When the filament breaks in one lamp in a parallel circuit, lamps in other branches of the circuit normally continue glowing as brightly.
What is Parallel Circuit Connection ?There are precisely two sets of electrically common points formed by the connections of all parts across one another. A path for electrical current created by one of the load components is referred to as a "branch" in a parallel circuit (such as a resistor).
The fact that it is all connected in parallel sequences, hence the name, is a crucial component of the "parallel" circuit. The "rungs" on either side of this sort of circuit must be descended for a current to pass through each component.
Aparallel circuit's characteristics :
The identical two places are joined by each gadget.The parallel branches divide the circuit's overall current.The overall current in the circuit is equal to the sum of the currents in the parallel branches.As the number of branches increases, the circuit's total resistance lowers.To learn more about parallel circuit refer to :
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you thoughtfully set a 1 kg box on top of a loaf of bread and the loaf compresses by 15 cm. Thinking of the bread as a spring, its spring constant is
Answer:
k = 65.3 N/m
Explanation:
Fs = Fg = mg = (1.0 kg)(-9.8 m/s²) = -9.8 N
x = 15 cm = 0.15m
Fs = -kx (Hooke's Law)
-k = Fs/x = (-9.8 N)(0.15 m) = -65.3
k = 65.3 N/m
In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is :A4×10 −3voltB2.5×10 −2voltC40 voltD2.5×10 5volt
In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is D) 2.5 × 10⁵ volt.
given that :
V = 100 v
R = 1Ω
ω = 200 rad/s
C = 2μF
ω² = 1 / LC
(200)² = 1/ L × 2 × 10⁶
L = 12.5 H
current = 100 A
now, at resonance ,
voltage across the L is equals to voltage across C
voltage across L = 100 × ( 1 / 200 × 2 × 10⁶)
voltage across L = 2.5 × 10⁵ volt.
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The linear density of a string is 1.6 10-4 kg/m. A transverse wave on the string is described by the equation y = (0.021 m) sin[(2.7 m-1)x + (20 s-1)t].what is the wave speed?what is the tension in the string?
The required wave speed and tension in the string are 15 m/s , 0.036 N respectively.
What is speed?Speed is characterized as. The pace of progress of position of an item toward any path. Speed is estimated as the proportion of distance to the time in which the distance was covered. Speed is a scalar amount as it has just course and no extent.
According to question:(a) The wave speed is given by v=λ/T=ω/k,
where λ is the frequency, T is the period ω is the precise recurrence (2π/T), and k is the rakish wave number(2π/λ).
The displacement has the structure y=y sin(kx+ωt), so 4k=2.0m
furthermore, ω=30 rad/s.
Hence v=(30 rad/s)/(2.0m)=15 m/s.
b) Since the wave speed is given by v= τ/μ
, where τ is the pressure in the string and μ is the straight mass thickness of the string, the strain is
τ=μv =(1.6×10 kg/m)(15 m/s) =0.036 N.
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a man who is 6 feet tall is walking away from a lamp post at a rate of 5 feet per minute the lamp post is 20 feet tall the person casts a shadow on the ground in from of them
(a) The growing rate of shadow when the person is 30 ft from the lamp post is 15/7 ft/m
(b) The moving rate of the tip of the shadow when the person is 30 ft from the lamp post is 50/7 ft/m
Given,
Height of the man = 6 ft
Height of the lamp post = 20 ft
[tex]\frac{dx}{dt} =5 ft/m[/tex]
Let,
The distance between the base of lamp and the man = x
From the geometry,
[tex]\frac{6}{20} =\frac{y}{x+y}[/tex]
[tex]6(x+y) = 20y[/tex]
[tex]3x=7y[/tex] .......................(1)
And,
[tex]6(\frac{dx}{dy} )=14(\frac{dy}{dt} )[/tex]
[tex]\frac{dy}{dt}=\frac{15}{7}[/tex]
∵ [tex]\frac{dx}{dt} =5 ft/m[/tex]
∴ [tex]\frac{dx}{dt}+\frac{dy}{dt} =5+\frac{15}{7}[/tex][tex]=\frac{50}{7}[/tex]
Hence,
(a) The growing rate of shadow when the person is 30 ft from the lamp post is 15/7 ft/m
(b) The moving rate of the tip of the shadow when the person is 30 ft from the lamp post is 50/7 ft/m
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A car is making a tight turn at 20m/s. What is the acceleration if the radius of the turn is
1.5m?
The acceleration of the car is 26.67 m/s^2.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
Given that: A car is making a tight turn at 20m/s.
the radius of the turn is 1.5m.
Hence, the centripetal acceleration of the car= speed^2/radius
= (20^2)/1.5 m/s^2.
= 26.67 m/s^2
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Induction charging is a method used to charge an object without actually touching the object to any other charged object.the process by which an object receives a static charge when placed near a second charged object is known as
Induction charging is a method used to charge an object without actually touching the object to any other charged object. The process by which an object receives a static charge when placed near a second charged object is known as inductance.
Induction charges another body without came in contact with that body.
During induction, charges move between objects that briefly touch; during conduction, charges move between objects that are rubbed together.
if the charges have the same sign, then the force is repulsive, this means that the forces point away from each other, so in this case the forces have opposite directions.
Charging by conduction refers to the contact of a charged object to a neutral object, which is the opposite of induction.
Charging by induction refers to charging an object without making contact, it could be through an electric field.
Therefore, the induction charging is a method used to charge an object without actually touching the object to any other charged object. The process by which an object receives a static charge when placed near a second charged object is known as inductance.
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Assume a small spacecraft is in open space. One panel is a dedicated radiator (dimensions in image) and is painted with S13 GLO white paint (emissivity = .89). If the radiator is at 30C and has a full view factor to space, how much heat can it reject from the system? (How much is this radiator radiating to space?). Use 3K for space temperature. Round answer up to one decimal place. No need to include units.
This radiator's Heat radiation is 12.8 W.
Provided, the temperature of the radiator θ = 30°C
So, the absolute temperature of the radiator,
T = ( θ + 273 ) K
= ( 30 +273 ) K
= 303 K
Also provided, the temperature of the surrounding space, T₀ = 3 K
The emissivity of the white paint, ε = 0.89
The length of one side of the radiator, L = 0.3m and the breadth, B = 0.1m.
Now, the amount of rate of heat transfer by a system at temperature T to a surrounding space at temperature T₀ is given by the formula,
Q = σεFA(T⁴-T₀⁴).
where A is the area of the system exposed to the surrounding, F is the view factor, σ is the Stefan-Boltzmann constant = 5.67 × 10⁻⁸Wm⁻²K⁻⁴ and σ is the emissivity of the system.
Here, the surface area of the radiator,
A = LB = (0.3m) (0.1m) = 0.03 m²
According to the question, the radiator has a full view factor to the space, i.e. we can say, the view factor in this case is, F = 1.
Substituting all known values into the equation we just mentioned we get,
Q = σεFA(T⁴-T₀⁴)
= (5.67 × 10⁻⁸Wm⁻²K⁻⁴) (0.89) (1) (0.03 m²) [ (303K)⁴ - (3K )⁴ ]
= 12.76 W
≈ 12.8 W
So, the rate of heat radiation is, Q = 12.8 W
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the gravitational force exerted on a solid object is 5.00 n. when the object is suspended from a spring scale and submerged in water, the scale reads 3.50 n (fig. p14.11). find the density of the object
Density of the object is 3333.33 kg/m³.
Density can be defined as the ratio of the mass of a body to its volume.
The SI unit of density is kg/m³.From Archimedes principle,
Rd = W/U = D/D'
Where Rd = relative density,
W = weight of the object in air,
U = upthrust in water,
D = Density of the object,
D' = Density of water.
W/U = D/D'
Density (D) of the solid can be calculated by the equation,
D = D'(W/U)
As we have,
W = 5.0 N,
U = 5.0 -3.5 = 1.5 N,
D' = 1000 kg/m³
Since U = lost in weight = weight in air - weight in water
D = 1000(5/1.5)
D = 3333.33 kg/m³
Thus the density of the solid object is 3333.33 kg/m³
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a rectangular coil of wire, 22.0cm by 35.0cm and carrying a current of 1.95a , is oriented with the plane of its loop perpendicular to a uniform 1.50 t magnetic field
If the plane of the loop is perpendicular to the magnetic field then the θ will be zero. Torque will likewise be 0 at that point.
Given that, a rectangular coil of wire, 22 cm by 35 cm and carrying a current of 1.95 A, is oriented with the plane of its loop perpendicular to a uniform 1.50 T magnetic field.
The strength of magnetic torque on the current-carrying circle is given by the below formula, if θ is the angle between A and B. Then we have
τ = I AB sin θ
When the loop plane is perpendicular to the magnetic field, the amplitude of magnetic torque on the current-carrying circle is zero.
Then θ = 0°
Then we have,
τ = I AB sin 0° = 0
The question is incomplete. The complete question is 'Find out the torque in the coil.'
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an object is in the air above a flat water surface. to an observer underwater looking up at it, it will appear to be higher than its true position.
The angle from which the light rays reach your eyes is greater than the angle they would in air because air and water have virtually the same index of refraction of 1.
Do objects appear larger when viewed from above the water when submerged?The refractive index of water is 4/3 that of air, and light rays are bent away from the normal when they enter air from water, therefore there is no doubt that objects are optically magnified.
Underwater, do objects become heavier or lighter?A: The mass of items does not change when they are submerged in water. But because of buoyancy, they appear to feel lighter.
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For a three-slit interference pattern, find the ratio of the peak intensities of a secondary maximum to a principal maximum.
In the 3-slit interference pattern, the secondary peak intensity is always half the principal maximum intensity. Therefore, the ratio of the peak intensity of the secondary peak to the primary peak is 1/2.
To understand why this is, consider the constructive interference that occurs at the main maxima. This occurs when the path difference of the waves reaching the screen through each slot is equal to an integer multiple of the wave's wavelength.
This gives us strong intensities at these points, which are the main maxima. On the other hand, at the second-order maximum, the path difference of the waves reaching the screen through each slit is equal to an odd multiple of half the wavelength of the wave.
This results in weaker intensity at these locations, which are secondary maxima. Since the sidelobe intensity is weaker than the main lobe, the ratio of the peak intensity of the sidelobe to the main lobe is 1/2.
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The figure shows a block of mass m resting on a 20 degree slope. The block has coefficients of friction us(static friction)=0.64 and uk(kinetic friction) with the surface slope. It is connected using a very light string over an ideal pulley to a hanging block of mass 2.0 kg. The string above the slope pulls parallel to the surface. What is the minimum mass m so the system will remain at rest when it is released from the rest?
The figure shows a block of mass m resting on a 20 degree slope. As the system is at rest For the equilibrium of 2 kg block
What is mass ?
A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.A measurement of how much matter is present in or makes up a physical body. In classical mechanics, an object's mass is crucial to Newton's laws of motion because it influences the force needed to accelerate it and, consequently, how much inertia it has.
[tex]$$\begin{aligned}& T-2 k g \times 9.8 \mathrm{~m} / \mathrm{s}^2=0 \\& T=2 \mathrm{~kg} \times 9.8 \mathrm{~m} / \mathrm{s}^2=19.6 \mathrm{~N}\end{aligned}$$[/tex]
For the equilibrium of second block
[tex]$$\begin{aligned}& T=m g \sin 20^0+f \\& T=m g \sin 20^0+\mu_s R \\& T=m g \sin 20^0+\mu_s m g \cos 20^0 \\& T=m\left(g \sin 20^0+\mu_s g \cos 20^0\right) \\& m=\frac{T}{\left(g \sin 20^0+\mu_s g \cos 20^0\right)} \\& m=\frac{19.6 N}{\left(9.8 \mathrm{~m} / \mathrm{s}^2 \sin 20^0+0.64 \times 9.8 \mathrm{~m} / \mathrm{s}^2 \cos 20^0\right)} \\& m=\frac{19.6 \mathrm{~N}}{9.25 \mathrm{~m} / \mathrm{s}^2}=2.12 \mathrm{~kg}\end{aligned}$$[/tex]
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(b) the current-carrying wire is within the earth's magnetic field. as a result, the pattern drawn in fig. 6.1 is superposed with the horizontal component of the earth's magnetic field. fig. 6.2 shows a plan view of the plane abcd with the current in the wire coming out of the plane.
The horizontal component of the earth's magnetic flux density at point P is approximately 0.43 T.
To determine the location of point P, where the magnetic field due to the current-carrying wire is equal and opposite to the earth's magnetic field, we can use the equation for the magnetic flux density of a long, straight wire:
B = μ0 × I / (2 × π × r)
We are given that the distance from the center of the wire to point P is 1.9 cm and the current in the wire is 1.7 A. Therefore, we can solve for the value of the horizontal component of the earth's magnetic flux density at point P:
B = μ0 × 1.7 A / (2 × π × 0.019 m)
= 4π × [tex]10^{-7}[/tex] × 1.7 A / (2 × π × 0.019 m)
= 0.43 T
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again, in just a couple of sentences, briefly consider the reason for visible differences between one wavelength image's contents versus another's.
Understanding an object's structure and function requires observation at a variety of wavelengths.
We perceive at different wavelengths for what reason?This is due to the fact that we have just lately been able to view the complete electromagnetic spectrum of the universe.There are objects in our universe that emit a wide variety of radiation having wavelengths either being too short or long for human eyes to see.
Why do astronomers capture photos using different wavelengths of light?Astronomers can learn something distinctive about an item by examining its light at various wavelengths.Astronomers may see "the broad picture" of what's actually happening with that object by examining all available wavelengths and developing models that account for everything those photographs show.
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On a baseball field, first base is about 30 m away from home plate and second base is 30 m away from first base. A batter gets a hit and makes it to second base. What is the hitters final displacement from home plate?
The hitters final displacement from home plate is 60 m.
What is displacement?The displacement of an object is the change in the position of the object.
The displacement of an object is determined from the shortest distance between the initial position and the final position of an object.
The hitters final displacement from home plate is calculated as follows;
Δx = x₁ - x₂
where;
x₁ is the initial position x₂ is the final positionΔx = x₁ - x₂
Δx = 30 m - ( - 30 m)
Δx = 30 m + 30 m
Δx = 60 m
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Which em spectrum pass through our atmosphere most easily?
Visible light, gamma ray, infrared radiation, or radio waves??
Answer:
Gamma Ray but read below
Explanation:
All of the types of electromagnetic radiation listed can pass through Earth's atmosphere, although some types are absorbed or blocked more easily than others.
Visible light, infrared radiation, and radio waves are able to pass through the atmosphere relatively easily, while gamma rays are more likely to be absorbed.
This is because gamma rays have a higher energy than the other types of radiation, so they are more easily absorbed by the atoms and molecules in the atmosphere.
Answer:
Gamma Rays
Explanation:
It has the highest possible frequency lowest wavelength and the most energetic charge. Its travels at the speed of light and is highly penerative
the activation energy of the forward reaction is equal to the sum of the activation energy for the reverse reaction and the enthalpy change for the forward reaction.
No, the activation energy for a forward reaction is not equal to the activation energy for the reverse of the same reaction.
In order for compounds to undergo a chemical reaction, a certain amount of energy is required, known as the activation energy. The unit of measurement for a reaction's activation energy (Ea) is either joules per mole (J/mol), kilojoules per mole (kJ/mol), or kilocalories per mole (kcal/mol). You can think of activation energy as the size of the potential barrier between the minima of the potential energy surface related to the initial and final thermodynamic states, which is also referred to as the energy barrier. If the system temperature is high enough, there should be a sizable number of molecules with translational energies that are equal to or higher than the activation energies.
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A job is done slowly, and an identical job is done quickly. Both jobs require the same amount of.... but different amounts of...
Answer:
work, power
Explanation:
Work = Fnet x distance
Work is NOT dependent on time
Power = Work ÷ time
The slower the work is done, the higher the power. The faster the same amount of work is done, the lower the power. Power, with work constant, is inversely proportional to time.
1. W= 500 Joules
t = 25 seconds
P = ?
The power is 20w when the work done is 500 joules in 25 seconds.
What is power?The amount of energy transferred or converted per unit time is referred to as power. The watt is the unit of power in the International System of Units, equal to one joule per second. In older works, power is sometimes called activity. A scalar quantity is power.Work divided by time equals power.P = W / T
Another formula for power based on energy and time is :
The formula is P = E/t, where P represents power, E represents energy, and t represents time in seconds. According to this formula, power is defined as the consumption of energy per unit of time.Here given,
W = 500 J
T = 25 sec
By substituting,
P = W/T
= 500 / 25
= 20w
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which of these situations corresponds to n independent bernoulli trials having the same probability p of success?
The probability mass function is obtained as:
[tex]p(x=x)=12 c_x \quad(0.4)^x(1-0.4)^{1 x-x} ; x=0,1,2 \ldots .12[/tex]
Outcome is,
[tex]n=12 \\ p=0.4[/tex]
Let X be discrete random variable which takes value [tex]$i=1,2 \ldots$[/tex].
Now the probability of mass function at point is is given by:
[tex]p(x=p)=p\left(x_i\right)=F\left(x_i\right)-F\left(x_{(i-1)}\right)[/tex]
By using Bernoulli's random variable:
[tex]P(x=x)=p^x(1-p)^{1-x} x=0,1[/tex]
where as [tex]$x=0 \Rightarrow$[/tex] corresponds to failure
[tex]$x=1 \Rightarrow$[/tex] correspond to Success
p is probability function of Success.
Therefore the total number of Success in ' n ' independent Bernoulli trials is Sum of ' n ' bernoulis random variable which gives binomial distribution.
By using multiplication rule the probability of observing ' x 'Successes in ' n ' independent bernoulli trials it can be written as:
[tex]\underbrace{p \times p \times \ldots \times p}_{x \text { times }} \times(\underbrace{() 1-p) \times(1-p) \times \ldots \times(1-p)}_{n-x \text { times }}[/tex]
The probability mass function :
[tex]p(x=x)=12 c_x \quad(0.4)^x(1-0.4)^{1 x-x} ; x=0,1,2 \ldots .12[/tex]
where as
[tex]n=12 \\ p=0.4[/tex]
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Note:- The question is as follow,
Consider the probability space [tex]$(S, M, P)$[/tex] that models the observed proportion of successes in n independent Bernoulli trials with probability of success equal to p. For example, given n=12 and p=0.4, the outcome [tex]\frac{5}{12}=.41 \overline{6} \:in $(S, M, P)$[/tex] should have the same probability as the outcome of 5 successes in 12 independent Bernoulli trials with probability of success equal to 0.4. Give a formula for the density function f(s) for this probability space in terms of the density [tex]$f_{n, p}$[/tex] of the binomial distribution with size n and probability p. ( points)
find the linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping:
The linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping: A spool of mass m and moment of inertia I (around its center) is free to roll without slipping on a table. It has an inner radius of r and an outer radius of R.
In mechanics, acceleration is the charge of the alternate velocity of an item with recognition of time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the internet pressure acting on that item.
Acceleration, is the price at which speed modifications with time, in terms of each pace and path. A point or an object transferring in an instant line is accelerated if it quickens or slows down. movement on a circle is multiplied although the rate is constant due to the fact the path is always converting.
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A child on a bike traveled 20 m east, and then 30 m north. What was the displacement of the child?
50 m, north
36 m, north
36 m, northeast
50 m, northeast
The displacement of the child is 36 m, northeast.
Define displacement.
Displacement is the difference between an object's starting location and any subsequent position (such as the position of a body or geometric figure). An object's position in relation to a reference frame changes when there is displacement. It is allegedly displaced. The vector quantity displacement has a magnitude and a direction.
Here, imagine
Distance travelled to east is side AB of a right sided traingle,
AB = 20m
Distance travelled to north is side BC of the same triangle ,
BC = 30m
To find total displacement is to find side AC of the above triangle,
According to Pythagorus theorem
(AC)^2= (AB)^2 + (BC)^2
(AC)^2 = (20)^2 + (30)^2
AC = 36m
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Two blocks, A and B (with mass 50 kg and 100 kg, respectively), are connected by a string, as shown in Figure P5.64. The pulley is frictionless and of negligible mass. The coefficient of kinetic friction between block A and the incline is ?k = 0.25. Determine the change in the kinetic energy of block A as it moves from C to D, a distance of 15 m up the incline if the system starts from rest. ____J
The change in the kinetic energy of block A is 1,837.5 J.
What is the change in the kinetic energy of the block?
The change in the kinetic energy of the blocks as it moves through the given distance is the work done in overcoming the force of friction.
Based on the law of conservation of energy, the equation is given as;
ΔK.E = W (f)
Where;
ΔK.E is the change in kinetic energyW (f) is the work done by force of frictionW (f) = μmgd
where;
μ is the coefficient of friction between block and the inclinem is the mass of block Ag is acceleration due to gravityd is the distance travelled by block AThe change in the kinetic energy of the block A is calculated as follows;
W (f) = μmgd
W (f) = 0.25 x 50 x 9.8 x 15
W (f) = 1,837.5 J
Thus, the change in the kinetic energy of block A is a function of work done by force of friction along the incline.
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Two blocks with masses 3m and 4m are on a collision course with the same initial speeds v The block with mass 3m is traveling to the left, and the 4 block is traveling to the right. They undergo a head-on elastic collision and each bounces back, along the same line as it approached. Find the final speeds of the particles (Enter your answers in terms of the initial speed of each mass.) Vam X Apply the final velocity equations for elastic collisions: mi 2m2 11+ 22 m, m2 + 2m m + mm Note that il- lvl = v. Be careful of your signs! Vam
The final velocity equations for elastic collisions is
[tex]$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}$$[/tex]
A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision.
Lat their final speeds of bouncing back are u_1 and u_2 As the collision is clastic, e=1So,u_1+u_2=v_i+v_i=2 v_i
From momentum conservation, 3 m v_i-4 m v_i=4 m u_2-3 m u_1
[tex]$$\begin{aligned}& \Rightarrow \quad-2 v_i=4 u_2-3 u_1 \\& \Rightarrow 3 u_1-5 u_2=2 v_i-\text { (2) }\end{aligned}$$[/tex]
From (1) and (2),
[tex]$$\begin{aligned}u_1+u_2 & =3 u_1-5 u_2 \\\Rightarrow 2 u_1 & =6 u_2 \Rightarrow u_1=3 u_2\end{aligned}$$[/tex]
From (1),
[tex]$3 u_2+u_2=2 v_i$[/tex]
[tex]$$\text { and } \begin{aligned}\Rightarrow u_2 & =\frac{1}{2} v_i \\u_1 & =3 u_2=\frac{3}{2} v_i .\end{aligned}$$[/tex]
So,
[tex]$$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}[/tex]
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two bags of oranges are dropped from a roof at the same time. one bag has two oranges, and the other has 14. which of the following statements is true? A) Bag two is seven times heavier than bag one so it falls seven times faster than bag one.
B) Bag two has seven times the force acting on seven times the mass so it falls as fast as bag one.
C) Bag one is seven times lighter than bag two so it falls seven times slower than bag two.
D) The force acting on bag one and the force acting on bag two are the same.
When two bags of oranges are dropped from a roof at the same time, of which one has two oranges and the other has 14, (d) The force acting on bag one and the force acting on bag two are the same.
Lighter bag and Heavy bag fall at the same time and same rate in vacuum because there is no air resistance and the acceleration in free fall doesn't depend on the mass of the object.
Gravitational force= GMm/R^2
G= gravitational constant(6.67/10^11)
M=mass of Earth
m= mass of object
According to Newton's second law of motion
F=ma
GMm/R^2 = ma
Mass of object gets cancelled. So acceleration of doesn't depend on mass of object.
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6. Which diagram demonstrates how crossing over contributes to genetic diversity during meiosis?
The diagram which demonstrates how crossing over contributes to genetic diversity during meiosis is referred to as option C.
What is Meiosis?This is referred to as a type of cell division in which the parent cells produce four unique daughter cells and it is mostly involved during formation of gametes and sexual reproduction.
Crossing over is a process which occurs between prophase I and metaphase I and involves the exchange of genetic material during the formation of germ cells in an organism and it results in the production of unique combinations and variation in the daughter cells.
This process is also characterized by the chromosomes of the same type being lined up before the exchange takes place which is therefore the reason why option C was chosen as the correct choice.
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Glenn works at the local grocery store and his gross pay is $800. Joe's
withholdings are as follows:
Federal Income Tax - $100.00
State Income Tax = $45.00
Local Income Tax- $20.00
Social Security Tax- $15.00
Medicare Tax - $5.00
401K Contribution - $50.00
a. What is the total dollar amount of withholdings? (2 points)
b. In dollars, what will Glenn's net pay be? (2 points)
Blank #1
Blank #2
a. The total dollar amount of withholdings equals to $185
b. Glenn’s net pay will be $615
What is Withholding?This means the income an employer takes out of an employee's paycheck and remits to the federal, state, and/or local government. A technique used to collect income tax in advance is withholding tax (WHT).
Net pay is what employees earn after all payroll deductions are subtracted from their gross pay, also known as take-home pay. Your payslip will typically include information about your net salary after all deductions have been made, frequently at the bottom. Keep in mind that net pay is your salary less any deductions. This will be in accordance with the sum of money deposited into your bank account.
The total dollar amount of withholdings is:
= Income Tax + State Income Tax + Social Security Tax + Medicare Tax
= $100.00 + $45.00 + $20.00 + $15.00 + $5.00
= $185
The amount of Net pay is:
= Gross pay - Withholdings
= $800 - $185
= $615
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A janitor is pushing an 17-kg trashcan across a level floor at constant speed. The coefficient of friction between can and floor is 0.16. a) if the janitor is pushing horizontally, what is the magnitude of the force he exerts on the can? b) If he pushes at an angle of 30∘ down from the horizontal, what must the magnitude of his pushing force be to keep the can moving at constant speed?
Answer:
a) >26.7 N
b) >13.3 N
Explanation:
a) Fg = (17 kg)(9.8 m/s²) = 166.6 N
Fnormal = Fg = 166.6 N
Ff = μFn = 0.16(166.6 N) = 26.7 N
Janitor needs to push >26.7 N to overcome the Force of friction (Ff) on a horizontal floor.
b) You have to determine Fn on the object by figuring out the y-component of Fg.
Fn/Fg = sin30
Fn = sin30(166.6 N) = 83.3 N
Now you can find Ff.
Ff = μFn = 0.16(83.3 N) = 13.3 N
Janitor needs to push >13.3 N down the incline to overcome Ff
Makes sense that he has to push less down an incline.
after extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the:
After extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the basement, second floor, and attic.
The vertical struts of the outer wall are continuous from the foundation to the roof with a balloon frame structure. When the roof collapses into a structure, it can provide a watertight cover over a buried fire. Heavy wood is more stable than lightweight structures in fire conditions.
Marion of the building is surrounded by balloons, from the foundation to the eaves line he extends upwards more than two stories. A mansard or mansard roof is his four-sided gambrel-style hipped roof characterized by his two slopes on either side, the lower slope pierced with dormer windows and angled more steeply than the upper.
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A 472 kg roller coaster is on top of a 12 m high hill. It starts from rest and then goes down the hill. How fast is
it going when it reaches the bottom?
The roller coaster is going with 15.34 m/s when it reaches the bottom.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.
According to the question, potential energy of the roller coaster at initial position = mass * acceleration due to gravity* height = mgh
Let the speed of the roller coaster at the bottom = v.
So, kinetic energy at the bottom = 1/2 * mass * speed^2 = 1/2 mv^2
From conservation of energy:
mgh = 1/2mv^2
v= √( 2gh)
= √( 2 × 9.8 × 12) m/s
= 15.34 m/s.
Hence, the speed of it at the bottom is 15.34 m/s.
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