Which of the following best describes the data distribution of the histogram below?
A. Symmetric
B. Uniform
C. Bimodal
D. Unimodal​

Answer:

x = 27

Step-by-step explanation:

I'm assuming the equation looks like this:

[tex]\frac{2}{3}x-\frac{1}{9}x+5=20[/tex]

Here's how to solve for x:

[tex]\frac{2}{3}x-\frac{1}{9}x+5=20[/tex]

(subtract 5 from both sides)

[tex]\frac{2}{3}x-\frac{1}{9}x=15[/tex]

(Find the GCF of 3 and 9, which is 3. Multiply 2/3 by 3/3. You get 6/9)

[tex]\frac{6}{9}x-\frac{1}{9}x=15[/tex]

(add like terms)

[tex]\frac{5}{9}x=15[/tex]

(multiply 9/5 to both sides, which is the same as dividing both sides by 5/9)

x = 27

Hope it helps (●'◡'●)

Answer:

the value of x is 29°

hope it helps

have a nice day

Answer:

a=5

Step-by-step explanation:

Answer:

Choosing a card randomly and noting its suit

Step-by-step explanation:

Choosing a card randomly and noting its suit

This is because binomial distributions only work for bernoulli trials (a trail in which there are only two outcomes)

Step-by-step explanation:

Recall that

[tex]1 + \tan^2 x = \sec^2 x[/tex]

and

[tex]\dfrac{d}{dx}(\tan x) = \sec^2 x[/tex]

so that

[tex]\displaystyle \int \tan^2 x = \int (\sec^2 x - 1)dx[/tex]

[tex]\:\:\:\:\:\:\:\:\:=\int \sec^2 xdx - \int dx[/tex]

[tex]\:\:\:\:\:\:\:\:\:=\tan x - x + C[/tex]

where C is the constant of integration.

Answer:

64 Bottles

Step-by-step explanation:

that is the procedure above

Answer:

0.7513 = 75.13% probability that no more than 1 employee was over 50

Step-by-step explanation:

The employees are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

4 + 16 = 20 employees, which means that [tex]N = 20[/tex]

4 over 50, which means that [tex]k = 4[/tex]

5 were dismissed, which means that [tex]n = 5[/tex]

What is the probability that no more than 1 employee was over 50?

Probability of at most one over 50, which is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,20,5,4) = \frac{C_{4,0}*C_{16,5}}{C_{20,5}} = 0.2817[/tex]

[tex]P(X = 1) = h(1,20,5,4) = \frac{C_{4,1}*C_{16,4}}{C_{20,5}} = 0.4696[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.2817 + 0.4696 = 0.7513[/tex]

0.7513 = 75.13% probability that no more than 1 employee was over 50

9514 1404 393

Answer:

Step-by-step explanation:

The formula for figuring the amount that can be borrowed (P) is shown on the first line of the attachment. (The second line rounds it to the nearest cent.) In this formula, ...

  a = monthly payment, r = annual interest rate, t = number of years

The amounts requested by the problem statement are shown in the attachment, and above. b is the amount that can be borrowed, p is the total of payments, and i is the interest paid. There are 360 monthly payments in 30 years, so the total paid is 360 times the monthly payment amount.

Answer:

[tex]\sf \dfrac{1}{24}=0.0417=4.17\%\:\:(3\:s.f.)[/tex]

Step-by-step explanation:

Given information:

Contents of Jar 1:

Contents of Jar 2:

Probability Formula

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

Therefore:

[tex]\sf P(white\:marble\:from\:Jar\:1)=\dfrac{4}{24}=\dfrac{1}{6}[/tex]

[tex]\sf P(white\:marble\:from\:Jar\:2)=\dfrac{20}{80}=\dfrac{1}{4}[/tex]

As the events are independent (i.e. drawing a marble from one jar does not influence or affect drawing a marble from the other jar), we can use the independent probability formula:

[tex]\sf P(A\:and\:B)=P(A) \cdot P(B)[/tex]

Therefore, the probability that a white marble will be drawn from both jars is:

[tex]\sf P(white\:marble\:from\:Jar\:1)\:and\:\sf P(white\:marble\:from\:Jar\:2)=\dfrac{1}{6} \cdot \dfrac{1}{4}=\dfrac{1}{24}[/tex]

#Jar 1

Total marbles =20+4=24

P(w)

#Jar 2

Total marbles=60+20=80

P(w)

P(w in total)

9514 1404 393

Answer:

  6,364.8 lb

Step-by-step explanation:

The centroid of the plate is its center, so is 1.5 ft above the bottom of the pool, or 8.5 ft below the surface. The area of the plate is (3 ft)(4 ft) = 12 ft². Then the fluid force is ...

  (62.4 lb/ft³)(8.5 ft)(12 ft²) = 6,364.8 lb

Answer:

305°

Step-by-step explanation:

The bearing in the reverse direction is 180° plus the bearing in the forward direction, that is

bearing of B from A = 180° + 125° = 305°

B is the answer for this question hope it helps

Answer:

a)  [tex]h=286.8ft[/tex]

b)  [tex]\frac{dh}{dt}=5.7ft/s[/tex]

Step-by-step explanation:

From the question we are told that:

Angle [tex]\theta=35[/tex]

a)

Slant height [tex]h_s=500ft[/tex]

Generally the trigonometric equation for Height is mathematically given by

[tex]h=h_ssin\theta[/tex]

[tex]h=500sin35[/tex]

[tex]h=286.8ft[/tex]

b)

Rate of release

[tex]\frac{dl}{dt}=10ft/sec[/tex]

Generally the trigonometric equation for Height is mathematically given by

[tex]h=lsin35[/tex]

Differentiate

[tex]\frac{dh}{dt}=\frac{dl}{dt}sin35[/tex]

[tex]\frac{dh}{dt}=10sin35[/tex]

[tex]\frac{dh}{dt}=5.7ft/s[/tex]

Answer:

45 mph

Step-by-step explanation:

This is a really good question to know the answer to. It is tricky and a bit indirect (which means you have to find something else before you can find the speed of the car.)

Let's keep track of what he does in the time allotted.

How far does Joe go in 5 minutes? That's the amount of time he's on the road before she is.

convert 5 minutes into hours. 5 minutes * 1 hour / 60 minutes = 1/12 of an hour

d = r*t

r = 30 km/hour

t = 1/12 hour

d = 30 km/hr * 1/12 hour = 2.5 km

Now she's about to start. She wants to catch him in 10 minutes

d = r*t

r = x mph

t = 10 minutes = 10 minutes * 1 hour * 60 minutes = 1/6 of an hour.

How far does he go in the 10 minute time?

d = 30 * 1/6 = 5 km

What is his total distance

5 km + 2.5 km = 7.5 km

Finally how fast does she need to go to catch him

d = 7.5 km

r = ?   This is what you are trying to find

t = 1/6 of an hour

d = r*t

7.5 km = r * (1/6)hour             divide by 1/6 hour

7.5 km // 1/6 hour = r

r = 7.5 * 6 = 45 mph

Answer:

The probability of getting two good coils is 77.33%.

Step-by-step explanation:

Since a batch consists of 12 defective coils and 88 good ones, to determine the probability of getting two good coils when two coils are randomly selected (without replacement), the following calculation must be performed:

88/100 x 87/99 = X

0.88 x 0.878787 = X

0.77333 = X

Therefore, the probability of getting two good coils is 77.33%.

Answer:

C'

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

[tex]A \to A'[/tex]

[tex]B \to B'[/tex]

[tex]C \to C'[/tex]

[tex]D \to D'[/tex]

Hence, C' corresponds to C

Answer:

C

Step-by-step explanation:

I took the test :)

Answer:

(a) 3178

(b) 14231

(c) 33152

Step-by-step explanation:

Given

[tex]y = \frac{269573}{1+985e^{-0.308t}}[/tex]

Solving (a): Year = 1998

1998 means t = 8 i.e. 1998 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*8}}[/tex]

[tex]y = \frac{269573}{1+985e^{-2.464}}[/tex]

[tex]y = \frac{269573}{1+985*0.08509}[/tex]

[tex]y = \frac{269573}{84.81365}[/tex]

[tex]y = 3178[/tex] --- approximated

Solving (b): Year = 2003

2003 means t = 13 i.e. 2003 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*13}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.004}}[/tex]

[tex]y = \frac{269573}{1+985*0.01824}[/tex]

[tex]y = \frac{269573}{18.9664}[/tex]

[tex]y = 14213[/tex] --- approximated

Solving (c): Year = 2006

2006 means t = 16 i.e. 2006 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*16}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.928}}[/tex]

[tex]y = \frac{269573}{1+985*0.00724}[/tex]

[tex]y = \frac{269573}{8.1314}[/tex]

[tex]y = 33152[/tex] --- approximated

Answer:

7. [tex]x^{11}[/tex]   8. [tex]y^{2}\\[/tex]  9. [tex]p^{12}[/tex]  10.[tex]a^{3} b^{2}[/tex]  11.[tex]g^{16}[/tex]  12.[tex]r^{9} h^{3}[/tex]  13.[tex]m^{15} p^{6}[/tex]  14.[tex]k^{6} y[/tex]  15.[tex]x^6 z^4[/tex]

Step-by-step explanation:

7. [tex]x^3[/tex] × [tex]x^8[/tex] = [tex]x^{11}[/tex] when multiplying with exponents you add

8. [tex]\frac{y^{6} }{y^{4} }[/tex] = [tex]y^{2}[/tex] when dividing with exponents you subtract

9. [tex](p^{3})^4[/tex] = [tex]p^{12}\\[/tex] when it's power to power, you multiply

10. [tex]\frac{a^{9} b^{4}}{a^{6} b^{2}}[/tex] = [tex]a^{3} b^{2}[/tex]  (subtract exponents)

11. [tex](g^{8})^2[/tex] = [tex]g^{16}[/tex]  (multiply exponents)

12. [tex]r^{4} h^{2} r^{5} h[/tex] = [tex]r^{9} h^{3}[/tex]  (add exponents [tex]r^4 + r^5\\[/tex] and [tex]h^2 +h^1\\[/tex] )

13. [tex](m^{5} p^{2})^3[/tex] = [tex]m^{15} p^{6}[/tex] (multiply exponents)

14. [tex]\frac{k^{7} y^{4}}{y^{3}k}[/tex] =  [tex]k^{6} y[/tex] (subtract exponents [tex]k^7-k^1[/tex] and [tex]y^4-y^3\\[/tex] )

15. [tex]x^3 z^2 x^3 z^2[/tex] = [tex]x^6 z^4[/tex] (add exponents same as #12)

Answer:

0.96784

Step-by-step explanation:

17-13.3/2

=1.85

p(x<1.85)

=0.96784

The probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

Mean [tex]\mu[/tex]=13.3 minutes

Standard deviation[tex]\sigma[/tex]=2 minutes

The value of the z-score tells you how many standard deviations you are away from the mean.

So, the z-score of the above data

[tex]z=\frac{x-\mu}{\sigma}[/tex]

[tex]z=\frac{17-13.3}{2}[/tex]

[tex]z=1.85[/tex]

From the standard normal table, the p-value corresponding to z=1.85

Or, p(x<1.85)=0.9678 or 96.78%

Hence, the probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

To get more about the z-score visit:

https://brainly.com/question/25638875

Answer:

The probability is 1/2500. (1/50)*(1/50)

Step-by-step explanation:

Answer:

221

Step-by-step explanation:

Given sequence is ,

> 5 , 6 , 7 , 8 , 9.

The common difference is 6-5 = 1 .

Therefore , the 221st number will be

> 221 st term = 221 × 1 = 221 .

Hence the 221 st term is 221 .

Answer:

225

Step-by-step explanation:

d = 6 - 5 = 1 (common differences)

a = 5 (first term)

221st term

a+(n-1)d

5 +(221 - 1) 1

5 + 220 =225

Therefore the answer is 225

Answer:

80 seconds

Step-by-step explanation:

10/10 = 1

now it takes 1 seconds to count 1 sheet

80 x 1 = 80 seconds to count 80 sheets

Step-by-step explanation:

10sheets=10seconds

1sheet=1sheet÷10sheets x 10seconds

=1second

80sheets=80sheets÷1sheet x 1second

80seconds

hope this is helpful

Answer:

Question 1: x = 6

Question 2: Correct!

Question 3: x = 11

Question 4: Correct!

Step-by-step explanation:

Question 1:

Angle 22x - 2 DOESN'T equal 50 degrees. Only Alternate Interior Angles will equal each other. These two angles are Same Side Interior Angles, meaning if you added them together, they would equal 180 degrees.

Knowing that adding 22x - 2 and 50 will equals 180 degrees, here's how we solve for x:

First, subtract 50 from 180 to find what angle 22x - 2 will equal:

180 - 50 = 130

130 = 22x - 2

Now use basic algebra to solve for x:

130 = 22x - 2

(add 2 to both sides)

132 = 22x

(divide both sides by 22)

x = 6

Question 3:

Angle 5x + 15 DOESN'T equal 9x + 11. They make up a line, which is 180 degrees, so they are supplementary angles.

With that in mind, to solve for x, add the two equations and set it equal to 180:

5x + 15 + (9x + 11) = 180

Now use basic algebra to solve for x:

5x + 15 + 9x + 11 = 180

(add like terms)

14x + 26 = 180

(subtract 26 from both sides)

14x = 154

(divide 14 from both sides)

x = 11

Hope it helps (●'◡'●)

Answer:

Hello?

Step-by-step explanation:

Answer:

2.409

Step-by-step explanation:

㏑ 9 = 2.2

ln 200 = 5.3

[tex]ln 9 = log_{e}9\\ln 200 = log_{e}200[/tex]

[tex]log_{9}200 = \frac{log_{e}200}{log_{e}9}[/tex]

           = [tex]\frac{5.3}{2.2}[/tex]

           = 2.409

The approximate value of log 200 would be; 2.409

When we raise a number with an exponent, there comes a result.

Let's say you get  a^b = c Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows [tex]b = \log_a(c)[/tex]'a' is called the base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'

We have given the values in 9 = 2.2 and 200 – 5.3

We need to find the approximate value of log, 200.

Therefore,

㏑ 9 = 2.2

ln 200 = 5.3

[tex]ln 9 = log_{e}9\\\\ln 200 = log_{e}200[/tex]

Using the logarithm property;

[tex]log_{9}200 = \dfrac{log_{e}200}{log_{e}9}\\ = \dfrac{ln 200}{ln 9}\\ = \dfrac{5.3}{2.2}[/tex]

=  2.409

Hence, the approximate value of log, 200 would be; 2.409

Learn more about logarithm here:

https://brainly.com/question/20835449

#SPJ2

Answer:

The total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.

Step-by-step explanation:

Given that last year, Manuel deposited $ 7000 into an account that paid 11% interest per year and $ 1000 into an account that paid 5% interest per year, and no withdrawals were made from the accounts, to determine what was the total interest earned at the end of year and what was the percent interest for the total deposited, the following calculations must be performed:

7000 x 0.11 + 1000 x 0.05 = X

770 + 50 = X

820 = X

8000 = 100

820 = X

820 x 100/8000 = X

82,000 / 8,000 = X

10.25 = X

Therefore, the total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.

Answer:

5 905 272

Step-by-step explanation:

you can refer to this lattice multiplication or u can search you tube for the examples of lattice multiplication

Answer:

B

Step-by-step explanation:

(6)^1/2 × (8)^1/2

6^1/2 × 2 (2)^1/2

4 (3)^1/2