Which answers describe the shape below? Check all that apply.

A. Parallelogram
B. Rectangle
C. Square
D. Rhombus
E. Trapezoid
F. Quadrilateral

Answer:

[tex]\displaystyle \int {84} \, dx = 84x + C[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int {84} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integrations

Answer:

Step-by-step explanation:

Do you mean 27 units² ?

A cube has six congruent, square faces. Area of one face = (27/6) units²

Length of one edge = √(27/6)

= √(9/2)

= √9/√2

= 3/√2

= 3√2/2 units

[tex]\begin{array}{c|c|c|c|c|c} p & q & r & p\land q & q\land \neg p & r \land q \\&&&&\\ T & T & T & T & F & T \\ T & T & F & T & F & F \\ T & F & T & F & F & F \\ T & F & F & F & F & F \\ F & T & T & F & T & T \\ F & T & F & F & T & F \\ F & F & T & F & F & F \\ F & F & F & F & F & F\end{array}[/tex]

An implication A => B is true if either A is false, or both A and B are true. So

[tex]\begin{array}{c|c|c}p\land q & (q\land\neg p) \implies (r\land q) & (p\land q) \implies \big[(q\land\neg p) \implies (r\land q)\big] \\&&\\T & T & \mathbf T\\T & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & F & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\end{array}[/tex]

and the given statement is a tautology.

Answer:

18

thả 5 sao nha.....

Step-by-step explanation:

..................

Answer:

C. [tex]5\frac{1}{4}[/tex]

Step-by-step explanation:

[tex]1\frac{1}{2}[/tex] cups of milk makes 1 quart of yogurt.

x cups  of milk makes [tex]3\frac{1}{2}[/tex] quarts of yogurt.

[tex]\frac{milk}{yogurt}= \frac{1\frac{1}{2} }{1} =\frac{x}{3\frac{1}{2} }[/tex]

Cross multiply.

[tex]1\frac{1}{2}[/tex] × [tex]3\frac{1}{2}[/tex] = 1 × x

You get:

[tex]5\frac{1}{4} =x[/tex]

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

(1) 16 x 14 x 10 Room: 2240 ft^3.

(2) How much greater the 18 x 16 x 10 Room is: 640 ft^3.

Step-by-step explanation:

To find the volume of a given space, all we need to do is multiply length*width*height. In this case, the values are 16*14*10, which equals 2240 ft^3.

The changed design would have a volume of 18*16*10, which would equal 2880 ft^3.

To find the difference in volume between the two rooms, all we have to do is subtract the smaller room from the bigger room. 2880 - 2240 = 640 ft^3.

Answer:

y=0.5x + 5

Step-by-step explanation:

The points are (0,5) and (-10,0)

to find the slope do

0-5/-10-0 = 5/10 = 1/2 = 0.5

next plug one of the points into point slope formula

y-y1=m(x-x1)

lets use the point (-10,0)

y1=0

x1= -10

m= 0.5

y-0=0.5(x- -10)

y = 0.5(x+10)

distribute the 0.5

y=0.5x+5

Answer:

Commission Received refers to a percentage amount received by the company (or) an individual on the total sales incurred. It is an indirect income/revenue recorded on the credit side of profit and loss account.

Step-by-step explanation:

mark me brainliest if my answer is correct

Answer:

The intersection of plane R and plane P is line DB

Point H is not on plane P.

CE and DB intersect at point D

Explanation:

got it right on edge 2021 :)

Answer:

there right^

Step-by-step explanation:

edge 22

Step-by-step explanation:

-x+4y= -15

-2x-3y=-8

the intersection point isn't (3,-5)

it's approximately (-1.1818 ,3.45455 )

Answer:

see below

Step-by-step explanation:

Check the solution in both equation

-x+4 = -15

-3 +4 = -15

1 does not equal -15 so it is not a solution

-2x-3y = -8

-2(3)+-3(-5) = -8

-6 +15 = -8

9 = -8

It is not a solution to either equation

Answer:

The answer is "[tex]\frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]".

Step-by-step explanation:

Given:

[tex]y = e^{{\color{\red}5}\sqrt{x}}[/tex]

let

[tex]\to t= 5\sqrt{x}\\\\\frac{dt}{dx}= 5 \frac{1}{2\sqrt{x}}\\\\\frac{dt}{dx}= \frac{5}{2\sqrt{x}}\\\\[/tex]

and

[tex]\to y=e^t\\\\\to \frac{dy}{dt}=e^t\\[/tex]

[tex]\to \frac{dy}{dt}=e^{5\sqrt{x} }\\[/tex]

So,

[tex]\to \frac{dy}{dx}= \frac{dy}{dt} \times \frac{dt}{dx}[/tex]

         [tex]=e^{5\sqrt{x} }\times \frac{5}{2\sqrt{x}}\\\\= \frac{5 e^{5\sqrt{x} }}{2\sqrt{x}}[/tex]

OR

[tex]\to g(x) = 5\sqrt{x} \\\\\to f(x) = e^{(x)}\\\\[/tex]

Derivate:  

[tex]\to f''g' = \frac{e^{(5\sqrt{x})}5}{(2\sqrt{x})}[/tex]

Answer:

The answer is "[tex]7.21 \times 10^{37}[/tex]".

Step-by-step explanation:

[tex]\to ^{n}_{C_r}=\frac{n!}{r!(n-r)!}[/tex]

       [tex]=^{66}_{C_{33}} \times ^{66}_{C_{22}} \times ^{55}_{C_{1}} \\\\=\frac{66!}{33! (66-33)!} \times \frac{66!}{22! (66-22)!} \times \frac{55!}{1! (55-1)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times \frac{55\times 54!}{1! (54)!}\\\\=\frac{66!}{33! (33)!} \times \frac{66!}{22! (44)!} \times 55\\\\= 7219428434016265740 \times 182183167981760400\times 55\\\\[/tex]

       [tex]= 7.21 \times 10^{18} \times 1.82\times10^{17}\times 55\\\\= 7.21 \times 10^{35} \times 1.82\times 55\\\\=721.721 \times 10^{35}\\\\=7.21\times 10^{37}[/tex]

Answer:

(2x – 1)2 = 9

4x-2=9

4x=9+2

4x=11

x=11/4

x=2.75

Answer in picture

….

Answer:

at most

Step-by-step explanation:

The sample drawn from the population is a relative representation not the absolute representation. The box has 100 tickets in it and sample of tickets is selected to identify difference between sample sum and 252. The at most value for the sample sum can be 278.32 and value cannot exceed beyond this.

Answer: a

Step-by-step explanation:

Answer:

A is the correct answer :)

Answer:

A

Step-by-step explanation:

checking if A is correct, if we get x as 76 then it is correct

if 5miles = 8 kilometers

47.5 miles= x

that is

5=8

47.5=x

cross multiply

5x=380

x=380/5

x=76

there fore A is correct

checking if B is correct, if we get x as 86 then it is correct

if 5miles = 8 kilometers

52.5 miles= x

that is

5=8

52.5=x

cross multiply

5x=420

x=420/5

x=84

therefore B is incorrect

checking if C is correct, if we get x as 34 then it is correct

if 5miles = 8 kilometers

22.5 miles=x

that is

5=8

22.5=x

Cross multiply

5x=180

x=180/5

x=36

therefore C is incorrect

checking if D is correct, if we get x as 22 then it is correct

if 5miles = 8 kilometers

12.5miles = x

that is

5=8

12.5=x

5x=100

x=100/5

x= 20

the function is given, and it's value is where the object is ("how far to the right").

so as long as it rises (going more right), this will be apply.

in the screenshot I graphed the function. of course t is graphed as x and "along the x-axis" is graphed as y, but the pattern is the same anyways.

for the first 1.25 seconds the object goes to the left, and after that always to the right.

since we look at t to calculate x, t effectively takes the role of the important variable that is normally given to x. the calculation pattern are just the same. so let's find the lowest point of this function by calculating it out.

x(t) = 2t² – 5t – 18

x'(t) = 4t -5

x'(t) = 0

0 = 4t -5

5 = 4t

1.25 = t

plugging it into the second derivative

x''(t) = 4

x''(1.25) = 4

it's positive, so at t=1.25 there is a low point

(of course the second derivative is constant anyways.)

the object is traveling toward the right

the object is traveling toward the rightfor t > 1.25

The object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have:

An object travels along the x-axis so that its position after t seconds is given by:

x(t) = 2t² – 5t – 18

x'(t) = 4t - 5

x'(t) = 0

4t -5 = 0

t = 5/4 = 1.25 seconds

x''(t) = 4

x''(1.25) = 4

x''(1.25) > 0

At t = 1.25 the object travels at a low point.

Thus, the object is moving to the right, for t > 1.25, the object is moving in a rightward direction.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ2

Answer:

Mean of sampling distribution = 50

Standard deviation of sampling distribution, = 0.625

Step-by-step explanation:

Given :

Mean, μ = 50

Standard deviation, σ = 5

Sample size, n = 64

The mean of sampling distribution, μxbar = population mean, μ

μxbar = μ

According to the central limit theorem, the sampling distribution converges to the population mean as the sample size increases, hence, , μxbar = μ = 50

Standard deviation of sampling distribution, σxbar = σ/√n

σxbar = 5/√64 = 5 / 8 = 0.625

Answer:

H0 : correlation is equal to 0

H1 : correlation is not equal to 0 ;

Pvalue < α ;

There is sufficient evidence

r = 0.945 ;

Pvalue = 0.01524

Step-by-step explanation:

Given the data :

Lemon_Imports_(x) Crash_Fatality_Rate_(y)

230 15.8

264 15.6

359 15.5

482 15.3

531 14.9

Using technology :

The regression equation obtained is :

y = 16.3363-0.002455X

Where, slope = - 0.002455 ; Intercept = 16.3363

The Correlation Coefficient, r = 0.945

H0 : correlation is equal to 0

H1 : correlation is not equal to 0 ;

The test statistic, T:

T = r / √(1 - r²) / (n - 2)

n = 5 ;

T = 0.945 / √(1 - 0.945²) / (5 - 2)

T = 0.945 / 0.1888341

T = 5.00439

The Pvalue = 0.01524

Since Pvalue < α ; Reject the Null and conclude that there is sufficient evidence to support the claim.

9514 1404 393

Answer:

  108.8 km/h at 84.3°

Step-by-step explanation:

The law of cosines can be used to find the resultant ground speed. In the attached diagram, the length of interest is OR. It will be found as ...

  OR² = OP² +PR² -2·OP·PR·cos(P)

  OR² = 130² +26² -2×130×26×cos(32°) ≈ 11843.19

  OR = √11843.19 ≈ 108.8

__

The angle POR can be found from the law of sines.

  sin(POR)/PR = sin(OPR)/OR

  sin(POR) = PR/OR×sin(32°) ≈ 0.12660

  ∠POR ≈ arcsin(0.12660) ≈ 7.27°

Then the bearing of the ground track of the airplane is 77° +7.27° = 84.27°.

The airplane is traveling at about 108.8 km/h on a bearing of 84.3°.

Answer:

absolutely B

Step-by-step explanation:

A is one type of tax

C) gross pay includes taxes, social security and something else

D) deductions are the type of fee

and B is the amount of money that he received

Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

It is defined as the tax rate applied on the solely earned money by a single entity.

It is given that:

Alejandro wants to determine how much money he made in the last month after taxes, social security, and Medicare were taken out of his paycheck.

The options are:

A) Federal tax amount

The Federal tax amount is one type of tax.

C) Gross pay

The gross pay includes taxes, social security, and other charges

D) Deductions

The deductions are the type of fee or negative amounts.

Alejandro should look at Net pay on his paystubs.

Thus, Alejandro should look at Net pay on his paystubs the answer is Net pay option (b) is correct.

Learn more about the income tax here:

brainly.com/question/17075354

#SPJ2

Answer:

PW, BW,  GW, PY,  BY, GY

Step-by-step explanation:

We need to determine the sample space

pink(P), blue (B), and green (G) cards,   (W) and yellow (Y) envelopes

Each color card can match with each color envelope

Start with the white envelopes and each color card

and then the yellow envelopes with each color card

PW   BW  GW

PY  BY   GY

Answer:

Swimming pool

Step-by-step explanation:

Let's say that we invite x people. The cost of the bowling alley will be $15 for the room, and we add $5 dollars for each person. Therefore, we can represent the cost of the bowling alley as

5 * x + 15

Similarly, the cost of the swimming pool is

4 * x + 12

To find the maximum of the function, one thing we can do is set the expressions of the cost equal to 40. This will give us the amount of people we can invite for exactly 40 dollars. Because cost increases with amount of people, this will give us the maximum number of people we can invite with $40.

We thus have

5 * x+ 15  = 40

subtract 15 from both sides to isolate the x and its coefficient

25 = 5 * x

divide both sides by 5 to isolate x

25/5 = x = 5

We can therefore invite 5 people to the bowling alley

4 * x+ 12  = 40

subtract both sides by 12 to isolate the x and its coefficient

28 = 4 * x

divide both sides by 4 to isolate x

x = 7

Therefore, we can invite 7 people to the swimming pool. As 7 > 5, we can invite more people to the swimming pool.

A quicker way to solve this could be by looking at the cost of each location. Because the bowling alley costs more both per person and for the room, and there is no way to decrease the cost except by decreasing the amount of people, there is no way that the bowling alley could get as many people as the swimming pool with the same amount of money

Answer:

Approximately 68% of people have IQs between 84 and 116.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100, standard deviation of 16.

Percentage of people with IQs between 84 and 116.

84 = 100 - 16

116 = 100 + 16

So within 1 standard deviation of the mean, which, by the Empirical Rule, is approximately 68%.

Answer:

probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 - (91/285)

=194/285 or 0.6807.

Step-by-step explanation:

The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.

The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements.

Hence

|E'| = C(14,3)

= 14×13×12/3!.

Therefore probability P(E')

= |E'|/|S|

= (14×13×12)/(20×19×18)

= (14×13×2)/(20×19×3)

=(7×13)/(5×19×3)

= 91/285.

Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 - (91/285)=194/285 or 0.6807.