which one ?
it says i need 20 characters so i’m just typing this

Answer:

J.

[tex]{ \bf{m \angle A}} = { \bf{180 \degree -48 \degree }} \\ { \tt{m \angle A = 132 \degree}}[/tex]

Answer: 19/3

Step-by-step explanation:

[tex]4x+3-x-5=30-3x\\\\3x-8=30-3x\\\\6x-8=30\\\\6x=38\\\\x=\frac{19}{3}[/tex]

or, - 12= - 5x-5-15

or, - 12= - 5x-20

or, - 12+20= - 5x

or, 8= - 5x

or, x= 8÷-5

Also,

F(x)= - 5(x+1+3)

or, f(8÷-5)= - 5(8÷-5+1+3)

= - 5(8-5-15÷-5)

= - 5×-12÷-5

= - 12 #

Answer:

18.29

Step-by-step explanation:

32000 ÷ 35 ÷ 50 = 18.2857143

1.4

2.8

3.7 by 10

*Others do by your self*

Step-by-step explanation:

1. 3×4/3= 4

2.⅖×20=8

3.6/5×7/18=7/15

4.10/7×9/5=18/7= 2 4/7. Mixed Fraction

5.4/15×25/8=5/6

6.6×¾= 9/2= 4 1/2. Mixed Fraction

Answer:

Since, the given solution is (2, 14). Therefore, 7x−y=0. Similarly, another equation can be−x+y=−2+14=12. Similarly, another equation can be−2x−y=−2(2)−14=18.

Answer:

This is the expression:

4*x+4*9

Respuesta:

1,4 kilometros

Explicación paso a paso:

Dado que :

Distancia que separa a Sandra y José en el mapa = 7cm

Dibujo a escala = 1: 20.000; Esto se puede interpretar en el sentido de que 1 cm en el mapa equivale a 20.000 cm en el suelo.

Por tanto, una distancia de 7 cm en el mapa será:

20.000 * 7 = 140.000 cm en el suelo = distancia real

Por lo tanto, la distancia real = 140.000 cm.

Recordar :

1 cm = 10 ^ -5 km

140000 cm = 1.4 kilometros

Por lo tanto, la distancia real entre Sandra y José es de 1,4 km.

Answer:

(x+3)^2=5

Step-by-step explanation:

x^2-4x+4=2x

x^2-6x+4=0

x^2-6x+9-5=0

(x-3)^2-5=0

(x-3)^2=5

Answer:

(x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Step-by-step explanation:

x² - 5 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - 5

= x² - ([tex]\sqrt{5}[/tex] )²

= (x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Answer:

20km is in 12.5miles

Step-by-step explanation:

5miles= 8km

12.5miles=xkm

12.5÷5miles=2.5miles

2.5miles/km

2.5×8km=20km

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as [tex]x + 2y\geq 1200[/tex].​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are [tex]\$600[/tex] a term.

So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.

The fees for a boarding student are [tex]\$1200[/tex] a term.

The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.

Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:

[tex]\text{Total fees}=600x+1200y[/tex]

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

[tex]600x+1200y\geq 720000[/tex]

[tex]600(x+2y)\geq 720000[/tex]

Divide both sides by 600.

[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]

[tex]x+2y\geq 1200[/tex]

Hence proved.

Answer:

I only have the answer for B

Step-by-step explanation:

This is the answer: 1st blank: 7y

2nd blank: 9

3rd blank: 42xy

Answer:

the area is 279 mm squared

Step-by-step explanation:

Answer:

dssadsasdsa

Step-by-step explanation:

ignore this need points for alt

Answer:

I think 3 but I am not pretty sure man .

Bonjour,

x est un nombre d'ordinateurs: il est donc un naturel (x € N)

y is the pay cost : y=3*x ==> y€ 3N ⊂ N

Answer last reply : 4.

Answer:

9

Step-by-step explanation:

f(2)=(2+1)^2

(3)^2

(9)

Answer:

5.8

Step-by-step explanation:

Y e s .

Using the Distance formula and all.

Answer:

A.

Step-by-step explanation:

4y = 12x + 16

3x = y - 4

=>

y = 3x + 4

using that in the first equation

4(3x+4) = 12x + 16

12x + 16 = 12x + 16

=> both lines/equations are identical, so they have infinitely many solutions.

Hi!

y = ax + b

y = 14x + 2 → a = 14 ∧ b = 2

Parallel lines have the same slope factor (a) so line parallel to the line with the equation y = 14x + 2 will be y = 14x - 12

Answer:

[tex](13 + 29 - 2) \div 2 \\ (42 -2 ) \div 2 \\ 40 \div 2 \\ = 20[/tex]

Answer:

hope it helps.

Answer:

A. 2a

Step-by-step explanation:

imagine an imaginary 1 in front of the a

3a + 7 – 1a – 7

subtract numbers without variables

3a + 7 – a – 7

3a-1a

subtract 1a from 3a

2a

Answer:

A. 2a

Step-by-step explanation:

3a + 7 - a + 7

= 3a - a + 7 - 7

= 2a + 0

= 2a

Answer:

It has to be...

Step-by-step explanation:

$55*x because that will be the total

Answer:

70°

Step-by-step explanation:

(180-40)/2

= 140/2

= 70

Answered by GAUTHMATH

Answer: 6

Step-by-step explanation: 6 is a median

Hey there!

To find your mean you have to put the numbers from descending (least/decreasing) to ascending (greater/increasing) order

Median is also understood as the “middle number”

2, 8, 6, 10, 4, 12​

= 2, 4, 6, 8, 10, 12

Based on that information, you have in your new data set you have 2 pairs in the middle (6 & 8), so you’ll have to total/average of the number. We have to DIVIDE them by 2 because it’s 2 numbers

6 ends the descending set and 8 starts the ascending set

Median = 6 + 8 / 2

6 + 8 = 14

= 14/2

= 7

Answer: therefore your MEDIAN is most likely 7

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

=x4y2z2−2x3y3z+2x3yz3+x2y4−4x2y2z2+x2z4+2xy3z−2xyz3+y2z2

Make me brainliest

Answer:

x2y-x2z-xy2+xz2+y2z-yz2

step by step

step.1

Equation at the end of step 1:(((x2)•(y-z)(+((y2)•(z-x)))+z2•(x-y)

step2

Equation at the end of step2

(((x2)•(yz))+yz•(z-x))+z2•(x-y)

step.3

equation at the end of step 3.

(x2•(y-z)+y2•(z-x))+z2•(x-y)

step4

trying to factor by pulling out:

factoring: x2y-x2z-xy2+xz2+y2z-yz2

thought fully split the expression at hand into groups,each group having two terms:

group1: y2z-yz2

group 2: x2y-x2z

group 3: xz2-yz2

pull out from each groups separately:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:(x-y)•(z2)

looking for common sub-expressions:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:( x-y)•(z2)

bad news !! factoring by pulling out fails:

The groups have no common factor and cannot be added up to form a multiplication.

final result:

x2y-x2z-xy2+xz2+y2z-yz2