Which expression represents the distance
between point G and point H?
|-12|16| |-12|+|-9|
1-9|-|-6|
|-12|+|6|
-15
H(-9,6)
G(-9,-12)
15+y
0
-15-
15

The population of interest is the group of students who submitted an application to the college in 2017.

A sample is a subset of a population that is selected and studied in order to make inferences or conclusions about the population. The sample is usually selected to be representative of the population in some way, so that the conclusions drawn from the sample can be generalized to the population as a whole.

The correct answer is C.

The purpose of the study is to determine why students who are interested in the college decide to enroll or not. Therefore, the population of interest is the group of students who submitted an application to the college in 2017.

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Instead of 2.00 as mentioned in the question, the semester GPA is 1.38. Please double-check your calculations or provide more details if you made an error when reporting your grades or computing your GPA.

Students must devote approximately 135 hours (45 x 3) of class, instructional, and independent time to a three credit unit course. Students who enroll in a course for four credit hours must dedicate around 180 (45 x 4) hours to it, split between in-class and out-of-class work.

You must first translate each letter grade using the common 4.0 scale into its equivalent numerical number before you can determine your semester GPA:

A = 4.0

B = 3.0

C = 2.0

D = 1.0

F = 0.0

E = 0.0 (equivalent to F)

Then, you can use the formula:

(Total grade points) / GPA (total credit hours)

Using this formula, we can calculate your semester GPA as follows:

FYE 105: F (0.0) x 3 credit hours = 0.0 grade points

MAT 150: E (0.0) x 3 credit hours = 0.0 grade points

ENG 101: D (1.0) x 3 credit hours = 3.0 grade points

BIO 112: A (4.0) x 3 credit hours = 12.0 grade points

BIO 113: B (3.0) x 1 credit hour = 3.0 grade points

Total grade points = 0.0 + 0.0 + 3.0 + 12.0 + 3.0 = 18.0

Total credits earned is 13 (3 + 3 + 3 + 3 + 1)

GPA = 18.0 / 13 = 1.3846

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Answer

6255 pounds

8.34×750=6255lbs

The conditions in which is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal : (C) A random sample of 10 taken from a population distribution that is skewed to the right.

In statistics, the normal or Gaussian distribution is a continuous probability distribution for real-valued random variables.

The normal distribution is important in statistics and is often used in the natural and social sciences to represent real-valued random variables whose distribution is unknown. Their importance is partly due to the central limit theorem. It states that in some cases the average of many samples (observations) of a random variable with finite mean and variance is itself a random variable - whose distribution converges to a normal distribution as the size of the l sample increases.

Now,

If we look at the options given below, we see that the random samples in options A and B are normally distributed, so their sample means will be approximately normally distributed.

Similarly, option E indicates that the population is uniform, so the sample mean will also be approximately normal.

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Answer:

the answer to that is -31

Answer:

[tex]v = \frac{7}{2}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

yr face add more points NOW

therefore, we have shown that: [tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})[/tex] assuming that x2 ≠ x1.

Slope refers to the measure of steepness of a line or a curve. In mathematics, slope is usually denoted by the letter "m" and is defined as the ratio of the change in the y-coordinate to the change in the x-coordinate between two points on a line.

The formula for calculating the slope between two points (x1, y1) and (x2, y2) on a line is:

[tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})[/tex]

by the question.

To finds the slope of a line passing through two points (x1, y1) and (x2, y2), we use the slope formula:

[tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})[/tex]

This formula represents the change in y divided by the change in x between the two points.

Now, assuming that x2 ≠ x1, we can simplify the formula as follows:

[tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})*(1/1)[/tex]

Multiplying the numerator and denominator by 1, which in this case is (x2 - x1) / (x2 - x1), we get:

[tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})*(x_{2}-x_{1})/(x_{2}-x_{1})[/tex]

Simplifying the numerator, we have:

[tex]m= (y_{2} -y_{1} )/(x_{2}-x_{1})/[(x_{2}-x_{1})*1][/tex]

The term (x2 - x1) cancels out, leaving us with:

[tex]m=(y_{2}-y_{1} /1[/tex]

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Answer:

Step-by-step explanation:

The result of the division in ordinary decimal notation is 300.

Scientific notation, also known as standard form or exponential notation, is a method of expressing very large or very small numbers in a compact and standardized way.

To perform the indicated operation, we need to divide 0.00036 by 0.0000012.

First, let's express both numbers in scientific notation

0.00036 = 3.6 x 10^(-4)

0.0000012 = 1.2 x 10^(-6)

Now we can divide the two numbers and simplify

3.6 x 10^(-4) / 1.2 x 10^(-6) = (3.6 / 1.2) x 10^(-4-(-6)) = 3 x 10^(2)

Finally, we can convert this result back to ordinary decimal notation

3 x 10^(2) = 300

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The given question is incomplete, the complete question is:

Convert each number to scientific notation and perform the indicated operations. Express the result in ordinary decimal notation. 0.00036/0.0000012

To calculate the actual distance in km, we need to use the scale factor of 1:100 000. This means that 1 cm on the map is equivalent to 100 000 cm in real life.

Therefore, 12.3 cm on the map is equivalent to 12.3 x 100 000 cm in real life.

Now, 1 km is equivalent to 100 000 cm.

Therefore, 12.3 x 100 000 cm is equivalent to 1.23 km.

Hence, the actual distance in km is 1.23 km.

Method to list all non-isomorphic trees on n vertices is to add edges to a single vertex tree. Using A, B, C, D, E, we list 5 non-isomorphic trees on 6 vertices.

A by-hand method to give a list of all non-isomorphic trees on exactly n vertices is to start with a tree on n vertices and then generate all possible trees by adding edges between vertices that are not already connected.

For example, to find all non-isomorphic trees on 4 vertices, we can start with a single vertex and then add edges to form a tree with 2 vertices, then add edges to form a tree with 3 vertices, and finally add edges to form a tree with 4 vertices. We can then check each tree for isomorphism by comparing their adjacency matrices.

Using the method from (a), we can find all non-isomorphic trees on exactly six vertices by starting with a single vertex and adding edges until we have a tree on six vertices.

To ensure that we generate all possible trees, we can use the following five vertices: A, B, C, D, E. We can then generate all trees by adding edges between vertices that are not already connected, making sure to avoid creating cycles. After generating all trees, we can check for isomorphism by comparing their adjacency matrices.

The resulting list of non-isomorphic trees on six vertices, in alphabetical order, is shown. The tree 1 and tree 2 are the same. Also, trees 3, 4, and 5 are not isomorphic to each other or to trees 1 and 2.

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To show that the properties of a probability distribution for a discrete random variable are satisfied, we need to verify that the probability distribution function (PDF) satisfies, The PDF must be non-negative for all values of the random variable and The sum of the probabilities for all possible values of the random variable must be equal to 1.

Let X be a discrete random variable taking values x1, x2, ..., xn, and let P(X) be the probability distribution function for X, such that P(X = xi) = pi for all i.

The PDF must be non-negative for all values of the random variable. This means that for any value xi of the random variable, the probability pi must be greater than or equal to zero. That is,

pi ≥ 0 for all i.

This property ensures that probabilities are never negative, which is a necessary condition for a valid probability distribution.

The sum of the probabilities for all possible values of the random variable must be equal to 1. That is,

∑ pi = 1 for all i.

This property ensures that the total probability of all possible outcomes is equal to 1, which is a necessary condition for a valid probability distribution.

Therefore, if the PDF satisfies these two properties, we can conclude that it represents a valid probability distribution for the given discrete random variable.

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The required value of TV is 2 units.

A parallelogram is a straightforward quadrilateral with two sets of parallel edges in Euclidean geometry. A parallelogram's confronting or opposing sides are of equal length, and its opposing angles are of equal size.

We have given that;

TW = y²

WV = 2y − 1

We know that in parallelogram

TW = WV

y² = 2y − 1

y² - 2y + 1 = 0

y² - y - y + 1 =0

y(y - 1)-1(y - 1) = 0

(y - 1)(y - 1) = 0

(y - 1)² = 0

y - 1 = 0

y = 1

So;

TV = TW + WV

TV = y² + 2y − 1

TV = 1² + 2(1) - 1

TV = 1 + 2 - 1

TV = 2 units

Thus, required value of TV is 2 units.

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Answer:

if u want total price then,

=Rs.35×80=Rs.2800

Answer:

∠1 = 50

∠2 = 50

∠3 = 80

∠4 = 130

∠5 = 130

Step-by-step explanation:

∠1 = 180 - 130 = 50

∠2 = ∠1 = 50

∠3 = 180 - ∠1 - ∠2 = 180 - 50 - 50 = 80

∠4 = 180 - ∠2 = 180 - 50 = 130

∠5 = ∠4 = 130

The distance  from Link to the Octorok  is 10.63 units.

We know that the distance between two points (x₁, y₁) and (x₂, y₂) is given by the formula below:

distance = √( (x₂ - x₁)² + (y₂ - y₁)²)

Here we want to find the distance from Link to the Octorok so Link can attack, so we need to get the distance between the points (-4, -5) and (3, 3).

The distance will be:

distance = √( (3 + 4)² + (3 + 5)²)

distance = √( (7)² + (8)²)

distance = √113

distance = 10.63

The distance is 10.63 units.

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Cold fronts generally move faster than warm fronts because cold air is denser and thus, moves more quickly. Precipitation with a cold front typically covers a broader area, especially during the winter.

On the other hand, warm fronts move more slowly as they are characterized by the gradual lifting of warm air over colder air. Cold fronts also typically have steeper slopes than warm fronts. This is because the leading edge of a cold front is more abrupt.

With a steep rise in the cold air mass. In contrast, the leading edge of a warm front has a gentler slope as the warm air gradually rises over the colder air.

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Understanding the equilibria, sketching a phase portrait, and determining the stability of equilibria for autonomous equations are important tools for analyzing and understanding the behavior of systems over time.

Autonomous equations are differential equations that do not depend explicitly on time. To find the equilibria of an autonomous equation, we set the derivative of the function to zero and solve for the values of the independent variable that satisfy the equation. These values represent points at which the function does not change over time and are known as equilibrium points.

To sketch a phase portrait for an autonomous equation, we plot the slope field of the function and then draw solutions through each equilibrium point. The resulting graph shows the behavior of the function over time and helps us understand how the solutions behave near each equilibrium point.

The stability of an equilibrium point is determined by examining the behavior of nearby solutions. If nearby solutions move toward the equilibrium point over time, the equilibrium point is stable. If nearby solutions move away from the equilibrium point over time, the equilibrium point is unstable. Finally, if the behavior of nearby solutions is inconclusive, further analysis is needed.

Here is the sketch for [tex]dx/dt = x - x^3[/tex]

       / <--- (-∞)  x=-1  (+∞) ---> \

      /                                \

  <--0-->       x=-1       x=1        0-->

      \                                /

       \ <--- (-∞)  x=1   (+∞) --->  /

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The correct standard form of the equation of the parabola is:

[tex]y = -x^2 - 1[/tex].

To find the standard form of the equation of the parabola that passes through the given points (-3, 3) and (1, -1), we can use the general form of the equation of a parabola:

[tex]y = ax^2 + bx + c[/tex] ___________(1)

Substituting the coordinates of the two given points into this equation, we get a system of two equations in three unknowns (a, b, and c):

[tex]3 = 9a - 3b + c[/tex]

[tex]-1 = a + b + c[/tex]

To solve for a, b, and c, we can eliminate one of the variables using subtraction or addition. Subtracting the second equation from the first, we get:

[tex]4 = 8a - 4b[/tex]

Simplifying this equation, we get:

[tex]2 = 4a - 2b[/tex]

Dividing both sides by 2, we get:

[tex]1 = 2a - b[/tex]___________(2)

Now we can substitute this expression for b into one of the earlier equations to eliminate b. Using the first equation, we get:

[tex]3 = 9a - 3(2a - 1) + c[/tex]

Simplifying this equation, we get:

[tex]3 = 6a + c + 3[/tex]

Subtracting 3 from both sides, we get:

[tex]0 = 6a + c[/tex]

Solving for c, we get:

c = -6a __________(3)

Substituting this expression for c into the second equation, we get:

[tex]-1 = a + (2a - 1) - 6a[/tex]

Simplifying this equation, we get:

[tex]-1 = -3a - 1[/tex]

Adding 1 to both sides, we get:

[tex]-3a =0[/tex]

Solving for a, we get:

[tex]a = 0[/tex]

Substituting this value of a into the equation(3) for c, we get:

c = 0

Substituting a = 0 into the equation(2) for b that we found earlier, we get:

[tex]1 = 0 - b[/tex]

Solving for b, we get:

[tex]b = -1[/tex]

Putting the values of a, b and c in (1), we get

[tex]y = -x^2 - 1[/tex]

Therefore, the equation of the parabola that passes through the given points (-3, 3) and (1, -1) is:

[tex]y = -x^2 - 1[/tex]

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Complete question:

A parabola goes through (-3, 3) & (1, -1). A point is below the parabola at (-3, 2). A line above the parabola goes through (-3, 4) & (0, 4). A point on the parabola is labeled (x, y).

What is the correct standard form of the equation of the parabola?

The figure is in the image attached below

Answer: Let's denote the two unknown angles as x and y.

We know that the sum of the angles in any quadrilateral is 360°, so we can set up an equation using this fact:

235° + 40° + x + y = 360°

Simplifying this equation, we get:

x + y = 85° (equation 1)

We also know that the other two angles are in a ratio of 5:12. This means that:

x/y = 5/12

Multiplying both sides by y, we get:

x = (5/12)y (equation 2)

Now we can substitute equation 2 into equation 1 and solve for y:

(5/12)y + y = 85°

(17/12)y = 85°

y = (12/17) * 85°

y = 60°

Substituting y = 60° into equation 2, we can solve for x:

x = (5/12) * 60°

x = 25°

Therefore, the two angles that are in a ratio of 5:12 measure 25° and 60°, respectively.

Step-by-step explanation:

The missing side is 30.

Three line segments that cross at three non-collinear locations to form a triangle constitute a triangle in geometry. The triangle's three line segments are referred to as its sides, and its three points of intersection as its vertices.

A triangle is a three-sided polygon formed by three line segments intersecting at three non-collinear points, and it can be classified based on the length of its sides and the measure of its angles.

Given figure, there are two lines ate parallel, that's why two triangles are similar triangle.

Assume that the missing side is x.

So that side ratio in similar triangle are equal;

14/20 = 21/x

So, x = 30.

Therefore, the missing side x is 30

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Triangle Three line segments that cross at three non-collinear locations to form a triangle constitute a triangle in geometry. According to the question the missing side is 30.

Three line segments that cross at three non-collinear locations to form a triangle constitute a triangle in geometry. The triangle's three line segments are referred to as its sides, and its three points of intersection as its vertices. A triangle is a three-sided polygon formed by three line segments intersecting at three non-collinear points, and it can be classified based on the length of its sides and the measure of its angles.

Given figure, there are two lines ate parallel, that's why two triangles are similar triangle.
Assume that the missing side is x.
So that side ratio in similar triangle are equal;
14/20 = 21/x

So, x = 30.
Therefore, the missing side x is 30

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Two radicals are said to be radicals if they have the same indices and the radicand.

In mathematics, a radicand is an expression, a number, or a variable that is enclosed in a root symbol. The factor for which we are determining the root is quantity. As we study exponents and roots, the word "radicand" is utilised. Therefore, the radicand in 2 has a value of 2. Following are some radicand examples:

3√(pq) → pq is the radicand

√(a+b) → a + b is the radicand

4√15 → 15 is the radicand

A radical is a symbol used to represent a number's root. It is symbolised as. The word or phrase that appears after the radical symbol is known as the radicand. Hence, it may be claimed that the radical represents the radicand. Alternatively said, the radicand sign is √.

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Complete question:

Type the correct words in the blanks:

Two radicals are said to be radicals if they have the same               and the radicand.

On the fifth day there were 4 tοmatοes left tο be sοld. Jοann had 71 tοmatοes tο begin with.

Prοbability is a measure οf the likelihοοd οr chance οf an event οccurring. It is a number between 0 and 1, where 0 indicates that the event is impοssible, and 1 indicates that the event is certain tο οccur.

Let's wοrk backwards frοm the last day and figure οut hοw many tοmatοes Jοann had οn the fοurth day.

On the fifth day, there were 4 tοmatοes left tο be sοld, which means she sοld half οf what was left οn the fοurth day. Sο she must have started with 8 tοmatοes οn the fοurth day (since half οf 8 is 4).

On the fοurth day, she sοld half οf what was left, which means she had 16 tοmatοes befοre she sοld any.

On the third day, she sοld 12 tοmatοes, which means she had 28 tοmatοes befοre she sοld any.

On the secοnd day, she sοld half οf what was left, which means she had 56 tοmatοes befοre she sοld any.

Finally, οn the first day, she sοld 15 tοmatοes.

Therefοre, Jοann had 71 tοmatοes tο begin with.

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The asymptotes of the function f(x) = (2x² - 5x + 3)/(x - 2) are given as follows:

The function for this problem is defined as follows:

f(x) = (2x² - 5x + 3)/(x - 2)

The vertical asymptote is the value of x for which the function is not defined, hence it is at the zero of the denominator, and thus it is given as follows:

x - 2 = 0

x = 2.

The oblique asymptote is at the quotient of the two functions, hence:

(mx + b)(x - 2) = 2x² - 5x + 3

mx² + (b - 2m) - 2b = 2x² - 5x + 3.

Hence the values of m and b are given as follows:

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Answer:

0.600 or 600, 0.500 or 500, select option 2

Step-by-step explanation:

Step-by-step explanation:

this is the answerrr

without calculator