Answer:its D
Explanation: but i think u meant to put not in the question but if u did mean to put not then its A
A spring has a spring constant of 120 N/m. How much energy is stored in the spring as it is stretched a distance of 0.20 meter?
Answer:
2.4J
Explanation:
Given parameters:
Spring constant = 120N/m
Extension = 0.2m
Unknown:
Amount of energy = ?
Solution:
The energy stored in this stretched spring is called the elastic potential energy.
It can be derived using the expression below:
Elastic Potential energy = [tex]\frac{1}{2}[/tex] ke²
k is the elastic constant
e is the extension
Insert the parameters;
Elastic potential energy = [tex]\frac{1}{2}[/tex] x 120 x 0.2² = 2.4J
Which stable element is used to determine the age of volcanic rock?
argon
carbon-14
potassium
carbon-12
Answer:
The answer is A
Explanation:
Argon is the stable element that is used to determine the age of volcanic rock as it is found inside of it.
I dont know if the top is correct but the answer is because i just took the test.
The age of volcanic rock is determined by argon-40 by radiometric dating. Hence option A is correct.
What is radiometric dating?Using radioactive isotopes found within an object, radiometric dating may determine how ancient something is, such as a fossil, rock, or piece of wood. By analyzing the ratio of radioactive argon to radioactive potassium within a rock, we can use the potassium-argon dating technique to determine the age of the rock or when it was formed.
The fundamental idea behind radiometric dating is that by comparing an isotope's presence in a sample to its abundance on Earth and its known half-life (rate of decay), you may determine the sample's age. Because many radioactive materials degrade more slowly than others, radiometric dating is useful for determining the age of ancient objects.
Argon-40 is used to determine the age of volcanic rock. Therefore, option A is correct.
Learn more about radiometric dating, here:
https://brainly.com/question/14799339
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Students are asked to design an experiment about Newton’s 2nd Law. One student decides to roll a marble down a ramp into a pile of sand to measure the force impact.
Which variable should she manipulate to best exemplify the relationship explained by this law?
A.She should use a heavier marble, because the marbles will roll at the same rate of acceleration but more mass will produce a larger impact force.
B.She should increase the slope of the ramp by propping it up to higher height, because a steeper ramp will cause a greater rate of acceleration and a larger impact force.
C.She should use a heavier marble, because a bigger marble will accelerate more quickly down the ramp and cause a greater impact force.
D.She should decrease the slope of the ramp, because a ramp with a smaller slope will allow the ball more time to build up speed and cause a greater impact force.
Answer:
A
Explanation:
Trust me I just took it !
the strongly blown ballon gets blasted why?
Answer:
Because of pressure.
Thanks
Explanation:
The pressure bursts out the balloo
PLEASE HELP ME IM TIMED
A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.25my, start subscript, 0, end subscript, equals, 0, point, 25, start text, m, end text on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0\,\text m2.0m2, point, 0, start text, m, end text horizontally until it stops.
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
[tex]Em_{f}[/tex] = K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v = [tex]\sqrt{2gy}[/tex]
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ = [tex]\frac{v^{2} }{2 g x}[/tex]
Let's calculate
μ = [tex]\frac{2.21^{2}}{2\ 9.8\ 2.0}[/tex]
μ = 0.125
A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.
What is the friction coefficient of the horizontal surface?
Answer: 0.125
A car accelerates from rest at a constant acceleration of 25.0 m/s^2. At some point, it then turns off its engine, letting the car decelerate slowly from the force of friction at a constant deceleration of 3 m/s^2 until it is at rest again. The total speed the car moves in this time is 200 meters. What is the minimum time needed for the car to move 200 meters given that it both starts and ends at rest?
Answer:
t = 9.14 s
Explanation:
We first analyze the accelerating motion by applying first equation of motion:
Vf₁ = Vi₁ + a₁t₁
where,
Vf₁ = Final Speed of Car before turning off engine
Vi₁ = Initial Speed of Car = 0 m/s
a₁ = acceleration of car = 25 m/s²
t₁ = time taken in accelerating motion
Therefore,
Vf₁ = 25t₁ ---------- equation (1)
Now, we apply second equation of motion:
s₁ = Vi₁ t₁ + (1/2)a₁t₁²
where,
s₁ = distance covered during accelerating motion
Therefore,
s₁ = (0)t₁ + (1/2)(25)t₁²
s₁ = 12.5 t₁² ----------- equation (2)
Now, we analyze the decelerating motion by applying first equation of motion:
Vf₂ = Vi₂ + a₂t₂
where,
Vf₂ = Final Speed of Car = 0 m/s
Vi₂ = Initial Speed of Car after turning off engine
a₂ = deceleration of car = - 3 m/s²
t₂ = time taken in decelerating motion
Therefore,
Vi₂ = 3t₂ ---------- equation (3)
Now, we apply second equation of motion:
s₂ = Vi₂ t₂ + (1/2)a₂t₂²
where,
s₂ = distance covered during decelerating motion
Therefore,
s₂ = (Vi₂)t₂ + (1/2)(-3)t₂²
s₂ = Vi₂ t₂ - 1.5 t₂²
using equation (3):
s₂ = 3 t₂² - 1.5 t₂²
s₂ = 1.5 t₂² ------------ equation (4)
Now, we know that the Final Velocity of accelerating motion (Vf₁) is equal to the initial velocity of decelerating motion (Vi₂):
Vf₁ = Vi₂
using equation (1) and equation (3):
25 t₁ = 3 t₂
t₁ = 0.12 t₂ ------------ equation (5)
Also, we know that sum of the distances is 200 m:
s₁ + s₂ = 200
using equation (2) and equation (4):
12.5 t₁² + 1.5 t₂² = 200
using equation (5):
12.5 (0.12 t₂²) + 1.5 t₂² = 200
3 t₂² = 200
t₂² = 200/3
t₂ = 8.16 s
substitute this in equation (5):
t₁ = 0.12(8.16 s)
t₁ = 0.97 s
Hence, the minimum time required for this motion is:
t = t₁ + t₂ = 0.97 s + 8.16 s
t = 9.14 s
I WILL GIVE BRAINLYIST
Which of the following types of stars had the smallest initial mass? (10 points)
Group of answer choices
Blue main sequence
Neutron star
Red supergiant
White dwarf
Answer:
White dwarf
Explanation:
Integrated science please help ASAP!...
Answer:
SewageAgricultural pollutionOilRadioactive substanceRiver dumpingMarine dumpingLittering trash Industrial wasteMining activitiesChemical fertilizersExplanation:
I hope this helps
(8th grade HELP)
1. Inertia causes a stationary object to...
a.stay still
b.move
c.have an increased velocity
d.change it’s speed or direction
2. Once an applied force causes an object to start moving, the object keeps moving because....
a.none of the above
b.the force continues to be applied to it
c.no other force is acting on it
d.it has inertia
bold completed over 100m in 9.58
seconds what is his average speed
Answer:
At the Berlin 2009 World Championships, Bolt set a world record time of 9.58 seconds for the 100m race, notching a top speed of 27.8 miles per hour (44.72 kilometers per hour) between meters 60 and 80, with an average speed of 23.5 mph.
Explanation:
The asthenosphere is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. Which is NOT true about the role of the asthenosphere in plate tectonics?
Complete option to the question:
A. The asthenosphere is broken up into large continental- and ocean-sized plates.
B. Convection currents within the asthenosphere push magma upward to create new crust.
C. Heat from deep within Earth is thought to keep the asthenosphere malleable.
D. The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.
Answer: The correct option is A (The asthenosphere is broken up into large continental- and ocean-sized plates.)
Explanation:
Among the components that makes up the earth crust are the lithosphere and the asthenosphere.
The LITHOSPHERE is the outer layer of the earth structure which consists of the upper part of the mantle and the crust.
The ASTHENOSPHERE is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. It is denser and weaker layer of the upper mantle which permits the movement of tectonic plates in the lithosphere.
The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.Heat from deep within Earth is thought to keep the asthenosphere malleable. And the convection currents within the asthenosphere push magma upward to create new crust. But it is not broken up into large continental- and ocean-sized plates.
If a student was spinning a key on a string around her head, the key would fly off in a straight line in one direction if she released the
string. What Law does this is example demonstrate?
A Newton's fourth law of motion
B. Newton's first law of motion
C. Newton's third law of motion
D. Newton's second law of motion
Answer:
B
Explanation:
the external force was applied
How can you double the acceleration of an object if you cannot alter the object’s mass?
plz helpppp
Answer:
If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
Explanation:
you can double the net force
What do scientists hope to learn from missions to visit asteroids?
Answer:
The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.
Explanation:
Hope this helps :)
How can we use magnetic fields to transport objects from one location to another?
A car decelerates uniformly from 54 m/s to 38 m/s in 8.0 seconds. How far does it travel dunng this time?
Answer:
368m
Explanation:
dx=vt
54+38/2=46
46*8=368m
Jason rides his bicycle for 3 hours at a speed to 40 km/h. What distance does he
travel? -
Answer:
120km
Explanation:
why does a thrown football have both potential and kinetic energy?what is the combined energy called?
i will give brainliest to who ever answers this question in a paraghraph
Answer:
The thrown football has Potential or stored Energy, PE, by virtue of its position in the air and the ability for it to fall by itself. The thrown football also has Kinetic Energy, KE, given that the ball is in motion and requires an equal and opposite amount of energy to stop it. Both the PE and the KE are forms of Mechanical Energy, ME and the Mechanical Energy of the football is equal to the sum of its Potential and Kinetic Energy. That is ME = PE + KE
Explanation:
Potential energy, PE, is the energy that is the held or stored energy of a body such that the body is able to do work without the addition of energy from an external source
A thrown football that has an elevation or height above the floor level has the capacity to come back down and bounce on the floor without the presence of assistance at the topmost height of the football. Therefore, the thrown football has potential energy, given to it by the thrower
Kinetic Energy, KE, is the energy possessed by a moving that comes from the motion of the object
Given that the thrown football is in motion, it posses kinetic energy
Therefore, the thrown football possesses both potential energy and kinetic energy which are forms of mechanical energy ME
The combined energy of the football is therefore called the Mechanical Energy ME of the ball which is the sum of the potential and kinetic energies of the football, given as follows;
The Mechanical Energy of the football = The Potential Energy of the football + The Kinetic Energy of the football
∴ ME = PE + KE
What is the mass of a rock that is accelerated to 1.4m/s^2 with a force of 350 N
F=m*a
350N=m*1.4m/s^2
m=350N/1.4m/s^2=250kg
A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 10.0 m/s due north relative to the water. If the river is 325 m wide, how far downstream is the boat when it reaches the north shore?
Answer:
Explanation:
Given that the velocity of the river is 1.50m/s due east.
The velocity of the boat with respect to the river is 10.0 m/s due north .
The width of the river is 325 m.
Note that the velocity of the boat will help in crossing the river.
Hence, speed = distance/time
Speed = 10.0 m/s
Distance = 325 m
Time = ?
10 = 325/time
Time = 325/10
Time = 32.5s
Hence in 32.5s the horizontal distance traveled by boat will be
= 1.50m/s × 32.5s
= 48.75m
Why was basketball invented?
According to the law of universal gravitation, gravity is the force keeping objects in the universe in their relative positions.
true
false
Answer true
Explanation
a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Answer:
Average speed = ( 2V + V1 + V2)/4
Explanation:
Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.
Since the distance is covered at equal intervals of time, and
Speed = distance/time
For the first half distance,
V = distance/t
Cross multiply
Distance = Vt
For the second half distance
(V1 + V2)/2 = distance/t
Distance = t(V1 + V2)/2
The average speed = total distance/ total time.
Average speed = [Vt + t( V1 + V2)/2] ÷ 2t
Average speed = (2Vt + V1t + V2t)/4t
Average speed = t( 2V + V1 + V2)/4t
Time t will cancel out
Average speed = ( 2V + V1 + V2)/4
A 2000 kg minivan runs into a 800 kg car that was at rest at a stop sign and they stick together. If the compact car does not stick to the van but, instead, causes the minivan to come to a complete stop. How fast will the car be going after the collision?
Answer:
v₂ = 2.5 v₁
car leaves at 2.5 times the speed of the minivan
Explanation:
This is an exercise of conservation of the momentum, to solve it we create a system formed by the minivan and the car, therefore during the crash the forces are internal and the momentum is conserved.
Initial instant. Before the crash
p₀ = M v₁+ 0
Final moment. After the crash
[tex]p_{f}[/tex] = M 0 + m v₂
how momentum is conserved
p₀ = p_{f}
M v₁ = m v₂
v₂ = [tex]\frac{M}{m}[/tex] v₁
let's calculate
v₂ = 2000/800 v₁
v₂ = 2.5 v₁
therefore the car leaves at 2.5 times the speed of the minivan
A book that weighs 5 N sits on a table. What force does the table apply to the book?
Answer:
E =F.d =[1/2]mv^2
mad = [1/2]mv^2
d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0
So d = at^2/2
F = ma= 20a= 50 , a=5/2 and t=2
so d = [5/2][2^2]/2=5
Explanation:
Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
The given data in the problem is ;
W is the weight of the book sits on table = 5N
N is the normal force on the book
From the equilibrium equation ;
Weight -Normal force on the book =0
Weight =Normal force on the book
The normal force on the book =5N
Hence the table exerts a force of 5 N on the book in order to be in stable condition.
To learn more about Newton's third law of motion refer to the link;
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Select the correct answer.
Which two factors does the power of a machine depend on?
Α. work and distance
B. force and distance
C. work and time
D. time and distance
Answer: C. work and time
Explanation: hope this helps
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10s. If the airplane is putting out an average force of 5.8810x10^4 N during this time, what is the average friction force exerted on the airplane by the air?
Given :
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.
If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].
To Find :
The average friction force exerted on the airplane by the air.
Solution :
Acceleration is given by :
[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]
Now, force equation is given by :
[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]
Therefore, frictional force exerted in the airplane by the air is 9810 N.
Jack jumped off a diving board and hit the water at 15.68 m/s downward. How long was he falling for before he hit the water?
Answer:
1.6 s
Explanation:
From the question given above, the following data were:
Velocity (v) = 15.68 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
Thus, we can calculate the time taken for Jack to hit the water by using the following formula:
v = gt
15.68 = 9.8 × t
Divide both side by 9.8
t = 15.68 / 9.8
t = 1.6 s
Therefore, it took Jack 1.6 s to hit the water.
Sharon is driving on a straight road. She is driving north, and her speed is
decreasing. If north is the positive direction, which of the following
statements is accurate?
A) Her velocity is positive, and her acceleration is negative.
B) Her velocity is negative, and
her acceleration is negative.
C) Her velocity is negative, and her acceleration is positive.
D) Her velocity is positive, and her acceleration is positive.
Plzz help
Answer:
b
Explanation:
b is the correct answer
Answer:
b. Her velocity is positive, and her acceleration is negative.
Explanation:
