Which of these can be mined from earth and used as an energy source?

A.Get rid of the waste and extra fluid

B.Ureters

C.Coal

D.Bladder​

Answers

Answer 1

coal

Which of these can be mined from earth and used as an energy source?

A.Get rid of the waste and extra fluid

B.Ureters

C.Coal

D.Bladder

ans is coal


Related Questions

6. How many meters are in 0.00253 kilometers?

Answers

Answer:

2.53 kilometers

As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9 mol/l). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7 mol/l).
1. Compute the total concentration of [D1]tot that is needed to bind 90% of the HIV-RT at the given concentration [E]tot. Provide your answer as a numerical expression with 3 significant figures in the unit mol/l. You do NOT have to consider competition betwwen the drugs D1 and D2! They are administered separately.
2. Compute the total concentration of [D2]tot that is needed to bind 90% of the HIV-RT at the given concentration [E]tot. Provide your answer as a numerical expression with 3 significant figures in the unit mol/l.You do NOT have to consider competition betwwen the drugs D1 and D2! They are administered separately.

Answers

Answer:

C)[D]/[ED] = 5.20

D)[D]/[ED] = 5.20

E)[D']_T = 1.495* 10 ^-7 M

F)[D'] / [ED']  = 0.0579

Explanation:

E = 250 nM =2.5* 10 ^-7 mol/L , T=298.15 K

Dissociation constant of K_D = 1.3 μM (1.3 *10 ^-6 M)

E + D ⇄ ED → K_a = [ED] / [D][E]   (association constant)

ED ⇄ E + D → K_D = [E][D] / [ED]  (dissociation constant)

C)

[E] =2.5*10^-7 mol/L

K_D = 1.3* 10^-6 M

K_D = [E][D] / [ED] → [D]/[ED] = K_D / [E]

= [D]/[ED] = 1.3* 10 ^-6 / 2.5 *10^-7

= 13/25 * 10

=130/25 = 5.20

[D]/[ED] = 5.20

D)

ΔG =RTln Kd

ΔG_2 for E and D = 1.987 * 298.15 * ln 1.3*10^-6

ΔG_2 592.454 * [ln 1.3 +ln 10^-6]

ΔG_1 = 592.424 [0.2623 - 13.8155]

ΔG_2 = -592.424 * 13.553

ΔG_1 = -8184.633 cal/ mol

ΔG_1 = -8184.633  * 4.18 J/mol = -34244.508 J?mol

ΔG_1 = -34.245 KL/mol

so, ΔG_2 = ΔG_1 - 10.5 KJ/mol

ΔG_2 = -34.245 - 10.5

ΔG_2 = -44.745KJ / mol

ΔG_2 =RT ln K_D

-44.745 *10^3

=8.314 *298.15 lnK_D

lnK_D' = - 44745 / 2478.81 g

ln K_D' = -18.051

K_D' = -18.051

K_D' = e^-18.051

[D]/[ED] = 5.20

E)

[E] = 2.5* 10 ^-7 mol/ L = a

K_D' = [E][D] / [ED']                                  E +D' → ED'

K_D' = a/2(x-(a/2) / (a/2)

KD' = x - a/2

=2.447 *10^-8 = (2.5/2) * 10^-7

x=2.447 * 10^-8 + 1.25 * 10^-7

x = 2.447 *10^-8 + 1.25 * 10 ^-7

x= 10^-7 [1.25 + 0.2447]

x = 1.4947 * 10^-7

[D']_T = 1.495* 10 ^-7 M

F)

K_D' = [E][D'] / [ED']

[D'] / [ED'] = KD' / [E]

[D'] / [ED'] = 1.447 *10^-8 / 2.5* 10^-7

[D'] / [ED'] = 0.5788 * 10^-1

[D'] / [ED']  = 0.0579

Explanation:

...

89. The element bromine at room temperature is a liquid with a
density of 3.12 g/mL. Calculate the mass of 125 mL of bro-
mine. What volume does 85.0 g of bromine occupy?

Answers

The mass of 125 mL of bromine and the volume occupied by 85 g of bromine are:  

1. The mass of bromine is 390 g. 2. The volume of bromine is 27.24 mL.

Density is simply defined as the mass of an object per unit volume of the object. It can be expressed mathematically as

[tex]Density = \frac{mass}{volume }[/tex]

1. Determination of the mass of bromine

Density = 3.12 g/mL

Volume = 125 mL

Mass =?

[tex]Density = \frac{mass}{volume} \\\\3.12 = \frac{mass}{125}[/tex]

Cross multiply

Mass = 3.12 × 125

Mass = 390 g

Therefore, the mass of bromine is 390 g

2. Determination of the volume of bromine

Density = 3.12 g/mL

Mass = 85 g

Volume =?

[tex]Density = \frac{mass}{volume } \\\\3.12 = \frac{85}{volume }[/tex]

Cross multiply

3.12 × Volume = 85

Divide both side by 3.12

[tex]Volume = \frac{85}{3.12}\\\\[/tex]

Volume = 27.24 mL

Therefore, the Volume of bromine is 27.24 mL

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Using the ruler, what is the value of A considering significant
figures?

Answers

Answer:

13.7 cm

Explanation:

If the number is between two whole numbers then that means it is going to be a decimal, how to determine the decimal is by how many ticks/lines are between it, so if you count from 13 cm and count each line as 1 you get to the number 7 and since that number is between the whole number it becomes 13.7

1. Distinguish between a mixture and a pure substance. ​

Answers

Answer:

1)Mixture is the combination of substance

2)There are two types of mixture such as heterogeneous mixture and homogeneous mixture

3)foreg=Salt solution ,sedimentation

Pure substance

1)Pure substances are also called elements

2)They are made up of small atoms

3)for eg= oxygen,Venadium ,Iron,Oxygen

Hehe someone help I have put down heat but I think there is another

Answers

Answer:

chemical potential enery

Mark brainliest

A popular car has a gas tank that holds a maximum of 14.5 gallons of fuel. What is
the size of the tank in liters ?

Answers

Answer:

54.883, so rougly about 54.9 liters.

Explanation:

To convert gallons to liters, multiply the amount of gallons by 3.785.

14.5 * 3.785 = 54.883

Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values ​​and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

[tex]D=\frac{CxB}{A}[/tex]

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

[tex]D=\frac{14.5 gallonsx3.785 liters}{1 gallon}[/tex]

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

Learn more with this example:

https://brainly.com/question/17839792?referrer=searchResultshttps://brainly.com/question/14586541?referrer=searchResults

Arrange the following aqueous solutions in order of increasing boiling points.
0.050 m Mg(NO 3) 2; 0.100 m ethanol; 0.090 m NaCl
a. Mg(NO3) < NaCl < ethanol
b. ethanol < Mg(NO3)2 < NaCl
c. ethanol < NaCl < Mg(NO3)2
d. NaCl < ethanol < Mg(NO3)2
e. Mg(NO3)2 < ethanol < NaCl

Answers

Answer:

The correct choice is option b. ethanol < Mg(NO3)2 < NaCl

Explanation:

Ethanol = 0.100 m

Mg(NO3)2 = 0.15 m

NaCl = 0.18 m

The molar concentration of NaCl is the highest, which is why its boiling point will be the highest, too.

What is the Molality of a solution prepared by dissolving 84.7 g of KMnO4 (potassium permanganate, an oxidizing agent) in 165 g of water?
a) 0.513 m
b) 11.3 m
c) 0.308 m
d) 3.25 m
e) 0.958 m

Answers

your answer is d 3.25

What is an atomic number

Answers

Answer:

the number of protons is called the atomic number

hope it helps you buddy

Answer: number of protons in an atom

Explanation:

Which of the following are considered elements:

Answers

Answer:

considered as element

Helium He

This picture shows students working in a
chemistry laboratory. What could they do to make
their lab safer?
Label the test tubes and plastic cups.
Move the fire extinguisher closer to their
table.
Wear chemical protective gloves.
Reduce the clutter on the table.
Stand at the table instead of sitting. Tie long hair back.
DONE

Answers

Answer:

yes it is true they apply necessary safety measures

Answer: Label the test tubes, wear chemical protective gloves, tie long hair back

Explanation:

Just got it wrong

Solid calcium oxide and gaseous water are produced by the decomposition of solid calcium oxide hydroxide. Write a balanced chemical equation for this reaction.​

Answers

[tex]\boxed{\sf {Ca(OH)_2(s)\atop Calcium\:Hydroxide}\longrightarrow {CaO(s)\atop Calcium\;oxide}+{H_2O(g)\atop water}}[/tex]

On reactant side

Hydrogen= 2atomsOxygen=2atomsCalcium=1atom

On product side

Hydrogen=Oxygen=2atomsCalcium=1atom.

hence balanced.

Which term best describes the important pieces of information that scientists gather and record during an experiment?
conclusions
data
research
supplies

Answers

Answer:

conclusions i think i am not confirmed

Answer:

b-data

Explanation:

right on the unit test review on edge

brainliest???

20,000 $ give a way but answer this first
Plz




12.Write the basis of naming of the following elements. 1.Neptunium,2.Mendelevium,​

Answers

Answer:juhygjdkeExplanation:

Mendelevium is named for Dmitri Mendeleev who produced one of the first periodic tables.

Abelson first found neptunium in 1940 after uranium had been bombarded by neutrons from the cyclotron at Berkeley, California. ... The element was named after the planet Neptune, which is the first planet beyond Uranus.

Answer in explanation

Explanation:

neptunium was named after the discovery of the planet neptune in september 23 1846

mendelevium was named as dimitri mendeleev

13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂​

Answers

Answer:

A= 15 atoms B= 3

Explanation:

5 x 2 + 5 x 1

3 + 2 x 1

13. Find the total number of atoms present in the following molecules.
a. 5 H₂O
b. Zn Cl₂​

Answers

Answer:

zxcdfzdg

Explanation:

zszghzd

how many grams are in one mole of CH3CO2H ?

Answers

Answer: 60.2g

Explanation:

One mole acetic acid weighs 60.2g

A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times and collects the following data: 40.220gmol, 40.654gmol, 40.314gmol, 40.165gmol, and 40.554gmol. What is the relative standard deviation (RSD) for this set of data?

Answers

The relative standard deviation for the set of data obtained by the student is 0.470%

The formula for calculating the relative standard deviation is given below as:

Relative standard deviation (RSD) = (S * 100)/x

where S stands for the standard deviation and x is the mean of the data set.

The following are the steps to calculate to determine the relative standard deviation using the given formula:

Step 1: Calculate the mean of the numbers in the data set.

mean, x = sum of numbers / number of numbers

(40.220 + 40.654 + 40.314 + 40.165 + 40.554)/5

mean = 40.381 g/mol

Step 2: Subtract the mean from each number in the data to determine the deviation for each number and then square the deviations.

(40.220 - 40.381)² = 0.0259

(40.654 - 40.381)² = 0.0745

(40.314 - 40.381)² = 0.00449

(40.165 - 40.381)² = 0.0466

(40.554 -40.381)² = 0.0299

Step 3: Sum the squared deviations.

0.0259 + 0.0745 + 0.00449 + 0.0466 + 0.0299 = 0.181

Step 4: Determine the variance by dividing the sum of the squared deviations by the total number of values.

Variance = 0.181/5 = 0.0362

Step 6: Determine the standard deviation of the data by taking square root of the variance.

Standard deviation, S = √0.0362 = 0.190

Step 7: Determine the relative standard deviation by inserting the values in the formula, (RSD) = (S * 100)/x

RSD = (0.190 * 100)/40.381

RSD = 0.470%

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Answer
Choice A
Answer
Choice B
Answer
Choice C
Question
A scientist hypothesizes that a new medication can reduce
the chances of catching a cold Which of these would most
likely be the dependent variable in a study involving this
medication?
//
The participants
who do not receive
the medication
Color PURPLE
The number of
participants who
catch a cold
Color YELLOW
The age of the
participants
Color GRAY
Tt remains the
T+ is purposely
It is used for

Answers

Answer:

what is the question????

what's the basic oxide​

Answers

Answer:

Basic oxides are oxides that show basic properties in opposition to acidic oxides and that either react with water to form a base; or react with an acid to form a salt and water which are called neutralization reactions.

Explanation:

Mark me as brainiliest

Explanation:

A basic oxide is an oxide that shows basic properties in opposition to acidic oxides and that either ⁕reacts with water to form a base; or ⁕reacts with an acid to form a salt.

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