Answer:
The reactivity order reflects both the strength of the C-X bond and the stability of X(-) as a leaving group and leads to the general conclusion that alkyl iodides are the most reactive members of this functional class
2 moléculas de clorato de potasio (KClO3) forman 2 moléculas de cloruro de potasio (KCl) y 3 moléculas de oxígeno (O2
The complete question is as follows: 2 molecules of potassium chlorate (KClO3) form 2 molecules of potassium chloride (KCl) and 3 molecules of oxygen (O2). Write a balanced equation for this reaction?
Answer: The balanced chemical equation is [tex]2KClO_{3} \rightarrow 2KCl + 3O_{2}[/tex].
Explanation:
A balanced equation is defined as the equation which contains same number of atoms on both reactant and product side when a chemical reaction occurs.
Hence, when 2 molecules of potassium chlorate [tex](KClO_{3})[/tex] form 2 molecules of potassium chloride (KCl) and 3 molecules of oxygen [tex](O_{2})[/tex] then its balanced equation will be as follows.
[tex]2KClO_{3} \rightarrow 2KCl + 3O_{2}[/tex]
Here, number of atoms on the reactant side as as follows.
K = 2Cl = 2O = 6Number of atoms on the product side are as follows.
K = 2Cl = 2O = 6Since, the number of atoms on reactant side are equal to the number of atoms on product side. So, this reaction equation is balanced.
Thus, we can conclude that the balanced chemical equation is [tex]2KClO_{3} \rightarrow 2KCl + 3O_{2}[/tex].
Summarize your findings in a short report of 150 words. Include your hypothesis, observations, data, calculations, and conclusion. The answers to the questions below should be included in your conclusion.
Why didn't the box slide off the table before you put enough coins in the bag?
What was the coefficient for the smooth surface? For the rough surface?
What was the difference between the two coefficients? What caused this difference?
What factors caused a margin for human error in this investigation?
Would the coefficient vary if you tied the string to a similar object of different masses, but on the same surface? Explain.
What did you learn from this investigation? Be thoughtful in your answer.
Answer:
Follow these steps.
1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.
2. Tie the string to the box. Allow the string to hang over the edge of the table.
3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.
4. Add coins one by one until the box is pulled off the table.
5. Count and record the number of coins and the weight of the bag with the coins in it.
6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.
7. Put the matchbox on the rollers farthest from the edge of the table.
8. Now add coins one by one to the bag until the box is pulled off the table.
9. Count and record the number of coins and the weight of the bag with the coins in it.
10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.
11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.
Explanation:
I think this is useful
please make me as breainlest
Answer:Follow these steps.
1. Fill the matchbox with pebbles. Weigh the matchbox with the pebbles inside. Record that weight.
2. Tie the string to the box. Allow the string to hang over the edge of the table.
3. Tie the other end of the string to a corner of the plastic bag, leaving an opening to put in coins.
4. Add coins one by one until the box is pulled off the table.
5. Count and record the number of coins and the weight of the bag with the coins in it.
6. Lay the round sticks on the table about 1 inch apart and about 2 inches from the edge of the table.
7. Put the matchbox on the rollers farthest from the edge of the table.
8. Now add coins one by one to the bag until the box is pulled off the table.
9. Count and record the number of coins and the weight of the bag with the coins in it.
10. Repeat the experiment. Determine your margin of error if your results vary. For accuracy, repeat the experiment if desired.
11. Using the equation for the coefficient of friction in the text above, determine the coefficient of friction for the matchbox in each experiment. Include this data in your summary.
Explanation:
Which are the fundamental particles whose masses are mainly responsible for the mass of an atom?Give Reason
No links
Answer:
Proton & neutron
Explanation:
electrons only affect the charge. neutrons affect the mass and stability of an atom.
32. Calculate the pH of a solution at 1.00 x 10- MIH") and identify the substance as an acid or base,
Answer:
[tex]{ \boxed{ \tt{formular : pH = - log[H {}^{ + } ]}}} \\ pH = - log(1.00 \times {10}^{-6} ) = 6: it's an acid\\ since \: we \: lack \: the \: exponent, \: this \: question \: is \: unsolvable \\ { \green{ \bf{take \: note}}} :{ \tt{pH \: below \: 7 \: that \: is \: { \red{acidic}}. \: \: pH \: greater \: than \: 7 \: is \: { \red {basic}}}}[/tex]
What characterizes an Arrhenius acid-base reaction?
O A. It forms a conjugate pair.
O B. It forms a salt and water.
O C. It forms hydrogen gas.
OD. It forms a buffer in water.
An Arrhenius acid-base reaction forms a salt and water.
Arrhenius acid base reaction forms a salt and water.
Hence, option (B) is correct answer.
What is Arrhenius acid-base reaction ?Arrhenius acid-base reaction is Arrhenius acid + Arrhenius Base means water + salt. When Arrhenius acid reacts with Arrhenius base it produce water and salt as product. This is known as neutralization reaction.
Thus, from the above conclusion we can say that Arrhenius acid base reaction forms a salt and water.
Hence, option (B) is correct answer.
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which element is most reactive among aluminium, boron, calcium and beryllium? Give reason.
Answer:
Well, if you check the reactivity series, calcium is more reactive than magnesium. This means there's a a trend of increasing reactivity as we go down the group. As beryllium is above magnesium, it must be the least reactive. Then magnesium is in the middle and the most reactive has to be calcium.
Answer:
Aluminium because highl elecronegativety element and more metalic hign melting and boling point from the other
Applicable in case of strong acid–
(i) gets completely ionized in aqueous solutions
(ii) gives H+ ion in aqueous solution
(iii) sour in taste
Which one is correct?
A
i, ii, iii
B
i, ii
C
ii, iii
D
i, iii
Answer:
A. i, ii, iii
Explanation:
A strong acid gets completely ionized in aqueous solutions releasing a large number of hydrogen ions. It also has a sour taste.
2. Which equation does not represent a neutralisation reaction?
HELP PLEASE
Answer:
Zn + 2HCl => ZnCl2 + H2
Explanation:
This equation represents salt formation or salt preparation. Thus not a neutralization reaction.
PCl5 <-> PCl3 + Cl2
PCl5 decomposes into PCl3 and Cl2 according to the equation above. A pure sample of Pcl5 is placed in a rigid, evacuated 1.00 L container. The initial pressure of the PCl5 is 1.00 atm. The temperature is held constant until the PCl5 reaches equilibrium with its decomposition products. The figures below shows the initial and equilibrium conditions of the system.
As the reaction progresses toward equilibrium, the rate of the forward reaction
A) increases until it becomes the same as the reverse reaction rate at equilibrium
B) stays constant before and after equilibrium is reached
C) decreases to become a constant nonzero rate at equilibrium
D) decreases to become zero at equilibrium
Answer:
PCl5 <-> PCl3 + Cl2
PCl5 decomposes into PCl3 and Cl2 according to the equation above. A pure sample of Pcl5 is placed in a rigid, evacuated 1.00 L container. The initial pressure of the PCl5 is 1.00 atm. The temperature is held constant until the PCl5 reaches equilibrium with its decomposition products. The figures below show the initial and equilibrium conditions of the system.
As the reaction progresses toward equilibrium, the rate of the forward reaction
A) increases until it becomes the same as the reverse reaction rate at equilibrium
B) stays constant before and after equilibrium is reached
C) decreases to become a constant nonzero rate at equilibrium
D) decreases to become zero at equilibrium
Explanation:
At equilibrium, both forward and backward reactions take place with constant speed.
The reaction will never cease.
Due to this reason chemical equilibrium is called dynamic in nature.
At equilibrium:
the rate of forward reaction = rate of backward reaction
As the reaction progresses toward equilibrium, the rate of the forward reaction decreases to become a constant nonzero rate at equilibrium.
Answer is option C).
When a system is in a state of chemical equilibrium, neither the reactant concentration nor the product concentration changes over time, nor does the system exhibit any further changes in its attributes. Here the correct option is C.
The system reaches a condition of chemical equilibrium when the rate of the forward reaction equals the rate of the reverse reaction. The system is considered to be in a state of dynamic equilibrium when the concentrations of the reactants and products do not change further as a result of the equal rates of the forward and reverse processes.
Equilibrium is impacted by a number of variables, including temperature, pressure, and the system's concentration. Here at equilibrium the rate of the forward reaction decreases to become a constant nonzero rate at equilibrium.
Thus the correct option is C.
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What determines the strength of a dipole dipole force?
Answer:
The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.
Explanation:
I hope this helps and please ask if you need further help!
Magnesium lon has less electrons than its atom
True
False
The solution of sugar at 60.0 degrees celcuis is 290.0 g/ 100 g water. If you add 100.0 g of sugar to 25 g of water at 60.0 degrees celcuis will the sugar dissolve?
Answer:
you will produce a saturated solution, At 0 degrees Celsius, sugar is claimed to dissolve 180 grams in 100 grams of water. This means that if you dissolve that much sugar in 100 g of water, you'll get a saturated solution.
Explanation:
The correct answer for the given question about Saturated solution is only 72.5 gram will get dissolved and rest which is 27.5 gram will remain undissolved.
How to apply concept of Saturated solution to solve this question?In question it is given that at 60° C 290 gram of sugar in 100 gram of water produce saturated solution.
So at 60° C 290/100 gram of sugar in 1 gram of water will produce saturated solution.
Hence we can say that at 60° C (290/100)×25 gram of sugar in 25 gram of water will produce saturated solution.
means at 60° C 72.5 gram of sugar in 25 gram of water will produce saturated solution.
Now, adding 100 gram of sugar in 25 gram of water.
Since you can only hope to dissolve 72.5 gram at 60°,
Hence the resulting solution will contain undissolved sugar.
So only 72.5 gram will get dissolved and rest which is 27.5 gram will remain undissolved.
Thus, We can conclude that Only 72.5 grams of sugar will dissolve, leaving the remaining sugar of 27.5 grams undissolved.
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Silicon is in the same group of the Periodic Table as carbon. The compound
formed between silicon and hydrogen is likely to have the formula
SiHz
SiH
SizH:
SizHs
Please hurry
Answer:
SiH
Explanation:
The symbol for Silicon is Si, and the symbol for Hydrogen is H. There is no need for extra characters in the name.
4. How much heat required to convert (heat up) 16 gm of ice to 125°C of steam
Cice = 2.03 J/gm.°C,
L = 2.264 J/gm
Cwater = 4.184 J/gm.°C
4 = 0.334 J/gm
Csteam = 1.996 J/gm.°C
Answer: it requires the amount of heat that it takes to make it steam
Explanation:
The study of the interaction of electrical and magnetic fields, and their interaction with matter, is called _____.
electromagnetism
superconductivity
relativity
magnetism
Answer:
The study of the interaction of electrical and magnetic fields, and their interaction with matter, is called Electromagnetism
Assuming the volume is constant, if a gas has an
initial pressure of 84.0 kPa at 30.0°C, what would
the new pressure be at 240.0°C? (Round to the
nearest whole number)
kPa
DONE
1) Intro
2 of 3
Answer:
672kP
Explanation:
Equate the initial pressure with respect the first temperature. The unknown pressure to the second temperature and you cross multiply
Answer: 142kPa.
Explanation:got it right on edge 2020
An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the molality of the solution.
Answer: The molality of [tex]NaC_2H_3O_2[/tex] solution is 0.782 m
Explanation:
Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:
[tex]\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}}[/tex] .....(1)
Given values:
Moles of [tex]NaC_2H_3O_2[/tex] = 0.395 mol
Mass of solvent (water) = 0.505 kg
Putting values in equation 1, we get:
[tex]\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m[/tex]
Hence, the molality of [tex]NaC_2H_3O_2[/tex] solution is 0.782 m
How many grams of HNO3 is needed to make 1.5 L of a 3 M solution of HNO3? Show work
Answer:
283.5g
Explanation:
first u need to know the molar mass of hno3 which is 63.01
the g=1.5×3×63.01
g= 283.5
During the process of condensation, water vapor
A. releases 334 J/g of heat energy
B. releases 2260 J/g of heat energy
C. gains 334 J/g of heat energy
D. gains 2260 J/g of heat energy
Answer:
A
Explanation:
it releases 4
334 J/g of heat energy
hope its correct
What is the predicted change in the boiling point of water when 2.10 g of
barium chloride (BaCl2) is dissolved in 5.50 kg of water?
The addition of any non-volatile solutes will elevate the boiling point of the solution. The change in boiling point of water by the addition of 2.10 of barium chloride is 0.0028 ° C. Hence, option A is correct.
What is boiling point?Boiling point of a substance is the temperature at which it changes from liquid to vapour where the two states are in equilibrium. Boiling point of a substance depends on the bond type, molecular mass and purity of it.
The change or elevation of boiling point of a solution can be determined from its molality m and elevation constant Kb and the Van't Hoff factor i as follows:
ΔT = i Kb m.
Molality of the solution is the no.of moles divided by the mass of solvent in kilogram. Given the mass of barium chloride is 2.10 g and its molar mass is 208.23 g . The no.of moles of solute is 2.10/208.23 g = 0.0100.
Molality of the solution can be calculated as follows:
Molality m = 0.0100 / 5.50 Kg
= 0.0018 mol/kg.
Now, the ΔT s calculated from these values. Provided Kb of water is 0.51 ° C /mol and i = 3.
ΔT = 0.0018 mol/kg × 0.51 × 3
= 0.0028 ° C.
Therefore, water will boil at 100.0028 ° C. Hence, option A is correct.
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Difference between
Atom and molecule
Answer:
Atoms are single neutral particles. Molecules are neutral particles made of two or more atoms bonded together.
Explanation:
its on safari ??????????
Help me with this science question on the middle one..
what are some ways you would expect people and things to be affected by an earthquake that moved the ground that much?
Answer:
Some of the common impacts of earthquakes include structural damage to buildings, fires, damage to bridges and highways, initiation of slope failures, liquefaction, and tsunami.
CHEMISTRY HW... DUE in 2.5 hours! HELP!!!!
Answer:
The final temperature aluminium-water system is 24° C
Explanation:
Heat energy, H = mcθ
Where m is mass of substance, c is specific heat capacity, θ is temperature difference
Using the principle, Heat lost = Heat gained
Let the final temperature of the aluminium-water system be Tfinal
Heat lost by aluminium, H₁ = -m₁c₁(Tfinal - 40)
Heat gained by water, H₂ = m₂c₂(Tfinal -21)
Heat lost by aluminium, H = -[30 × 0.21 × (Tfinal - 40)]
H₁ = -6.3Tfinal + 252
Heat gained by water, H₂ = 50 × 1.0 × (Tfinal - 21)
H₂ = 5Tfinal - 21
Equating H₁ and H₂
-6.3Tfinal + 252 = 5 Tfinal - 21
5Tfinal + 6.3Ffinal = 252 + 21
11.3 Tfinal = 273
Tfinal = 273/11.3
Tfinal = 24° C
Therefore, the final temperature aluminium-water system is 24° C
Nitrogen makes up what part of the air?
3/5
2/5
4/5
About 4/5.
Hope this helps.
Answer: c
Explanation:
Performance Task #4.3
If you will cross a parent with black eye color (BB) and the other is
brown eye (bb), what will be the color of the eyes of their offspring?
BB
b
b
Ex. Rr - Round
Ir - oblong
Genotypic Ratio:
BB
bb-
%
R
rrr
rr
Phenotypic Ratio:
%
Rr
re
Genotypic Ratio:
50% Rr
Bb
b
b
50% IT
Phenotypic Ratio: 50% round
50% oblong
Bb -
bb-
Genotypic Ratio:
%
%
Phenotypic Ratio:
(continuation at the back)
%
I need answers pls, help me brainliest ko po maka ans ng tama, report nonsense thanks.
Answer:
The offspring are all black eye colored.
Explanation:
Since we have genes BB for black eye color and genes bb for brown eye color, crossing the genes, the resulting genotypes in the offspring is Bb, Bb, Bb and Bb. We note that all the genes have the dominant B gene. Since the black eye color dominant gene is present in all the offspring, the offspring are thus all black-eye colored.
So, If you will cross a parent with black eye color (BB) and the other is
brown eye (bb), the offspring are all black eye colored.
Compare the stability of primary, secondary and tertiary carbocation
Answer:
Primary carbocations are most stable, Secondary carbocations are more stable, tertiary carbocations are least stable.
Explanation:
This is due to Asterric hinderance.
(20 points and excuse any offensive or seemingly bad language in this question) Budding and regeneration are two types of asexual reproduction.
Answer: true
Asexual reproduction is the process by which an organism is produced from a single parent cell. There are four major forms of asexual reproduction - budding, binary fission, regeneration and parthenogenesis. ... Regeneration is a type of asexual reproduction in which the organism is capable of regrowing certain body parts.
Explanation:
id k what u r talking abt but hope this helps
Help please and thank you
Answer:
5. The coefficients are: 2, 7, 2, 4
6. The coefficients are: 1, 4, 1, 2
Explanation:
5. Balancing the equation.
__NO₂ + __H₂ —> __NH₃ + __H₂O
The above equation can be balance as illustrated below:
NO₂ + H₂ —> NH₃ + H₂O
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before NO₂ and 4 before H₂O as shown below:
2NO₂ + H₂ —> NH₃ + 4H₂O
There are 2 atoms of N on the left side and 1 atom on the right side. It can be balance by writing 2 before NH₃ as shown below:
2NO₂ + H₂ —> 2NH₃ + 4H₂O
There are 2 atoms of H on the left side and a total of 14 atoms on the right side. It can be balance by writing 7 before H₂ as shown below:
2NO₂ + 7H₂ —> 2NH₃ + 4H₂O
Now the equation is balanced. Thus, the coefficients are: 2, 7, 2, 4
6. Balancing the equation:
__SiO₂ + __HF —> __SiF₄ + __H₂O
The above equation can be balance as illustrated below:
SiO₂ + HF —> SiF₄ + H₂O
There are 4 atoms of F on the right side and 1 atom on the left side. It can be balance by writing 4 before HF as shown below:
SiO₂ + 4HF —> SiF₄ + H₂O
There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:
SiO₂ + 4HF —> SiF₄ + 2H₂O
Now the equation is balanced. Thus, the coefficients are: 1, 4, 1, 2
A solution of the ionic salt CaSO3 would have blank pH
Answer: basic
Explanation:
I just answered it on acellus it's correct ;)
A solution of the ionic salt CaSO₃ would have basic pH as on reaction with base it gives an acid.
What is an acid?
Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.
According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic acids depending on the number of protons which are liberated on dissociation.
Acids are widely used in industries for production of fertilizers, detergents batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.
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