When firing a handgun, how far should you hold it from your body?

Answers

Answer 1

Answer:

Far away as your hand takes you

Answer 2
As long as your arm, make sure the arm is straight as well

Related Questions

Before the collision, the toy train is travelling at 0.5 m/s. The train and the stationary
truck both have a mass of 75 g.
Calculate the momentum of the toy train before the collision?

Answers

Answer:

Explanation:

p = mv = 0.075(0.5) = 0.0375 kg•m/s

Which scientist is credited with having the greatest contribution to early microscopy and was the first to observe and describe single-celled organisms?

Answers

Answer:

Antonie van Leeuwenhoek

Explanation:

What on earth is equal to 9.8m/s/s

Answers

Answer:

Acceleration due to gravity

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.

What is the acceleration of the SRB and main engine during the first 2.0 minutes of flight?

A. 52 m/s2
B. 13 m/s2
C. 9.8 m/s2
D. 11 m/s2

Answers

A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).

A rocket ship has several engines and thrusters. We can divide its initial movement into 2 parts:

From t = 0 min to t = 2.0 min, the SRB and the main engines act together and the speed goes from 0 m/s (rest) to 1341 m/s.From t = 2.0 min to t = 8.5 min, the main engines alone accelerate the ship form 1341 m/s to 7600 m/s.

We want to know the acceleration in the first part (first 2.0 minutes). We need to consider that:

The speed increases from 0 m/s to 1341 m/s.The time elpased is 2.0 min.1 min = 60 s.

The acceleration of the ship during the first 2.0 minutes is:

[tex]a = \frac{\Delta v }{t} ) \frac{(1341m/s-0m/s)}{2.0min} \times \frac{1min}{60s} = 11 m/s^{2}[/tex]

A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).

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An object moves 45m due East and then 15m due West, the total distance is

Answers

Answer:30m east

Explanation: 45m-15m=30m, which cancels out the one to the west. All that is left is 30m east.

Is this a test/quiz btw?

what is the approximate distance from the surface of the earth center 2900km 700km 50000km 6400km

Answers

Answer:

6400km is the closest

Explanation:

Pushing a chair is a law of______?

A. Law of friction
B. Law of interaction
C. Law of acceleration
D. Law of universal gravitation​


please help..

Answers

I believe your answer would be A. Due to the friction of pushing the chair while it’s on the floor

Answer:

A.Law of friction

Explanation:

because friction is the move chair floor

an electric field is 16 n/c northwest. that makes it a

a) magnitude
b)direction
c)vector
d)scalar

Answers

16 n/c to the northwest lies an electric field. hence it qualifies as a direction. Thus, the correct response is (b). It is assumed that the field's direction corresponds to the direction in which a positive test charge should experience force.

With a positive point charge, the electric field radiates outward, whereas with a point charge that's negative, it radiates in.

How big and which way is the electric field pointing?

A positive point charge is pointed directly away by the electric field, while a negative point charge is pointed directly inside the opposite direction. When you go away again from point charge, the power of the electrical field diminishes as 1 / r 2 1/r21, slash, r, square.

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Answer:

c)vector

Explanation:

I got it right :)

Which of Newton’s Laws of motion help explain the following scenario?
A paddle wheel boat pushes on the water and the water pushes back causing the boat to move

Answers

Answer:

Newton #3

Explanation:

For every action there is an equal and opposite reaction.

ILS) Retake question
If you saw these 2 structures in a cell, you would definitely be looking at an animal
cell.

Answers

Answer:

lysosome,flagellum are the 2 structures in a cell

WILL DO BRAINLIEST A jar contains seven pink, 6 orange, and four blue marbles. If you pick one without looking, what is the probability that the marble you pick will be orange?
6/10
6/17
11/17
7/11

Answers

Answer:

Choice 2: 6/17

Explanation:

4+7=11. 6+11= 17. so it's 6/17

Why does air pressure decrease with increasing altitude? (Select all that apply.)
Colder air is less dense.
The weight of the air below is smaller.
Less air above pushes down.
Hot air rises.
The weight of the air above is smaller.
There is more air below to push up more strongly

Answers

The air pressure decrease with increasing altitude as less air above pushes down and the weight of the air above is smaller.

When the temperature cools, molecules often slow down and they do not move and bump into each other.

When altitude increases, the amount of gas molecules in the air also decrease.

The air becomes less dense than air nearer to sea level.

When the atmospheric pressure is high at lower altitudes, the density being higher.

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Which of the following scenarios would have the MOST friction force between the object and the surface?
A. a 7 kilogram bicycle with rubber tires on concrete
B. a 7 kilogram bicycle with rubber tires on ice
C. a 0.25 kilogram toy car with rubber tires on ice
D. a 0.25 kilogram toy car with rubber tires on concrete

Answers

Answer: A

Explanation: mass and friction are proportional if the mass increases the friction increases

During a ball in the cup lab students notice that a ball rolling horizontally on the table pass through two photogates .30 meters apart in 0.133 seconds. They measure the height of the table to be 0.85 meters. Determine the distance away from the tables edge the students must place a cup to catch the ball to complete the activity?

Answers

Answer:

2 meters

Explanation:

Colette launches an air rocket in the upward, positive direction. It launches with an initial velocity of 25.5 m/s. It accelerates in the downward, negative direction at a rate of 9.81 m/s2. After 3.5 seconds, what is the magnitude of the rocket's displacement?

Answers

Answer:

Give me some hint please

Explain the difference in how a concave lens and a convex lens affect an object's appearance.

Answers

Answer: Varies

Explanation: Concave lens curve inward while convex lens are outward.

Answer:

CONCAVE LENS:

concave lens is thinner in the middle and thicker at the edges. it is also called diverging lens.image formed is virtual and smaller than the object. it's focal length is always negative. it is used for the correction of problem of short sight. Appear smaller and farther. Used to Correct myopia.Curves inward.

CONVEX LENS:

convex lens is thicker in the middle and thinner at the edges. it is aso called converging lens.image formed is real and inverted. it's focal length is always positive. used for the correction of problem of long sight. Appear closer and larger. Used to Correct hyperopia.Curves outward.

Explanation:

Vesta is a minor planet (asteroid) that takes 3.63 years to orbit the Sun.
Calculate the average sun -Vesta distance

Answers

Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.

According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]

Where;

T = period of the planet

r = average distance of the planet

When;

T =  3.63 years

r = [tex]\sqrt[3]{T^2}[/tex]

r = [tex]\sqrt[3]{(3.63)^2}[/tex]

r = 2.36 AU

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For a horizontally projectile object if the initial velocity doubled, the Vertical displacement (angle y) will be :

Answers

Answer:

Unchanged

Explanation:

horizontal projection always has initial vertical velocity equal to zero.

gravity works pretty much the same at any point on earth and will accelerate any falling object at the same rate traveling the same vertical distance in the same time. Neglecting air resistance of course.

By the way, Δy is read "delta y" not "angle y" which would be "∠ y"

delta represents a change in something, in this case the y coordinate.

Question 2 of 5 Which two statements are true for both compounds and mixtures? A. They can be separated into two or more elements. B. Their particles all have the same chemical formula. C. Their particles are held together by chemical bonds. D. They are made up of more than one type of atom.​

Answers

Answer:

D and A

I'm not sure about A lol

A driver entering the outskirts of a city takes her foot off the accelerator so that the car slows down from 90 km/h to 50 km/h in 10.0s. Find the car’s average acceleration

Answers

Answer:

Explanation:

a = (vf - vi) / t

a = (50 - 90) / 10.0

a = -4 km/h/s(1000 m/km / 3600 s/h)

a = - 1.11 m/s²

need some help plsss!

Answers

Answer:

1and4attract and1and 2repel

Which force, in real life, will have the least effect on a bowling ball rolling down a lane toward bowling pins?

A) magnetism

B) air resistance

C) gravity

D) friction

Answers

Answer:

Its Friction

Explanation:

the pins are not floating and they are not a magnet and not involved with air

The force, in real life, that will have the least effect on a bowling ball rolling down a lane toward bowling pins is magnetism. The correct option is A.

What is magnetism?

Magnetism is basically the force which indeed magnets exert when they attract or even repel one another. The movement of electric charges resulting in magnetism.

Every substance is composed of tiny units referred to as atoms. Each atom contains electrons, which are charged particles.

To increase stability, the pins themselves have a low center of gravity. Because they are spherical in shape, they can roll and strike other pins in a variety of directions.

The force acting on the bowling ball is friction and air resistance. The friction force is equal to the friction coefficient multiplied by the normal force, and thus mass times acceleration.

Thus, the correct option is A.

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Which language style would be most appropriate for the given situation?
dinner at a neighbor's birthday party
o informal language
o formal language
o technical language

Pls help

Answers

Answer:

informal language

Explanation:

you do not need to be formal! you are not at a business conference. technical is not needed either since you are not discussing the intricacies of your job or some computer language.

Option B.
Consider a setup in which two springs are attached to a mass in parallel.
Convince yourself that in this setup, the compression of each spring must be the same. Using
this fact, derive the effective spring constant for springs in parallel
This is asking, "ll1 replace the two springs by a single imaginary spring, what would its spring
constant be such that the force stays the same?" Your answer should only depend on k, and k

Answers

Answer:

it would be...

Explanation:

A 15 g bullet is fired at 630 m/s into a 4.9 kg block that sits at the edge of a 75-cm-high table. The bullet embeds itself in the block and carries it off the table.

How far from the point directly below the table's edge does the block land?

Answers

The horizontal distance traveled below the table's edge is 29.4 cm.

The given parameters;

mass of the bullet, = 15 g = 0.015 kgspeed of the bullet, = 630 m/smass of the block, = 4.9 kg

The final velocity of the bullet-block system is calculated as follows;

[tex]m_1 u_1 + m_2u_1 = v(m_1 + m_2)\\\\0.015(630) + 4.9(0) = v(0.015 + 4.9)\\\\9.45 = 4.915 v\\\\v = \frac{9.45}{4.915} \\\\v = 1.923 \ m/s[/tex]

The time for the bullet-block system to reach the ground from the table is calculated as follows;

[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.75}{9.8} }\\\\t = 0.153 \ s[/tex]

The horizontal distance traveled below the table's edge is calculated as follows;

[tex]X = vt\\\\X = 1.923 \times 0.153\\\\X = 0.294 \ m\\\\X = 29.4 \ cm[/tex]

Thus, the horizontal distance traveled below the table's edge is 29.4 cm.

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In a car crash, how are force, mass, acceleration, and velocity related?

Answers

Answer:

the answer is simple but click on the brainiest and thank me.

Explanation:

F=force, m=mass, a=acceleration, v=velocity

v=displcement/time

a= v/t

F= m×a

F= m× (v/t)

Market researchers were interested in the relationship between the number of pieces in a brick-building set and the
cost of the set. Information was collected from a survey and was used to obtain the regression equation ý =
0.08x + 1.20, where x represents the number of pieces in a set and ŷ is the predicted price in dollars) of a set.
What is the predicted price of a set that has 500 pieces?
$40
$41.20
$600
$6,235

Answers

Plug in 500 for x and solve. 500(0.08) = 40

Then do 40 + 1.2 = 41.20

Answer B

50 Points Help Asap !!

Briefly describe V-T graph For every point please if its increasing if its flat or if its positive or negative help fast

Answers

#A

It's flat as no change can be seen on the graph of A part

#B

Its increasing as the line goes up in B part.

#C.

It's flat as no change can be seen on the graph of C part

#D

It's decreasing as the graph goes down in D part.

#E

It's decreasing as the graph goes down in E part

#F

It's decreasing as the graph goes down in F part.

#G

It's increasing as the graph goes up in G part.
G partt hope helpsss

1
2) Mighty Mouse can lift seven mammoths with a total mass of 525 kg. Using the acceleration of
gravity, find the total WEIGHT that Mighty Mouse is lifting. (answer: 5250 N)

Answers

Answer:

5250N

Explanation:

Weight= Mass × acceleration due to gravity

= 525kg × 10m/s^2

= 5250N

Why are electromagnetic waves used to transmit signals?

Answers

Because everybody who is trying to receive signals is using an electromagnetic wave receiver. If you used anything else to transmit your signals, the person looking for your signals would never know when they show up.

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