Answer:
O B. Alkaline earth metals
Explanation:
Noble gases → 8th column.
Alkali metal → first column.
Halogen → 7th
Answer:
B. Alkaline earth metals
Explanation:
Alkaline-earth metals: The alkaline-earth metals make up Group 2 of the periodic table, from beryllium (Be) through radium (Ra). Each of these elements has two electrons in its outermost energy level, which makes the alkaline earths reactive enough that they're rarely found alone in nature. But they're not as reactive as the alkali metals. Their chemical reactions typically occur more slowly and produce less heat compared to the alkali metals.
Which one of the following molecule is planer?
a. NF3 c. PH3
b. BH3 d. NCl3
Answer:
option a
hope helps you
have a great day
Name the compound CuI2
Answer:
Copper iodide. I think
Answer:
copper iodide(Cul2)hope it helps
stay safe healthy and happy..Draw the Lewis structure for the polyatomic hydronium H3O cation. Be sure to include all resonance structures that
Answer:
Lewis structure of Hydronium ion is shown below :
Explanation:
Lewis structure : It is a representation of valence electrons on the atoms in a molecule
Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .
Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .
Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence electrons of oxygen atom two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .
Resonance structure will be same as the hybrid structure because all three atoms are same , that is hydrogen .
For the following reaction, 11.6 grams of sulfur are allowed to react with 23.8 grams of carbon monoxide .
sulfur(s) + carbon monoxide(g) sulfur dioxide(g) + carbon(s)
What is the maximum amount of sulfur dioxide that can be formed?
What is the formula for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete?
Answer:
S + 2CO = SO2 + 2C
First, look for the amount of substance of sulfur:
n(S) = m / M
n(S) = 14.8 g/32 g / mol = 0.4625 mol
n(CO) = m (CO) / M (CO)
M(CO) = 12 + 16 = 28 g/mol
n(CO) = 19.9 g/28 g/mol = 0.71 mol
S in excess, so for calculating we take CO:
n(SO2) = n(CO)/2 = 0.71 mol/2 = 0.355 mol
m(SO2) = M(SO2)*n(SO2)
M(SO2) = 32 + 16*2 = 64 g/mol
m(SO2) = 64 g/mol * 0.355 mol = 22.74 g
Assign oxidation state to each atom in each element ion or compound.
a. Ag
b. Ag+
c. CaF2
d. H2S
e.CO3
f. CrO4
g. Cl2
h. Fe
i. CuCl2
j. CH4
Answer:
a. [tex]Ag^0[/tex]
b. [tex]Ag^{+}[/tex]
c. [tex]Ca^{2+}F_2^-[/tex]
d. [tex]H_2^+S^{2-}[/tex]
e. [tex](C^{4+}O_3^{2-})^{-}[/tex]
f. [tex](Cr^{6+}O_4^{2-})^{2-}[/tex]
g. [tex]Cl_2^0[/tex]
h. [tex]Fe^0[/tex]
i. [tex]Cu^{2+}Cl_2^-[/tex]
j. [tex]C^{4-}H_4^+[/tex]
Explanation:
Hello there!
In this case, according to the concept of charge balance, which tell us that the overall charge is zero for any compound, except ions, it turns out possible to proceed as follows:
a. [tex]Ag^0[/tex]
b. [tex]Ag^{+}[/tex]
c. [tex]Ca^{2+}F_2^-[/tex]
d. [tex]H_2^+S^{2-}[/tex]
e. [tex](C^{4+}O_3^{2-})^{-}[/tex]
f. [tex](Cr^{6+}O_4^{2-})^{2-}[/tex]
g. [tex]Cl_2^0[/tex]
h. [tex]Fe^0[/tex]
i. [tex]Cu^{2+}Cl_2^-[/tex]
j. [tex]C^{4-}H_4^+[/tex]
Keep in mind lonely elements have 0 as their oxidation state.
Regards!
The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes superconducting in degrees Celsius.
Answer:
The correct answer is "-268.667°C".
Explanation:
Given:
Temperature,
= 4.483 K (below)
Now,
The formula of temperature conversion will be:
⇒ [tex]T(^{\circ} C)=T(K)-273.15[/tex]
By putting the values, we get
⇒ [tex]=4.483-273.15[/tex]
⇒ [tex]=-268.667^{\circ} C[/tex]
Thus the above is the correct answer.
Di- n- pentyl ether can be converted to 1- bromopentane by treatment with HBr through essentially a(n) ________ mechanism.
Answer:
SN1 mechanism
Explanation:
The mechanism of this reaction is shown in the image attached.
The Di- n- pentyl ether is first protonated. The CH3(CH2)4OH is now a good leaving group as shown.
The attack of the bromide ion on the cation formed completes the mechanism to yield 1- bromopentane as shown in the mechanism.
Excluding any secondary chemical reactions,
which would be more effective as an antifreeze; a
solution containing
Select one:
25m CH3OH
the combination of 25m CH3OH and 25m
KCI.
O 25m KCI.
O
none of these
Answer:
Excluding any secondary chemical reactions,
which would be more effective as an antifreeze; a
solution containing
Select one:
25m CH3OH
the combination of 25m CH3OH and 25m
KCI.
25m KCI.
Explanation:
Antifreeze is the one that reduces the freezing point of a solvent further and will not allow the solvent to freeze.
Among the given options, the correct option is:
25 m CH3OH and 25m KCl.
Since, KOH is a strong electrolyte and dissociates into two ions.
So, the freezing point of solvent decreases further.
C3H8 is ________
A. unsaturated
B. saturated
What change would increase the amount of solid solute able to be dissolved in liquid water?
Decreasing rate of stirring
Decreasing surface area
Increasing pressure
Increasing temperature
Answer:
D: Increasing temperature
Explanation:
From collision theory, we know that the more the increase in collisions, the faster the rate of the chemical reaction.
Now, the amount of solid solute in a solvent will change with a corresponding change in temperature. What we mean is that, the higher the temperature increases, the higher the number of collisions between the solvent molecules as well as leading to an increase in the solute particles which will mean an increase in the amount of the solid solute dissolved. The correct answer is option D.
Answer:
Increasing temperature.
Explanation:
Pls pls help me me pls
Answer:
Danger
Explanation:
How do I solve this?
Explanation:
a) Since this is a double displacement reaction, we write the balanced equation as
[tex]2AgNO_3(aq) + CaCl_2(aq) \\ \rightarrow 2AgCl(s) + Ca(NO_3)_2(aq)[/tex]
b) Next we find the number of moles of AgNO3 in the solution.
[tex](0.005\:\text{L})(0.500\:M\:AgNO_3) \\ = 0.0025\:\text{mol}\:AgNO_3[/tex]
Next, use the molar ratio to find the necessary amount of CaCl2 to react with the AgNO3:
[tex]0.0025\:\text{mol}\:AgNO_3× \left(\dfrac{1\:\text{mol}\:CaCl_2}{2\:\text{mol}\:AgNO_3} \right)[/tex]
[tex]= 0.00125\:\text{mol}\:CaCl_2[/tex]
The volume of 0.500 M solution of CaCl2 necessary to react all of the given AgNO_3 is then
[tex]V = \dfrac{0.00125\:\text{mol}\:CaCl_2}{0.500\:\text{M}\:CaCl_2}[/tex]
[tex]= 0.0025\:\text{L} = 2.5\:\text{mL}\:CaCl_2[/tex]
c) The theoretical yield can then be calculated as
[tex]0.0025\:\text{mol}\:AgNO_3 × \left(\dfrac{2\:\text{mol}\:AgCl}{2\:\text{mol}\:AgNO_3} \right)[/tex]
[tex]= 0.0025\:\text{mol}\:AgCl[/tex]
Converting this amount of AgCl into grams, we get
[tex]0.0025\:\text{mol}\:AgCl × \left(\dfrac{143.32\:\text{g}\:AgCl}{1\:\text{mol}\:AgCl} \right)[/tex]
[tex]= 0.358\:\text{g}\:AgCl[/tex]
An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV at this distance
Answer:
(a) The potential near its surface is 45 * 10^6 V.
(b) The distance from which its center is the potential 1.00 MV is 45 m.
(c) Its energy in MeV when the atom is at the distance found in part b is 132 MeV.
Explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question.
A research Van de Graaff generator has a 2.00-m diameter metal sphere with a charge of 5.00 mC on it. (a) What is the potential near its surface?
(b) At what distance from its center is the potential 1.00 MV?
(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?
The explanation of the answer is now provided as follows:
(a) What is the potential near its surface?
Q = Charge on the generator = 5 mC = 5 * 10^(-3)C
r = Sphere radius = 2 / 2 = 1 m
k = Constant of the electric force = 9 * 10^(9) N . m^2 / C^2
Therefore, the electric potential of a point charge can be calculated as follows:
V = kQ / r
V = (9 * 10^9 * 5 * 10^(-3)) / 1 = 45 * 10^6 V
Therefore, the potential near its surface is 45 * 10^6 V.
(b) At what distance from its center is the potential 1.00 MV?
This implies the distance where the potential is 1 MV.
Since the electric potential of a point charge is as follows:
V = kQ / r
Therefore, we can solve for r and estimate it as follows:
R = kQ / V = (9 * 10^9 * 5 * 10^(-3)) / 1 * 10^6 = 45 m
Therefore, the distance from which its center is the potential 1.00 MV is 45 m.
(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?
The link between the potential difference and electrical potential energy can be stated as follows:
ΔV = ΔU / q
Therefore, we have:
ΔU = qΔV = q(Va - Vb) = 3 * (45 – 1) = 132 MeV
Therefore, its energy in MeV when the atom is at the distance found in part b is 132 MeV.
Vocabulary: dipole, dipole-dipole force, dipole-induced dipole force, electronegativity, intermolecular force, ionic bond, London dispersion force, molecule, nonpolar, nonpolar covalent bond, partial charges, polar, polar covalent bond, valence electron Prior Knowledge Questions (Do these BEFORE using the Gizmo.) 1. A big bully is having a tug-of-war with a small child. There is a ball attached to the middle of the rope. Toward whom will the ball move
Answer:
Towards the big bully
Explanation:
If a big bully and a small child are involved in a thug of war, it is clear that the bully is stronger than the child and he/she will pull the rope used in the thug of war with a greater force.
By so doing, the ball attached at the centre of the rope will naturally be drawn towards the stronger bully.
To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?
Answer:
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
Explanation:
Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.
In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
In a solution it is fulfilled:
Ci* Vi = Cf* Vf
where:
Ci: initial concentration Vi: initial volume Cf: final concentration Vf: final volumeIn this case:
Ci= 1.40 MVi= 20 mLCf= 0.088 MVf= ?Replacing:
1.40 M* 20 mL= 0.088 M* Vf
Solving:
[tex]Vf=\frac{1.40 M* 20 mL}{0.088 M}[/tex]
Vf= 318.18 mL
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
A technical machinist is asked to build a cubical steel tank that will hold "265" L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .
Answer:
0.64 m
Explanation:
Given that;
1L = 0.001 cubic metre
Then;
263 L = 263 L × 0.001 cubic metre/1L
= 0.263 cubic metre
Volume of a cube = l^3
l= 3√V
l= 3√0.263 cubic metre
l= 0.64 m
Predict the products of each reaction, and whether the solution at equilibrium will be acidic, basic, or neutral.1. P4O10 + 6H2O (l)---->2. Na2O + H2O(l) ------>3. N2O5 + 3H2O (l)------>
Answer:
For 1: The product is phosphoric acid and the solution is acidic in nature.
For 2: The product is sodium hydroxide and the solution is basic in nature.
For 3: The product is nitric acid and the solution is acidic in nature.
Explanation:
For the given options:
(1): When diphosphorus pentoxide reacts with water, it leads to the formation of phosphoric acid, which makes the solution acidic in nature.
The chemical equation for the reaction follows:
[tex]P_4O_{10}+6H_2O(l)\rightarrow 4H_3PO_4(aq)[/tex]
(2): When disodium oxide reacts with water, it leads to the formation of sodium hydroxide, which makes the solution basic in nature.
The chemical equation for the reaction follows:
[tex]Na_2O+H_2O(l)\rightarrow 2NaOH(aq)[/tex]
(3): When dinitrogen pentoxide reacts with water, it leads to the formation of nitric acid, which makes the solution acidic in nature.
The chemical equation for the reaction follows:
[tex]3N_2O_5+3H_2O(l)\rightarrow 6HNO_3(aq)[/tex]
If a hydrogen atom and a helium atom have the same kinetic energy:________
a. the wavelength of the hydrogen atom will be about 4 times longer than the wavelength of the helium atom.
b. the wavelength of the hydrogen atom will be about 2 times longer than the wavelength of the helium.
c. the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.
d. the wavelength of the helium atom will be about 2 times longer than the wavelength of the hydrogen atom.
e. the wavelength of the helium atom will be about 4 times longer than the wavelength of the hydrogen atom.
Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.
Explanation:
The relation between energy and wavelength is as follows.
[tex]E = \frac{hc}{\lambda}\\[/tex]
This means that energy is inversely proportional to wavelength.
As it is given that energy of a hydrogen atom and a helium atom is same.
Let us assume that [tex]E_{hydrogen} = E_{helium} = E'[/tex]. Hence, relation between their wavelengths will be calculated as follows.
[tex]E_{hydrogen} = \frac{hc}{\lambda_{hydrogen}}[/tex] ... (1)
[tex]E_{helium} = \frac{hc}{\lambda_{helium}}[/tex] ... (2)
Equating the equations (1) and (2) as follows.
[tex]E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'[/tex]
Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.
the force of attraction between non polar molecules are what (a)electrovalent bond (b)covalent bond (c)Hydrogen bond (d)Van der waals forces
Answer:
d. van der waals force
Explanation:
Van der Waals force :
the weakest intermolecular forceand consist of dipole-dipole force and dispersion force.
Please help me ASAP in my final project I am ready to pay 20$
Answer:
$20
ASAP PROJECT
>
Which statement describes an electron?
EEEE
It has a positive charge and is located in the nucleus.
O It has a positive charge and is located in orbitals around the nucleus.
It has a negative charge and is located in the nucleus.
O It has a negative charge and is located in orbitals around the nucleus.
Answer:
It has a negative charge and is located in orbitals around the nucleus
Explanation:
The statement describes an electron is " It has a negative charge and is located in orbitals around the nucleus."
What is electron?The electron would be a subatomic particle with a negatively one elementary charge electric charge.
What is nucleus?Protons, that have a positive charge, as well as neutrons, which have no electrical charge, make up the nucleus. Quarks were subatomic particles that make up protons but also neutrons.
Electrons were present surrounding the atom's nucleus, in contrast to protons as well as neutrons, that are contained within the nucleus at its core. Negative electrons were drawn to the positive nucleus since the electric charges of opposite polarity attract one another.
To know more about electrons and nucleus.
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find out the equivalent weight of Ca(OH)2
Answer:
The equivalent weight of calcium hydroxide is 1/2 he mass of a mol of calcium hydroxide. 1 mol Ca(OH)2 = 74 grams Ca(OH)2 ; 1 equivalent Ca(OH)2 = 37 grams Ca(OH)2......
Explanation:
HOPE IT HELPS YOU
How does a scientist form a hypothesis?
Explanation: The hypothesis is a prediction, but it involves more than a guess. Most of the time, the hypothesis begins with a question which is then explored through background research. It is only at this point that researchers begin to develop a testable hypothesis.
(Unless you are creating an exploratory study, your hypothesis should always explain what you expect to happen)
What mass of NaOH would need to be dissolved in 500.0 mL of water to produce a solution with a pH of 12.40
Answer:
0.5024 g
Explanation:
Step 1: Calculate the concentration of H⁺
We will use the definition of pH.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -12.40 = 3.981 × 10⁻¹³ M
Step 2: Calculate the concentration of OH⁻
We will use the ionic product of water expression.
[H⁺] [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/3.981 × 10⁻¹³ = 0.02512 M
Step 3: Calculate the initial concentration of NaOH
NaOH is a strong base and the molar ratio of NaOH to OH⁻is 1:1. Thus, the initial concentration of NaOH is 1/1 × 0.02512 M = 0.02512 M.
Step 4: Calculate the moles of NaOH
We will use the definition of molarity.
M = moles of NaOH/liters of solution
moles of NaOH = M × liters of solution
moles of NaOH = 0.02512 mol/L × 0.5000 L = 0.01256 mol
Step 5: Calculate the mass of 0.01256 moles of NaOH
The molar mass of NaOH is 40.00 g/mol.
0.01256 mol × 40.00 g/mol = 0.5024 g
the force of attraction between non polar molecules are what
Answer:
dispersion force
Explanation:
What is the molecular formula of the structure below?
Picture is attached pls help I’ll mark as brainliest for the right answer
Answer:
C₆H₆
Explanation:
Each border of the figure represents 1 atom of carbon. We have 6 borders = 6 atoms of carbon.
Each atom of carbon form 4 bonds. All the carbons are doing a double bond and a single bond with other carbons. That means are bonded 3 times. The other bond (That is not represented in the figure. See the image) comes from hydrogens. As we have 6 carbons that are bonded each 1 with one hydrogen. There are six hydrogens and the molecular formula is:
C₆H₆This structure is: Benzene
Identify the options below that are results of adding a catalyst to a chemical system.
The reaction rates are increased.
The reaction quotient is unaffected.
The reaction quotient decreases.
The equilibrium constant is unaffected.
Answer:
The correct options are a, b and d
Explanation:
A catalyst is a substance that increases the rate of a chemical reaction by reducing the activation energy. Le Catelier's principle explains how a substance or an "action" can affect a reaction in equilibrium.
The principle states that when a change is made to the conditions of a reacting system at equilibrium, the position of the equilibrium moves to counteract the change made. These changes are change in temperature, pressure, volume and/or concentration. These changes will either cause the equilibrium to shift forward or backward.
However, the presence of a catalyst DOES NOT affect a chemical equilibrium/equilibrium constant nor does it affect the reaction quotient because the same amount of reactants and products are available just as in uncatalyzed reaction except that the reaction proceeds faster (which does not affect equilibrium).
The rate of reaction is given as the time required by the reactant to convert into the product. The addition of catalyst increases the rate of reaction, while the reaction quotient and the equilibrium remain unaffected.
What is a catalyst?A catalyst is a chemical or compound that adds to the reaction and lowers the activation energy by providing an alternative path to the reaction.
The catalyst takes part in the reaction but did not consume in the chemical reaction.
The equilibrium and the reaction quotient are dependent on the conversion of the reactant to the product. The catalyst is not used in the reaction and thus did not affect the reaction quotient or the equilibrium.
Hence, options A, B, and D are correct for the use of catalysts in the chemical reaction.
Learn more about catalysts, here:
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What is the mass of 2.30x10^22 formula units of NaOH (molar mass =40.0g/mol)
Answer:
643(%=:(¥75 )(:7$"8"),"7$"()9_/"¥?:
If I have 25g of Sodium, how much Sodium Chloride will I theoretically create?
O 50g NaCl
0 58.3g NaCl
O 63.7g Naci
0 35.4g NaCl
Answer:
64 g
Explanation:
Step 1: Write the balanced equation
2 Na + Cl₂ ⇒ 2 NaCl
Step 2: Calculate the moles corresponding to 25 g of Na
The molar mass of Na is 22.98 g/mol.
25 g × 1 mol/22.98 g = 1.1 mol
Step 3: Calculate the moles of NaCl formed from 1.1 moles of Na
The molar ratio of Na to NaCl is 2:2. The moles of NaCl formed are 2/2 × 1.1 mol = 1.1 mol.
Step 4: Calculate the mass corresponding to 1.1 moles of NaCl
The molar mass of NaCl is 58.44 g/mol.
1.1 mol × 58.44 g/mol = 64 g
Consider reaction AgCIO3(aq)+Mgl2(aq)
Answer:
the product is Mg(Clo3)2 + AgI
