Which expression is equivalent to (q6)2

Which Expression Is Equivalent To (q6)2

Answers

Answer 1

Answer:

q¹²

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Exponential Rule [Powering]: [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

(q⁶)²

Step 2: Simplify

Exponential Rule [Powering]:                                                                           q⁶⁽²⁾[Exponents] Multiply:                                                                                        q¹²
Answer 2

Answer :

q¹²

step-step explanation:

( q⁶)²

( use exponent rule ) multiply the exponents

q⁶ × ²

q¹²


Related Questions

CAN SOMEONE HLEP ME OUT WITH THIS PLEASE AND THANK YOU

Answers

Answer:

12 5/24 thats the answer

Step-by-step explanation:

use this website for mixed number calculator: https://www.calculatorsoup.com/calculators/math/mixednumbers.php

help pls! i cant figure it out.

Answers

3 x 5 = 15 + 12= 27 and there is your answer!

[tex]\longrightarrow{\green{x\:=\:5}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

➝[tex]\: \frac{3x}{5} = \frac{x + 1}{2} [/tex]

➝[tex]\:2 \times 3x = 5(x + 1)[/tex]

➝[tex]\:6x = 5x + 5[/tex]

➝[tex]\:6x - 5x = 5[/tex]

➝[tex]\:x = 5[/tex]

To verify:-

✒[tex] \:\frac{3 \times 5}{5} = \frac{5 + 1}{2} [/tex]

✒[tex]\: \frac{15}{5} = \frac{6}{2} [/tex]

✒[tex]\:3 = 3[/tex]

✒[tex]\:L. H. S. =R. H. S. [/tex]

Hence verified.

[tex]\bold{ \green{ \star{ \orange{Mystique35☂}}}}⋆[/tex]

Find the length of the hypotenuse to the nearest tenth. (example 4.5)
7
2

Answers

Answer:

hypotenuse = 7.3

Step-by-step explanation:

the length two legs of the given triangle are 7 and 2 respectively.

using pythagoras theorem

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.3 = c

a. x ll y
b. y ll z
c. a ll b
d. x perpendicular to b

Answers

Answer:

Option B

Step-by-step explanation:

By applying the converse theorem of corresponding angles,

"If corresponding angles formed between two parallel lines and the transversal line are equal then both the lines will be parallel"

Angle between line B and Y = 90°

Angle between line B and Z = 90°

Therefore, corresponding angles are equal.

By applying converse theorem, line Y and line Z will be parallel.

Option B will be the answer.

$500 is shared in ration 2:3 between two girls how much money did each girl receive workout please step by step ​

Answers

Answer:

100:350                   simplified: [tex]\frac{2}{7}[/tex]

Step-by-step explanation

A ratio of 2:3 means that for every item of A, we can expect of item B. Therefore, our total group is 2+3=5.

Calculate expected number of item A:

[tex]\frac{2x500}{5}[/tex]

Expected number of item A: [tex]\frac{1000}{5}[/tex]

This fraction can be reduced by 5 giving you:

Expected number of item A: 200

Calculate expected number of item B:

[tex]\frac{3x500}{5}[/tex]

Expected number of item B: [tex]\frac{1500}{5}[/tex]

This fraction can be reduced by 5 giving you:

Expected number of item B: 300

Which function is graphed?

Answers

Answer:

I think that a Cube Root Function

Step-by-step explanation:

Is this set of data right-skewed, left-skewed, normal, or something else?

Answers

Answer:

The data represents data right-skewed because it's numerical data are in the right place and showing the percentage of an event/object.

#LearnwithBrainly

please find the result !​

Answers

Answer:

[tex] \displaystyle - \frac{1}{2} [/tex]

Step-by-step explanation:

we would like to compute the following limit:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]

if we substitute 0 directly we would end up with:

[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]

thus apply L'hopital rule which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]

simplify which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]

simplify which yields:

[tex] \displaystyle - \frac{1}{2} [/tex]

finally, we are done!

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

Evaluating the expression directly at x=0 gives ...

  [tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]

Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.

The approximations of interest are ...

  [tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]

__

Then as x nears zero, the limit we seek is reasonably approximated by the limit ...

  [tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]

_____

I find a graphing calculator can often give a good clue as to the limit of a function.

By the definition of a ▱, AD∥BC and AB∥DC. Using, AD as a transversal, ∠A and ∠ are same-side interior angles, so they are . Using side as a transversal, ∠B and ∠C are same-side interior angles, so they are supplementary. Using AB as a transversal, ∠A and ∠B are same-side interior angles, so they are supplementary. Therefore, ∠A is congruent to ∠C because they are supplements of the same angle. Similarly, ∠B is congruent to ∠.

Answers

Step-by-step explanation:

is it a question ? please check.

Answer:

Step-by-step explanation:

D.

supplementary.

BC.

D.

Sum of two digit number is9.When we interchange the digits it is found that the resulting new number becomes twice the other number. What are the numbers

Answers

Answer:

4 and 5

Step-by-step explanation:

Let the numbers be x and y

If their sum is 9, hence;

x + y = 9 ....1

When reversed

10y+x = 2(10x+y)

10y+x = 20x + 2y

10y - 2y = 20x - x

8y = 19x

y = 10x/8 ...2

Substitute equation 2 into 1;

From 1;

x+y = 9

x +(10x/8) = 9

18x/8 = 9

18x = 72

x = 72/18

x = 4

Since x+y =9

y = 9-x

y =9-4

y = 5

Hence the numbers are 4 and 5

Write a quadratic equation that has the solutions: 4 and -7

Answers

Answer:

y = ( x-4)(x+7)

Step-by-step explanation:

When we know the zeros of the equation, we can write the equation in the form

y= a(x-z1) (x-z2)   where a is a constant and z1 and z2 are the zeros (solutions)

y = a( x-4)(x--7)

y =a( x-4)(x+7)

Since its says write an equation, we can pick a and I will let a=1

y = ( x-4)(x+7)

(1.8 + 1.3) + 0.7 = 1.8 + (1.3 + 0.7) is an example of which property?

Answers

Answer:

Associative property

Step-by-step explanation:

The associative property is a math rule that says that the way in which factors are grouped in a multiplication problem does not change the product.

Hope this helps

Please help! Pleaseeeeeee

Answers

Answer:

The answer is D

Step-by-step explanation:

-x is n

Y=0

Answer:

D

Step-by-step explanation:

Basically....... graph shown in picture

what is f(0) for the function f(x) =2x+3

Answers

Answer:

3

Step-by-step explanation:

f(x) =2x+3

Let x=0

f(0) =2*0+3

Multiply

f(0) =0+3

Add

f(0) =3

Answer:

3

step-by-step explanation

f ( x ) = 2 x + 3

f ( 0 ) = 2 × 0 + 3 .. ( f ( x = 0 ) - given )

multiply

f ( 0 ) = 0 + 3

Add the numbers

f ( 0 ) = 3

a) Draw the graph of y = 4x - 1 on the grid. b) Use the graph to estimate the value of x when y = 1​

Answers

Hello,

a) photo attached

b) When y = 1, x ≈ 0.5

Verification through calculation :

We have :

y = 4x - 1

⇔ 1 = 4x - 1

⇔ 4x = 2

⇔ x = 2/4 = 0.5

This is just !

:-)

which one of the following is product of(-3n)and(4mn-5n)​

Answers

I think the answer isX=50 x=10

A motorist drives at an average speed of 80 km/hr. How far does she travel in 3(1/2)
hours?

Answers

Answer: 280 km

Step-by-step explanation:

[tex]3\dfrac{1}{2} \: hours = 3.5 \: hours[/tex]

S = V × t

V = 80 km/h

t = 3.5 h

S = 80 × 3.5 = 280 km

Can someone help me? Which of the following verifies that triangle YXZ is similar to triangle QPR?

Answers

Answer:

a

Step-by-step explanation:

What is an equation of the line that passes through the points (-5, -1) and (5, 3)?

Answers

So two co-ordinates are (2,-5) and (0,-3)

First obtain the gradient (slope) by (y2-y1)/(x2-x1) so (-3–-5)/(0–2) so 2/-2 = -1

So the first part of the equation is y=-x.

Then to find out how many you need to + or - just calculate it:

In (2,-5), -x is -2. To get to -5 you need to subtract another 3, hence y=-x-3. It shouls be the same in the other co-ordinate (0,-3) if I’ve done it right: -x = 0. Subtract 3 for -3.

So y = -x - 3 should do it.
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Related Questions (More Answers Below)

Identify the rule that correctly describes each
sequence.
12, 8, 4, 0, -4, ...
Each term is 4 more than the previous term.
Each term is 4 less than the previous term.
Each term is 1/2 the previous term.
Each term is 2/3 the previous term.
6, 12, 24, 48, 96, ...
Each term is 6 more than the previous term.
Each term is 12 more than the previous term.
Each term is 1/2 the previous term.
Each term is 2 times the previous term.
COMPLETE
COMPLETE
here’s the answers

Answers

Answer:

Each term is 4 less than the previous term.

Step-by-step explanation:

If this helps you mark as brainlist!

Answer:

B and D are your answers for that whole page

Step-by-step explanation:

Identify the rule that correctly describes each sequence.

12, 8, 4, 0, –4, …

Each term is 4 more than the previous term.

This Is the right one: Each term is 4 less than the previous term.

Each term is 1/2 the previous term.

Each term is 2/3 the previous term.

6, 12, 24, 48, 96, …

Each term is 6 more than the previous term.

Each term is 12 more than the previous term.

Each term is 1/2 the previous term.

This is the right one: Each term is 2 times the previous term.

Two large parallel metal plates carry opposite charges. They are separated by 85mm. The work done by the field is 6x10-3J and its field exerts on a particle with charge +8µC. Calculate the surface charge density on each plate.

Answers

Answer:

The surface charge density is [tex]7.8\times10^{-8} C/m^2[/tex].

Step-by-step explanation:

separation, d = 85 mm

Work, W = 6 x 10^-3 J

charge , Q = 8µC

The potential difference is given by

W = q V

[tex]V=\frac{6\times 10^{-3}}{8\times 10^{-6}}=750 V[/tex]

Let the charge on he capacitor is q.

[tex]q = CV\\\\q = \frac{\varepsilon oA}{d}\times V\\\\\frac{q}{A} = \frac{8.85\times 10^{-12}\times750}{0.085} =7.8\times10^{-8} C/m^2[/tex]

Analyze the diagram below and complete the instructions that follow.

Answers

i think the ans is 10

Linda makes chocolate truffles . The recipe for 20 dark chocolate truffles is 1 cup cream 2 cups dark chocolate Complete the recipe for 40 dark truffles

Answers

Answer:

2 cups of Ice cream and 4 cups of dark choclate

Step-by-step explanation:

If 20 needs 1 cup cream 2 cups dark chocolate you want to find 40 you need to double all ingrediants so answer is 2 cups of Ice cream and 4 cups of dark choclate

what should I do if I accidentally break my pet rock that has googly eyes on him? i need to fix Rocky Ronny McRonkster

Answers

Answer:

Try to glue it back together

Step-by-step explanation:

I heard gorilla glue works, but be careful and don't get the glue on your body. If that happens it can cause irritation and call posion control immediately.

Express 5m2 in cm2 please answer fast!

Answers

Answer:

500000 cm2

Step-by-step explanation:

If sally completed 6 laps around a circular track with the dimensions shown below, how many meters will she have run? Use 3.14 for up and round your answer to the nearest tenth

Answers

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

A cube has square sides with area x2 +24x + 144. What expression represents the surface area of the cube?

Answers

Given:

A cube has square sides with area [tex]x^2+24x+144[/tex].

To find:

The expression that represents the surface area of the cube.

Solution:

It is given that,

The area of each side of cube = [tex]x^2+24x+144[/tex]

Number of sides of a cube = 6

Total surface area of the cube is the product of number of sides of the cube and the area of each side. So, the total surface area of the cube is

[tex]SA=6(x^2+24x+144)[/tex]

[tex]SA=6(x^2)+6(24x)+6(144)[/tex]

[tex]SA=6x^2+144x+864[/tex]

Therefore, the expression that represents the surface area of the cube is [tex]6x^2+144x+864[/tex].

Help please thanks! :)

Answers

Answer:

Option A = 1/15 cubic meters

Step-by-step explanation:

Formule to find volume of rectangular prism:

Volume = width × height × length

V = w×h×l

V = 1/3 × 1/4 × 4/5

V = 1/15 cubic meters

Devons current financial goals are to reduce his credit card debt start a retirement plan and save for a down payment on a house which smart goal attribute in the table applies to each of devons financial goals

Answers

Answer:

timely, timely,measurable

Step-by-step explanation:

Answer:

specific, timely, measurable

Step-by-step explanation:

i took the test on plato

In a school there are 1800 boys and 1200 girls. In an exam only 32 % of the boys passed and 50 % of the girls passed. Find the percentage of the total who did not pass.​

Answers

Answer:

Step-by-step explanation:

The total number of students is 1800 + 1200 =  3000

The % of boys who did not pass is 100% - 32% = 68%

The number of boys who did not pass is 68/100 * 1800 =       1224

The % of the girls who did not pass is 100%  - 50% = 50%

The number of girls who did not pass was 50/100 * 1200 =    600

The total number who did not pass was                                  1824

The % who did not pass was 1824/3000 * 100 = 60.8%

Other Questions
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