Which statement about the dark nebulae is true? Group of answer choices They can be penetrated only with longer wavelengths such as radio and infrared. They block the vast majority of radio waves from our Galaxy. Hydrogen and helium are the chief absorbing and scattering agents. They can be penetrated only with shorter waves, such as UV and x-ray. Only one is known to exist.

Answers

Answer 1

Answer:

They can be penetrated only with longer wavelengths such as radio and infrared.

Explanation:

A dark nebula can be defined as an interstellar cloud that is so dense as a result of high concentration of gas and dust and as such it obscures the visible wavelengths of light from stars behind it, thus appearing completely opaque (dark patch) in front of a bright emission nebula or in regions having  plenty stars.

Hence, dark nebulae can be penetrated only with longer wavelengths such as radio and infrared light because they cannot be absorbed by the dust layers or particles coated with frozen carbon monoxide and nitrogen residing in the dark nebulae.


Related Questions

A body with an initial velocity of 10m/s has an acceleration of 8m/s^2. Determine graphically the velocity after 5 seconds, & the distance travelled in that time. Verify your answer using the equations of motion.

Answers

Answer:

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

Explanation:

The initial velocity of the body =  m/s

The acceleration of the body = 8 m/s²

The velocity after 5 seconds can be determined graphically and by calculation as follows;

Graphically, we have the data points which can be found by the straight line relation  v = u + a×t,

Where ,

a = The slope = 8 m/s²

u = 10 m/s = The y-intercept

Which gives;

v = 10 + 8 × t

The following data can be calculated for various time t;

Time, t     Velocity , v

0,             10

1,              18

2,             26

3,             34

4,             42

5,             50

6,             58

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

By calculation, we have;

v = u + a×t

Where;

v = The final velocity

u = The initial velocity = 10 m/s

a = The acceleration = 8 m/s²

t = The time = 5 seconds

v = 10 + 5× 8 = 50 m/s.

Which instrument is used to measure the height of a 20 litre jerrican​

Answers

tape measure?

Hope that helped!!! k

instrument is used to measure is Tape measure

Which of the following illustrates an increase in potential energy? Group of answer choices a wind-up toy winding down a person climbs a set of stairs an apple dropping from a tree a firecracker explodes

Answers

Answer:

A person climbs a set of stairs

Explanation:

Potential energy is said to be possessed by an object due to its position. As the height from the ground level increase, the potential energy increases. It is calculated by the below formula as :

P = mgh

Out of the given options, the option that illustrates an increase in potential energy is option (b) i.e. a person climbs a set of stairs. As he steps one stair, its position from ground increases. It means its potential energy increases.

Pls help promise to mark as brainlist

Answers

Answer:

The answers to your questions are given below

Explanation:

A. Definition of momentum.

Momentum of an object can be defined as the product of the mass of the object and its velocity. Mathematically, it expreessed as:

Momentum = mass x Velocity

From the above equation, we can derive the SI unit of momentum as follow:

Mass is measured in Kilogram (Kg)

Velocity is measured in meter per second (ms¯¹).

Momentum = mass x Velocity

Momentum = Kg x ms¯¹

Momentum = Kg•ms¯¹

Therefore, the SI unit of momentum is Kg•ms¯¹.

Bi. Determination of the force of the body from O to A.

Mass (m) = 5 kg

Velocity (v) = 40 ms¯¹

Time (t) = 2 secs.

Force (F) =?

Next, we shall determine the acceleration of the body.

Acceleration (a) = Velocity (v) /Time (t)

a = v /t

Velocity (v) = 40 ms¯¹

Time (t) = 2 secs.

Acceleration (a) =.?

a = v/t

a = 40/2

a = 20 ms¯²

Now, we can obtain the force as follow:

Mass (m) = 5 kg

Acceleration (a) = 20 ms¯²

Force (F) =?

Force (F) = mass (m) x Acceleration (a)

F = ma

F = 5 x 20

F = 100 N

Therefore, the force of the body from O to A is 100 N.

Bii. Determination of the force of the body from B to C.

Mass (m) = 5 kg

Velocity (v) = 40 ms¯¹

Time (t) = 10 – 6 = 4 secs.

Force (F) =?

Next, we shall determine the acceleration of the body.

Acceleration (a) = Velocity (v) /Time (t)

a = v /t

Velocity (v) = 40 ms¯¹

Time (t) = 4 secs.

Acceleration (a) =.?

a = v/t

a = 40/4

a = 10 ms¯²

Now, we can obtain the force as follow:

Mass (m) = 5 kg

Acceleration (a) = 10 ms¯²

Force (F) =?

Force (F) = mass (m) x Acceleration (a)

F = ma

F = 5 x 10

F = 50 N

Therefore, the force of the body from B to C is 50 N.


Explain.
4. State the limitations of our senses to obtain accurate in
formation concerning
our environment.

Answers

Answer:

The limits of our senses are

Limits of Sight

Our vision field of view is 120° sideways and 135° vertically

Angular visual resolution is about an 1/60 of one degree

The presence of blind spots in the eyes

Limits of sound

The hearing range is within 20 - 20,000 Hz and our threshold hearing above 0 to 5 decibel of sound

Limits of taste

We have very limited sense of taste which is partly dependent on our sense of smell with little objectivity in distinguishing tastes

Sense of smell

The establishing of the effectiveness of human sense of smell is gauged on numerous parameters with certain tests being inconsistent, as such, it is difficult to clearly establish the effectiveness of the human sense of smell

In comparison with the sense of smell of other living things such as dogs, the human sense organ is comparatively low

Explanation:

Explain the structure of a clinical thermometer​

Answers

Explanation:

a clinical thermometer is a thermometer used to measure human body temperature. mostade in the 20th century are mercury-in-glass thermometer. they ate accurate and sensitive having a narrow place where the mercury level rises very fast. a kink in the tube stops the mercury level from falling on its own.

hope it helps you

Air contains 78.08% nitrogen, 20.095% oxygen, and 0.93% argon. a sample of air occupies 8 l at 273 k and applies a pressure of 2.45 atm to its container. the sample of air is heated to 550 k, at which time it takes up 11.8 l. what is the partial pressure of nitrogen after the air has been heated

Answers

Answer:

the partial pressure of nitrogen after the air has been heated is 2.61atm

Explanation:

Using combined gas law which is the combination of Boyle's Law and Charles' Law, and it gives The relationship between pressure, volume, and absolute temperature

PV/T= K

P1₁V₁/T₁=P₂V2₂/T₂

P₂=final pressure= ?

P₁= initial pressure=2.45 atm

.T₁= initial temperature= 273k

T₂= final temperature= 550 K,

We can make P₂ subject of the formula then we have

P₂=P₁V₁T₂/T₁T₂

=( 2.45×8×550)/(273×11.8)

P2=3.35atm

Now we can calculate the partial pressure of N₂

N₂= 3.35×(78.08/10)

=2.61atm

Therefore, the partial pressure of nitrogen after the air has been heated is 2.61atm

Communication satellites are often put in a geo-synchronous orbit, meaning they have an orbital period of 24 hours and stay over the same spot above the equator at all times. Given that the Earth has a mass of 5.97 x 1024 kg and a radius of 6.37 x 106 meters, determine the following: a. What is the orbital height of the satellite relative to the surface of the Earth

Answers

Answer:

h = 35857 km

Explanation:

A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.

We are given;

Radius of earth(R) = 6.37 x 10^(6) m

Mass of earth (Me) = 5.97 x 10^(24) kg

Gravitational constant = 6.67 × 10^(-11) m³/kg.s²

The earth has a rotational period of 24 hours per day. This gives in seconds

T = 24 × 60 × 60

T = 86400 s

Let's make the height of the orbit from Earth's surface to be h

Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit

Now, equating the centripetal force with the gravitational force gives us;

mω²(R + h) = G•Me•m/(R + h)²

m will cancel out. Also ω can be written as 2π/T

Thus,we now have;

(R + h) = ∛(G•Me•T²/(4π²))

Plugging in the relevant values, we have;

(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))

(R + h) = 42227 Km

Since R = 6.37 x 10^(6)m = 6370 km

Thus;. h = 42227 - 6370 = 35857 km

A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.9 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.

Answers

Answer:

22.73 m/s or 81.72 kph

Explanation

We can find the combined mass of both cars as

970 kg + 2300 kg = 3270 kg.

Then the normal force of the cars can be calculated as

F(n)= mg

Where g is acceleration due to gravity 9.8m/s^2

3270 kg ×9.8 = 32046 kg*m/s^2.

coefficient of kinetic friction between tires and road to be 0.80 × F(n)

Then the frictional force can be calculated as

= (32046kg*m/s^2 × 0.80 )

= 25636.8 kg*m/s^2

We can now calculate the work done that was used stopping the cars as

Frictional force × distance

(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2

From kinetic energy formula, the combined velocity of the car can be determined

E=0.5 M V²

√(2E/M) = V

√(2*74346.72kg*m^2/s^2 / 3270 kg) = V

V= √ (45.472)

V=6.743293m/s

the momentum of both cars can be determined as

6.743293m/s * 3270 kg

= 22050.57kg*m/s

Now the final momentum of both cars must be equal to the the momentum of

the sports car just prior to the collision. Therefore, the speed of the sports car at impact.

=(22050.57 kg*m/s) / 970 kg = 22.73 m/s

We can convert that to km/h.

22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph

Sound waves move the fastest through which medium?

Answers

Answer:

Sound travels fastest through solids.

Explanation:

This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Sound waves move the fastest through the solid. The speed of the sound wave  in the liquid and gas is low,

What is sound wave?

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Solids transmit sound the fastest. Because the molecules in a solid medium are much closer together than in a liquid or gas, sound waves can move through it much faster.

Hence, sound waves move the fastest through the solid.

To learn more about the sound wave, refer to the link;

https://brainly.com/question/11797560

#SPJ2

with solutions please give with solution
if u give me with solution I will mark in brainlist​

Answers

Answer:

Magnitude of Force : 0.8 N

Explanation:

We know that the velocity of this particle changes from 15ms⁻¹, or in other words 15m / s, to the respective velocity 25m / s over the course of 2.5 seconds. Given this information we can determine the acceleration of the particle,

a = v₁ - v₂ / t = 25 - 15 / 2.5 = 10 / 2.5 = 4m / s²

Knowing the acceleration we can calculate the magnitude of the force using the formula f = ma - Newton's second law of motion,

f = m [tex]*[/tex] a = 200g [tex]*[/tex] 4m / s² = 800 g [tex]*[/tex] m / s²

Remember however that Newtons are in the standard units kg [tex]*[/tex] m / s². Therefore we have to convert 800 g to kg to receive our solution,

800 g = 800 / 1000 kg = 0.8 kg,

Magnitude of Force = 0.8 N ; Solution = Option B

An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux through each turn of the coil at an instant when the current is 3.70 A?

Answers

Answer:

[tex]\phi=1.56\times 10^{-5}\ Wb[/tex]

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

[tex]L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H[/tex]

We have,

[tex]L=\dfrac{N\phi}{I}[/tex], [tex]\phi[/tex] is magnetic flux

[tex]\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb[/tex]

So, the magnetic flux is [tex]1.56\times 10^{-5}\ Wb[/tex].

Answer answer answer it it it

Answers

Answer:

(B) Parachutes

Explanation:

Air resistance works to slow down trains and airplanes, so it isn't desirable.  Air resistance also causes pendulums to slow and stop.

Parachutes need air resistance to slow a person's fall.  So air resistance is desirable here.

Answer:

B i answered it it it

Explanation:

The temperature of air changes from 0 to 10°C while its velocity changes from zero to a final velocity, and its elevation changes from zero to a final elevation. At which values of final air velocity and final elevation will the internal, kinetic, and potential energy changes be equal?

Answers

Answer:

Final velocity = 119.83 m/s

Final elevation = 731.9 m

Explanation:

We are told that temperature of air changes from 0 to 10°C

Thus;

Change in temperature; ΔT = 10 - 0 = 10°C

Also, its velocity changes from zero to a final velocity. Thus;

v1 = 0 m/s

v2 is unknown

Also, its elevation changes from zero to a final elevation.

So, z1 = 0 and z2 is unknown

Now, we want to find v2 and z2 when the internal, kinetic and potential energy are equal.

Thus Equating the formula for both kinetic and internal energy gives;

½m(v2² - v1²) = mc_v•ΔT

m will cancel out and v1 is zero to give;

v2² = 2c_v•ΔT

v2 = √(2c_v•ΔT)

Where c_v is specific heat of constant volume of air with a constant value of 718 J/Kg.K

Thus;

v2 = √(2 × 718 × 10)

v2 = √14360

v2 = 119.83 m/s

To find z2, we will equate potential energy formula to that of the internal energy.

Thus;

mg(z2 - z1) = mc_v•ΔT

m will cancel out and since z1 is zero, then we have;

z2 = (c_v•ΔT)/g

z2 = 718 × 10/9.81

z2 = 731.9 m

A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current is drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?

Answers

Answer:

a) 0.73A

b) 0.23A

c) 2.76V

Explanation:

We need to first resolve the two resistors in series. The resistors in series are

12 Ω and 3 Ω  AND 6 Ω and 3 Ω

For  12 Ω and 3 Ω in series, total effective resistance =  12 Ω + 3 Ω = 15 Ω

For  6 Ω and 3 Ω in series, total effective resistance =  6 Ω + 3 Ω = 9 Ω

Since the equivalent series resistors i.e 15Ω ND 9Ω are connected in parallel, the total effective resistance Rt will be expressed as;

1/Rt = 1/15+1/9

1/Rt = (3+5)/45

1/Rt = 8/45

Rt = 45/8 Ω

a) If a potential difference of 4 V is applied across it, the total current I in the circuit can be derives using the ohms law.

According to the law E = IRt

Given E = 4V, Rt = 45/8

I = E/Rt

I = 4/(45/8)

I = 4 * 8/45

I = 32/45

I = 0.73A

Hence, the current drawn from the battery is 0.73A

b) Before we can calculate the current in the 12Ω resistor, we need to calculate the current in the equivalent resistance of 15Ω(sum of 12Ω and 3Ω)

Current in the 15Ω resistor = Voltage across the 15Ω resistor/Resistance

Current in the 15Ω resistor = 4/15

Current in the 15Ω resistor = 0.27A

Since the same current flows in a series connected resistors, hence the correct in the 12ohms resistor is also 0.27A.

c) Before we can calculate the pd across the 6ohms resistor, we need to know the voltage across the effective resistance of 9ohms(6ohms+3ohms). The pd across the 9ohm resistance will be the same as the source voltage i.e 4Volts.

We will need to share this 4volts between the 6ohms and the 3ohms using ohms law.

According to the law, V = IR

For the 6ohms resistor, voltage across it will be;

V = (0.73-0.27)×6

V= 0.46×6

V = 2.76Volts.

Hence the voltage across the 6ohms resistor is 2.76V.

An iron ball at 40°C is dropped in a mug containing water at 40°C.
The heat will
(a) flow from iron ball to water.
(b)
not flow from iron ball to water or from water to iron ball
(c)
flow from water to iron ball
(d) increase the temperature of both
10. A wooden spoon is dipped in a cup of ice cream. Its other end
(a) becomes cold by the process of conduction.
(b) becomes cold by the process of convection
(c) becomes cold by the process of radiation.
(d) does not become cold.​

Answers

Answer:

1. option a

2. option d

Explanation:

HOPE IT HELPS YOU

the standard unit of measurement of preasure
2. What is
N/m square or Pascal​

Answers

Answer:

Both are the same.

Explanation:

[tex]pressure= \frac{force}{area} = \frac{f}{a} = \frac{n}{m {}^{2} } [/tex]

The SI unit was named after Bláise Pascal to honor him.

Hope this helps ;) ❤❤❤

A 30-µF capacitor is charged to an unknown potential V and then connected across an initially uncharged 10-uF capacitor. If the final potential difference across the .10-µF capacitor is 20 V, determine V

Answers

Answer:

V = 26.6 volts

Explanation:

Let Initial Potential Difference be V.

Charge (Q) accumulated in 30 mF Capacitor =

Q = C * V

Q= 30 * V

Now, Common Potential after connecting to uncharged 10mF capacitor in parallel = 20 Volt

Total Charge =Total Capacity * Common Potential

30 * V = ( 30 + 10) * 20

V = 26.6 volts

The unknown potential across the 30-µF capacitor is 6.67 V.

The given parameters;

initial capacitance of the capacitor, C = 30 µFunknown potential in the 30 µF capacitor  = V₁potential difference in 10 µF capacitor = 20 V

Since the potential difference between the two capacitors are different, the two capacitors are in series connection.

In series circuit arrangement, the quantity of charge flowing in each capacitor is the same.

[tex]Q_{30\ \mu F} = Q_{10 \ \mu F}[/tex]

[tex]Q_{10 \ \mu F} = CV = 10\times 10^{-6} \times 20 = 0.0002 \ C[/tex]

The potential difference are different and the total potential is given as;

[tex]V_{T} = V_1 + V_2\\\\V_1 = \frac{Q}{C_1} \\\\V_2 = \frac{Q}{C_2} \\\\V_1+V_2 = \frac{Q}{C_1} + \frac{Q}{C_2}\\\\V_1 + V_2 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1 + 20 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1+ 20 = \frac{Q(C_2+ C_1)}{C_1 C_2} \\\\V_1 = \frac{Q(C_2+ C_1)}{C_1 C_2} - 20[/tex]

[tex]V_1 = \frac{0.0002(10\times 10^{-6}\ + \ 30\times 10^{-6})}{(30\times 10^{-6}) (10\times 10^{-6})} - 20\\\\V_1 = \frac{8\times 10^{-9}}{3\times 10^{-10}} - 20\\\\V_1 = 26.67 - 20\\\\V_1 = 6.67 \ V[/tex]

Thus, the unknown potential across the 30-µF capacitor is 6.67 V.

Learn more here:https://brainly.com/question/23899758

ball is thrown upward from a window that is 12 m above the ground.  The ball reaches a maximum height of 4 m above the window before falling all the way down to the ground.  What distance did the ball travel?​

Answers

Answer:

20 m

Explanation:

The ball travels 4 m up, then 16 m down.  It travels a total distance of 20 m.

A negative charge feels a force when stationary in an electric field. moving parallel to an electric field. moving parallel to a magnetic field. moving perpendicular to a magnetic field. stationary in a magnetic field. moving perpendicular to an electric field.

Answers

Answer:

stationary in an electric field.

moving perpendicular to a magnetic field.

moving perpendicular to an electric field.

Explanation:

Negative charge: In physics, the term "negative charge" is defined as a phenomenon that consists of a surplus or different electrons in any field i.e magnetic or electric field.

However, the correct answer in the question above, would be:

"stationary in an electric field".

"moving perpendicular to a magnetic field".

"moving perpendicular to an electric field".

A ship sets out to sail to a point 123 km due north. An unexpected storm blows the ship to a point 112 km due east of its starting point. (a) How far and (b) in what direction (as an angle from due east, where north of east is a positive angle) must it now sail to reach its original destination

Answers

Answer:

Explanation:

We shall represent the point of destination and point of new starting point in vector form .

i and j will represent east and north .

point of destination = 123 j

starting point = 112 i

distance between the two

D = 123 j - 112 i

magnitude of D = √ ( 123² + 112² )

= 166.35 km

Direction of D

Tanθ = -  123 / 112

= - 1.09

θ = 132.54 degree from east in positive angle .

An object is to be dropped from an aeroplane so as to hit a target on the ground. If the aeroplane is travelling horizontally at 80m/s at a height of 2000m, calculate the position of the aeroplane when the object is released​

Answers

Answer:

you live it will be around 23 to 82% angle

Explanation:

just think about yourself going in the high-speed and then jumping and then just think of all know that person just jumping without being going to high speed


9. An object of weight 80kg on earth is taken to a
planet where the acceleration due to the gravity is one-
third of its value on earth. The weight of the object on
the planet is

Answers

Answer:

266. 4

Explanation:

acceleration due to vravity on earth is 10m/s.

One third of it is (1/3)*10

=3.333m/s.

Weight is mass × acceleration

weight= 80kg÷ 3.333m/s

W= 266.4 Newton.

20 pts. What type of forces do not change the motion of an object? Acceleration forces Balanced forces Inertia forces Unbalanced forces

Answers

Answer:

Balanced forces

Explanation:

Answer:

its balance force

Explanation:

A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball of mass 500g is thrown upwards with a velocity of 15m/s. Calculate its momentum at the highest point.

Answers

Explanation:

Hello there!!!

You just need to use simple formula for force and momentum,

F= m.a

and momentum (p)= m.v

where m= mass

v= velocity.

a= acceleration .

And the solutions are in pictures.

Hope it helps..

If an object floats, the volume of the displaced water is equal to the volume of the whole object. True or false?

Answers

Answer:

True

Explanation:

This is in fact what the Archimedes principle states, and what he used in the famous anecdote about finding if  the crown of the King was really made of gold.

Dennis throws a volleyball up in the air. It reaches its maximum height 1.1\, \text s1.1s1, point, 1, start text, s, end text later. We can ignore air resistance. What was the volleyball's velocity at the moment it was tossed into the air?

Answers

Answer:

If max height = 1.1 meters, then initial velocity is 3.28 m/s

If max height is 1.1 feet, then the initial velocity is 5.93  ft/s

Explanation:

Recall the formulas for vertical motion under the acceleration of gravity;

for the vertical velocity of the object we have

[tex]v=v_0-g \,t[/tex]

for the object's vertical displacement we have

[tex]y-y_0=v_0\,t - \frac{g}{2} \,t^2[/tex]

If the maximum height reached by the object is given in meters, we use the value for g in [tex]m/s^2[/tex] which is: [tex]9.8\,\,m/s^2[/tex]

If the maximum height of the object is given in feet, we use the value for g in  [tex]ft/s^2[/tex]  which is : [tex]32\,\,ft/s^2[/tex]

Now, when the ball reaches its maximum height, the ball's velocity is zero, so that allows us to solve for the time (t) the process of reaching the max height takes:

[tex]v=v_0-g \,t\\0=v_0-g \,t\\g\,\,t=v_0\\t=\frac{v_0}{g}[/tex]

and now we use this to express the maximum height in the second equation we typed:

[tex]y-y_0=v_0\,t - \frac{g}{2} \,t^2\\max\,height=v_0\,(\frac{v_0}{g}) - \frac{g}{2} \,(\frac{v_0}{g})^2\\max\,height= \frac{v_0^2}{2\,g}[/tex]

Then if the max height is 1.1 meters, we use the following formula to solve for [tex]v_0[/tex]:

[tex]1.1= \frac{v_0^2}{2\,9.8}\\(9.8)\,(1.1)=v_0^2\\v_0=10.78\\v_0=\sqrt{10.78} \\v_0=3.28\,\,m/s[/tex]

If the max height is 1.1 feet, we use the following formula to solve for [tex]v_0[/tex]:

[tex]1.1= \frac{v_0^2}{2\,32}\\(32)\,(1.1)=v_0^2\\v_0=35.2\\v_0=\sqrt{35.2} \\v_0=5.93\,\,ft/s[/tex]

Answer:

11

Explanation:

for khan academy, this is the answer

given that the amplitude of the scattered light is (1) directly proportional to that of incident light (2) directly propotional to the volume of the scattering dust particles (3)inversely proportional to its distance from the scattering particles and (4) dependent upon the wavelength of the light. show that the intensity of scattered light varies as 1/wavelength^4

Answers

Answer:

The correct answers are 2, 4

Explanation:

The dispersion of light occurs due to the interaction of electromagnetic radiation with matter, let's analyze the phenomenon, when a ray of light reaches a particle is absorbed and subsequently re-emitted in all directions, for radiation of lower wavelength (higher frequency ) the highest absorptions and therefore the missionary also the highest; An example of this is the blue light from the atmosphere, which is the absorption of blue light and its subsequent re-emission

Based on this explanation, the dispersion in gas particles or molecules is proportional to the frequency of the light (inversely proportional to the wavelength) and is also proportional to the number of dispersing particles in the air, that is, to the total volume of the particles. dispersers.

The correct answers are 2 and 4

A 5000 g toy car starts from rest and moves a distance of 300 cm in 3 s under the action of a single constant force. Determine the magnitude of the force? help good answer please

Answers

Answer:

3.33 N

Explanation:

First, find the acceleration.

Given:

Δx = 3 m

v₀ = 0 m/s

t = 3 s

Find: a

Δx = v₀ t + ½ at²

3 m = (0 m/s) (3 s) + ½ a (3 s)²

a = ⅔ m/s²

Use Newton's second law to find the force.

F = ma

F = (5 kg) (⅔ m/s²)

F ≈ 3.33 N

The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one important model is missing. An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle. An image at right with a purple center outlined in black with two concentric black circles around the center, the inner circle having 2 small green balls on it and the outer circle having 8 small green balls on it. Which atomic model is missing from this set? Bohr’s model Dalton’s model Rutherford’s model Thomson’s model

Answers

Answer:

Thomson’s model

Explanation:

Thompson regarded the atom largely as a sphere of positively charged matter in which negative charges were embedded.

This came to be known as the plum pudding model of the atom because it resembles a pudding studded with currants.

This was an early model of the atom and did not survive further experimental scrutiny of the structure of the atom.

Answer:

Thompsons model

Explanation:

i got it right on the quiz

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