Which of the following must be equal to 30% of x?
3x
(A)
1,000
3x
(B)
100
3x
(C)
10
(D) 3x

Answer:

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Step-by-step explanation:

We need to compare the given two fractions .The given fractions are ,

[tex]\implies \dfrac{3}{10} [/tex]

[tex]\implies \dfrac{1}{5} [/tex]

Firstly let's convert them into like fractions . By multiplying 1/5 by 2/2 . We have ,

[tex]\implies \dfrac{1}{5} =\dfrac{1*2}{5*2}=\dfrac{2}{10} [/tex]

Now on comparing 2/10 and 3/10 we see that ,

[tex]\implies 2< 3 [/tex]

Therefore ,

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Answer:

hope you find it useful and helpful

Answer:

the graph looks like this:-

Step-by-step explanation:

for inequality 1

if we take x = 0 we get y = -4

and if we take y =0 we get x = 16

so we get 2 points (0, -4) and (16, 0) and the graph must pass thru these two.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is not greater than or equal to -16

so origin doesn't satisfy the inequality.

shade the graph on the side, of the line, opposite to where the origin is.

for inequality 2

if we take x = 0 we get y = 2

and if we take y =0 we get x = -⅔

so we get 2 points (0, 2) and (-⅔, 0) and the graph must pass thru these two.

the line should be a dotted line.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is less than 2

so origin satisfies the inequality.

shade the graph on that side of the line where the origin is.

[ red line shows graph 1 whereas the blue dotted line represents graph ]

Answer:

X o punto Y O punto z

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

15*.1=1.5

so either one or two people of the 15 would be left handed

Answer:

10, 8, 6, 4, 2, ...

Step-by-step explanation:

For this problem, you were given the recursive rule. The recursive rule consists of an equation that represents how the former term is modified to get the current term and the first term of the sequence. F(1) means the first term; in this case, the first term is 10. The equation in the rule shows that 2 is subtracted from the last term to get the current term. This means that the common difference is -2 and each term decreases by 2. Therefore, the last option, 10, 8, 6, 4, 2, ..., is correct.

Answer:

if x=0 then they have same value

1 and 2 options are out

for x=-1

g(-1)=1

h(-1)=-1

3 is true

4th

FALSE

for all values except 0, g(x)>h(x)

correct ones are

g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

Step-by-step explanation:

Answer:

Step-by-step explanation:

Your equation is weird. The position equation for this situation is

[tex]s(t)=-4.9t^2+15t+7[/tex] and set it equal to 0 to solve for the time it takes to hit the ground. Those times come out to be

t = 3.47 sec and t = -.411 sec. But since time can never be negative, our time is 3.47 seconds

(What is that -52?)

Answer:

33km

Step-by-step explanation:

Let the distance traveled by bus be x, then distance traveled by train would be 2x

Therefore,

5 + x + 2x = 104

5 + 3x = 104

3x = 104 - 5

3x = 99

x = 33

Answer:

[tex]{ \tt{2x + 4y = 8 - - - (a)}} \\ { \tt{x = 3y - 6 - - - (b)}} [/tex]

Substitute for x in equation (a) :

[tex]{ \tt{2(3y - 6) + 4y = 8}} \\ { \tt{6y - 12 + 4y = 8}} \\ { \tt{10y = 20}} \\ y = 2[/tex]

Substitute for y in equation (b) :

[tex]{ \tt{x = (3 \times 2) - 6}} \\ x = 0[/tex]

2x+4y =8

x=3y-6 ——> x–3y=–6

x–3y = – 6 ] ×(–2) ——> –2x +6y=12

2x+4y=8

–2x+6y =12

__o_o____

0+10y=20 —> 10y= 20 —> y= 20/10 —> y= 2

2x+4y=8 —> 2x + 4(2) = 8 —> 2x + 8=8 —> 2x = 0 —> x=0

(x,y) —> (0,2)

Answer:

8/15

Step-by-step explanation:

Answer:

8/15

Step-by-step explanation:

when you divide 8/15 its 0.53

Answer:

Step-by-step explanation:

From the picture attached,

m∠COB = 90° - m∠BOS

              = 90° - 40°

              = 50°

tan(30°) = [tex]\frac{AC}{OC}[/tex]

[tex]\frac{1}{\sqrt{3}}=\frac{AC}{OC}[/tex]

AC = [tex]\frac{OC}{\sqrt{3}}[/tex]  ------(1)

Similarly, tan(50°) = [tex]\frac{BC}{OC}[/tex]

BC = OC[tan(50°)] -------(2)

Now AC + BC = 30 cm

By substituting the values of AC and BC from equation (1) and (2),

[tex]\frac{OC}{\sqrt{3}}+OC(\text{tan}50)=30[/tex]

(1.769)OC = 30

OC = 16.96

1). cos(30°) = [tex]\frac{OC}{AO}[/tex]

[tex]\frac{\sqrt{3}}{2}= \frac{16.96}{OA}[/tex]

[tex]OA=19.58[/tex] cm

Therefore, distance between the ship and town A is 19.58 cm.

2). cos(50°) = [tex]\frac{OC}{OB}[/tex]

0.6428 = [tex]\frac{16.96}{OB}[/tex]

OB = 26.38 cm

Therefore, distance between the ship and town B is 26.38 cm.

9514 1404 393

Answer:

  x = 22, y = 123

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  (2x +13)° +57° +3x° = 180°

  5x +70 = 180 . . . . . . . . . . . . . collect terms, divde by °

  5x = 110 . . . . . . . . . . . subtract 70

  x = 22 . . . . . . . . divide by 5

__

Angles in a linear pair are supplementary.

  y° + 57° = 180°

  y = 123 . . . . . . . . divide by °, subtract 57

The number of new professors needed to hire to keep the ratio of students and professors the same is 16.66  professors.

Given,

A small college has 1200 students and 80 professors.

The college is planning to increase enrollment to 1450 students next year.

We need to find how many new professors should be hired to keep the

ratio of students to professors the same.

If the two ratios are the same then we called it that they are in proportion.

Example:

4/6 = 10/15

2/3 = 2/3

Find the ratio between the students and professors before the increase in enrollment.

= Number of students / Number of professors

= 1200 / 80

Dividing by 8

= 150 / 10

= 15 / 1

This means one professor for 15 students.

Find the number of students after the increase in enrollment.

= 1450

Find the number of new students enrolled.

= 1450 - 1200

= 250

Since the ratio between the students and professor is 15 students for one professor.

For 250 new students, the number of new professors we need is:

= 250 ÷ 15

= 16.66

This means we need around 16.66 new professors.

Thus the number of new professors needed to hire to keep the ratio of students and professors the same is 16.66 professors.

Learn more about finding the number of students in a college with students and professors relation is given here:

https://brainly.com/question/4773301

#SPJ2

Answer:

the answer is 86°

Step-by-step explanation:

look at the photo

Answer:

B. -21.012÷ -3.4

its yr correct ans.

hope it helps

Pentagon has sum of 540°

Answer:

Step-by-step explanation:

[tex]30\% \: \: as \: fraction[/tex]

Answer:

Step-by-step explanation:

- joonie

9514 1404 393

Answer:

  6/20, 3:5, 50/100 are all less than 8/10

Step-by-step explanation:

It can help to give all the ratios a common denominator. (We'll use 100, and fudge the last one a bit.)

  8/10 = 80/100 . . . . our reference value

__

  6/20 = 30/100 . . . less than 8/10

  3/5 = 60/100 . . . . less than 8/10

  50/100 . . . . . . . . . less than 8/10

  13/15 ≈ 86.7/100 . . . more than 8/10

Answer:

C. -1.5 < -0.5

Step-by-step explanation:

On a number line, the farther a number is to the right away from 0, the greater the number. While the farther it is from 0 to the left, the smaller it is.

Thus, the out of the options given, the only inequality given that is true is:

-1.5 < -0.5

This is because, -1.5 on the numberline is farther away to the left from 0 than -0.5. therefore, -1.5 is lesser than -0.5.

Answer:

Step-by-step explanation:

Arrival rate = ∧ = 2.2 customers per hour  

Service rate = u = 5 customers per hour  

1. Probability that one customer is receiving a haircut and one customer is waiting  

P(2 customers)=(∧/u)^2 * (1-∧/u)=(2.2/5)^2 * (1-2.2/5)=0.1936*0.56= 0.108416

2. Probability that one customer is receiving a haircut and two customers are waiting  

P(3 customers)= (∧/u)^3 * (1-∧/u)=(2.2/5)^3 * (1-2.2/5)= 0.085184  

* 0.56= 0.04770304

3. Probability that more than two customers are waiting  

P(more than 3 customers)=1- P(less than 3 customers) =  

1- [P(0)+P(1)+P(2)+P(3)]=  

= 1- [(1-2.2/5) +2.2/5*(1- 2.2/5) + 0.108416+0.04770304]=1-0.9625=0.0375

Answer:

Step-by-step explanation:

[tex]f(x) = \frac{4}{x}\\\\f(a) = \frac{4}{a}\\\\f(a+h) = \frac{4}{a+h}\\\\\frac{f(a+h) - f(a)}{h} = \frac{\frac{4}{a+h} - \frac{4}{a}}{h}[/tex]

                [tex]=\frac{\frac{4(a)}{(a+h)a} - \frac{4(a+h)}{a(a+h)}}{h}\\\\=\frac{\frac{4a - 4a - 4h}{a(a+h)}}{h}\\\\=\frac{\frac{ - 4h}{a(a+h)}}{h}\\\\= \frac{-4h}{a(a+h) \times h}\\\\= -\frac{4}{a(a+h)}\\\\[/tex]

Answer:

1st blank=[tex]y_{1}[/tex]

2nd blank=[tex]x_{1}[/tex]

3rd blank= [tex]y_{2}[/tex]

3*27=81

so 1*[tex]y_{1}[/tex]=81

hence [tex]y_{1}[/tex]=81

9* [tex]x_{1}[/tex]= 81

[tex]x_{1}[/tex]=9

27*[tex]y_{2}[/tex]=81

[tex]y_{2}[/tex]=3

Thus solved.

Hope this helps.

Please mark me as brainliest.

Answer:

Amount should be reported in investing activities = $173,000

Step-by-step explanation:

Given:

Amount of land costing = $140,000

Sold amount of land = $173,000

Find:

Amount should be reported in investing activities

Computation:

Amount should be reported in investing activities = $173,000

The cash flow statement shows how much money is coming in and going out. The whole amount of cash received, which is 173,000 dollars, will be recorded as proceeds from the sale of land in the investment activity. As a result, the right answer is 173,000.

An equation can be defined as a mathematical statement in which two expressions are set equal to each other. In simple words, equations mean equality i.e. the equal sign. Since equations are all about “equating one quantity with another”,they are simply known as equation

Answer:

In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. ... For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

Answer:

[tex]\mu =2.16[/tex] --- Mean

[tex]\sigma^2 = 1.4944[/tex] -- Variance

[tex]\sigma = 1.222[/tex] --- Standard deviation

Step-by-step explanation:

Given

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.12} & {0.2} & {0.2} & {0.36} & {0.12} \ \end{array}[/tex]

Solving (a): The population mean

This is calculated as:

[tex]\mu = \sum x * P(x)[/tex]

So, we have:

[tex]\mu =0*0.12 + 1 * 0.2 + 2 * 0.2 + 3 * 0.36 + 4 * 0.12[/tex]

[tex]\mu =2.16[/tex]

Solving (b): The population variance

First, calculate:

[tex]E(x^2)[/tex] using:

[tex]E(x^2) = \sum x^2 * P(x)[/tex]

So, we have:

[tex]E(x^2) = 0^2*0.12 + 1^2 * 0.2 + 2^2 * 0.2 + 3^2 * 0.36 + 4^2 * 0.12[/tex]

[tex]E(x^2) =6.160[/tex]

So, the population variance is:

[tex]\sigma^2 = E(x^2) - \mu^2[/tex]

[tex]\sigma^2 = 6.16 - 2.160^2[/tex]

[tex]\sigma^2 = 6.160 - 4.6656[/tex]

[tex]\sigma^2 = 1.4944[/tex]

Solving (c): The population standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\sigma^2}[/tex]

[tex]\sigma = \sqrt{1.4944}[/tex]

[tex]\sigma = 1.222[/tex]