Which equation would find the distance between the
two points show on the coordinate plane?

Answer:

Step-by-step explanation:

Find zero's:

The intervals:

As we see correct choices are b and d

Answer:

167.64 cm

Step-by-step explanation:

I dont kno how to work it out

Answer:

fyi b's answer has imaginary numbers in it...

Imaginary: 1 +[tex]\frac{\sqrt{2i} }{2 }[/tex]    

Imaginary: 1 -  [tex]\frac{\sqrt{2i} }{2 }[/tex]  

Step-by-step explanation:

[tex]2x^{2} - 4x -3 = 0[/tex]

[tex]\sqrt{-4^{2} -4(2)(3)}[/tex] = [tex]\sqrt{-8}[/tex] ... the negative root will produce imaginary solutions

9514 1404 393

Answer:

  1a. -4, 3/4

  1b. 1-0.71i, 1+0.71i

Step-by-step explanation:

The directions tell you to use the quadratic formula. Factoring may get you the solution somewhat more easily, but does not comply with the directions.

The quadratic formula tells you ...

  [tex]\text{The solution to }ax^2+bx+c=0\text{ is given by }\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

__

1a. a=4, b=13, c=-12

  [tex]x=\dfrac{-13\pm\sqrt{13^2-4(4)(-12)}}{2(4)}=\dfrac{-13\pm\sqrt{361}}{8}=\dfrac{-13\pm19}{8}\\\\x=\left\{-4,\dfrac{3}{4}\right\}[/tex]

__

1b. After adding 3 to both sides, a=2, b=-4, c=3

  [tex]x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(2)(3)}}{2(2)}=\dfrac{4\pm\sqrt{-8}}{4}=1\pm\dfrac{\sqrt{2}}{2}i\\\\x=\left\{1-\dfrac{\sqrt{2}}{2}i,1+\dfrac{\sqrt{2}}{2}i\right\}\approx\{1-0.71i,1+0.71i\}[/tex]

Answer:

-15

Step-by-step explanation:

Let a = 2 and c = -7.

[tex]c-4a\\(-7)-4(2)\\-7-8\\-15[/tex]

we know that the value of a is 2 and c is -7

Expression-

c-4a

= (-7)-4×2

= (-7)-8

= -15

The answer is "Option B", and the further explanation can be defined as follows:

The wrong choice can be defined as follows:

Therefore, "Option B" is correct and its diagram is defined in the attached file.

Learn more:

2 rotational symmetry: brainly.com/question/1531736

The answer is A and D

good luck

Answer:

450 runners

Step-by-step explanation:

Answer:

B) 32

Step-by-step explanation:

(sin 74) / 10 = (sin c) / 10

c = 74

180 - 74 -74

= 32

Answer:

The answer is option C
2 in., 3 in., 4 in. and 5 in., 6 in., 7 in.

Step-by-step explanation:

Answer:

49.09°

Step-by-step explanation:

c = circumference = 2×π×r

= 2× 22/7 ×7 = 44 ft

θ = 6/c × 360°

= 6/44 × 360° = 49.09°

Step-by-step explanation:

what happens if there is excess or deficit of proteins in our body

Answer:

The sample mean that will cut off the upper 95% of all samples of size 20 taken from the population is of 1963.2 pounds.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The average breaking strength of a certain brand of steel cable is 2000 pounds, with a standard deviation of 100 pounds.

This means that [tex]\mu = 2000, \sigma = 100[/tex]

A sample of 20 cables is selected and tested.

This means that [tex]n = 20, s = \frac{100}{\sqrt{20}} = 22.361[/tex]

Find the sample mean that will cut off the upper 95% of all samples of size 20 taken from the population.

This is the 100 - 95 = 5th percentile, which is X when Z has a p-value of 0.05, so X when Z = -1.645. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-1.645 = \frac{X - 2000}{22.361}[/tex]

[tex]X - 2000 = -1.645*22.361[/tex]

[tex]X = 1963.2[/tex]

The sample mean that will cut off the upper 95% of all samples of size 20 taken from the population is of 1963.2 pounds.

Answer:

is y=x^2 a proportional relationship?

[tex]{ \sf{yes. \: constant \: of \: proportionality = 1}}[/tex]

is y=2+x a proportional relationship?

[tex]{ \sf{no. \: unless \: y \: is \: proportinal \: to \: (2 + x)}}[/tex]

is y=2/x a proportional relationship?

[tex]{ \sf{yes. \: where \: proportianality \: constant \: is \: 2}}[/tex]

is y=2x a proportional relationship?

[tex]{ \sf{yeah. \: constant \: is \: 2}}[/tex]

Answer:

4

Step-by-step explanation:

The given data is :

8, 10, 12,14,16,18,20

We need to find the standard deviation. Here,

Count = 7

Sum, Σx: 98

Mean, μ: 14

The standard deviation is given by :

[tex]\sigma=\sqrt{\dfrac{1}{N}\Sigma(x_i-\mu)^2}[/tex]

or

[tex]\sigma^2=\dfrac{1}{N}\Sigma(x_i-\mu)^2\\\\=\dfrac{(8-14)^2+...+(20-14)^2}{7}\\\\=\dfrac{112}{7}\\\\\sigma^2=16\\\\\sigma=4[/tex]

So, the standard deviation of the given data is 4.

Answer:

63°

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

g(1)=5

f(g(1))=f(5)

f(5)=2

Answer:

The change is of -1.3 percentage points.

Step-by-step explanation:

The humidity is currently 56% and falling at a rate of 4 percentage points per hour.

This means that after n hours the humidity is of:

[tex]H(n) = 56 - 4n[/tex]

Estimate the change in humidity over the next 20 minutes.

It currently is 56%.

20 minutes is 20/60 = 1/3 of an hours, so:

[tex]H(\frac{1}{3}) = 56 - 4\frac{1}{3} = 54.7[/tex]

Change:

54.7 - 56 = -1.3

The change is of -1.3 percentage points.

The change in humidity over the next 20 minutes falling at a rate of  4 percentage points per hour is -1.3.

The humidity is currently 56% and falling at a rate of 4 percentage points per hour.

The change is determined by the small about of humidity changes x to x+h, so the output of x+h is the value of f at x plus the approximate change in f, that is

[tex]\rm f(x+h) =f(x) + f'(x) \times h[/tex]

f(x)= 56%

20 minutes is 20/60 = 1/3 of an hours

So, The change in humidity is

[tex]f'(x) = 4 \times 1/3[/tex]

f'(x) = 1.3

Here, it is falling at the rate of 4% point per hour so we will take it as negative as -1.3.

Learn more about changes in humidity;

https://brainly.com/question/14363655

Answer:

y=2x-3

Step-by-step explanation:

4x-2y=3

-2y=3-4x

2y=4x-3

y=4x/2-3/2

y=2x-1.5  m1=2 (the number near x)

If the searched line is parallel to the line 4x−2y=3, m1=m2= 2

y=m2x+b - the searched line

1=2*2+b

b=-3

y=2x-3

Answer:

1/11 of a gallon

Step-by-step explanation:

He used 2/11 of 1/2 gallon

2/11 * 1/2 = 1/11 of a gallon

Answer:

[tex]\frac{1}{11}[/tex]

Step-by-step explanation:

Step 1:  Find how much of a gallon he used

[tex]\frac{2}{11} * \frac{1}{2} =\frac{2}{22}[/tex]

[tex]\frac{2}{22}=\frac{1}{11}[/tex]

Answer:  [tex]\frac{1}{11}[/tex]

Answer:

totally 16 numbers can be formed

It is hard and the condition of repeat of number should be clear if you have formula ( it is obvious to have) you can use that.

Answer:

False

Step-by-step explanation:

x

The opposite of x is -x

x* -x = -x^2

This is not always 1

Answer:

false

Step-by-step explanation:

x*-x= - x ² so its not always 1

so I just started using brainly sorry if its not appropriate

Answer:

0.5145

Step-by-step explanation:

Mean is also known as average. It is expressed as:

Mean  = Sum of data/Sample size

Sum of data = 0.33+0.33+0.54+0.46+0.30+0.77+0.42+0.44+0.60+0.32+0.47+0.64+0.61+0.69+0.41+0.39+0.66+0.60+0.61+0.70

Sum of data = 10.29

Sample size = 20

Mean = 10.29/20

Mean = 0.5145

Hence the mean of the data is 0.5145

Answer:

The number of hits would follow a binomial distribution with [tex]n =10,\!000[/tex] and [tex]p \approx 4.59 \times 10^{-6}[/tex].

The probability of finding [tex]0[/tex] hits is approximately [tex]0.955[/tex] (or equivalently, approximately [tex]95.5\%[/tex].)

The mean of the number of hits is approximately [tex]0.0459[/tex]. The variance of the number of hits is approximately [tex]0.0459\![/tex] (not the same number as the mean.)

Step-by-step explanation:

There are [tex](26 + 10)^{6} \approx 2.18 \times 10^{9}[/tex] possible passwords in this set. (Approximately two billion possible passwords.)

Each one of the [tex]10^{9}[/tex] randomly-selected passwords would have an approximately [tex]\displaystyle \frac{10,\!000}{2.18 \times 10^{9}}[/tex] chance of matching one of the users' password.

Denote that probability as [tex]p[/tex]:

[tex]p := \displaystyle \frac{10,\!000}{2.18 \times 10^{9}} \approx 4.59 \times 10^{-6}[/tex].

For any one of the [tex]10^{9}[/tex] randomly-selected passwords, let [tex]1[/tex] denote a hit and [tex]0[/tex] denote no hits. Using that notation, whether a selected password hits would follow a bernoulli distribution with [tex]p \approx 4.59 \times 10^{-6}[/tex] as the likelihood of success.

Sum these [tex]0[/tex]'s and [tex]1[/tex]'s over the set of the [tex]10^{9}[/tex] randomly-selected passwords, and the result would represent the total number of hits.

Assume that these [tex]10^{9}[/tex] randomly-selected passwords are sampled independently with repetition. Whether each selected password hits would be independent from one another.

Hence, the total number of hits would follow a binomial distribution with [tex]n = 10^{9}[/tex] trials (a billion trials) and [tex]p \approx 4.59 \times 10^{-6}[/tex] as the chance of success on any given trial.

The probability of getting no hit would be:

[tex](1 - p)^{n} \approx 7 \times 10^{-1996} \approx 0[/tex].

(Since [tex](1 - p)[/tex] is between [tex]0[/tex] and [tex]1[/tex], the value of [tex](1 - p)^{n}[/tex] would approach [tex]0\![/tex] as the value of [tex]n[/tex] approaches infinity.)

The mean of this binomial distribution would be:[tex]n\cdot p \approx (10^{9}) \times (4.59 \times 10^{-6}) \approx 0.0459[/tex].

The variance of this binomial distribution would be:

[tex]\begin{aligned}& n \cdot p \cdot (1 - p)\\ & \approx(10^{9}) \times (4.59 \times 10^{-6}) \times (1- 4.59 \times 10^{-6})\\ &\approx 4.59 \times 10^{-6}\end{aligned}[/tex].

Answer:

Point has co-ordinates, (0, 5)

Step-by-step explanation:

If they cut y-axis, then x = 0

[tex]2y - x = 10 \\ 2y - 0 = 10 \\ 2y = 10 \\ y = 5[/tex]

Notice that

75.8 = 82.4 - 6.6 = 82.4 - 2 × 3.3

89 = 82.4 + 6.6 = 82.4 + 2 × 3.3

Then the percentage of students with scores between 75.8 and 89 make up the part of the distribution that lies within 2 standard deviations of the mean. The empirical (68-95-99.7) rule says that approximately 95% of any distribution lies within this range.

Answer:

b

Step-by-step explanation:

Answer:

‼️D) To the right‼️

Explanation

There is an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

Answer:

27

Step-by-step explanation:

x-y

We are subtracting and we want the smallest number

We want the smallest number for x and the largest number for y

The smallest number for x is 71

The largest number for y is 44

71-44

27

Answer:

x=30.5

Step-by-step explanation:

Using midsegment 's theorea:

[tex]2=\dfrac{RG}{RS} =\dfrac{RH}{RQ} =\dfrac{GH}{SQ} \\\\4x-65=2x-4\\\\2x=61\\\\x=\dfrac{61}{2} \\\\x=30.5\\[/tex]

Answer:

x = π/4.

Step-by-step explanation:

3sin(2x) = 2sin(2x) + 1

3sin(2x) - 2sin(2x) = 1

1sin(2x) = 1

sin(2x) = 1

When a variable n = π/2, sin(π/2) = 1 [refer to the unit circle].

2x = π/2

x = π/4.

Hope this helps!

Answer:Y=25:3

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]