Answer:
use graphs
Step-by-step explanation:
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
What percent of the bottle of apple juice is water?
percent of water is: 32/80*100= 40%
Help with this problem pls!
Answer:
uh.. shii i dont know
Step-by-step explanation:
What is the equation of the line in slope-intercept form?
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Answer:
[tex]y=-\frac{1}{4}x\\[/tex]
Step-by-step explanation:
The slope is calculated by "up ÷ across".
= -1 ÷ 4
= [tex]-\frac{1}{4}[/tex]
The y-intercept is just 0 (because the line meets at the y axis at 0).
So, using [tex]y=mx+b[/tex] (where m = slope and b = y-intercept),
[tex]y=-\frac{1}{4}x+0[/tex]
but the '+0' is unnecessary so we just say [tex]y=-\frac{1}{4}x[/tex]
Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price
Answer:
$14.40 is the discount price.
Step-by-step explanation:
0.2 x 18 = 3.6
18 - 3.6 = 14.4
The circumference of a circle is 14.444 miles. What is the circle's diameter?
Answer:
2.29883
formula
[tex]c = 2 \times \pi \times r[/tex]
solving for (r) radius
[tex]r = \frac{c}{2\pi} = \frac{14.44}{2 \times \pi} [/tex]
= 2.29883
The greatest possible number whose digits are all even numbers from 1 to 9
Answer:
8642Step-by-step explanation:
Our even numbers from 1-9 are:
2,4,6,8The largest possible number using the even numbers once is 8642.
Hoped this helped
Andrew shovels snow for 4 %2 hours and makes
$27. How much did he make per hour?
And how much does he earn in 8 hours?
How many 2 digit numbers have unit digit 6 but are not perfect squares
9514 1404 393
Answer:
7
Step-by-step explanation:
Of the 9 2-digit numbers ending in 6, only 2 are perfect squares: 16 and 36. The other 7 are not perfect squares.
if you help me you get brainly
Answer:
3 ( 917 ) = 3 ( 900 ) + 3 ( 10 ) + 3 ( 7 )
5 ( 209 ) = 5 ( 200 ) + 5 ( 0 ) + 5 ( 9 )
6 ( 347 ) = 6 ( 300 ) + 6 ( 40 ) + 6 ( 7 )
9 ( 821 ) = 9 ( 800 ) + 9 ( 20 ) + 9 ( 1 )
11 ( 142 ) = 11 ( 100 ) + 11 ( 40 ) + 11 ( 2 )
Step-by-step explanation:
Answer:
Hint(look at the first number in each part and math it with the first number in each answer.) For example, 3(937), the distributive property for that one would be 3(900) + 3(30) + 3(7). Then for 5(209) it would be 5(200) + 5(0) + 5(9), then for 6(342), it would be 6(300) + 6(40) + 6(2). Then for 9(821), it would be 9(800) + 9(20) + 9(1), and for the last one it would be 11(143), it would be 11(140) + 11(40) + 11(3). You basically distribute each amount into different place values.
Step-by-step explanation:
Hope it helps. Mark brainiest if it does!
170 students or 85% of the students went to attend college what are the total number of students?
Answer:
200
Step-by-step explanation:
I think sorry if I am wrong
Complete the equation to calculate the cost of the portable speaker, including sales tax.
$53
=
% of $50
Answer: The answer to this math question about completing the equation in order to calculate the cost of the portable speaker, including the sales tax is $94.34.
Step-by-step explanation: I don't have any step-by-step explanation, I'm sorry about that, but anyway, I hope that my given short answer is very helpful to your own math question about completing the equation in order to calculate the cost of the portable speaker, including the sales tax, please mark me as Brainliest, take care, always be safe, and have a great rest of the day! :D
Sincerely,
Jason Ta,
The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.
Simplify the linear expression.
−2/3a+1/8−1/6a−3/4
Enter your answer as simplified fractions in the boxes.
Answer:
-5/6a - 5/8
Step-by-step explanation:
i took the k12 quiz
can someone help
me on one of these please!
3 t-shirts cost £25.95.
How much do 10 t-shirts cost?

Answer:
£86.50
Step-by-step explanation:
To find how much 10 t-shirts cost we have to find how much they cost individually.
3 T- Shirts / 25.95 = 8.65 which means that each T-Shirt Costs 8.65.
8.65 x 10 T-Shirts = £86.50
PRETTY PLS HELP ME JUST 2 MORE QUESTIONS PLS 50 POINTS
Answer:
I think that you should take your time and answer, every one can help you
Step-by-step explanation:
Step-by-step explanation:
ok give question and intro new sis
Identify the similar triangles.
ΔHFE=
ΔHFE=
∆HFE is similar to ∆HFG and ∆ HEG (they all are right triangles and have the same, shape.)
The given triangle ΔHFE is similar to triangle GFH and triangle GHE.
What are similar triangles?Similar triangles are two triangles that have the same shape but may differ in size. They have corresponding angles that are congruent and corresponding sides that are proportional.
Here,
Since triangle HFE is similar to triangle GFH,
∠HEF = ∠GHF,
∠FHE = ∠HGF, and ∠HFE = ∠HFG
Similarly
ΔHFE is similar to triangle ΔGHE.
Similar triangles are useful in many areas of mathematics and in the real world, such as in architecture, engineering, and cartography, where they are used to make scale models of buildings and other structures.
Thus, the given triangle ΔHFE is similar to triangle GFH and triangle GHE.
Learn more about similar triangles here:
https://brainly.com/question/12101336
#SPJ2
How many solutions can be found for the system of linear equations represented on the graph?
A) no solution
B) one solution
C) two solutions
D) infinitely many solutions
Answer:
A) No solution
Step-by-step explanation:
Given the systems of linear equations, y = 2x + 1 and y = 2x - 1:
Both equations in the system have the same slope, m = 2, thus forming parallel lines. Since their lines are parallel from each other, then it means that their lines will never intersect.
Therefore, the given systems of linear equation is an inconsistent system that has no solution.
Plzzzzzx help meeeeee
Step-by-step explanation:
first find out the area of sector ECF
π(10)² × 40°/360°
=100π×1/9
=100π/9 m²
now find the area of sector DCG
π(2)² × 40°/360°
=4π/9 m²*
so the area of the shaded region would be the big sector minus the small sector
so
100π/9 - 4π/9
=96π/9
=33.5 m² (3sig.fig.)
*Note that 4π/9 DOES NOT equal to 2π/3
4/9 DOES NOT EQUAL TO 2/3
Write a linear inequality for each graph (back page)
Answer:
I can't read that...........
What is the period of y=2cos(3x-2(3.14))?
A. 3(3.14)
B. 6(3.14)
C. 3(3.14)-2
D. 3(3.14)/3
Answer:
the correct answer is B
Step-by-step explanation:
I got it correct on 2021 edge
help me please !!!!
Answer:
graph X only
Step-by-step explanation:
because with the rate of change it makes a straight line
Please help. ASAP. Work out, giving your answer in its simplest form:
3 1/2 divided by 2 3/5
Answer:
26/35
Step-by-step explanation:
1. First to divide the 3 1/2 by 2 3/5 you have to turn them both into improper fractions
First take 3 1/2. You have to multiply the whole number (3) by the denominator (2) and you would get 6. Then you would add then you add the product (6) to the numerator (1) and get 7.
You keep the denominator the same so the improper fraction is 7/2
Do the same thing to 2 3/5 and the improper fraction is 13/5
2. Now we can divide 13/5 by 7/2 using "keep, change, flip"
Keep: 13/5
Change: division to multiplcation
Flip: 7/2 to make 2/7
Your new equation is 13/5 × 2/7. Multiplcation is easy so you just have to multiply staight across: 13 × 2 and 5 × 7 giving you 26/35
If you divide 35 by 26 you will get 1.34 and a bunch of other numbers but I usually stop at two decimal places
hope this helps :)
FInd the value of T - triangle measerments
JK=JH
[tex]\\ \sf\longmapsto 10t=7t+15[/tex]
[tex]\\ \sf\longmapsto 10t-7t=15[/tex]
[tex]\\ \sf\longmapsto 3t=15[/tex]
[tex]\\ \sf\longmapsto t=15/3=5[/tex]
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
