When performing the ipconfig command, what does the following output line depict if found in the tunnel adapter settings?
IPv6 Address: 2001:db8:0:10:0:efe:192.168.0.4
a. IPv6 is disabled.
b. The addresses will use the same subnet mask.
c. The network is not setup to use both IPv4 and IPv6.
d. IPv4 Address 192.168.0.4 is associated with the global IPv6 address 2001:db8:0:10:0:efe

Explanation:

The following six steps must be followed to solve a problem using computer.

Problem Analysis.

Program Design - Algorithm, Flowchart and Pseudocode.

Coding.

Compilation and Execution.

Debugging and Testing.

Program Documentation.

Which XXX declares a student's name.

public class Student {

   XXX

   private double myGPA;  

   private int myID;

   public int getID() {

        return myID;

   }

}

Group of answer choices

a. String myName;

b. public String myName;

c. private myName;

d. private String myName;

private String myName;

To declare a student's name, the following should be noted.

i. The name of the student is of type String

ii. Since all of the instance variables (myGPA and myID) have a private access modifier, then myName (which is the variable name used to declare the student's name) should be no exception. In other words, the student's name should also have a private access.

Therefore, XXX which declares a student's name should be written as

private String myName;

Option (a) would have been a correct option if it had the private keyword

Option (b) is not the correct option because it has a public access rather than a private access.

Option (c) is not a valid syntax since, although it has a private access, the data type of the variable myName is not specified.

Option (d) is the correct option.

Answer:

Electronic boards

Videoconferencing ability

Search engines

Cloud services

Computing softwares

Explanation:

Technology tools are used to simplify task bring ease, comfort as well as better satisfaction :

The use of electronic boards for teaching is an essential tool for students and educators alike as it provides great features aloowibg teachers to write and make drawings without hassle. This clear visual display goes a long way to aide student's understanding.

Videoconferencing breaks the barrier that distance and having to travel bring swhen it comes to learning. With this tools, students and educators can now organize classes without having to be physically present un the same class room.

Search engines : the means of finding solutions and hints to challenging and questions is key. With search engines, thousands of resources can now be assessed to help solve problems.

Cloud services : this provud s a store for keeping essential information for a very long time. Most interestingly. These documents and files can be assessed anywhere, at anytime using the computer.

Computing softwares : it often seems tune consuming and inefficient solving certain numerical problems, technology now p ovide software to handles this calculation and provides solutions in no time using embedded dded to codes which only require inputs.

Answer: Its............ A Chromebook type of Chromebook...??

Explanation:

Ion know I aint a geek, geezer -_- (Thats a lie)

Answer:

A. true

Explanation:

because 5s is the.................

Answer:

128 KB      

Explanation:

Given data :

The block size = 512 bytes

Block pointer size = 2 bytes

In an indexed allocation, a special block named Index Block contains all the pointers to the blocks that the file had occupied.

Therefore, the maximum number of block pointer in 1 block :

[tex]$=\frac{\text{block size}}{\text{pointer size}}$[/tex]

[tex]$=\frac{512}{2}$[/tex]

= 256

Thus, a block can hold maximum 256 pointers.

It is given the level of indexing is one. So,

Maximum size of the file =  maximum number of block pointers in 1 file x block size

                                          = 256 x 512

                                          [tex]$=2^8 \times 2^9$[/tex]

                                          [tex]$=2^{8+9}$[/tex]

                                           [tex]$=2^{17}$[/tex]

                                          [tex]$=2^7 \times 2^{10}$[/tex]

                                          [tex]$=128 \times 2^{10}$[/tex]

                                          = 128 KB   (∵ 1 KB = [tex]2^{10} \ B[/tex] )

Therefore, the largest file that 1 level if indexed allocation method can handle is 128 KB.

Answer:

False

Explanation:

They are not applied in the hardware and software of information systems.