Which answers describe the shape below? Check all that apply.
A. Trapezoid
B. Parallelogram
C. Rhombus
D. Rectangle
E. Quadrilateral
F. Square

The answer is d: As x gets closer to 3, the value of g gets closer to 4.

The limit of a function h of x as  x approaches the value a, written as [tex]\lim_{x \to a} h(x) = L[/tex] is the value the function h(x) approaches as x tends to the value "a", written as x → a. In this case, L.

Given the domain and range for function g are D(−∞, ∞) and R(−∞, ∞) and that the limit as x approaches 3 of the function g of x equals 4.

This implies that as x gets closer and closer to 3, the value of g gets closer and closer to 4.

Since the value g gets closer to is 3 as x gets closer to 4, we can write that the limit as x approaches 3 of the function g of x equals 4.

we can write this as

[tex]\lim_{x \to 3} g(x) = 4[/tex]

So, as x gets closer to 3, the value of g gets closer to 4.

So, the answer is d: As x gets closer to 3, the value of g gets closer to 4.

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Answer:

48

Step-by-step explanation:

We need to find the multiples of 8

8,16,24,32,40,48

48 is between 45 and 50 so he must have bought 48

Answer:

6 bottles

Step-by-step explanation:

For this question we need to know the multiple of 8 which are:

8 x 1 = 8

8 x 2 = 16

8 x 3 = 24

8 x 4 = 32

8 x 5 = 40

8 x 6 = 48

8 x 7 = 56

There is only one multiple, which is greater than 45 but less than 50, which is 8x6 l.

This means he bought 6 bottles.

Answered by g a u t h m a t h

Answer:

2,200

Step-by-step explanation:

6.6 x 10^10

= 66,000,000,000

3 x 10^7

= 30,000,000

66,000,000,000 ÷ 30,000,000

2,200

Answer:

2200.

Step-by-step explanation:

6.6 / 3  *  10^10/10^7

= 2.2 * 10^3

= 2200

Answer:50

Step-by-step explanation:(40x100):80

Answer: 50 workers

Let the ratio be

(40×100):80

= 400/80

= 50

Therefore 50 workers will complete the same work in 80 hours.

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This is of Both

Range = Highest - Lowest data

Range = 45 - 10

Range = 35

Only A

Range = 45 - 10

Range = 35

Only B

Range = 40 - 15

Range = 25

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Answer:

Your answer is (C)

Explanatory variable: miles on the car odometer

Response variable: depth of tire tread

ED2021

Mercury will sink

(sorry if Im wrong)

Answer:

Sink.

Step-by-step explanation:

Mercury is a quicksilver and hence will sink.

Answer:

yggnvfghg46777tuutyuyt6yffttgdfhurdvhu

Answer:

16.25

Step-by-step explanation:

first do 12 -5 = 7. then 7/4 = 1.75 then 9+1.75 = 10.75 and finally 27-10.75= 16.25

Answer:

90

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

105 = 1/2 (120+x)

210 = 120+x

Subtract 120 from each side

210-120 = x

90 =x

The value of  Intercepted Arcs x will be 90. so option C is correct.

If the considered circle has center O and chord AB, then if there is perpendicular from O to AB at point C, then that point C is bisecting(dividing in two equal parts) the line segment AB.

Or

|AC| = |CB|

Angle Formed by Two Chords= 1/2 (Sum of Intercepted Arcs)

105 = 1/2 (120+x)

210 = 120+x

Subtract 120 from each side;

210-120 = x

90 =x

Hence, the value of  Intercepted Arcs x will be 90. so option C is correct.

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Answer:

D = 120 Degrees ,  E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees

Step-by-step explanation:

4X+2X = 180

6X=180

X=30

<ABD = 4X = 4(30) = 120

Answer:

4 ther are 4 line symmetery

Answer:

two lines of symmetry

(a vertical and a horizontal)

The 95% confidence interval is (8.3%,17.7%), and the correct option is C.

------------------------------------------

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

------------------------------------------

13% of a sample of 200 students do not like ice cream.

This means that [tex]\pi = 0.13, n = 200[/tex]

------------------------------------------

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

------------------------------------------

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 - 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.083[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 + 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.177[/tex]

------------------------------------------

As a percentage:

Thus, the 95% confidence interval is (8.3%,17.7%), and the correct option is C.

A similar problem is given at https://brainly.com/question/22223066

Answer:

a) 0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.

b) 0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

Question a:

Event A: Jumbo

Event B: Business

60% of its capacity is provided on jumbo jets.

This means that [tex]P(A) = 0.6[/tex]

On jumbo jets, 30% of the passengers are on business

This means that [tex]P(B|A) = 0.3[/tex]

Desired probability:

We want to find [tex]P(A \cap B)[/tex], so:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]P(A \cap B) = P(B|A)P(A) = 0.6*0.3 = 0.18[/tex]

0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.

b) What is the probability a randomly chosen non-business customer flying with Global is on an ordinary jet?

Event A: Ordinary

Event B: Non-business

60% of its capacity is provided on jumbo jets.

So 100 - 60 = 40% are ordinary, which means that [tex]P(A) = 0.4[/tex]

On ordinary jets 25% of the passengers are on business.

So 100 - 25 = 75% are non-business, that is [tex]P(B|A) = 0.75[/tex]

Desired probability:

We want to find [tex]P(A \cap B)[/tex], so:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]P(A \cap B) = P(B|A)P(A) = 0.75*0.4 = 0.3[/tex]

0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.

A number has fixed number of factors but infinite number of multiples

Ex:-

Take a number 12

It has factors 1,2,3,4,6,12

It is fixed.

But

It has multiples 12,24,36,48,60...

It is infinite

Answer:

45x=-44

x=-44/45

Step-by-step explanation:

is this a free question?

[tex]\\ \sf\longmapsto \frac{ - 3}{7} \leqslant - 4x \\ \\ \sf\longmapsto - 3 \leqslant 7( - 4x) \\ \\ \sf\longmapsto - 3 \leqslant - 28x \\ \\ \sf\longmapsto \ 3 \leqslant 28x \\ \\ \sf\longmapsto x \geqslant \frac{3}{28} [/tex]

Answer:

16[tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Answer:

The critical value is [tex]T_c = 2.5706[/tex].

The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).

Step-by-step explanation:

Before building the confidence interval, we need to find the sample mean and the sample standard deviation:

Sample mean:

[tex]\overline{x} = \frac{6+16+19+12+15+14}{6} = 13.67[/tex]

Sample standard deviation:

[tex]s = \sqrt{\frac{(6-13.67)^2+(16-13.67)^2+(19-13.67)^2+(12-13.67)^2+(15-13.67)^2+(14-13.67)^2}{5}} = 4.4121[/tex]

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.5706, that is, the critical value is [tex]T_c = 2.5706[/tex]

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.5706\frac{4.4121}{\sqrt{6}} = 4.63[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 13.67 - 4.63 = 9.04.

The upper end of the interval is the sample mean added to M. So it is 13.67 + 4.63 = 18.30.

The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).

Answer:

Below

Step-by-step explanation:

You can use this formula to calculate the volume of an object

     Volume = Mass / Density

Plugging everything in...

     Volume = 800g / 8 g/cm^3

                   = 100 cm^3

Hope this helps!

The volume of the boulder will be equal to 100 cubic centimeters.

A substance's density is defined as its mass per unit volume. The density in other words can be defined as the ratio of mass and volume. Its unit will be kg per cubic meter.

The volume is defined as the space occupied by an object in three-dimensional geometry.

It is given that an 800g boulder has a density of 8g/cm^3. The volume will be calculated by using the formula below:-

Volume = Mass / Density

Volume = 800g / 8 g/cm^3

             = 100 cm^3

Therefore, the volume of the boulder will be equal to 100 cubic centimeters.

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Answer:

X = 28/3, or 9 1/3 or 9.3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Step-by-step explanation:

Answer: D) 2 ohms and 2 ohms

The standard deviation for the given data items is 2.6

The standard deviation of the given data items can be calculated by taking the square root of the variance.

Variance is a measure of variability and it is calculated by taking the average of squared deviations from the mean.

Hence, we will first determine the mean of the given data items.

Mean is simply the average of the numbers.

Therefore mean of the given data items is

[tex]Mean = \frac{9+11+11+16}{4}[/tex]

[tex]Mean = \frac{47}{4}[/tex]

Mean = 11.75

Now, for the variance of the data

[tex]Variance = \frac{(9-11.75)^{2}+(11-11.75)^{2}+(11-11.75)^{2}+(16-11.75)^{2} }{4}[/tex]

[tex]Variance = \frac{(-2.75)^{2}+(-0.75)^{2}+(-0.75)^{2}+(4.25)^{2} }{4}[/tex]

[tex]Variance = \frac{7.5625+0.5625+0.5625+18.0625}{4}[/tex]

[tex]Variance = \frac{26.75}{4}\\[/tex]

∴ Variance = 6.6875

But,

Standard deviation [tex]= \sqrt{Varinace}[/tex]

∴Standard deviation  [tex]=\sqrt{6.6875}[/tex]

Standard deviation = 2.586

Standard deviation ≅ 2.6

Hence, the standard deviation for the given data items is 2.6

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Step-by-step explanation:

sec⁴B - sec²B = sec²B(sec²B - 1)

= (1 + tan²B)(tan²B)

= tan⁴B + tan²B

= Right-hand side (Proven)

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

[tex]A = wl[/tex]

w(2w + 3) = 9

From this, we get that:

[tex]l = 2w + 3, A = 9[/tex]

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

In this question:

[tex]w(2w+3) = 9[/tex]

[tex]2w^2 + 3w - 9 = 0[/tex]

Thus a quadratic equation with [tex]a = 2, b = 3, c = -9[/tex]

Then

[tex]\Delta = 3^2 - 4(2)(-9) = 81[/tex]

[tex]w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5[/tex]

[tex]w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3[/tex]

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at https://brainly.com/question/16995958

Answer:

z=0

50%

Step-by-step explanation: