Answers
Answer:
A
Step-by-step explanation:
Well I am not fully sure but I would say A
Related Questions
FLIGHT TO TOKYO TAKE 2 HOURS 20 MINUTES U ARRIVE AT 4:15PM WHICH TIME DID HE SET OFF
Answers
Answer: 1:55 PM
Step-by-step explanation:
Turn 4:15 to 24-hr clock system which is 1615hrs
16:15 - 02:20 = 1355hrs
Wayne is picking out some movies to rent, and he is primarily interested in dramas and horror films. He has narrowed down his selections to 7 dramas and 16 horror films. How many different combinations of 3 movies can he rent if he wants at least two dramas
Answers
Answer:
The number of selections is 49.
Step-by-step explanation:
drama = 7
horror films = 16
Select 3 movies at least two dramas
For 2 drama and 1 horror film
(3 C 2) x (16 C 1) = 48
For 3 drama
(3 C 3) = 1
So, total number of selections is 48 + 1 = 49.
someone plz help me porfavor!!!!!
Answers
Answer:
c. y = ¼x - 2
Step-by-step explanation:
Find the slope (m) and y-intercept (b) then substitute the values into y = mx + b (slope-intercept form)
Slope = change in y/change in x
Using two points on the graph, (0, -2) and (4, -1):
Slope (m) = (-1 - (-2))/(4 - 0) = 1/4
m = ¼
y-intercept = the point where the line intercepts the y-axis = -2
b = -2
✔️To write the equation, substitute m = ¼ and b = -2 into y = mx + b:
y = ¼x - 2
To the nearest degree, find the measure of angle A.
Answers
Cosine(angle) = adjacent leg/ hypotenuse
Cosine( angle ) = 18/20
Angle = arccos(18/20)
Angle = 26 degrees
Answer:
26°
Step-by-step explanation:
For a right triangle, we can use trigonometry equations :-
In this case we need to use cosine equation .
cos A = adjacent side / hypotenuse
cos A = 18 / 20
A = cos × 18/20
A = arccos × 18/20
A = 26°
After a certain number of football matches , a footballer averages 1 goal per game.He only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game .How many football matches did he play altogether?
Answers
Answer:
He played 40 matches in total, scoring 32 goals.
Step-by-step explanation:
Since after a certain number of football matches, a footballer averages 1 goal per game, and he only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game, to determine how many football matches did he play altogether you must perform the following calculation:
10/10 + 2/10 = 12/20 = 0.6
8/8 + 2/10 = 10/18 = 0.55
12/12 + 2/10 = 14/22 = 0.64
20/20 + 2/10 = 22/30 = 0.73
24/24 + 2/10 = 26/34 = 0.76
30/30 + 2/10 = 32/40 = 0.8
Thus, he played 40 matches in total, scoring 32 goals.
If 21% of kindergarten children are afraid of monsters, how many out of
each 100 are afraid?
Answers
Answer:
The appropriate answer is "21".
Step-by-step explanation:
Given:
Afraid percentage,
p = 21%
or,
= 0.21
Sample size,
n = 100
As we know,
⇒ [tex]X=np[/tex]
By putting the values, we get
[tex]=0.21\times 100[/tex]
[tex]=21[/tex]
1. Two-thirds of the sum of the number x and 5 is written
2x+5
a.
2
-x+ 5
3
b. §
(5x) <(x+5)
d.
e. x+ķ(x+5)
{(+5)
3
Answers
9514 1404 393
Answer:
cbaStep-by-step explanation:
This is as much about English comprehension as it is about math. When you read an English sentence, you need to figure out what each of the pronouns, phrases, and modifiers is referring to. When the sentence refers to math operations, you need to determine what each math operation is being applied to. In most cases, a math operation involves two operands, so the trick is to figure out what those are.
__
1. "Two-thirds of the sum ..." will look like 2/3( + ). "The sum of a number and 5" will look like (x+5). So, the words are describing ...
2/3(x +5) . . . . matches C
__
2. "Seven decreased by ..." will look like 7 -( ). "The quotient of a number and 3" will look like (n/3). So, the words are describing ...
7 -n/3 . . . . matches B
__
3. Consider the order of operations. When you evaluate 2x²+9, the last operation you perform is addition. That is, the result is a sum. One of the elements of that sum is 9 (the second one). The other element of that sum is the product 2x². The elements of that product are 2 and the square of x. So, one way to describe this expression is ...
the sum of the product of 2 and the square of a number, and 9.
The order of operations requires that squares be evaluated before multiplication and division, so it is not unreasonable (if slightly more ambiguous) to write this as ...
the sum of 2 times a number squared and 9 . . . . choice A
A custodian has 5 and 1/2 gallons of paint each of the book cases she is painting requires 1/2 gallon of paint how many book cases will the custodian be able to paint with that amount of paint A.3 B.4 C.11 D.15
Answers
Answer:
Option C.
Step-by-step explanation:
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B
Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Answers
Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Step-by-step explanation:
The median weight for shelter A is greater than that for shelter B.
The median of A = 21 and the median of B = 18 true
The median weight for shelter B is greater than that for shelter A.
The median of A = 21 and the median of B = 18 false
The data for shelter A are a symmetric data set.
False, looking at the box it is not symmetric
The data for shelter B are a symmetric data set.
true, looking at the box it is symmetric
The interquartile range of shelter A is greater than the interquartile range of shelter B.
IQR = 28 - 17 = 11 for A
IQR for B = 20 -16 = 4 True
How many solutions does the nonlinear system of equations graphed below have?
Answers
Answer:
2
Step-by-step explanation:
2 is the answer because the circle touches the line only 2 times.
Hope this helps.
Do the following lengths form a right triangle?
Answers
Answer:
Yes
Step-by-step explanation:
The lengths of this right angle triangle (6, 8, 10) proves that the polygon is indeed a right angle triangle. This is because there are certain ratios to prove that a right angle triangle is indeed a right angle triangle. These are called the Pythagorean Triples . Some examples include; (3, 4, 5), (7, 24, 25) and (28, 45, 53). The Pythagorean Triple 3, 4, 5 can be scaled up to provide the triple 6, 8, 10, where the scale factor is 2.
Annual windstorm losses, X and Y, in two different regions are independent, and each is uniformly distributed on the interval [0, 10]. Calculate the covariance of X and Y, given that X+ Y < 10.
Answers
Answer:
[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]
Step-by-step explanation:
Given
[tex]Interval =[0,10][/tex]
[tex]X + Y < 10[/tex]
Required
[tex]Cov(X,Y)[/tex]
First, we calculate the joint distribution of X and Y
Plot [tex]X + Y < 10[/tex]
So, the joint pdf is:
[tex]f(X,Y) = \frac{1}{Area}[/tex] --- i.e. the area of the shaded region
The shaded area is a triangle that has: height = 10; width = 10
So, we have:
[tex]f(X,Y) = \frac{1}{0.5 * 10 * 10}[/tex]
[tex]f(X,Y) = \frac{1}{50}[/tex]
[tex]Cov(X,Y)[/tex] is calculated as:
[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]
Calculate E(XY)
[tex]E(XY) =\int\limits^X_0 {\int\limits^Y_0 {\frac{XY}{50}} \, dY} \, dX[/tex]
[tex]X + Y < 10[/tex]
Make Y the subject
[tex]Y < 10 - X[/tex]
So, we have:
[tex]E(XY) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{XY}{50}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {XY}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{XY^2}{2}}} }|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2} - \frac{X(0)^2}{2}}} }\ dX[/tex]
[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2}}} }\ dX[/tex]
Rewrite as:
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X(10 - X)^2\ dX[/tex]
Expand
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X*(100 - 20X + X^2)\ dX[/tex]
[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 100X - 20X^2 + X^3\ dX[/tex]
Integrate
[tex]E(XY) =\frac{1}{100} [\frac{100X^2}{2} - \frac{20X^3}{3} + \frac{X^4}{4}]|\limits^{10}_0[/tex]
Expand
[tex]E(XY) =\frac{1}{100} ([\frac{100*10^2}{2} - \frac{20*10^3}{3} + \frac{10^4}{4}] - [\frac{100*0^2}{2} - \frac{20*0^3}{3} + \frac{0^4}{4}])[/tex]
[tex]E(XY) =\frac{1}{100} ([\frac{10000}{2} - \frac{20000}{3} + \frac{10000}{4}] - 0)[/tex]
[tex]E(XY) =\frac{1}{100} ([5000 - \frac{20000}{3} + 2500])[/tex]
[tex]E(XY) =50 - \frac{200}{3} + 25[/tex]
Take LCM
[tex]E(XY) = \frac{150-200+75}{3}[/tex]
[tex]E(XY) = \frac{25}{3}[/tex]
Calculate E(X)
[tex]E(X) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{X}{50}}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {X}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 { (X*Y)|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)] - [X * 0])\ dX[/tex]
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)]\ dX[/tex]
[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 10X - X^2\ dX[/tex]
Integrate
[tex]E(X) =\frac{1}{50}(5X^2 - \frac{1}{3}X^3)|\limits^{10}_0[/tex]
Expand
[tex]E(X) =\frac{1}{50}[(5*10^2 - \frac{1}{3}*10^3)-(5*0^2 - \frac{1}{3}*0^3)][/tex]
[tex]E(X) =\frac{1}{50}[5*100 - \frac{1}{3}*10^3][/tex]
[tex]E(X) =\frac{1}{50}[500 - \frac{1000}{3}][/tex]
[tex]E(X) = 10- \frac{20}{3}[/tex]
Take LCM
[tex]E(X) = \frac{30-20}{3}[/tex]
[tex]E(X) = \frac{10}{3}[/tex]
Calculate E(Y)
[tex]E(Y) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{Y}{50}}} \, dY} \, dX[/tex]
Rewrite as:
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {Y}} \, dY} \, dX[/tex]
Integrate Y
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 { (\frac{Y^2}{2})|\limits^{10 - X}_0 \, dX[/tex]
Expand
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] - [\frac{(0)^2}{2}])\ dX[/tex]
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] )\ dX[/tex]
[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 [\frac{100 - 20X + X^2}{2}] \ dX[/tex]
Rewrite as:
[tex]E(Y) =\frac{1}{100}\int\limits^{10}_0 [100 - 20X + X^2] \ dX[/tex]
Integrate
[tex]E(Y) =\frac{1}{100}( [100X - 10X^2 + \frac{1}{3}X^3]|\limits^{10}_0)[/tex]
Expand
[tex]E(Y) =\frac{1}{100}( [100*10 - 10*10^2 + \frac{1}{3}*10^3] -[100*0 - 10*0^2 + \frac{1}{3}*0^3] )[/tex]
[tex]E(Y) =\frac{1}{100}[100*10 - 10*10^2 + \frac{1}{3}*10^3][/tex]
[tex]E(Y) =10 - 10 + \frac{1}{3}*10[/tex]
[tex]E(Y) =\frac{10}{3}[/tex]
Recall that:
[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]
[tex]Cov(X,Y) = \frac{25}{3} - \frac{10}{3}*\frac{10}{3}[/tex]
[tex]Cov(X,Y) = \frac{25}{3} - \frac{100}{9}[/tex]
Take LCM
[tex]Cov(X,Y) = \frac{75- 100}{9}[/tex]
[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]
You measure 37 dogs' weights, and find they have a mean weight of 69 ounces. Assume the population standard deviation is 9.2 ounces. Based on this, construct a 90% confidence interval for the true population mean dog weight.Give your answers as decimals, to two places_______ ± ________ ounces (Enter your answer as an integer or decimal number. Examples: 3, -4, 5.5172 ; Enter DNE for Does Not Exist, oo for Infinity)
Answers
Solution :
Given :
mean weight of the dogs, [tex]$\overline x$[/tex] = 69
Number of dogs, n = 37
Standard deviation, σ = 9.2
Confidence interval = 90%
At 90% confidence interval for the true population mean dog weight is given by :
[tex]$= \overline x \pm \frac{\sigma}{\sqrt n} \times z_{0.05}$[/tex]
[tex]$= 69\pm \frac{9.2}{\sqrt_{37}}} \times 1.64485$[/tex]
[tex]$=69 \pm 2.487799$[/tex]
= (66.5122, 71.4878)
What is the surface area of the regular pyramid below?
Answers
Surface area is just finding the area of each face of a 3d figure and adding it up together:
Area of square base:
8 • 8 = 64 sq units
Area of ONE triangle face:
1/2 • 15 • 8 = 60 sq units
MULTIPLY that by 4 because we have 4 triangle faces: 60 • 4 = 240 sq units
ADD area of square base and 4 triangle faces: 240 + 64 = 304
FINAL ANSWER OF SURFACE AREA:
304 sq. units
BRAINLIEST will be much appreciated!
-SpaceMarsh, have a nice day/night!
José tiene 30 años menos que su padre y 27 más que su hijo. entre los 3 suman 135 años ¿ cuántos años tiene cada uno?
Answers
Answer:
44 años tiene jose . el padre 74 y el hijo 17 años.
Step-by-step explanation:
A trailer is 22 feet long. 9 feet wide,
and 7 feet high. What is the volume of
the trailer?
Answers
Answer:
1386
Step-by-step explanation:
22 × 9 × 7 = 1386 cubic feet
Given the functions:
g(n) = 3n - 5
f(n) = n2 + 50
Find:
(g+f)(8)
Answers
Answer:
[tex](g + f)(8) =133[/tex]
Step-by-step explanation:
Given
[tex]g(n) = 3n - 5[/tex]
[tex]f(n) = n^2 + 50[/tex]
Required
[tex](g + f)(8)[/tex]
This is calculated as:
[tex](g + f)(n) =g(n) + f(n)[/tex]
So, we have:
[tex](g + f)(n) =3n - 5 + n^2 +50[/tex]
[tex]Substitute[/tex] 8 for n
[tex](g + f)(8) =3*8 - 5 + 8^2 +50[/tex]
[tex](g + f)(8) =24 - 5 + 64 +50[/tex]
[tex](g + f)(8) =133[/tex]
Which term describes the ability to repay debt?
A
capacity
B.
creditworthiness
c. capability
Answers
Answer:
B. CreditworthinessStep-by-step explanation:
❣️(◍•Jess bregoli•◍)❣️#keep learning!!Answer:
B
Step-by-step explanation:
Which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle?
The triangle is acute because 22 + 52 > 42.
The triangle is acute because 2 + 4 > 5.
The triangle is not acute because 22 + 42 < 52.
The triangle is not acute because 22 < 42 + 52.
Answers
9514 1404 393
Answer:
The triangle is not acute because 2² + 4² < 5²
Step-by-step explanation:
The square of the hypotenuse of a right triangle with the given short sides would be 2² +4² = 20. So, that hypotenuse would be √20, about 4.47. The long side of this triangle is longer than that, so the angle opposite is larger than 90°. The triangle with sides 2, 4, 5 is an obtuse triangle.
The triangle is not acute because 2² + 4² < 5²
The triangle is not acute because 22 + 42 < 52.
Option C is the correct answer.
What is a triangle?A triangle is a 2-D figure with three sides and three angles.
The sum of the angles is 180 degrees.
We can have an obtuse triangle, an acute triangle, or a right triangle.
We have,
To determine if a triangle is acute, we need to check whether all three angles of the triangle are acute angles (less than 90 degrees).
Pythagorean theorem,
- If the square of the length of the hypotenuse is greater than the sum of the squares of the other two sides, then the triangle is acute.
- If the square of the length of the hypotenuse is less than the sum of the squares of the other two sides, then the triangle is obtuse.
Now,
The triangle with side lengths 2 in., 5 in., and 4 in. is not a right triangle.
So we can't use the Pythagorean theorem directly.
Now,
We can check if the sum of the squares of the two shorter sides is greater than the square of the longest side.
2² + 4² = 4 + 16 = 20
5² = 25
Since 20 < 25, we know that the triangle is not acute.
Therefore,
The triangle is not acute because 22 + 42 < 52.
Learn more about triangles here:
https://brainly.com/question/25950519
#SPJ7
Find the product with the exponent in simplest
form. Then, identify the values of x and y.
6
X
- 64
.
6
X
y =
DONE
Answers
Answer:
[tex]\displaystyle 8^\bigg{\frac{8}{3}}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Exponential Rule [Powering]: [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex]Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \bigg(8^\bigg{\frac{2}{3}} \bigg)^4[/tex]
Step 2: Simplify
Exponential Rule [Powering]: [tex]\displaystyle 8^\bigg{\frac{2}{3} \cdot 4}[/tex]Multiply: [tex]\displaystyle 8^\bigg{\frac{8}{3}}[/tex]The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they charge for the product: P(c) = –20c2 + 320c + 5,120. What is the maximum profit the company can make from the product?
Answers
Answer:
6400
Step-by-step explanation:
Given the profit function ;
P(c) = –20c2 + 320c + 5,120
The maximum value is given by :
f(h) ; where, h = - b /2a
From P(C) ; a = - 20 ; b = 320
h = - b / 2a = - 320 / 2(-20) = - 320 / 40 = 8
c = h
P(8) = –20(8)² + 320(8) + 5,120
P(8) = - 1280 + 2560 + 5120
= 6400
Answer:
B.) $640,000
Step-by-step explanation:
What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0
Answers
Answer:
Step-by-step explanation:
(x²-6x)+(y²+8y)=-21
(x²-6x+9)+(y²+8y+16)=-21+9+16
(x-3)²+(y+4)²=4
center=(3,-4),radius=√4=2
The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an alphabetical list of all 4247 employees at the company and wants to conduct a systematic sample of size 40.
Required:
a. What is k?
b. Determine the individuals who will be administered the survey. Randomly select a number from 1 to k. Suppose that we randomly select 19. Starting with the first individual selected, the individuals in the survey will be: _________
Answers
Answer:
a). 106
b). See Explanation
Step-by-step explanation:
According to the Question,
Given, The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an alphabetical list of all 4247 employees at the company and wants to conduct a systematic sample of size 40.
a). Thus, the Required Value of K is 4247/40 = 106.175 ≈ 106
b). The individuals who will be administered the survey. Randomly select a number from 1 to k. Suppose that we randomly select 19. Starting with the first individual selected, the individuals in the survey will be
19(19+106) = 125(125+106) = 231337443549655761867973107911851291139715031609171518211927203321392245235124572563266927752881298730933199330534113517362337293835394140474153explain what it means for a function to be O(1)
Answers
Answer:
a function that converges to 0. '' This means that there is some input size past which the function is always between -0.1 and 0.1; there is some input size past which the function is always between -0.01 and 0.01; and so on.
2x-5y=22n y=3x-7 Use substitution to solve the system.
Answers
Answer:
x = 1 , y = -4
Step-by-step explanation:
2x - 5y = 22 ------- ( 1 )
y = 3x - 7 ------- ( 2 )
Substitute ( 2 ) in ( 1 ) :
2x - 5 (3x - 7) = 22
2x - 15x + 35 = 22
- 13x = 22 - 35
- 13x = - 13
x = 1
Substitute x in ( 1 ) :
2x - 5y = 22
2 ( 1 ) - 5y = 22
- 5y = 22 - 2
-5y = 20
y = - 4
What is the solution to the HELP HELP equation m+4
m2
-?
m2-16
4-m
Om =-4
O m = -2
Om = 2.
Om = 4
Answers
Answer:
m = -2
Step-by-step explanation:
[tex]\frac{m}{m+4} + \frac{4}{4-m} = \frac{m^2}{m^2-16}\\\\\frac{m}{m+4} + \frac{4}{-(m-4)} = \frac{m^2}{m^2-16}\\\\[/tex] [tex][ \ ( 4 - m) = - (m -4) \ ][/tex]
[tex]\frac{m}{m+4} + \frac{-4}{(m-4)} = \frac{m^2}{m^2-16}\\\\[/tex] [tex][ \ \frac{a}{-b} = \frac{-a}{b}\ ][/tex]
[tex]\frac{m}{m+4} - \frac{4}{m-4} = \frac{m^2}{m^2-16}\\\\[/tex] [tex][ \ \frac{x}{y} + \frac{-a}{b} = \frac{x}{y} - \frac{a}{b} \ ][/tex]
[tex]\frac{m(m-4)-4(m+4)}{(m-4)(m+4)} = \frac{m^2}{m^2-16}\\\\\frac{m^2 -4m -4m-16}{(m^2-16)} = \frac{m^2}{m^2-16}\\\\[/tex] [tex][ \ T aking \ LCM \ and \ simplifying\ ][/tex]
[tex]m^2 - 8m -16 = m^2[/tex] [tex][ \ \frac{a}{b} = \frac{c}{b} => a = c \ ][/tex]
[tex]m^2 - m^2 - 8m - 16 = 0\\\\0 -8m = 16\\\\-8m = 16 \\\\m = \frac{16}{-8} = -2[/tex]
In The Diagram, P, Q, R, Are Points On The Circle With Centre 0 And Diameter 14cm. Angle PQR=35 Degree. Find, Correct To One Decimal Place A. The Length Of The Minor Are PQ; B. The Chord PQ.
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in the diagram, P, Q, R, are points on the circle with centre 0 and diameter 14cm. angle PQR=35 degree. find, correct to one decimal place
a. The length of the minor are PQ;
B. The chord PQ.
Answers
Answer:
a
Step-by-step explanation:
because the diagram the length decimal place degree
I need to find the equal expression to -m(2m+2n)+3mn+2m². Help please?
Answers
[tex]m(2m+2n)+3mn+2m^2\implies \stackrel{\textit{distributing}}{2m^2+2mn}+3mn+2m^2 \\\\\\ 2m^2+2m^2+2mn+3mn\implies \stackrel{\textit{adding like-terms}}{4m^2+5mn}[/tex]
Which of the following is NOT a solution to the linear equation y=3x+2?
Select the correct answer below:
(1,5)
(2,8)
(3,10)
(4,14)
Answers
Answer:
(3,10)
Step-by-step explanation:
When x is 3
[tex]{ \bf{y = 3x + 2}} \\ { \bf{y = (3 \times 3) + 2}} \\ { \bf{y = 11}}[/tex]
y is 11, and this is invalid because it is not at accord.
The correct coordinates which is NOT a solution to the linear equation
y = 3x+2 is,
⇒ (3, 10)
What is Equation of line?The equation of line in point-slope form passing through the points
(x₁ , y₁) and (x₂, y₂) with slope m is defined as;
⇒ y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
Linear equation is,
⇒ y = 3x + 2
We know that;
The solution of linear equation is satisfy the eqaution.
Hence, We can check as;
⇒ y = 3x + 2
Put x = 1. y = 5
⇒ 5 = 3 × 1 + 2
⇒ 5 = 5
Thus, It is solution of linear equation.
⇒ y = 3x + 2
Put x = 2. y = 8
⇒ 8 = 3 × 2 + 2
⇒ 8 = 8
Thus, It is solution of linear equation.
⇒ y = 3x + 2
Put x = 3, y = 10
⇒ 10 = 3 × 3 + 2
⇒ 10 ≠ 11
Thus, It is not solution of linear equation.
Thus, The correct coordinates which is NOT a solution to the linear equation y = 3x+2 is,
⇒ (3, 10)
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the second difference 4;x;8;y;20;.... is 2
Answers
9514 1404 393
Answer:
x = 5y = 13Step-by-step explanation:
First differences are ...
x -4, 8 -x, y -8, 20 -y
Then second differences are ...
(8 -x) -(x -4)
(y -8) -(8 -x)
(20 -y) -(y -8)
Each of these is said to be 2, so we have ...
12 -2x = 2 ⇒ x = 5
28 -2y = 2 ⇒ y = 13
And an equation we can use to check:
x +y -16 = 2 ⇒ 5 +13 -16 = 2 . . . . true
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The explicit formula for the sequence is ...
an = n^2 -2n +5
