with a 3.00 mM solution of M(NO) and the right half cell with a 3.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C.
1. Which electrode will be positive? What voltage will the voltmeter show?
a. left
b. right
2. Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answer:
Explanation:
From the information given:
left half-cell = 3.00 mM M(NO)
right half-cell = 3.00 M M(NO)
Since the electrode are the same in both cells, then the concentration for the cell are also the same.
Negative electrode = Anode = lower concentration = 3.00 mM
Positive electrode = cathode = higher concentration = 3.00 M
Thus, right half cell will be postive electrode.
To determine the concentration cell:
[tex]Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)[/tex]
SInce [Cathode] > [anode],
[tex]R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol[/tex]
n = 3
[tex]Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}[/tex]
[tex]\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}[/tex]
Neutralization Reactions
5. Acids and bases go to completion via neutralization reactions, thus titrations are applicable. Refer to educational resources and provide an example of the chemical reactions for the solutions in a–c.
a. A mixture between a strong acid and a strong base.
b. A strong base mixed with a weak acid.
c. A strong acid mixed with weak base.
Answer:
its a option neutralization takes place between acid and base plz mark me branliest
i
CH3-CH2-CO-CH2-CH2-CH3 + H2
Pd
Answer:
i don't know but I just want to have coins
How many grams are in 1.2 x 10^24 atoms of sodium?
An iron sulfide compound is analyzed, and found to contain 11.26 g iron and 9.70 g sulfur. Determine the molar ratio of sulfur to iron in this compound, and hence its chemical formula.
Answer:
Molar ratio = 1.5Chemical formula = Fe₂S₃Explanation:
First we convert the given masses of each element into moles, using their respective molar masses:
Fe ⇒ 11.26 g ÷ 55.845 g/mol = 0.202 mol FeS ⇒ 9.70 g ÷ 32.065 g/mol = 0.302 mol SNow we divide them in order to calculate the molar ratio of S to Fe:
0.302 / 0.202 = 1.5Meaning that for each 1 Fe mol, there's 1.5 S moles. We can write that as Fe₁S₁.₅
Finally we double those subscripts so that they become the lowest possible integers: Fe₂S₃.
According to the text, fission occurs when the nucleus
two lighter nuclei.
Answer:
Splits into
Explanation:
Because fission reaction is divided into two or more pieces.
Lets make this one quick.
