Answer:
sorry,but there is no graph ...its difficutlt to say u the ans
group the like terms separately? 3v^5-10v^2-12v^5+14v^2
Use the drop-down menus to correctly relate each pair of numbers
manee help meh son
Answer:
Sorry for the late response, I had to have lunch.
1. >
2. =
3. <
4. >
Step-by-step explanation:
Have a great summer :)
decompose 17x^3+7x^2-17x-7 divided by (x-1)^2(x+1)^2 into partial fraction
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hello i need help with these questions attached.
Answer:
Beep
Step-by-step explanation:
Find the value of angle y
Answer:
116
Step-by-step explanation:
116 is parallel to y so that are the same its called corresponding angles
When a transversal cuts two parallel lines, the corresponding angles are equal.
In the given figure, the corresponding angles are 116° and y
So, they are equal
⇒ y = 116°
Find the exact value of sin2Θ if tanΘ=[tex]\frac{-2\sqrt{5} }{5}[/tex] and 90 < Θ < 180.
Answer:
[tex]sin 2 \theta = \frac{4 \sqrt5}{9}[/tex]
Step-by-step explanation:
Identities used :
[tex]1. sin^2 \theta = 1 - cos^2\theta\\\\2. tan^2 \theta + 1 = sec^2 \theta\\\\3.cos \theta = \frac{1}{sec \theta} \\\\4. sin 2 \theta = 2 sin\theta cos\theta[/tex]
[tex]Given \ tan \theta = -\frac{2 \sqrt5}{5}\\[/tex]
[tex]we \ know \ tan ^2 \theta + 1 = sec^2\theta[/tex]
[tex](-\frac{2 \sqrt 5}{5})^2 + 1 = sec^2 \theta\\\\\frac{4 \times 5}{25 } + 1 = sec^2 \theta \\\\\frac{20 + 25}{ 25} = sec^2 \theta \\\\\frac{45}{25} = sec^2 \theta \\\\sec \theta = \sqrt{ \frac{45}{25}}\\\\sec \theta = \sqrt{ \frac{9 \times 5}{5 \times 5}} \\\\sec \theta = \frac{3 \sqrt {5}}{5}\\\\[/tex]
[tex]We \ know \ cos \theta = \frac{1}{ sec \theta}[/tex]
[tex]So , \cos \theta = \frac{5}{3 \sqrt5}[/tex]
[tex]Next \ sin^2 \theta = 1 - cos^2 \theta[/tex]
[tex]= 1 - (\frac{5}{3 \sqrt5})^2\\\\=1 - \frac{25}{9 \times 5}\\\\=1 - \frac{25}{45}\\\\=\frac{45 - 25}{45}\\\\=\frac{20}{45}\\\\=\frac{4}{9}[/tex]
[tex]sin \theta = \sqrt{ \frac{4}{9}} = \frac{2}{3}[/tex]
[tex]Find \ sin 2 \theta[/tex]
[tex]sin 2 \theta = 2 (sin \theta \times cos \theta)[/tex]
[tex]= 2 \times \frac{2}{3} \times \frac{5}{3\sqrt5}\\\\= \frac{4 \times \sqrt5 \times \sqrt5}{9 \times \sqrt 5}\\\\=\frac{4 \sqrt5}{9}[/tex]
The button on David's coat has a radius of 4
millimeters. What is the button's diameter?
Answer:
0.013
I think.
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
So there are two things that must be remembered.
The radius is half of the diamater. It is the distance from the side of a circle to its center.
The diamater is two times the radius. It is the distance from one side of the circle to the opposite side of the circle.
In this case, we know the radius is 4.
The radius is half of the diamamter, or the diamater is two times the radius.
This can be though of as:
2r=d
Or
1/2d=r
So lets plug 4 in for r:
2*4=d = 8=d
1/2d=4 = 2*1/2=4*2 = 1d=8
So using either of these formulas, we find d is equal to 8.
Hope this helps!
2. The average daily rainfall in London during April was 3.5 mm. How much rain fell during the month?
Answer:
105mm
Step-by-step explanation:
To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall
Number of days in April: 30
Average daily rainfall: 3.5mm
Rainfall during the month = 30 * 3.5 = 105mm
What is the value of this expression when a = 7 and b = -4? 1201 - 6 3 OA. -6 OB. - 31 Oc. 37 D. 6
Answer:
OA . -6
Step-by-step explanation:
correct me if I'm wrong
The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of RT and R1, what is R2 R2 blank is ohms
[tex]R_2[/tex] is 3 ohms
Step-by-step explanation:In a circuit containing two resistors [tex]R_1[/tex] and [tex]R_2[/tex] connected together in parallel, the total resistance [tex]R_T[/tex] is given by;
[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}[/tex] ---------(i)
Make [tex]R_2[/tex] subject of the formula;
=> [tex]\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}[/tex]
=> [tex]\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}[/tex]
=> [tex]{R_2} = \frac{R_TR_1}{R_1 - R_T}[/tex] ---------------(ii)
From the question,
[tex]R_1[/tex] = 6Ω
[tex]R_T[/tex] = 2Ω
Substitute these values into equation (ii) as follows;
=> [tex]{R_2} = \frac{2*6}{6 - 2}[/tex]
[tex]{R_2} = \frac{12}{4}[/tex]
[tex]R_2[/tex] = 3Ω
Therefore, the value of [tex]R_2[/tex] = 3 ohms or [tex]R_2[/tex] = 3Ω
Answer: is 3 ohms.
Explanation: edmentum/plato :)
In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?
O 10
O 15
O 20
O 25
Answer:
x = 25
Step-by-step explanation:
Correct question
In a right triangle Sin (40-x)=cos(3x) what is the value of x
Since Sin theta = Cos(90-theta)
Sin (40-x) = Sin(90-3x)
40 - x = 90 - 3x
-x+3x = 90 - 40
2x = 50
x = 25
Hence the value of x is 25
I need help
Solve the expression when X =5;3(X+2)=
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {21}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex]3 \: ( \: x + 2 \: )[/tex]
Plugging in the value [tex]x = 5[/tex] in the above expression, we have
[tex] = 3\:( \: 5 + 2 \: )[/tex]
[tex] = 3 \: ( \: 7 \: )[/tex]
[tex] = 3 \times 7[/tex]
[tex] = 21[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}[/tex]
Can someone please help me out with this question
Answer:
C.
Step-by-step explanation:
Find the distance between the points given.
(-3,-4) and (0,0)
Answer: 5 Units
Step-by-step explanation:
Convert 23cm2 into mm2
Answer:
2300 mm^2
Step-by-step explanation:
Which is equivalent to7^(3/2) over 7^(1/2)?
A. 7^(1/3)
B. 7^(3/4)
C. 7^1
D. 7^2
E. 7^3
Given the expression below:
[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } }[/tex]
Use the following property:
[tex] \large \boxed{ {a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} } }[/tex]
Therefore:
[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } = \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } } \\ \large{ \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } = \frac{ \sqrt{7 \times 7 \times 7} }{ \sqrt{7} } \longrightarrow \frac{7 \sqrt{7} }{ \sqrt{7} } } \\ \large{ \frac{7 \cancel{ \sqrt{7} }}{ \cancel{ \sqrt{7} }} = 7}[/tex]
Note that a¹ = a. Therefore, 7¹ = 7.
Answer
7¹ or 7.please help guys! i don’t wanna fail
Answer:
25: 6,000
26: 450
27: 70,000,000
28: 10,500
29: 3,052
30: (cant really see the exponent but I think its 10^5) 500,000
31: 9.87
32: 5.43
A
B
С
D
If mZACD = 70°, then mZBCD = [? ]°
Answer:
35 is correct
Step-by-step explanation:
hope this helps.
Answer:
35°
Step-by-step explanation:
Angle ACD is 70°. The little tick marks on the angle mean both sides of the split are the same amount. This means if you divide the angle in half, you will find out what both of them are equal to.
what number represents the same amount as 4 tens+0 ones
how to solve -4x+8y=-16
4x+3y=5
Answer:
X=2, y=-1
Step-by-step explanation:
-4x +8y=-16 equation 1
4x +3y=5 equation 2
11y=-11 add two equations to eliminate x
y=-1
solve for x by inputting y value into either equation
4x+3y=5
4x+3(-1)=5
4x-3=5
4x=8
x=2
?????????????????????
Answer:
[tex]\sqrt{x+6}[/tex]
Step-by-step explanation:
So, there are a few things we need to go over to graph a function,
When a number is outside of a root, it changes the y value. For example:
y=[tex]\sqrt{x}+6[/tex]
With the +6, y will always be 6 higher than normal.
If it was -6, then y will always be 6 lower than normal.
What if the number is inside the root? Well, it works a little differently.
Instead of changing the y value, it changes the x value. For example:
y=[tex]\sqrt{x+6}[/tex]
So if you put a number in for x, lets say -6, wht would you get?
You would get -6+6=0
The square root of 0 is 0, so when x=-6, y=0
Normally, x would have to equal 0 for the y value to be 0.
So basically, when we see the number isnide of the root, we can think the our x coordinate being subtracted by that number.
This makes since, because if we subtract the +6 from x:
x-(+6)= x-6, and -6 is our x coordinate.
If it was -6 at the start, this would also work:
x-(-6)= x+6. So our x coordinate would start at 6.
Now, lets look at our graph.
As we can see, the x values start at -6, and the y values starts at 0.
This eliminates A and D, since the +6 would change the y value, not the x.
Remember that x-6 would make x a postive 6.
x+6 however, would make x a negative 6.
So we need x+6 in a square root.
This eliminates B, since it has a x-6, making the x coordinate postive 6, not negative 6.
So c is our answer.
Hope this helps!
What is the simplified form of [tex]3\sqrt{135}[/tex]?
The answer is: [tex]9\sqrt{15}[/tex]
What’s the answer please.
Answer:
[tex]\frac{m^{3}n+5 }{m^{2}n^{2} }[/tex]
Explanation :
is down below in the picture
Please give me brainiest!!
NEED HELP ASAP Let the function f(x) have the form f(x) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of C be?
Answer:
[tex]C = 2[/tex] (A)
Step-by-step explanation:
We assume the constant A is different than 0
We notice that the graph of the function intercepts the x-axis when x = -0.5
we know that cos(x) = 0 when x = π/2 or x = -π/2
thus, [tex]-0.5 + C = \pi /2[/tex] or [tex]-0.5 + C = -\pi /2[/tex]
then [tex]C = \pi /2 + 0.5 = 2[/tex] or [tex]C = -\pi /2 = 0.5 = -1[/tex]
so [tex]C = 2[/tex]
Point of intersection Question:
Mike has $9.85 in dimes and quarters. If there are 58 coins altogether,
how many dimes and how many quarters does Mike have? Use the point of intersection to find the answer. Explain how you used a formula to calculate the # of quarters and dimes
Answers:
He has 27 quarters and 31 dimes
=========================================================
Work Shown:
d = number of dimes
q = number of quarters
d+q = 58 since there are 58 coins of only these two types
d = 58-q
10d+25q = 985 .... note that 985 cents is $9.85
10(58-q)+25q = 985 .... replace d with 58-q
580-10q+25q = 985
15q+580 = 985
15q = 985-580
15q = 405
q = 405/15
q = 27 ..... Mike has 27 quarters
d = 58-q
d = 58-27
d = 31 .... Mike also has 31 dimes
-----------
As a way to check:
d+q = 31+27 = 58 so that works out
and
10d+25q = 10*31+25*27 = 310+675 = 985
so that works out as well. The answer is confirmed.
find the area of the figure below
A.832in^2
B.768^2
C.416^2
D.384in^2
Find the sum.
b/ b^2+4b+4 + 9/b^2+7b+10
Answer:
11b^3+14b^2+b+9
---------------------------
b2
Step-by-step explanation:
if gon had 40 tubs of orange juice then killua gave gon 29348211239587316837637869437637689767609 more tubs of orange juice, how many tubs of orange juice would gon have?
Answer:
It would be 2.9348211e+40
Step-by-step explanation:
Use a calculator
Need help with probabilities (math) plz
Answer:
What is your question for probabilities?
whats the answer to this
Answer:
its the 2nd one
hope that helps<3
Answer:
jhkkkhj
Step-by-step explanation:
jkjkjkjkj
