Which points have an x value less than zero? (last answer choice says (D,J,E)​

Answer:

Step-by-step explanation:

There are a couple of ways you could solve this problem. B is one of them.

The correct answer is going to be Small hypotenuse / Large hypotenuse = tree / building height

Let the tree equal x

100/220 = x / 176           Multiply both sides by 176

100 * 176 / 220 = x

x = 80

Notice that 80 is almost 1/2 of 176 so the answer should be right since 100 is nearly 1/2 of 220

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Explanation:

He answered 5/7 of the 35 short-answer questions correctly. So he got (5/7)*35 = 25 of those questions correct. At 2 marks each for these questions, he earned 25*2 = 50 points from this group alone.

There are 35 short-answer questions and 15 long-answer questions. That's 35+15 = 50 questions total.

We're told that he answered 60% of all the questions correctly. So he answered 0.60*50 = 30 questions correctly.

Earlier we found that he answered 25 short-answer questions, which must mean he got 30-25 = 5 long-answer questions done correctly. At 4 marks a piece, Keith earns 5*4 = 20 points in this group.

So overall, he earned 50+20 = 70 points from both types of questions.

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If he got all answers correct, then he would earn 35*2 = 70 points from the short-answer questions and 15*4 = 60 points from the long-answer questions. That's a total of 70+60 = 130 points to get a perfect score.

The ratio of his score to the perfect score is 70:130 which reduces to 7:13 when dividing both parts by the GCF 10.

9514 1404 393

Answer:

  70/130 . . . . reduces to 7/13

Step-by-step explanation:

The problem statement describes 2 kinds of quiz questions, and different relations regarding the numbers of questions answered correctly. The problem asks for the number of marks Keith had relative to the total number of marks.

This means you need to find Keith's marks and the available marks for each question type (4 numbers).

Because of the way the problem tells you the number of long-answer questions answered, additional computations are required to find the total number of questions Keith answered and the number of short-answer questions Keith answered. (The difference of these is the number of long-answer questions answered.) That's 3 more computations.

You have to keep in mind the purpose of each computation and how it fits in to the final result. This is why we label the intermediate results.

Short Answer Marks

There were 35 short-answer questions for 2 marks each. That's a total of ...

  (35)(2) = 70 . . . . marks for all short-answer questions

Keith got 5/7 of those, so got ...

  (5/7)×70 = 50 . . . . Keith's marks for short-answer questions.

__

Long Answer Marks

There were 15 long-answer questions for 4 marks each. That's a total of ...

  (15)(4) = 60 . . . . marks for all long-answer questions

The total number of questions on the quiz was 35 +15 = 50. Keith answered 60% of them, so answered ...

  0.60×50 = 30 . . . . total number of questions Keith answered

We know Keith answered (5/7)(35) = 25 short-answer questions, so must have answered 30-25 = 5 long-answer questions. His marks for those were ...

  (5)(4) = 20 . . . . Keith's marks for long-answer questions

__

Total Marks

Then the total number of marks for all answers on the quiz is ...

  short marks + long marks = 70 +60 = 130 . . . available marks

And Keith's overall score was ...

  (Keith's short marks + Keith's long marks)/(available marks)

  = (50 +20)/130 = 70/130 . . . . Keith's score ratio for the quiz

Given:

The slope of a line is [tex]-\dfrac{3}{4}[/tex].

To find:

The lines in the options are parallel, perpendicular or neither parallel nor perpendicular to the given line.

Solution:

We know that the slopes of parallel lines are equal.

The slope of line Q and the slope of given line are same, i.e., [tex]-\dfrac{3}{4}[/tex]. So, the line Q is parallel to the given line.

The slope of a perpendicular line is the opposite reciprocal of the slope of the line because the product of slopes of two perpendicular lines is -1.

The slope of a line is [tex]-\dfrac{3}{4}[/tex]. It means the slope of the perpendicular line must be [tex]\dfrac{4}{3}[/tex]. So, the line N is perpendicular to the given line.

The slopes of line M and P are neither equal to the slope of the given line nor opposite reciprocal of the slope of the line.

Therefore, the lines M and P are neither parallel nor perpendicular.

Answer:3

Step-by-step explanation:

Just count from -1 to positive 2 the dot doesn’t move

Answer: 0. 92 = 92%

100% = 500

92% = 500 × 92/100 = 460

Step-by-step explanation:

Answer:

a) 1/4

b) 1/6

c) 1/12

Step-by-step explanation:

Let S be the sample space.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

n(s) =12

Events

A: coin with head and die with prime number .

B:coin with head and die with composite number.

C:coin with tail and die with even prime number.

a) A={H2,H3,H5}

n(A) = 3

P(A) =n(A)/n(S)

=3/12

= 1/4

b) B={H4,H6}

n(B)= 2

P(B) = n(B)/n(S)

= 2/12

= 1/6

c) C ={T2}

n(C) = 1

P(C) = n(C)/n(S)

= 1/12

Answer:

B: 0.25 = 1/4

Step-by-step explanation:

Queremos encontrar otra representación del número 0.25

Notar que hay dos decimales luego de la coma, por lo que podemos multiplicar este número y dividir por 100.

0.25 = 0.25*1 = 0.25*(100/100) = (0.25*100)/(100) = 25/100

Ahora tenemos el número escrito como una fracción, la cual debemos simplificar.

25/100

Podemos ver que tanto el numerador como el denominador son multiplos de 5, por lo que podemos dividir ambos por 5:

25/100 = (25/5)/(100/5) = 5/20

Nuevamente, ambos son multiplos de 5, por lo que podemos dividir ambos por 5.

5/20 = (5/5)/(20/5) = 1/4

así tenemos:

0.25 = 25/100 = 5/20 = 1/4

0.25 = 1/4

La opción correcta es B.

Answer:

10

Step-by-step explanation:

First, we need to find the sum of the 15 consecutive numbers. The formula to finding the average of a set of numbers is the sum of the terms divided by the number of terms. So to find the sum, you do 15x15 because the average is 15 and there are 15 numbers. 15x15=225, so you know the sum of the consecutive numbers is 225. Let X be equal to the first consecutive number of the 15 consecutive numbers.

X+(X+1)+(X+2)+(X+3)....+(X+14)=225

=15X+(105)=225

=15X=225-105

=15X=120

=X=8

So the first consecutive number of the 15 is 8. Therefore, the second consecutive number is 9, the third is 10, and so on. The question asks for the average of the first five numbers, which is 8, 9, 10, 11, and 12.

The summation formula is [tex]S=(\alpha_{1}+\alpha_{n})\frac{n}{2\\}[/tex].

[tex]S=(\alpha_{1}+\alpha_{n})\frac{n}{2\\}\\ S=(8+12)\frac{5}{2}\\ S=(20)2.5\\ S=50[/tex]

So the sum of the first five consecutive numbers is 50. Since there are 5 numbers, you do 50÷5=10. Therefore, the answer is 10.

Step-by-step explanation:

p = 2×( l+w)

p = 2×l + 2×w

=> 2×w = p - 2×l

w = (p - 2×l) / 2

w = (11 - (2×2.8))/2

= (11- 5.6)/2

= 5.4 /2

= 2.7 cm

Answer:

f the answer to the question is A

Answer:b

Step-by-step explanation:

Answer:

$9.04 /gal

Step-by-step explanation:

1 gallon = 128 oz

8 * 4.23 oz = 33.84 oz

$2.39 /33.84 oz = .0707 $/oz

 .0707 $/oz * 128 = $9.04 $/gal

Answer:

Step-by-step explanation:

Total amount with Gerald = $32

Cost of fuel per gallon = $2.75

Cost of each bottle of windshield = $3

38 miles per gallon. If Gerard must fill his car with enough fuel to drive 250 miles,

Total gallons of fuel = 250 miles / 38 miles

= 6.5789473684210 gallons

Total cost of fuel = Total gallons of fuel × cost per gallon

= 6.5789473684210 × $2.75

= $18.1

Amount left for windshield = Total amount with Gerald - Total cost of fuel

= $32 - $18.1

= $13.9

what is the maximum number of bottles of windshield washer fluid Gerard can buy?

= Amount left for windshield / Cost of each bottle of windshield

= $13.9 / $3

= 4.6333333333333 bottles

Maximum number of bottles =

4 bottles

Answer:

Students Major

Cheat reporting response

Number of Alcohols taken

Student's Height

Step-by-step explanation:

The Variables are the following:

Categorical variables

1. Major – The student's majors -

Arts & Social Science or STEM

2. Cheat - Response about reporting cheating - Yes or No

Quantitative Variables

3. Alcohol - Number of alcoholic beverages consumed in a typical week

4. Height - Self-reported height (in inches)

Answer:

15/2 that is the answer man

It looks like the equation is

-sin²(x) = cos(2x)

Recall the half-angle identity for sine:

sin²(x) = (1 - cos(2x))/2

Then the equation can be written as

-(1 - cos(2x))/2 = cos(2x)

Solve for cos(2x):

-1/2 + 1/2 cos(2x) = cos(2x)

-1/2 = 1/2 cos(2x)

cos(2x) = -1

On the unit circle, cos(y) = -1 when y = arccos(-1) = π. Since cosine has a period of 2π, more generally we have cos(y) = -1 for y = π + 2nπ where n is any integer. Then

2x = π + 2nπ

x = π/2 + nπ

In the interval [-π, π], you get two solutions x = -π/2 and x = π/2.

Answer: See image and explanation below

Step-by-step explanation:

The problem gives us 6 points to draw into the sketch.

The first and second point gives the domain and range of the sketch. The last 4 points tell us the coordinates.

Let's do the first two points. This tells us that the sketch should not go further (-3,0) and (3,0) of the x-axis, and should not go further (0,0) and (0,4) of the y-axis.

For the last 4 points, we can convert them to coordinates and graph them. The points would be (-2,3), (1,2), (-3,0), (3,0), and (0,4).

After we draw the 5 points listed above onto the graph, we can connect the points.

In the image I attached, the lines are straight, but when you draw it out, you should make your lines more curved.

Explanation:

The probability of picking red is 0.13

The probability of picking orange is 0.20

The probability of picking either of these is 0.13+0.20 = 0.33

So the probability of picking neither of them is 1 - 0.33 = 0.67

There's a 67% of this happening.

Answer:

0.34

Step-by-step explanation:

because the probability of red is 20 and the probability of orange is 14 20 + 14 is 34.

Answer: 5 s

Step-by-step explanation:

Given

Height of the rocket can be modelled as [tex]h=80-16t^2[/tex]

Rocket will land on earth when it's height becomes 0

[tex]\Rightarrow 80t-16t^2=0\\\Rightarrow t(80-16t)=0\\\\\Rightarrow t=0\ \text{or}\ t=\dfrac{80}{16}=5\ s[/tex]

Neglecting 0 value

Thus, rocket remains in air for 5 s.

Answer:

no change in area

Step-by-step explanation:

The original area is

A = 12*5 = 60 ft^2

The new length and width

l = 12 + .25 (12) = 12+3 =15

w = 5 - .2 (5) =5-1 = 4

The new area is

A = l*w =15*4 = 60 ft^2

The area is the same

Answer:

$1,500,000

Step-by-step explanation:

Given

Principal = $1,000,000

Rate = 5%

Time = 10years

Interest = PRT/100

Interest = 1000000*5*10/100

Interest = 100000*5

Interest = $500,000

Amount after 10years =  $1,000,000+ $500,000

Amount after 10years = $1,500,000

Answer:

Answer is in attached image

I hope it help...

Answer:

31.50 mm²

Step-by-step explanation:

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Characteristics of a trapezoid

It has 4 vertices and edges

If both pairs of its opposite sides of a trapezoid are parallel, it becomes a parallelogram

Area of a trapezoid =  1/2 x (sum of the lengths of the parallel sides) x height

1/2 x ( 7.3 + 5.3) x 5 = 31.50 mm²

Answer:

6+2+(32×2)

6+2+(64)

8+64

72

difference between 72 and 28

72-28

=44

add 44 to make the value 28

Answer:

(x, y) = (5,8)

Step-by-step explanation:

Comparing the ordered pairs we get, x+y=13 and 2=2x-y. Solving it we will get, x=5 and y=8

Given:

The recursive formulae.

To find:

The correct explicit formulae for the given recursive formulae.

Solution:

If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:

[tex]f(n)=ar^{n-1}[/tex]

Where, a is the first term and r is the common ratio.

The first recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:

[tex]f(n)=5(3)^{n-1}[/tex]

Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].

If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:

[tex]f(n)=a+(n-1)d[/tex]

Where, a is the first term and d is the common difference.

The second recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:

[tex]f(n)=5+(n-1)5[/tex]

[tex]f(n)=5+5(n-1)[/tex]

Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].

The third recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:

[tex]f(n)=5+(n-1)3[/tex]

[tex]f(n)=5+3(n-1)[/tex]

Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].

Answer:

Equation:  [tex]70=(x+3)x[/tex]

x = -10 or x = 7

x = 7 (width can't be negative)

x + 3 = 10

Step-by-step explanation:

Represent the width of the rectangle by  x.  "The length of a rectangle EXCEEDS the width by 3" means the length is 3 LONGER than the width, so the length is represented by the expression  x + 3.

Area = (length)(width)

70 = (x + 3)x

Multiply out the right side.

[tex]70=x^2+3x\\x^2+3x-70=0[/tex]

Factor the left side.

[tex](x+10)(x-7)=0[/tex]

Each binomial could equal 0, so

[tex]x+10=0 \text{ or }x-7=0\\x=-10\text{ or }x=7[/tex]

The negative solution does not make sense as the width of a rectangle.

x = 7, making the length, x + 3 = 10

Answer:

Pls mark this as brainiest

Step-by-step explanation:

Area of the rectangle = length x breadth

consider 'x' to be width

therefore length = x+3

area = (x+3)*x

Area = 70 square

x = 7

x+3 = 7+3

      = 10

verification

7 x 10

= 70

Answer:

Hello,

Answer B (-5/3,-4/3)

Step-by-step explanation:

I am going to use the substitution 's method.

[tex]\left\{\begin{array}{ccc}x+y&=&-3\\y&=&2x+2\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\x+2x+2&=&-3\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\3x&=&-5\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&2*(-\dfrac{5}{3})+2\\\end {array} \right.\\\\\\\boxed{\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&-\dfrac{4}{3}\\\end {array} \right.\\}[/tex]

Answer:

Side-Side-Side (SSS)

Step-by-step explanation:

Side-Side-Side is a rule used to prove whether a given set of triangles are congruent. The SSS rule states that: If three sides of one triangle are equal to three sides of another triangle, then the triangles are congruent.