which methods could you use to calculate the y coordinate of the midpoint of a vertical line segment with end points at (0,0) (0, -12). check all that apply

Answer:

where is the figure without figure how to find out

Answer:

130

Step-by-step explanation:

65/50*100= 130

Answer:

x=4

Step-by-step explanation:

(x-1+5)×5=(2+x+4)×4

or, 5×(x+4)=4×(x+6)

or, 5x+20=4x+24

or, 5x-4x=24-20

or, x=4

Answer:

25

Step-by-step explanation:

product of 18 and -3=18*-3= -54

positive difference=52-29=23

(18x-3)+56+(52-29)

= -54 + 56 + 23

=25

Answer:

73 1/3 %

Step-by-step explanation:

8 pieces were left

30-8 = 22 so 22 were consumed

22/30 is the percent consumed

.7333333

73.333333%

We know .333333333 is 1/3

73 1/3 %

Answer:

either 5 or 6

Step-by-step explanation:

I can't have a direct answer because you didn't get all of the histogram in there, but from what I can conclude from just this there's definitely either 5 or 6.

Answer:

The properties of right angle triangle are as follows

Answer:

Omg why are you soo beautiful? I love it

Answer:

the cost of the tire=341.4$

Answer:

FG = 120 cm

Step-by-step explanation:

The explanation is in the picture!

Answer:

3√13

Step-by-step explanation:

3√13

This expression cannot be simplified because you cannot take any common factor outside the root.

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

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The function is:

[tex]f(x) = \frac{2x}{2x^3 - 5x^2 - 12x} = \frac{2x}{x(2x^2 - 5x - 12)} = \frac{2}{2x^2 - 5x - 12}[/tex]

The points outside the domain are the zeros of [tex]2x^2 - 5x - 12[/tex], which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

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[tex]2x^2 - 5x - 12[/tex] is a quadratic equation with [tex]a = 2, b = -5, c = -12[/tex].

[tex]\Delta = b^{2} - 4ac = (-5)^2 - 4(2)(-12) = 121[/tex]

[tex]x_{1} = \frac{-(-5) + \sqrt{121}}{2(2)} = 4[/tex]

[tex]x_{2} = \frac{-(-5) - \sqrt{121}}{2(2)} = -\frac{6}{4} = -\frac{3}{2}[/tex]

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The domain is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

A similar problem is given at https://brainly.com/question/13136492

Answer:

Step-by-step explanation:

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that , second option.

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The domain of a function is all possible values that the input value x can assume.

The domain of a fraction is all real values of x except the zeros of the denominator.

----------------------

The function is:

The points outside the domain are the zeros of , which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots  such that , given by the following formulas:

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is a quadratic equation with .

----------------------

The domain is: x is an element of all real numbers such that , second option.

A similar problem is given at brainly.com/question/13136492

Answer:

100km

Step-by-step explanation:

Time taken to travel to Bangi:

x/80 hours

15min = 1/4hrs

Time taken to travel back:

x/80 - 1/4

x= x/(x/80-1/4)

x^2-100x=0

x(x-100)=0

x=0 (rejected) or x=100

Answer:

B. 100km

Step-by-step explanation:

Brainliest please

Answer:

8

Step-by-step explanation:

By power of a point, (x-2)(x+13) = (x-3)(x+16). Solving, we find that x=11, so FG= 11-3 = 8

Answer:

the answer is 10 or 6^2+8^2=100

√100=10

Answer:

I think this is right for the 2nd problem

Step-by-step explanation:

a1=7+(3)(1)

Step 1: Simplify both sides of the equation.

a1=7+(3)(1)

a=7+3

a=(7+3)(Combine Like Terms)

a=10

a=10

Answer:

a=10

Answer:

2ax(y-2ay^2+3a^2x)

Step-by-step explanation:

2axy-4a^2xy^2+6a^3x^2

Given data

we have the following expression

2axy-4a^2xy^2+6a^3x^2

let us factor this expression

we have

2ax(y-2ay^2+3a^2x)

The common factor is 2ax

And the factorized expression is 2ax(y-2ay^2+3a^2x)

Answer:

0.36

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

Add 7 onto 12 to find answer.

Answer:

b = 19

Step-by-step explanation:

b = 12 + 7

Simplify 12+7 to 19.

Answer:

-60 and -28

Step-by-step explanation:

-60 + 42= -18

CHECK:

-42-18=-60

-56+-28=-84

CHECK:

-84+28=-56

Hope this helps <3 Need thanks? Comment /hearthelp

Answer:

-60

-28

Step-by-step explanation:

x +42 = -18

Subtract 42 from each side

x+42-42 = -18-42

x = -60

-56 +y = -84

Add 56 to each side

y = -84+56

y = -28

Use the law of cosines, which says

189² = 215² + 123² - 2×215×123 cos(∠P)

==>   cos(∠P) = 25,633/52,890

==>   ∠P ≈ 61.06°

Answer:

A

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = length × breadth

   = (2x - 5)(x + 4) ← expand using FOIL

   = 2x² + 8x - 5x - 20

  = 2x² + 3x - 20 → A

Answer:

30 quarts

Step-by-step explanation:

4 quarts = 1 gallon

7.5 gallons * 4 quarts/ 1 gallon = 30 quarts

Answer:

The inequality is -3<x<3

Step-by-step explanation:

(-3,3)

Answer:

7 pots of coffee (If you want to be precise its 6 2/3)

Step-by-step explanation:

So basically you need 10 cups of coffe in fifteen minutes, so 60/15=4 then time 10. so 40 is how much coffee you need in a hour, but we are solving the pot so 40/6= 6 2/3. but it says how many pots so we round it up so its 7. (Unless you wanna be precise)

Answer:

see below

Step-by-step explanation:

5^2  means 5*5  not 5*2

5^2 = 5*5 = 25  not 10

Answer:

5*5 = 25

bobby mistake is doing 5*2 = 10

Step-by-step explanation:

Answer:

37500

Step-by-step explanation:

pattern is multiplying by -5.

-7,500*-5 = 37,500

Have a nice day! :-)

Answer:

1) 6а-9b=3(2a-3b)

2)8a-12b=4(2a-3b)

3) 5ab-5ac=5a(b-c)

4) 6ax+6ay=6a(x+y)

Answer:  [tex]\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)[/tex]

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

From there, we can then say the following:

[tex]\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}[/tex]