3. Which of the following statements best explains the purpose of Mitosis?
A. Mitosis is a cellular process that creates a copy of the cell's DNA.
B. Mitosis is a cellular process that creates new organelles inside of the cell.com
C. Mitosis is a process of cell division which creates two genetically identical daughter cells.
D. Mitosis is a cellular process that doubles the amount of chromosomes in a cell.
Answer:
C
Explanation:
During mitosis, a eukaryotic cell undergoes a carefully coordinated nuclear division that results in the formation of two genetically identical daughter cells.
What are the two arms of chromosome called?
a. Centromere
b. Chromatid
c. Nucleotides
d. Histones
how do you use fossils to see change
Fossils help show use how the earth looked like millions of years ago, Plant fossils show use what the wild life would have ate and the nutrients they had. it also helps show the bone structure of animals helping us create an actually picture of the past.
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How does humus help in plant growth?
Explanation:
Humus gives the soil the ability to absorb and retain moisture. Such soils do not dry out and require significantly less irrigation. Humus provides a reservoir for the plant nutrients available in the soil for balanced plant growth.
Answer:
Humus gives the soil the ability to absorb and retain moisture. Such soils do not dry out and require significantly less irrigation. Humus provides a reservoir for the plant nutrients available in the soil for balanced plant growth.
What is a fishing bed
what factors determine if a species is fit to survive?
Answer: variation, reproduction, and heritability.
Explanation: Genetic variation is an important force in evolution as it allows natural selection to increase or decrease frequency of alleles already in the population. Genetic variation is advantageous to a population because it enables some individuals to adapt to the environment while maintaining the survival of the population.
All species must reproduce to survive. Organisms cannot live forever, so they must reproduce to allow their species to continue to live on. Reproduction is nature's way of allowing a species to survive.
Higher heritability means the trait evolves faster; fewer generations are required for the trait to increase to the same degree as a trait with lower heritability. For this reason, genetic correlation and heritability show how a trait might change from one generation to the next and into the future.
if mammalian cells receive a go-ahead signal at the g1 checkpoint, they will:
If mammalian cells receive a go-ahead signal at the G1 checkpoint, they will complete the cell cycle and divide normally.
What is the Cell Cycle?The cell cycle may be defined as the entire sequence of events happening from the end of one nuclear division to the beginning of the next nuclear division.
There are three major checkpoints in the cell cycle. One at the end of the G1 phase, the second at the end of the G2 phase, and while third is during the M phase.
Therefore, if mammalian cells receive a go-ahead signal at the G1 checkpoint, they will complete the cell cycle and divide normally.
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Processes that add carbon to the atmosphere are called what
Answer:
Combustion
Explanation:
explain how the internal parts of a leaf are adapted for photosynthesis
Explanation:
Leaves have a large surface area so more light hits them. The upper epidermis of the leaf is transparent, allowing light to enter the leaf. The palisade cells contain many chloroplasts which allow light to be converted into energy by the leaf.
how do you propagate trees
Answer:
The simplest method of propagating a tree vegetatively is rooting or taking cuttings. A cutting (usually a piece of stem of the parent plant) is cut off and stuck into soil.
Remove any flowers or fruit on the cutting. Trim the stem to just below where the bottom most leaf meets the stem. On each of the leaves on the stem, cut off half of the leaf. Put the end to be rooted.
What are some geological characteristics of glaciers in Glacier National Park?
Answer:
The minimum size criterion for a glacier is 0 .1 km², or about 25 acres. Below this size, the accumulated ice generally does not move and is stagnant. Many years of snow accumulation compacts the bottom layers of snow into ice. Under the huge weight of the snowpack (usually 100ft/30.5m thick or more), the ice becomes viscous and allows the mass to slide downhill. The appearance of crevasses and cracks attest to a glacier’s movement. Glaciers don't "bulldoze" landscape as much as they melt and re-freeze, plucking material from areas of snow deposition and moving it to other areas, like downhill conveyor belts.
Explanation:
Right on ED2021, good luck!
a section of a dna molecule that controls the thumb is called a
Answer:
gene
Explanation:
Why is it important that mitosis occurs like this
Answer: The cell divides upon these processes during a process known as mitosis. In mitosis, two daughter cells are formed. It is important that each of the daughter cells contain genetic information that is identical to that of the mother cell, as well as that there be no mutations. Mitosis is Important for three main things:
> Growth
> Repair
> Reproduction
hope it helps.
To be honest i didn't get your question but i gave the basic info for Mitosis
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Explanation:
Which plate is the Eurasian plate?
A. D
B. C
C. B
D. A
which of these organs is an accessory organ of the digestive system?
Answer:
Where is the picture??
Explanation:
how many DNA molecules were in the beginning of the gif?
Answer:The result of DNA replication is two DNA molecules consisting of one new and one old chain of nucleotides
Explanation:
i just did :)
A place where animals and plants are protected is called
A) an ecosystem
B) a refuge
C) a sanctuary
D) both B and C
Hello! can someone help me w this pls
Is it True or false?
plant and animal mitosis are very similar except for cytokinesis. explain how this process is different.
Answer:
Cell division or cytokinesis in mitosis or meiosis is very similar... There is a region of division to separate the two daughter cells in both processes; however, the division plate is slightly different between animal cells and plant cells. In animals, the region of division is a division plate. hope this helps! :)
Out in the distance you see
How do you know that flowers have undergone fertilizer even before they turn into fruits?
Answer:
we can know for eg an apple when u buy it and scrape the skin of the apple if you wind some waxy substance from it we can say this has been done to increase the shine so customers think this is a good apple and please do was fruit and vegetables after buying them throughly.
help help pls
choose the right letter
29. The ABO blood type gene is an example of which means that heterozygous display two phenotypes at the same time.
A. Fading
B.Incomplete dominance
C. Codominance
D. Advanced hybridism
Answer:
Codominance i believe :)
How many minutes are there in a 40-hour week?
A:2,000
B:2,400
C:1,400
D:1,200
There will be 2,400 minutes in a week of 40 hours. This can be calculated by the help of unit conversion of time. Thus, the correct option is B.
What is Unit conversion?
Unit conversion is the change of one form of unit to another form of unit of different system such as conversion of units of measurement of weight from gram to kilogram or milligram.
Unit conversion of one unit to another unit is used in order to have accuracy and avoiding the confusion in measurements. For example, the length of pencil is not measured in kilometers rather it is measured in centimeters or inches, which are comparatively smaller than kilometers. In such a case, one has to convert the unit of length from kilometer (km) to centimeter (cm).
The week of 40 hours can be converted into minutes by:
Number of minutes in 1 hour = 60
Therefore, the number of minutes in 40 hours = 60 × 40 = 2,400 minutes
Therefore, the correct option is B.
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How can slime molds be both unicellular and multicellular?
What is oxidative phosphorylation.
Answer:
Oxidative phosphorylation is energy given by electron transport and this takes place during aerobic respiration in the mitochondria.
Explanation:
This process produces huge amounts of ATP, which is the unit of energy for metabolic processes.
Which two atoms form an ionic bond?
A.sodium and bromine
B. two sodium atoms
C. two oxygen atoms
D fluorine and chlorine
Answer:
sodium and bromine
Explanation:
The one valence electron from sodium would be transferred to the bromine atom so they can both have an octet.
Which two atoms form an ionic bond?
Answer : A
Explanation : Ionic bond is a type of chemical bond and binds the chemical molecules together. Ionic bond is formed by the transfer of electrons from an electropositive element ( metal) to the electronegative element (non metal).
Sodium is an electropositive element and contains one positive charge. Bromine is an electronegative element with a single negative charge over it. Sodium gives the electron to bromine and results in the formation of ionic bond.
Thus, the correct answer is option (C).
Hope this helps you!
A) Identify a signaling molecule from the model present. Explain how receptors play a role in cell differentiation.
B) Identify the dependent variable and two controls the experimenters used when conducting this experiment.
C) Evaluate if the number of Variant 1-Type cells with mating projections was significantly different from those of the Wild Type. Use chi-square analysis.
D) Scientists propose that a mutation has occurred that either changed the mating pheromone or receptor site on the Variant 1-Type yeast cells. Predict where the mutation occurred. Justify your prediction with evidence from the experiment and scientific reasoning, based on your knowledge of cell-signaling pathways.
Answer:
A) A signaling molecule from the model shown is the pheromone. The pheromone binds to the receptor to create the cellular response in yeast to stop growth and produce shmoo. Shmoo is a nodule that allows the yeast cells to join together. Receptors play a role in cell differentiation, because the signaling molecules bind to the receptor in order to produce a response. When the pheromone binds to the receptor, a series of steps are followed in the transduction pathway in order to create shmoo, a differentiation in the cell. Without the receptor, the signaling pheromone would not be able to trigger the transduction pathway that ultimately results in the differentiation of the cell. Only signaling molecules with a specific shape and size can bind to a specialized receptor and cause a cellular response. Different yeast cell types may have varying receptors, affecting the ability of each pheromone to bind to the receptor to create a mating differentiation and, therefore, the rate of mating.
B) The dependent variable of the experiment is the number of cells that differentiated. The number of cells that differentiated depended on the type of yeast exposed to the pheromones. In this experiment, the experimenters controlled the sample size and the application of the pheromones. Each treated group consisted of 1,000 cells and was given the same concentration of pheromones. The same three pheromones, Wild Type-created, Variant 1-created, and Variant 2-created, were also used for each yeast cell type. These controls allowed the experimenters to observe how yeast cell type affects the rate of mating without the influence of other factors that could have skewed the results.
C) Chi-square analysis can be used to determine if the number of Variant 1-Type cells with mating differentiations significantly differed from those of the Wild Type. The Variant 1-Type yeast cells are being compared to the Wild Type cells, so the Variant-1 Type cells are the observed data and the Wild Type cells represent the expected data. In order to find the chi-square value, the square of the difference between the observed and expected values divided by the expected value must be calculated for each category. For the Wild Type-created pheromone type, there were 450 differentiated cells in the Wild Type cells and 203 in the Variant 1-Type cells. By using these values in the formula, a value of approximately 135.58 results. There were 606 differentiated Wild Type cells and 411 differentiated Variant 1-Type cells in the groups exposed to the Variant 1-created pheromone, showing a value of about 62.75. The value for the Variant 2-created pheromone category can be calculated as 16.82, with 50 differentiated Wild Type yeast cells and 21 differentiated Variant 1-Type cells. Then, these values are added to find the final chi-square value, 215.15, which can be compared to a critical chi-square value to determine the significance of the difference. The critical value with a 95% confidence for three categories is 5.99. The calculated chi-square value is far greater than the critical value, showing a significant variation between the number of cells with mating projections in the Wild Type and Variant 1-Type yeast cells. This also rejects the null hypothesis that there is not an important variation in the values, supporting the alternative hypothesis that a factor is affecting the rates of mating in Variant 1-Type yeast cells.
D) The significant variation between the data values could have resulted from a mutation in the Variant 1-Type cells. This mutation likely changed the receptor site of the cell by affecting its shape. Without the proper shape of specialized receptor sites, the pheromones are inhibited from binding to the receptor. When signals bind to receptors, the signal is received and a sequence of changes occurs throughout the transduction pathway in order to produce a response. Since pheromones cannot bind to the receptor sites to produce a response as easily, the overall cellular response of differentiation cannot be produced as often. The mutation resulted in the inability for signals in the pheromones to be received and communicate the correct response. Therefore, the mutation in the receptor site Variant 1-Type cells explains the significant variation in the values between the Variant 1-Type cells and the Wild Type cells. The data in the experiment shows that different pheromones resulted in differing amounts of cell differentiation in the Variant 1-Type yeast cells. This further suggests that the mutation affected the receptor site, not the pheromones, as the pheromones could still bind in some cells and the differences in the pheromones were not lost. The data indicates that the receptor sites of Variant 1-Type cells were changed by a mutation, creating a significant difference between the number of differentiated cells in the Wild Type and Variant 1-Type yeast cells.
Ligands are called signaling molecules because they bind to receptors and carries information.
A) The signaling molecule in the model is the pheromone. It binds to the receptor to generate a cellular response in the yeast system. It inhibits the growth of yeast cells and secretes shmoo.
Receptors are important in cell differentiation as they bind with receptors and create shmoo via the transduction pathway.
In the absence of a receptor, the transduction pathway will not occur and shmoo will not be produced.
Signaling molecules having specific shapes and sizes can only bind to receptors.
B) In the above experiment, a dependent variable is the number of cells differentiated. The number of cells differentiated depends on its exposure to pheromones.
The application of pheromones and the sample size of cells were in control by the experimenters. The yeast cell types were exposed to Variant 1-created, Variant 2-created and Wild Type-created pheromones equally.
This helped the researchers in determining the rate of mating without any influence of other factors.
C) Chi-square can be used to evaluate the number of variant 1 type cells with that from wild type.
The observed data includes variant type 1 cells and the expected data includes the wild type cells.
[tex]\rm Chi - square = \dfrac{( Observed - Expected \:values)^{2}}{ \:Expected \:values}[/tex]
The required value with a 95% certainty for the three types is 5.99. The calculated chi-square value is greater than that of critical values.
This shows the difference in the mating of variant and wild type varieties. It also repudiates the null hypothesis.
D) The mutation likely occurred on the receptor site of the variant type that changed the shape of the site binding.
The change in the receptor site will inhibit the pheromones from binding. This will affect the cell differentiation and transduction pathway.
Therefore, mutation on the receptor site indicated the variant and the wild type have different cell differentiation and mating rates. The mutation is responsible for the varied data and not pheromones.
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Which of the following best explains what will happen if the blood gets too cold? A) It will have a high viscosity and increased resistance. B) It will have a low viscosity and increased resistance. C) It will cause low blood pH and decrease resistance. D) It will change the shape of blood cells and decrease resistance.
It will have a high viscosity and increased resistance.
Effect of temperature on bloodLow temperatures cause narrowing of blood vessels and arteries which leads to restricting blood flow and reducing oxygen to the heart.
Our heart must pump harder to circulate blood through the blood vessels which results in increasing of our blood pressure and heart rate.
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Answer:
The correct answer is A
Explanation:
i got it correct on my flvs exam
Identify the organelles in the cell to the right.
А
חד
F
В.
А
B
С
с
C
D
E
F
E
DONE
D
plant cell
Answer:
A- Vacuole
B- Chloroplast
C- Cell membrane
D- Golgi bodies
E- Smooth and rough endoplasmic reticulum
F- Cell wall
Explanation:
This is a structure of a plant cell which unlike animal cell has a cell wall as well as plasma membrane. It also contains large vacuoles present in the center of the cell. The green color of the plants is due to the presence of chlorophyll which is present in an organelles called chloroplast.
Organelles which are labelled in the cell are
A:Cell membrane
B:Vacuole
C:Nucleus
D:Cytoplasm
E:Chloroplast
F:Cell wall
The given figure represents a plant cell. So, the correct option is C.
What is Plant cell?Plant cells are defined as eukaryotic cells that contain a true nucleus as well as specialized structures known as organelles that perform certain specialized functions. Plant and animal cells both contain a nucleus with similar organelles but plant cells differ due to the presence of a cell wall outside the cell membrane.
In the given figure, labelled organelles function are as follows:
Vacuole stores food, extra water, and waste while cell membrane permits selective passage of things into and out of the cell. The cell's nucleus serves as the activity's control centre, while the cytoplasm is the fluid that gives the cell its jelly-like consistency. Chloroplasts contain a substance called chlorophyll that is a green pigment that aids in photosynthesis. The cell wall of a plant gives it form, stiffness, strength, and protection.
Thus, the given figure represents a plant cell. So, the correct option is C.
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Your question is incomplete, most probably the complete question is:
Identify the organelles in the cell to the right and label the parts A, B, C, D, E and F.
A.
A:Cell membrane
B:Vacuole
C:Nucleus
D:Chloroplast
E:Cytoplasm
F:Cell wall
B
A:Cell membrane
B:Vacuole
C:Nucleus
D:Cytoplasm
E:Chloroplast
F:Cell wall
C
A:Cell membrane
B:Nucleus
C:Cytoplasm
D:Vacuole
E:Chloroplast
F:Cell wall
D
A:Cell wall
B:Cell membrane
C:Nucleus
D:Cytoplasm
E:Chloroplast
F:Vacuole
what is the general purpose of the light reactions of photosynthesis
Answer:
The overall purpose of the light-dependent reactions is to convert light energy into chemical energy. This chemical energy will be used by the Calvin cycle to fuel the assembly of sugar molecules.
Explanation:
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