Which choice is equivalent to the quotient shown here for acceptable
values of X?
square root 30(x - 1)/square root15(x - 1)^2?
A. sr30(x - 1) - 5(x - 1)?
B. sr6(x - 1)
C. sr 6/(x - 1)
D. sr150(x - 1)^3

Answer:

227 is the 74th term of your question.

Answer:

The answer is the second graph, Option 2

9514 1404 393

Answer:

  row 13

Step-by-step explanation:

The sum of row n is 2^n, so the row number with a particular sum is ...

  2^n = sum

  n·log(2) = log(sum)

  n = log(sum)/log(2)

The row with sum 8192 is ...

  n = log(8192)/log(2) = 13

The row of Pascal's triangle that has a sum of 8192 is row 13.

Answer:

g(a + 1) - g(a - 1) = 4a

Step-by-step explanation:

g(x) = x^2 + 5,

when x = a+1, g(a+1) = (a+1)^2 + 5.

when x = a-1, g(a-1) = (a-1)^2 +5.

g(a+1)-g(a-1) = (a+1)^2 + 5 - [(a-1)^2 + 5]

= a^2 + 2a + 1 + 5 - [a^2 - 2a + 1 + 5]

= 4a

9514 1404 393

Answer:

  4

Step-by-step explanation:

2/3 = 4/6

There are four 1/6-cup servings of rice in 4/6 cups of rice.

Answer:

The answer is B

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

0.99218

9514 1404 393

Answer:

  $55,085.44

Step-by-step explanation:

The formula for the account balance is ...

  A = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years. Using the given values, we find the balance to be ...

  A = $21,000(1 +0.082/2)^(2·12) = $21,000(1.041^24) ≈ $55,085.44

The balance is $55,085.44 after 12 years.

Answer:

The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care

Step-by-step explanation:

A journal article reports that 34% of fathers take no responsibility for child care. A group of fathers believes that this estimate is too high.

At the null hypothesis, we test if the proportion is of at least 34%, that is:

[tex]H_0: p \geq 0.34[/tex]

At the alternative hypothesis, we test if the proportion is less than that, that is:

[tex]H_1: p < 0.34[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.34 is tested at the null hypothesis:

This means that [tex]\mu = 0.34, \sigma = \sqrt{0.34*0.66}[/tex]

In a random sample of 80 fathers, it was found that 23 of those fathers take no responsibility for child care.

This means that [tex]n = 80, X = \frac{23}{80} = 0.2875[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.2875 - 0.34}{\frac{\sqrt{0.34*0.66}}{\sqrt{80}}}[/tex]

[tex]Z = -0.99[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.2875, which is the p-value of Z = -0.99.

Looking at the Z-table, Z = -0.99 has a p-value of 0.1611.

The p-value of the test is 0.1611>0.01, which means that there is not significant evidence at the 1% significance level that less than 34% of fathers take no responsibility for child care

Answer:

$66.3

Step-by-step explanation:

price of a ticket without discount = $78

discount  % = 15%

discount amount = ?

price of a discounted ticket = ?

discount amount = discount% of price of a original ticket

=15/100 * $78

=$1170/100

=$ 11.7

price of the discounted ticket = $78 - $11.7

=$66.3

The discounted price of the stadium's normal ticket is  $66.3

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, A stadium's normal ticket price is $78 and As a special promotion they offer 15% off.

Therefore, The discounted price of the ticket should be (100 - 15)% = 85% of the original price which is,

= (85/100)×78.

= $66.3 is the discounted price.

learn more about percentages here :

https://brainly.com/question/24159063

#SPJ6

Perpendicular Definition:

[tex] \large \boxed{m_1m_2 = - 1}[/tex]

Slopes of two different equations multiply each others and must equal to -1. We can also say that the perpendicular occurs only if both equations are negative reciprocal to each others. For example, we are given the equation of y = 2x. The perpendicular to y = 2x would be y = (-1/2)x. See how both are reciprocal to each others.

From the equation below:

[tex] \large{x + 5y = - 2}[/tex]

Since the equation is in the form of Ax+By = C. It is better to use the another slope formula which is:

[tex] \large \boxed{m = - \frac{A}{B} }[/tex]

From the equation above, use the slope formula to find the slope.

[tex] \large{m = - \frac{1}{5} }[/tex]

Therefore the equation has a slope of -1/5. Next to find the perpendicular equation to the original equation. Since our slope is -1/5 - that means the negative reciprocal of -1/5 is 5. Therefore the slope of perpendicular line is 5.

Next we will be using the point-slope form below:

[tex] \large \boxed{y - y_1 = m(x - x_1)}[/tex]

Given the y1 and x1 or (x1,y1) are the points. Our perpendicular slope is 5 which passes through the point (3,0). Substitute both slope and the point in.

[tex] \large{y - 0 = 5(x - 3)}[/tex]

Simplify in the slope-intercept form as we get:

[tex] \large{y = 5x - 15}[/tex]

Answer

Hope this helps and let me know if you have any doubts!

9514 1404 393

Answer:

  C

Step-by-step explanation:

The step shown indicates that y was eliminated from the equations. For choices A, B, D, this is done by adding the equations together (the y-coefficients are opposites). The result of doing that gives x-terms of 4x, 0x, and 0x, respectively. These x-terms do not match the one given: 2x.

For choice C, the y-term is eliminated by subtracting twice the second equation from the first. Doing that gives ...

  (4x +2y) -2(x +y) = (14) -2(3)

  4x +2y -2x -2y = 14 -6 . . . . eliminate parentheses

  2x = 8 . . . . . . . . . . . . . . collect terms

Answer:

x=7

Step-by-step explanation:

take 30 degree as reference angle

using sin tan rule

tan 30=opposite/adjacent

[tex]\frac{1}{\sqrt{3} }[/tex]=x/[tex]7\sqrt{3}[/tex]

[tex]\frac{1}{\sqrt{3} }[/tex] *[tex]7\sqrt{3}[/tex]

[tex]7\sqrt{3} /\sqrt{3}[/tex]

7=x

Answer:

c) it appears to be sound because the data are not biased in anyway.

Step-by-step explanation:

From the information given regarding the sample selection method , the size, the larger sample from which the survey subject were selected, we can conclude that the data is sound and not in anyway biased. The subject were selected from a reputable market research firm, which means the subjects were chosen from a larger sample which is reliable and not just a voluntary pool of subjects. Also, the selection process is randomized. Based on these, there are no flaws which are likely to cause the introduction of bias into the sample selected. Hence, the data is sound and not in any way biased.

Answer:

B

Step-by-step explanation:

Answer:

B EDGE

Step-by-step explanation:

===================================================

Explanation:

16/31 represents the probability of picking a white marble

This is because there are 16 white out of 15+16 = 31 total.

---------

After we make a first selection, we have 16-1 = 15 white marbles left out of 31-1 = 30 marbles overall. The probability of selecting another white marble is 15/30 = 1/2.

Multiply those two fractions:

(16/31)*(1/2) = (16*1)/(31*2) = (2*8)/(31*2) = 8/31

which represents the probability of selecting two white marbles in a row, such that we don't put the first one back (and there's no replacement).

Answer:

I think there is no solution.

Step-by-step explanation:

Substitute:

Z = -3y-5x+25

X = 3y-2z-13

Put into the last formula:

14(3y-2z-13)-2y+3(-3y-5x+25) = 48

Then:

14(3y-2(-3y-5x+25)-13)-2y+3(-3y-5(3y-2z-13)) = 48

So:

14(3y-2(-3y-5(3y-2z-13)+25)-13)-2y+3(-3y-5(3y-2(-3y-5x+25)-13)) = 48

And so on.

Answer:

[tex]P(6am-12\ noon) = 0.305[/tex]

[tex]P(12\ noon - 6pm) = 0.143[/tex]

[tex]P(6pm-12\ midnight) = 0.322[/tex]

[tex]P(12\ midnight - 6am) =0.230[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Time} & {Inventors} & {6am - 12\ noon} & {295} & {12\ noon -6pm} & {138} & {6pm - 12\ midnight} & {311} & {12\ midnight - 6am} & {222} & {Total} & {966} \ \end{array}[/tex]

Required

The probability of each time interval

To do this, we simply divide the number of inventors in the interval by the total inventors (966)

So, we have:

[tex]P(6am-12\ noon) = \frac{6am-12\ noon}{Total}[/tex]

[tex]P(6am-12\ noon) = \frac{295}{966}[/tex]

[tex]P(6am-12\ noon) = 0.305[/tex]

[tex]P(12\ noon - 6pm) = \frac{12\ noon - 6pm}{Total}[/tex]

[tex]P(12\ noon - 6pm) = \frac{138}{966}[/tex]

[tex]P(12\ noon - 6pm) = 0.143[/tex]

[tex]P(6pm-12\ midnight) = \frac{6pm-12\ midnight}{Total}[/tex]

[tex]P(6pm-12\ midnight) = \frac{311}{966}[/tex]

[tex]P(6pm-12\ midnight) = 0.322[/tex]

[tex]P(12\ midnight - 6am) =\frac{12\ midnight - 6am}{Total}[/tex]

[tex]P(12\ midnight - 6am) =\frac{222}{966}[/tex]

[tex]P(12\ midnight - 6am) =0.230[/tex]

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Equations according the given:

Solve for q by substitution:

Find the value of d:

Nathaniel has 10 dimes and 4 quarters

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

the top one that's orange

Given:

The equation of a line is:

[tex]2y+3x=10[/tex]

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

[tex]2y+3x=10[/tex]

For [tex]x=0[/tex],

[tex]2y+3(0)=10[/tex]

[tex]2y+0=10[/tex]

[tex]y=\dfrac{10}{2}[/tex]

[tex]y=5[/tex]

For [tex]x=2[/tex],

[tex]2y+3(2)=10[/tex]

[tex]2y+6=10[/tex]

[tex]2y=10-6[/tex]

[tex]2y=4[/tex]

Divide both sides by 2.

[tex]y=\dfrac{4}{2}[/tex]

[tex]y=2[/tex]

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

[tex](x,y)\to (3x,3y)[/tex]

Using this rule, we get

[tex]A(0,5)\to A'(3(0),3(5))[/tex]

[tex]A(0,5)\to A'(0,15)[/tex]

Similarly,

[tex]B(2,2)\to B'(3(2),3(2))[/tex]

[tex]B(2,2)\to B'(6,6)[/tex]

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-15=\dfrac{6-15}{6-0}(x-0)[/tex]

[tex]y-15=\dfrac{-9}{6}(x)[/tex]

[tex]y-15=\dfrac{-3}{2}x[/tex]

Multiply both sides by 2.

[tex]2(y-15)=-3x[/tex]

[tex]2y-30=-3x[/tex]

[tex]2y+3x=30[/tex]

Therefore, the equation of the line after the dilation is [tex]2y+3x=30[/tex].

Answer:

hi, yes the option B is the correct answer

Step-by-step explanation:

[tex]\frac{( \csc x+1)( \csc x-1)}{ \csc ^2x} = \frac{ { \csc }^{2} x - 1}{ \csc^{2} x} \\ = 1 - \sin^{2} x = \cos^{2} x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

b. Since csc theta = 1/sin theta, we can multiply both sides by sin theta and you will end up with

[tex] \cos^{2} \theta + \sin^{2} \theta = 1[/tex]

which is an identity.