Options :
A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line
B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.
C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
Answer:
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
Step-by-step explanation:
The equation y > 3x – 8
Interpreting as a linear relation :
y > ax + b
Where, a = slope ; b = intercept
a = 3 ; that is a slope value of 3
b = -8 ; that is an intercept value of - 8
Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.
Answer: The answer is D on edu 2021
Step-by-step explanation:
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression. How many people clicked on the banner ad
Answer:
300
Step-by-step explanation:
[tex] \frac{1.5}{100} = 20000 \\ 20000 \div 100 = 200 \\ 200 \times 1.5 = 300[/tex]
if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression.
We need to find how many people clicked on the banner ad.
Let us find the value of 1.5% of 20000
Convert 1.5 % to decimal
1.5/100=0.015
Now multiply 0.015 with 20000
0.015×20000
300
Hence, if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
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Name some real-life situations where graphing could be useful. Discuss your ideas. Name some real-life situations where finding the coordinates of the midpoint of a line segment could be useful.
Answer:
mapping an area
Step-by-step explanation:
One situation and probably the most common is mapping an area. Graphs are great for dividing a geographical location into various sections and creating a model representation of the area. The graph itself allows for specific directions to be shared using the x and y coordinates on the graph. The same applies for finding the midpoint of a line segment. For example, this is useful if you were trying to find a place to meetup with a friend that is an equal distance from where you are and from where your friend is currently located. Therefore, allowing you to meetup at the midpoint.
A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.
Answer:
[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]
Step-by-step explanation:
Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.
We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.
In other words, given da/dt = 410 and x = 5, find dx/dt.
From the Pythagorean Theorem:
[tex]a^2+4=x^2[/tex]
Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:
[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]
Simplify:
[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]
Find a when x = 5:
[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]
Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:
[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]
The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.
Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]
[tex]\small\color{blak}{{\underline{\bold{ Find \:a X } } } }[/tex]
[tex]\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}[/tex]
[tex]\small\color{blak}{{\underline{\bold{ Find\:a\:m<QSR } } } }[/tex]
[tex]\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m<QSR=68°\:\:\:\: }}}}[/tex]
[tex]\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}[/tex]
The measure of angle QSR is 68 degrees.
What is substitution?Substitution means putting numbers in place of letters to calculate the value of an expression.
According to the given question.
m ∠TSQ = 15x
m ∠TSR = 173 degrees
m ∠QSR = 10x -2
Since,
m ∠TSR = m ∠TSQ + ∠QSR
Substitute the value of m ∠TSR, m ∠TSQ and m ∠QSR in the above expression.
⇒ [tex]173 = 15x + 10x - 2[/tex]
⇒ [tex]173 = 25x - 2[/tex]
⇒ [tex]175 = 25x[/tex]
⇒ [tex]x = \frac{175}{25}[/tex]
⇒ [tex]x = 7[/tex]
Again, for finding the value of angle QSR substitute the value of x in 10x - 2.
Therefore,
m ∠QSR = 10(7) - 2
⇒ m ∠QSR = 70 - 2
⇒ m ∠QSR = 68 degrees
Hence, the measure of angle QSR is 68 degrees.
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HELP AGAIN sorry
What is the measure of ∠AOB?
The measure of angle ∠AOB is 180°. The correct option from the following is (A).
A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.
A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.
For the given quadrilateral, the sum of angles is:
∠A + ∠O + ∠B = ∠AOB
60° + 60° + 60° = 180°
Hence, the correct option is (A).
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Evaluate double integral of f(u,v)=∬dudv over region R where R is bounded by v^2-nu=0 , v^2-(n+1)u=0 and uv=n,uv=(n+1). Sketch neat graph and shade the bounded region. Clearly mention the points of intersection. Reverse the order of integration then evaluate. Where n is 100.
Answer:
5670272728262728227627
Can anyone help me please? I've been trying for so long, but I can't figure out the answer to this problem. Picture attached. Thank you so much.
Answer:
C
Step-by-step explanation:
Start by simplifying what you can in each radicalfor example, the
∛(xy⁵)= y∛(xy²)
and
∛(x⁷y¹⁷)=x²y⁵∛(xy²)
So know our equation looks like
y∛(xy²)*x²y⁵∛(xy²)
Now because what's inside the radical is the same we can combine them
y⁶x²∛(xy²)²
distribute the square
so
∛(xy²)²= ∛(x²y⁴)= y∛(x²y)
and finally,
y⁶x²*y∛(x²y)= y⁷x²∛(x²y)
this is equal to option C
1. Find the exact value of sin( a−B), given that sin a=−4/5 and cos B=12/13, with a in quadrant III and B in quadrant IV.
2. Find all real numbers in the interval [0,2pi) that satisfy the equation.
3sec^2 x tan x =4tan x
3. Simplify the following trigonometric expressions, using identities as needed:
sin(x)/1−cos(x) + 1−cos(x)/sin(x)
(1) Recall that
sin(x - y) = sin(x) cos(y) - cos(x) sin(y)
sin²(x) + cos²(x) = 1
Given that α lies in the third quadrant, and β lies in the fourth quadrant, we expect to have
• sin(α) < 0 and cos(α) < 0
• sin(β) < 0 and cos(β) > 0
Solve for cos(α) and sin(β) :
cos(α) = -√(1 - sin²(α)) = -3/5
sin(β) = -√(1 - cos²(β)) = -5/13
Then
sin(α - β) = sin(α) cos(β) - cos(α) sin(β) = (-4/5) (12/13) - (-3/5) (-5/13)
==> sin(α - β) = -63/65
(2) In the second identity listed above, multiplying through both sides by 1/cos²(x) gives another identity,
sin²(x)/cos²(x) + cos²(x)/cos²(x) = 1/cos²(x)
==> tan²(x) + 1 = sec²(x)
Rewrite the equation as
3 sec²(x) tan(x) = 4 tan(x)
3 (tan²(x) + 1) tan(x) = 4 tan(x)
3 tan³(x) + 3 tan(x) = 4 tan(x)
3 tan³(x) - tan(x) = 0
tan(x) (3 tan²(x) - 1) = 0
Solve for x :
tan(x) = 0 or 3 tan²(x) - 1 = 0
tan(x) = 0 or tan²(x) = 1/3
tan(x) = 0 or tan(x) = ±√(1/3)
x = arctan(0) + nπ or x = arctan(1/√3) + nπ or x = arctan(-1/√3) + nπ
x = nπ or x = π/6 + nπ or x = -π/6 + nπ
where n is any integer. In the interval [0, 2π), we get the solutions
x = 0, π/6, 5π/6, π, 7π/6, 11π/6
(3) You only need to rewrite the first term:
[tex]\dfrac{\sin(x)}{1-\cos(x)} \times \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin(x)(1+\cos(x))}{1-\cos^2(x)} = \dfrac{\sin(x)(1+\cos(x)}{\sin^2(x)} = \dfrac{1+\cos(x)}{\sin(x)}[/tex]
Then
[tex]\dfrac{\sin(x)}{1-\cos(x)}+\dfrac{1-\cos(x)}{\sin(x)} = \dfrac{1+\cos(x)+1-\cos(x)}{\sin(x)}=\dfrac2{\sin(x)}[/tex]
Tim Hortons is hiring and offers $200 every week plus $5 per hour. McDonalds offers $300 every week plus $2 per hour. State the conditions under which Tim Hortons is the better employer
Answer:
Assuming you want better payment each week, any number of hours above 33.333 or 33 hours and 20 minutes per week
Step-by-step explanation:
There are several ways we could do this. We could say we want to have Tim Hortons be the better employer on the first week, or after so many weeks by adjusting the hours. I am going to assume we are saying we want it to be a better employer on the first week, so the profit will be the amount made every week plus the money made per hour times the number of hours.
Let's say number of hours is H
So Tim Hortons winds up as 200 + 5H for one week and Mcdonalds will be 300 + 2H.
If you set the two expressions equal to each other you will find where they intersect, which means at that number of hours they will give the same amount of money while any amount before one of the companies will give more and after that many hours the other will. Let's go ahead and solve.
200 + 5H = 300 + 2H
3H = 100
H = 100/3
So H is about 33.333. let's check.
200 + 5(33.333) = 366.665 which rounds to 366.67 dollars
300 + 2(33.333) = 366.666 which also rounds to 366.67 dollars
So at 33.333 hours both give 366.67 dollars. Let's look at a value below it, say 32.
200 + 5(32) = 360
300 + 2(32) = 364
So you can see here Tim Hortons pays less. Now we will try 34 as a value above 33.333
200 + 5(32) = 370
300 + 2(32) = 368
Here Mcdonalds pays less. This was to show that values below 33.333 make Tim Hortonspay less and values above 33.333 make Mcdonalds pay less. In other words any value above 33.333 hours will have Tim Hortons be the better employer. And this is per week
I want to repeat, you can expand this to be multiple weeks and see which of the two becomes better in that epriod of time. This was, I think, the simplest way to answer though.
So the conditions where Tim Horton pays more isif you work more than 33.333 hours per week. This will make them pay more every single week.
Solve for x in the triangle. Round your answer to the nearest tenth.
Answer:
7.3 units
Step-by-step explanation:
Hi there!
We're given an angle and one leg of this right triangle and we must solve for the other leg. Given this circumstance, we can use the tangent ratio:
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
Plug in all values
[tex]tan39=\frac{x}{9}\\9*tan39=x\\7.3=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 7.3 units.
I hope this helps!
Merci de m'aider rapidement !
Answer:
I will answer in English.
We can prove that the angle APS is a triangle rectangle.
Remember that for a triangle rectangle of catheti A and B, and hypotenuse H, the Pythagorean's theorem says that:
A^2 + B^2 = H^2
In this case, we can assume that the hypotenuse is the longer side, AS, and the other two sides are the catheti.
Then we have:
H = 5x + 10
A = 3x + 6
B = 4x + 8
Now let's write the equation from the theorem, and let's see if its true.
A^2 + B^2 = H^2
( 3x + 6 )^2 + (4x + 8)^2 = (5x + 10)^2
So we can start with:
( 3x + 6 )^2 + (4x + 8)^2
And try to "transform" this into:
(5x + 10)^2
First, let's expand it:
((3x)^2 + 2*(3x)*6 + 6^2) + ( (4x)^2 + 2*(4x)*8 + 8^2)
9x^2 + 24x + 36 + 16x^2 + 64x + 64
25x^2 + 40x + 100
Now we can complete squares on the left side, by writing:
(5x)^2 + 2*10*(5x) + 10^2
(5x + 10)^2
Then we saw that the equation is true for every value of x, then we just prove that the triangle fulfills the theorem, thus, the triangle is a triangle rectangle.
Put -3.0-3.45, -15, and -3.15 in order from least to greatest.
Answer:
-15 -3.45 -3.15 -3.0
Step-by-step explanation:
Solve the following inequality.
- 202-16
Which graph shows the correct solution?
solve 5x^2-2=-12 by taking the square root
Answer:
[tex]x = \sqrt{-2} = 2i[/tex]
Step-by-step explanation:
[tex]5x^2-2=-12[/tex]
[tex]5x^2 =-10[/tex]
[tex]x^2 =-2[/tex]
[tex]x = \sqrt{-2} = 2i[/tex]
prove that
[tex]2 \tan30 \div 1 + tan ^{2} 30 = sin60[/tex]
prove that
.
Step-by-step explanation:
2tan 30° / 1 + tan² 30° =
2(⅓√3) /1 + (⅓√3)² =
⅔√3 / 1+ ⅓ =
⅔√3 / 4/3 =
2/4 √3 =
½√3 = sin 60° (proven)
on the provided graph, plot the points where the following function crosses the x-axis and the y-axis g(x) = -5^x + 5, what does the graph look like?
Answer:
see image
Step-by-step explanation:
Calculate the difference and enter it below
-6 - 12
Answer:
-18
Step-by-step explanation:
Answer: -18 is the difference
Step-by-step explanation:
Evaluate = -18
With a.b.c=1 and a+b+c=1
Prove that:
Answer:
HOPE IT HELPS PLZ MARK ME BRAINLIEST
Step-by-step explanation:
abc=1
⟹c=1/ab
1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a)
=1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a)
=b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab)
=1+b+ab/(1+b+ab)
=1
Please help me i will give you brainlest
Answer:
a speaker receive credibility is a combination of competence trustworthiness and caring
Can someone help me please! Thanks
Answer:
hello again.. I think you have a problem about figures
Step-by-step explanation:
please be brave when you try to solve..try to draw new lines to get angle and then look at the overall of shape.. the photo helps you good bye
Gloria received a 4 percent raise and is now making $24,960 a year, what was her salary before the raise?
She gets a 4% raise so her new pay is 100% + 4% of her previous pay.
104% = 1.04 as a decimal.
Divide her new pay by 1.04:
24,960 / 1.04 = 24,000
Her previous pay was $24,000
This Bar Chart shows the number of DVDs sold at a local music store during one week.
Which measure(s) of central tendency can be used to determine the average number of DVDs sold each day?
A. the median
B. the mean
C. the mean and the median
D. the mode
Answer:
B. the mean
Step-by-step explanation:
According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.
Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.
This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.
Answer:
The Mean
Step-by-step explanation:
I took the test
Which law would you use to simplify the expression?
Answer:
A. quotient of Powers
Step-by-step explanation:
hope it helps
Answer:
A. Quotient of powers
Step-by-step explanation:
Hope it helps
Find the solution of the differential equation that satisfies the given initial condition. (dP)/(dt)
Answer:
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Step-by-step explanation:
Given
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]P(1) = 2[/tex]
Required
The solution
We have:
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]
Split
[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]
Divide both sides by [tex]P^\frac{1}{2}[/tex]
[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]
Multiply both sides by dt
[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]
Integrate
[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Rewrite as:
[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the left hand side
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the right hand side
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)
To solve for c, we first make c the subject
[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]
[tex]P(1) = 2[/tex] means
[tex]t = 1; P =2[/tex]
So:
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]
[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]
So, we have:
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]
Divide through by 2
[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]
Square both sides
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Does the expression represents a positive or negative 3(-2 1/3)
Answer:
Positive
Step-by-step explanation:
This is an equation, with distribution in it. The number on the outside is positive, and the one inside is negative. Furthermore, since the number on the outside is larger than the one inside, the outcome will be positive.
Answer:
positive
Step-by-step explanation:
when both positive and negative will multiply then will makes negatives. so negative is correct option.
What is 5.071 in words?
Answer:
Step-by-step explanation:
The number 5.071 written in english words is "five and seventy-one thousandths
How do you graph this helppp and explain
Answer:
bottom graph
Step-by-step explanation:
f(x) = |3q-6|
because you have absolute value there are 2 possibilities
y= +(3q-6) and y= -(3q-6)
to find where the graph intersects the x-axis make y=0 because there the y coordinate is 0, so we have...
3q-6 =0 and -3q+6 =0
3q= 6 and -3q =-6
q=2 and q=2
the bottom graph has the intersection with x-axis only at 2, so is the correct one
9514 1404 393
Answer:
bottom graph shown
Step-by-step explanation:
It can be helpful to rearrange the equation to either of the equivalent forms ...
f(x) = |3(x -2)|
or ...
f(x) = 3|x -2|
_____
The first of these forms represents a horizontal compression of the absolute value function by a factor of 3, then a right-shift by 2 units. This matches the bottom graph shown.
__
The second of these forms represents a horizontal right-shift by 2 units, and a vertical expansion by a factor of 3. This matches the bottom graph shown.
__
The attached graph shows the function given here along with the absolute value parent function.
_____
Additional comment
The transformations we're usually interested in are ...
g(x) = k·f(x) . . . . vertically scaled (stretched) by a factor of k
g(x) = f(kx) . . . . .horizontally compressed by a factor of k
g(x) = f(x) +k . . . shifted up by k units
g(x) = f(x -k) . . . . shifted right by k units
In many cases, as here, horizontal scaling and vertical scaling are indistinguishable as to which caused a given effect.
What angles can you construct using just a pair of compasses and a ruler?
Answer:
By using a pair of compasses and a ruler you can draw all angles
HELPPPP ME ASAP
If f(x) = x2, g(x) = 5x, and h(x) = x +4, find each value.
Find g[h(-2)]
9514 1404 393
Answer:
10
Step-by-step explanation:
Put the values where the arguments are and do the arithmetic.
g(h(-2)) = g(-2+4) = g(2) = 5(2)
g(h(-2)) = 10
Graph the solution set to this Inequality.
-2x + 9 < 51 12
Answer:
X<-2551.5
Step-by-step explanation:
-2x<5112-9
-2x/-2<5103/-2
x<-2551.5
