When heat is applied to 80 grams of CaCO3, it yields 39 grams of CO2. Determine
the percentage of the yield.

Answer:

(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.

Answer:

0.702M

Explanation:

Molarity of a solution, which refers to the molar concentration of that solution can be calculated thus;

Molarity = number of moles (n) ÷ volume (V)

Firstly, we convert 18.5 grams of NaCl to moles using the formula; mole = mass/molar mass

molar mass of NaCl = 23 + 35.5 = 58.5g/mol

mole = 18.5/58.5

mole = 0.32moles

Volume of water (V) = 450mL = 450/1000 = 0.450L

Molarity = n/V

Molarity = 0.32/0.450

Molarity = 0.702M

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

a. Moles NH3 -Molar mass. 17.031g/mol-

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

Answer:

a) NH₃ is the limiting reactant

b) 44.1 g NO

c) 39.7 g H₂O

Explanation:

The chemical equation is the following:

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(l)

According to the balanced chemical equation, 4 moles of NH₃ reacts with 5 moles of O₂ to produce 4 moles of NO and 6 moles of H₂O.

a) To determine which is the limiting reactant we have to compare the stoichiometric amounts of reactants (NH₃ and O₂) with the actual amounts.

Stoichiometric amounts:

Molecular weight of NH₃= 14 g/mol + (1 g/mol x 3) = 17 g/mol

Stiochiometric amount of NH₃ = 4 moles NH₃ x 17 g/mol = 68 g NH₃

Stiochiometric amount of O₂ = 5 moles

⇒ Stiochiometric ratio = 68 g NH₃/5 moles O₂

Then, we multiply the stoichiometric ratio by the actual amount of O₂ to calculate the required amount of NH₃:

required NH₃ = 4 moles O₂ x 68 g NH₃/5 moles O₂ = 54.4 g NH₃

Thus, we need 54.4 grams of NH₃ to completely react with 4 moles of O₂, but we only have 25 grams of NH₃. Therefore, NH₃ is the limiting reactant.

b) To calculate the amount of NO formed, we use the limiting reactant (NH₃). According to the equation, 4 moles of NH₃ produce 4 moles of NO.

Molecular weight NO = 14 g/mol + 16 g/mol = 30 g/mol

4 mol NH₃ x 17 g/mol = 68 g NH₃

4 mol NO x 30 g/mol = 120 g NO

⇒ Stiochiometric ratio = 120 g NO/68 g NH₃

Now, we multiply the stoichiometric ratio by the actual amount of NH₃ to calculate the mass of NO formed:

NO formed = 25 g NH₃ x 120 g NO/68 g NH₃ = 44.1 g NO

c) According to the chemical equation, 4 moles of NH₃ (68 g) produce 6 moles of H₂O.

Molecular weight H₂O = (2 x 1 g/mol) + 16 g/mol = 18 g/mol

6 mol H₂O x 18 g/mol = 108 g H₂O

⇒ Stoichiometric ratio = 108 g H₂O/68 g NH₃

Finally, we multiply the stoichiometric ratio by the actual amount of NH₃ (limiting reactant) to obtain the mass of H₂O formed:

H₂O formed = 25 g NH₃ x 108 g H₂O/68 g NH₃ = 39.7 g H₂O

Answer:

C2H4O2

Explanation:

because you do mr of CH2O= 12+2+16=30

so 60÷30=2 empirical units

so CH2O × 2=C2H4O2

hope this helps :)

The Empirical formula of the given compound is CH₂O

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

Empirical formula mass  = 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol

Molecular formula mass / Empirical formula mass = 60 g/mol / 30 g/mol

                                                                                   = 2

Molecular formula = 2 × CH₂O = C₂H₄O₂

Empirical formula = CH₂O

Empirical formula mass  = 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol

Therefore, The Empirical formula of the given compound is CH₂O

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Answer:

Irrigation is the artificial process of applying controlled amounts of water to land to assist in production of crops. Irrigation helps to grow agricultural crops, maintain landscapes, and revegetate disturbed soils in dry areas and during periods of less than average rainfall.

Answer: The watering of crop plants in regular intervals is known as irrigation. ... Weeds are unwanted plants thet grows with the crop plants. Weeding means to remove those plants. It is done manually or by machine. Using khurpi it is done manually and using seed drill it is done by machine.

Explanation:

Irrigation is the artificial application of water to the soil through various systems of tubes, pumps, and sprays. Irrigation is usually used in areas where rainfall is irregular or dry times or drought is expected.

Hope it helps

Answer:

answer: B or D

Explanation:

hope it helps thanks❤

Answer:

correct

Explanation:

I belve ou got it

Answer:

b

Explanation:

because it's more orange in the boxes then others

Answer:

Nitrogen has 5 valence electrons

Explanation:

nitrogen has it's attoms form triple bonds which are very hard to break

so non-reactive

Answer:

C. All of the above

Explanation:

They all happen beyond critical point.

Explanation:

heat and pressure are two main forces that transform organic matter into fossil fuels

Answer:

3) 9.1 x 10^3 J

Explanation:

Question : Which issue surrounding nuclear power creates the biggest concern?

Answer : How to deal with the radioactive waste (B)

The following issues surrounding nuclear power that create the biggest concern is What nuclear power should be used for?

Nuclear powers are those powers that are produced by nuclear reactions. These reactions include nuclear fission, nuclear fusion, and nuclear decay. Nuclear power is currently in use to produce electricity. The reaction uses uranium and plutonium reaction to produce electricity.

Nuclear power is used for generating electricity, and it is necessary to use the correct radioisotopes to produce electricity.

Thus, the correct option is D. What nuclear power should be used for?

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Answer: D

Explanation:

Answer:

Explanation:

meiosis

Haploid sperm and eggs are produced via meiosis.

Answer:

Sb

Explanation:

Sb (antimony) is an metalloid

Answer:

16.12 V

Explanation:

Ohms law explains or portrays the relationship between the voltage (V), current (I) and resistance (R). This is represented using the equation as follows:

V = IR

Where;

V = voltage (Volts)

I = current (amperes)

R = resistance (ohms)

According to the information provided in the question, resistance (R) = 13 Ohm, current (I) = 1.24 Amperes, V = ?

V = 13 × 1.24

V = 16.12 V

32.7 g Zn

Explanation:

First convert the amount of gas into moles:

11.2 L H2 × (1 mol H2/22.4 L H2) = 0.500 mol H2

Then use the molar ratio to find the amount of zinc necessary to produce the amount of gas above:

0.500 mol H2 × (1 mol Zn/1 mol H2)

= 0.500 mol Zn

Now use the molar mass of zinc to find the number of grams of zinc for the reaction to occur:

0.500 mol Zn × (65.38 g Zn/1 mol Zn)

= 32.7 g Zn

Answer:

oxidation, synthesis, polymerization.

Answer:

Red: 17.24%

Yellow: 32.76%

Green: 50%

Explanation:

Answer:

the energy of the products is less than the energy of the reactants.

Explanation:

the the change is enthalpy is negative, and heat is released to the surroundings.

When liquid 5.0 molar NiCl₂ is added to 0.3 M of NiCl₂ solution :  

  Molarity will increase  ( A )

What is Molarity ?

Molarity is the measure of the number of moles of solute present per volume of the solution. The addition of 5.0 molar nickel chloride into a 0.3M Nickel chloride solution will lead to an increase in the number of moles of Nickel chloride present in the solution.

Molarity is directly proportional to moles of solute in a solution therefore the molarity of the solution will increase.

Hence we can conclude that When liquid 5.0 molar NiCl₂ is added to 0.3 M of NiCl₂ solution :   Molarity will increase.

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Answer:

It lead to scientific breakthroughs in chemistry.

Explanation: