Which expression is equivalent to 3/2

Answer:

1/10

Step-by-step explanation:

1/5*1/2

1/10

9514 1404 393

Answer:

  2√3 ≈ 3.4641016

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  (4x +4)^(1/2) at x=2 is ...

  (4·2 +4)^(1/2) = 12^(1/2) = 2√3 ≈ 3.4641016

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Additional comment

If you really mean (4x+4)^1/2, then you have 12^1/2 = 12/2 = 6.

If the exponent is 1/2, it needs to be in parentheses.

Answer:

3/2

Step-by-step explanation:

y2 - y1 / x2 - x1

1 - 7 / -5 - (-1)

-6 / -4

= 3/2

Answer:

m=3/2

Step-by-step explanation:

m=y2-y1/x2-x1

m=1-7/-5-(-1)

m=-6/-4

m=3/2

5X + 8 = 53

5X = 53 - 8

X = 45 / 5

X = 9

Answer:

X=9

Step-by-step explanation:

5X+8=53

To solve this we need to make X the subject of the equation that means X should be alone on one side of the equation. Taking the following steps

5X=53-8

5X=45

X=45/5

X=9

Answer:

6x + 24

Step-by-step explanation:

6 * (4 + x) = 6 * 4 + 6 * x = 6x + 24

Answer:

a)

[tex]|z| < 2.054[/tex]: Do not reject the null hypothesis.

[tex]|z| > 2.054[/tex]: Reject the null hypothesis.

b) [tex]z = 2.81[/tex]

c) Reject.

d) The p-value is 0.005.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and the subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Population 1:

Sample of 42, standard deviation of 3.3, mean of 101, so:

[tex]\mu_1 = 101[/tex]

[tex]s_1 = \frac{3.3}{\sqrt{42}} = 0.51[/tex]

Population 2:

Sample of 53, standard deviation of 3.6, mean of 99, so:

[tex]\mu_2 = 99[/tex]

[tex]s_2 = \frac{3.6}{\sqrt{53}} = 0.495[/tex]

H0 : μ1 = μ2

Can also be written as:

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

H1 : μ1 ≠ μ2

Can also be written as:

[tex]H_1: \mu_1 - \mu_2 \neq 0[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error .

a. State the decision rule.

0.04 significance level.

Two-tailed test(test if the means are different), so between the 0 + (4/2) = 2nd and the 100 - (4/2) = 98th percentile of the z-distribution, and looking at the z-table, we get that:

[tex]|z| < 2.054[/tex]: Do not reject the null hypothesis.

[tex]|z| > 2.054[/tex]: Reject the null hypothesis.

b. Compute the value of the test statistic.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

From the samples:

[tex]X = \mu_1 - \mu_2 = 101 - 99 = 2[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.51^2 + 0.495^2} = 0.71[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{2 - 0}{0.71}[/tex]

[tex]z = 2.81[/tex]

c. What is your decision regarding H0?

[tex]|z| = 2.81 > 2.054[/tex], which means that the decision is to reject the null hypothesis.

d. What is the p-value?

Probability that the means differ by at least 2, either plus or minus, which is P(|z| > 2.81), which is 2 multiplied by the p-value of z = -2.81.

Looking at the z-table, z = -2.81 has a p-value of 0.0025.

2*0.0025 = 0.005

The p-value is 0.005.

Translate the given point and line together so that you get a new point and a new line that passes through the origin. This turns the problem into finding the distance between the new point,

p = (4, 4, -4) - (-1, 1, 3) = (5, 3, -7)

and the new line,

r*(t) = r(t) - ⟨-1, 1, 3⟩ = ⟨2t, 2t, -3t⟩

Let p = ⟨5, 3, -7⟩, the vector starting at the origin and pointing to p. Then the quantity ||p - r*(t)|| is the distance from the point p to the line r*(t).

Let u be such that ||p - r*(t)|| is minimized. At the value t = u, the vector p - r*(t) is orthogonal to the line r*(t), so that

(p - r*(u) ) • r*(u) = 0

I've attached a sketch with all these elements in case this description is confusing. (The red dashed line is meant to be perpendicular to r*(t).)

Solve this equation for u :

p • r*(u) - r*(u) • r*(u) = 0

p • r*(u) = r*(u) • r*(u)

and x • x = ||x||² for any vector x, so

p • r*(u) = ||r*(u)||²

⟨5, 3, -7⟩ • ⟨2u, 2u, -3u⟩ = (2u)² + (2u)² + (-3u)²

10u + 6u + 21u = 4u ² + 4u ² + 9u ²

17u ² - 37u = 0

u (17u - 37) = 0

==>   u = 0   or   u = 37/17

We ignore u = 0, since the dot product of any vector with the zero vector is 0.

Then the minimum distance distance between the given point and line is

||p - r*(u)|| = ||⟨5, 3, -7⟩ - 37/17 ⟨2, 2, -3⟩|| = √(42/17)

Step-by-step explanation:

a1. The shape will be a vertical or horizontal line.

a2. The shape will be shaped like a diagonal line increasing as we go right.

a3. The shape will be shaped like a diagonal line decreasing as we go right.

a4. The shape will be shaped like a U facing upwards.

a5.The shape will be shaped like a U facing downwards.

a6. The shape will look like a S shape and it increases as we go right.

a7. The shape will look like a S shape and it decreases as We go right.

a8. The shape look like a W shape and it facing upwards.

a9. The shape look a W shape facing downwards.

We are given function.

[tex]x {}^{5} - 3x {}^{4} - 5x {}^{3} + 5x {}^{2} - 6x + 8[/tex]

b. We can test by the Rational Roots Test,

This means a the possible roots are

plus or minus(1,2,4,8).

c. If we apply Descrates Rule of Signs,

d. Use Desmos to Graph the Function. Some roots are (-2,1,4).

e.

[tex](x {}^{2} + 1) (x - 1)(x - 4)(x + 2)[/tex]

f. The complex zeroes are

i and -i

Polynomial [tex]f(x) = x^{5} -3x^{4} - 5x^{3} + 5x^{2} - 6x + 8[/tex] in factor form: (x-1)(x+2)(x-4)(x-i)(x+i)

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

Shape of the graph for the following polynomial:

Finding zeros of the polynomial given:

[tex]f(x) = x^{5} -3x^{4} - 5x^{3} + 5x^{2} - 6x + 8[/tex]

By factor theorem, if f(t) = 0, t is a zero of the polynomial.

Taking t = 1.

f(1) = 1 - 3 - 5 + 5 - 6 + 8 = 0

(x - 1) is a factor of the polynomial f(x).

Divide f(x) by (x-1) using long division to find the other factors.

f(x)/(x-1) = [tex]x^{4} -2x^{3}-7x^{2} -2x-8[/tex] is also a factor of f(x).

Factorizing it further:

g(x) = [tex]x^{4} -2x^{3}-7x^{2} -2x-8[/tex]

g(-2) = 16 + 16 - 28 + 4 - 8 = 0

(x + 2) is a factor of g(x) and thus f(x).

g(x)/(x+2) = [tex]x^{3} - 4x^{2} +x - 4[/tex] is a factor of f(x).

Factorizing it further:

k(x) = [tex]x^{3} - 4x^{2} +x - 4[/tex]

k(4) = 64 - 64 + 4 - 4 = 0

(x - 4) is a factor of k(x) thus of f(x).

k(x)/(x-4) = [tex]x^{2} +1[/tex]

Factorizing it further:

l(x) = [tex]x^{2} +1[/tex] = (x + i)(x - i)

Zeros of f(x) = 1, -2, 4, ±i

Rational zeros :  1, -2, 4

Positive real zeros: 1, 4

Negative real zeros: -2

Complex zeros: ±i

Polynomial in factor form: (x-1)(x+2)(x-4)(x-i)(x+i).

Learn more about polynomial here

https://brainly.com/question/11536910

#SPJ2

Answer:

16

Step-by-step explanation:

1) Find out r of the sequence. The first term(a1) is 16384, the second term (a2) is 8192.

8192=16384*r. r= 0.5

2) Use the rule that an=a1*r^(n-1)

a11=a1*r^10

a11= 16384*((0.5)^10)= 16384/ (2^10)=16.

Answer:

A. Increase the level of confidence

Step-by-step explanation:

The margin of error is given by:

The margin of error is:

[tex]M = \frac{Ts}{\sqrt{n}}[/tex]

In which T is related to the level of confidence(the higher the level of confidence, the higher T is), s is the standard deviation of the sample and n is the size of the sample.

Increase the width:

That is, increasing the margin of error, as the width is twice the margin of error, the possible options are:

Increase T -> increase confidence level.

Increase s -> Increase the standard deviation of the sample.

Decrease n -> Decrease the sample size.

Thus, the correct answer is given by option A.

Step-by-step explanation:

we have denominators 5, 6 and 30.

the smallest number that is divisible by all 3 is clearly 30.

so, we have to multiply everything by 30 to eliminate the fractions.

180/5 + 60/5 x = 89 + 210/6 x + 30/6 =

36 + 12x = 89 + 35x + 5

-58 = 23x

x = -58/23

Answer:

(a) 4 sample points

(b) See attachment for tree diagram

(c) The probability that no tail is appeared is 1/4

(d) The probability that exactly 1 tail is appeared is 1/2

(e) The probability that 2 tails are appeared is 1/4

(f) The probability that at least 1 tail appeared is 3/4

Step-by-step explanation:

Given

[tex]Coins = 2[/tex]

Solving (a): Counting principle to determine the number of sample points

We have:

[tex]Coin\ 1 = \{H,T\}[/tex]

[tex]Coin\ 2 = \{H,T\}[/tex]

To determine the sample space using counting principle, we simply pick one outcome in each coin. So, the sample space (S) is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

The number of sample points is:

[tex]n(S) = 4[/tex]

Solving (b): The tree diagram

See attachment for tree diagram

From the tree diagram, the sample space is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

Solving (c): Probability that no tail is appeared

This implies that:

[tex]P(T = 0)[/tex]

From the sample points, we have:

[tex]n(T = 0) = 1[/tex] --- i.e. 1 occurrence where no tail is appeared

So, the probability is:

[tex]P(T = 0) = \frac{n(T = 0)}{n(S)}[/tex]

This gives:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Solving (d): Probability that exactly 1 tail is appeared

This implies that:

[tex]P(T = 1)[/tex]

From the sample points, we have:

[tex]n(T = 1) = 2[/tex] --- i.e. 2 occurrences where exactly 1 tail appeared

So, the probability is:

[tex]P(T = 1) = \frac{n(T = 1)}{n(S)}[/tex]

This gives:

[tex]P(T = 1) = \frac{2}{4}[/tex]

[tex]P(T = 1) = \frac{1}{2}[/tex]

Solving (e): Probability that 2 tails appeared

This implies that:

[tex]P(T = 2)[/tex]

From the sample points, we have:

[tex]n(T = 2) = 1[/tex] --- i.e. 1 occurrences where 2 tails appeared

So, the probability is:

[tex]P(T = 2) = \frac{n(T = 2)}{n(S)}[/tex]

This gives:

[tex]P(T = 2) = \frac{1}{4}[/tex]

Solving (f): Probability that at least 1 tail appeared

This implies that:

[tex]P(T \ge 1)[/tex]

In (c), we have:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Using the complement rule, we have:

[tex]P(T \ge 1) + P(T = 0) = 1[/tex]

Rewrite as:

[tex]P(T \ge 1) = 1-P(T = 0)[/tex]

Substitute known value

[tex]P(T \ge 1) = 1-\frac{1}{4}[/tex]

Take LCM

[tex]P(T \ge 1) = \frac{4-1}{4}[/tex]

[tex]P(T \ge 1) = \frac{3}{4}[/tex]

Answer:

try 91.78, 91.58, 91.26, 363.4

Step-by-step explanation:

Answer:

2.97m

Step-by-step explanation:

1% of 3m =1/100×3=0.03

0.03m of cloth was shrunk,

So, New lenght : 3-0.03=2.97m

Answer:

C- 35 °

Step-by-step explanation:

Interior angle adjacent to 90° angle = 90° (supplementary angles of a line segment).

Interior angle adjacent to 125° angle = 55° (supplementary angles of a line segment).

Sum of two interior angles of the triangle = 55+90 = 145°

∠p = 180° - 145° = 35°

Answer:

Sharjah Call Girls +971529238486 | Call Girls In Sharjah

Step-by-step explanation:

Sharjah Call Girls and our group are very a good deal satisfied to participate withinside the boom of the leisure field. Lots of customers are touring Sharjah now no longer handiest for playing the splendor of the town however additionally to the sensual entertainments our profiles.

Answer:

Need to see the problem, but the "zero of the function" is the x value when y=0.

Substitute '0' for y.

Solve for x

Answer: D

Step-by-step explanation:

Answer:

divide 99 by 5

99/5= 19.8

Answer:

Does the answer help you?

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

a) The first 5 partial sums are listed in the table in the attachment.

__

b) Sigma notation makes use of the general term shown:

  [tex]\displaystyle\sum_{n=1}^\infty{\frac{3^n+(-2)^n}{6^n}}[/tex]

__

c) The sum appears to be close to 3/4. (For large n, a calculator cannot evaluate the terms of the series--they are too small.) The attachment shows the 100th sum to be rounded to 3/4 (from 12 significant digits).

QUESTION:- SOLVE EQUATION BY FACTORISATION

EQUATION:-

[tex] {x}^{2} + x - 72 = 0[/tex]

ANSWER:-

[tex] {x}^{2} + x - 72 = 0\\{x}^{2} + 9x - 8x - 72 = 0 \\ x(x + 9) - 8(x +9) = 0 \\ (x - 8)(x + 9) = 0 \\ [/tex]

NOW FOR VALUE OF X ->

[tex]x - 8 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 9 = 0\\ x = 8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 9[/tex]

9514 1404 393

Answer:

  C. 4 +√(x+5)

Step-by-step explanation:

The sign between the terms changes to form the conjugate. The radical contents are unchanged.

The conjugate of 4 -√(x+5) is 4 +√(x+5).

_____

Additional comment

The utility of a conjugate is that the product of a number and its conjugate is the difference of two squares. The squares are intended to remove an undesirable feature of the number, its imaginary part or its irrational part, for example. Here, the product of the number and its conjugate would be ...

  (a -b)(a +b) = a² -b²

  4² -(√(x+5))² = 16 -(x +5) = 11 -x . . . . no longer contains a root

Answer:

The number is 16

Step-by-step explanation:

Number : x

Procedure and resolution:

6x = 96

x = 96/6

x = 16

Answer:

[tex]\frac{dy}{dt}=304mi/h[/tex]

Step-by-step explanation:

From the question we are told that:

Height of Plane [tex]h=3mi[/tex]

Speed [tex]\frac{dx}{dt}=460mi/h[/tex]

Distance from station [tex]d=4mi[/tex]

Generally the equation for The Pythagoras Theorem is is mathematically given by

[tex]x^2+3^2=y^2[/tex]

For y=d

[tex]x^2+3^2=d^2[/tex]

[tex]x^2+3^2=4^2[/tex]

[tex]x=\sqrt{7}[/tex]

Therefore

[tex]x^2+3^2=y^2[/tex]

Differentiating with respect to time t we have

[tex]2x\frac{dx}{dt}=2y\frac{dy}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{x}{y}\frac{dx}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{\sqrt{7}}{4} *460[/tex]

[tex]\frac{dy}{dt}=304.2614008mi/h[/tex]

[tex]\frac{dy}{dt}=304mi/h[/tex]

9514 1404 393

Answer:

  x = 5.0

Step-by-step explanation:

The tangent relation is helpful:

  Tan = Opposite/Adjacent

  tan(50°) = x/4.2

  x = 4.2·tan(50°) ≈ 5.0054 . . . . multiply by 4.2

  x ≈ 5.0

Answer:

x = - 12/11

Step-by-step explanation:

Multiply by LCM (or LDC if you like that term better)

2 & 3 LCM = 6

6(3/2) x  + 6(1/3)x  + 5*6 = 3*6

9x + 2x + 30 = 18

11x = - 12

x = - 12/11

Answer:

Slope passes through (-6, 5) and (-2, 7)

[tex]m_1=\frac{y_2-y_1}{x_2-x_1} =m_1=\frac{7-5}{-2+6}[/tex]

[tex]m_1=\frac{2}{4} =\frac{1}{2}[/tex]

Slope passes through (4, 2) and (6, 6)

[tex]m_2=\frac{6-2}{6-4}[/tex]

[tex]\frac{4}{2} =2[/tex]

[tex]m_1\times m_2 \neq -1[/tex] [tex]m_1\neq m_2[/tex]

Answer:- A) neither perpendicular nor parallel.

OAmalOHopeO

Answer:

Step-by-step explanation:

1 km = 0.621 mi

1 hr = 60 min

(5 km)/(4.5 hr) × (0.621 mi)/km × (1 hr)/(60 min) = (0.0115 mi)/min