Which transformation preserves the property of a shape of a figure

Step-by-step explanation:

QR--DE

RS--- EF

RQ-----DE

Answer:

The difference is 3 for 4-7, and 39 for 52-91. So basically its a change of 3 for every 4-7 I think this is what you ask for. Let me explain and show results and then pick what you need.

Step-by-step explanation:

So, we know 4 to 7 is 3.

52 to 91 is 39.

So one is a change in 3. the other is a change is 39.

However, could these be the same, just bigger?

Lets divide the 52 to 91 with a change of 39 by 4 to 7 with a change of 3:

52/4 to 91/7 with a change of 39/3 =

13 to 13 with a change of 13.

So this tells us that the 52 to 91 with a chang eof 3 is 13 times bigger than 4 to 7 with a change of 3.

Hope this helps!

Answer:

Division property of equality

Step-by-step explanation:

7q=49

Divide each side by 7

7q/7 = 49/7

q = 7

Answer:

-166

Step-by-step explanation:

Answer:

Step-by-step explanation:

Decreased students = 1050 - 798 = 252

Decreased percentage = (decreased students ÷ number of last year students) * 100

= [tex]\frac{252}{1050}*100[/tex]

= 24%

Answer:

24%

Step-by-step explanation:

% change = [tex]\frac{difference}{original amount}[/tex] x 100

; 1050 - 798 = 252

% change = [tex]\frac{252}{1050}[/tex] x 100

% change = 0.24 x 100

% change = 24

the percentage decrease in the number of students enrolled is 24%

Answer:

There are two simple, compelling reasons to use a heart-rate monitor: to train and race at the best pace for you. The table below shows you how to find your perfect paces for: (1) the three most important workouts in any training program; and (2) the four most popular road-race distances.

Step-by-step explanation:

Hope this helps :)

Answer:

x = 3.24, x = -1.24

Step-by-step explanation:

The standard form for a quadratic equation is [tex]ax^2+bx+c=0[/tex]. For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is [tex]x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex].

Plug in a = 1, b = -2, and c = -4 into the formula.

[tex]=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}[/tex]

We'll do the top part first:

[tex]\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}[/tex]

Apply rule [tex]- (-a) = a[/tex]

[tex]=\sqrt{\left(-2\right)^2+4\cdot \:1\cdot \:4}[/tex]

Apply exponent rule [tex](-a)^{n} =a^n[/tex] if [tex]n[/tex] is even

[tex](-2)^2=2^2[/tex]

[tex]=\sqrt{2^2+4\cdot \:1\cdot \:4}[/tex]

Multiply the numbers

[tex]=\sqrt{2^2+16}[/tex]

[tex]2^2=4[/tex]

[tex]=\sqrt{4+16}[/tex]

Add

[tex]=\sqrt{20}[/tex]

The prime factorization of 20 is [tex]2^2*5[/tex]

20 divides by 2. 20 = 10 * 2

[tex]=2*10[/tex]

10 divides by 2. 10 = 5 * 2

[tex]=2* \:2*5[/tex]

2 & 5 are prime numbers so you don't need to factor them anymore

[tex]=2*2*5[/tex]

[tex]=2^2*5[/tex]

[tex]=\sqrt{2^2\cdot \:5}[/tex]

Apply radical rule [tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]

[tex]=\sqrt{5}\sqrt{2^2}[/tex]

Apply radical rule [tex]\sqrt[n]{a^{n} } =a[/tex]; [tex]\sqrt{2^2} =2[/tex]

[tex]=2\sqrt{5}[/tex]

[tex]=\frac{-\left(-2\right)\pm \:2\sqrt{5}}{2\cdot \:1}[/tex]

Because of the [tex]\pm[/tex] you have to separate the solutions so that one is positive and the other is negative.

[tex]x=\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1},\:x=\frac{-\left(-2\right)-2\sqrt{5}}{2\cdot \:1}[/tex]

Positive x:

[tex]\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1}[/tex]

Apply rule [tex]-(-a)=a[/tex]

[tex]=\frac{2+2\sqrt{5}}{2\cdot \:1}[/tex]

Multiply

[tex]=\frac{2+2\sqrt{5}}{2}[/tex]

Factor [tex]2+2\sqrt{5}[/tex] and rewrite it as [tex]=2\cdot \:1+2\sqrt{5}[/tex]. Factor out 2 because it is the common term. [tex]=2\left(1+\sqrt{5}\right)[/tex].

[tex]=\frac{2\left(1+\sqrt{5}\right)}{2}[/tex]

Divide 2 by 2

[tex]x=1+\sqrt{5}[/tex] or [tex]x=3.24[/tex] (You'll probably have to use a calculator for the square root of 5)

^Repeating the process of positive x for negative x in order to get [tex]x=1-\sqrt{5}[/tex] or [tex]x=-1.24[/tex]

Answer: B. DBC

Step-by-step explanation:

Answer:  [tex]\angle DBC[/tex]  (choice b)

================================================

Explanation:

When naming any angle, you need 3 points. The middle point is the vertex of the angle. The other two points can be in any order as long as they are on the lines or rays that we want.

We go for angle DBC, which we can write as [tex]\angle DBC[/tex], since B is at the vertex and points D and C are on either side of the vertex.

Angle ABD is adjacent to the marked angle, but it's not what we're after.

Angle BDC isn't drawn, so we cross this off the list as well.

Saying [tex]\angle B[/tex] is too vague in this context because it could mean either [tex]\angle ABD[/tex] or it could mean [tex]\angle DBC[/tex] since they both share the same vertex B.

C⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Answer:

2*(-3)= -6

Step-by-step explanation:

I do not see how "a*b=2a-3b" would change the fact 2 times negative 3 is -6

Answer:

the answer would be 193.77

Step-by-step explanation:

literally, subtract 45.87 from 239.64.

you get 193.77.

(you put 44 instead of 45, so the sum with 44 would be 194, that is incorrect.)

Answer:

[tex]\huge\boxed{p^3+p^2=p^2(p+1)}[/tex]

Step-by-step explanation:

[tex]p^3+p^2\\\\p^3=p^{2+1}=p^2\cdot p\\\\p^3+p^2=p^2\cdot p+p^2\cdot1=p^2(p+1)[/tex]

Used:

[tex]a^n\cdot a^m=a^{n+m}\\\\\text{distributive property}:\ a(b+c)=ab+ac[/tex]

Answer:

[tex]{ \tt{1 \: hour = 60 \: minutes}} \\ { \tt{5 \: hours = (5 \times 60) \: minutes}} \\ = 300 \: { \bf{minutes}}[/tex]

Given:

Initial number of participants = 128

During each round, half of the players are eliminated.

To find:

The number of players remain after 5 rounds.

Solution:

It is given that, the initial number of participants is 128 and during each round, half of the players are eliminated.

If half of the players are eliminated, then half of the players are remained.

So, the initial value is 128 and the decay factor is [tex]\dfrac{1}{2}[/tex].

The general exponential decay model is:

[tex]y=a(b)^x[/tex]

Where, a is the initial value and b is the decay factor.

Putting [tex]a=128[/tex] and [tex]b=\dfrac{1}{2}[/tex] in the above model, we get

[tex]y=128\left(\dfrac{1}{2}\right)^x[/tex]

Here, y is the number of remaining players after x rounds.

Substituting [tex]x=5[/tex], we get

[tex]y=128\left(\dfrac{1}{2}\right)^5[/tex]

[tex]y=128\left(\dfrac{1}{32}\right)[/tex]

[tex]y=4[/tex]

Therefore, the required model is [tex]y=128\left(\dfrac{1}{2}\right)^x[/tex] and the number of players remain after 5 rounds is 4.

Answer:

14 : -17 : 2

Step-by-step explanation:

8 + (9 · 2 – 3) : 25 – 4 2 : 2

= 14 : -17 : 2

Answer:

- 12.4

Step-by-step explanation:

[tex]8 + \frac{9 * 2 - 3}{25} - \frac{42}{2}[/tex]

[tex]8 + \frac{18 - 3}{25} - 21[/tex]

[tex]8 + \frac{15}{25} - 21[/tex]

[tex]8 + \frac{3}{5} - 21[/tex]

[tex]8 \frac{3}{5} - 21[/tex]

[tex]-12 \frac{2}{5}[/tex]

Answer:

A. [tex]UPC = 0-03700-80049-9[/tex]

Step-by-step explanation:

Given

[tex]ID = 037000[/tex]

[tex]Item\ Number = 80049[/tex]

Required

The valid UPC

First, the UPC is represented as:

UPC = ID followed by item number followed by the checksum

So, we have:

[tex]upc = 0-03700-80049-X[/tex]

To calculate X (the checksum)

Add up digits at odd positions

[tex]Odd = (0 + 7 + 0) + (8 + 0 + 9)[/tex]

[tex]Odd = 24\\[/tex]

Multiply by 3

[tex]Product = Odd * 3[/tex]

[tex]Product = 24 * 3[/tex]

[tex]Product = 72[/tex]

Add up digits at even positions

[tex]Even = (3 + 0 + 0) + (0 + 4)[/tex]

[tex]Even = 7[/tex]

Add the product and the sum of even

[tex]Result = Product + Even[/tex]

[tex]Result = 72+7[/tex]

[tex]Result = 79\\[/tex]

The last digit of the UPC is 9.

Hence, the UPC is:

[tex]UPC = 0-03700-80049-9[/tex]

Answer:

x=8

Step-by-step explanation:

The angles shown are vertical angles and vertical angles are equal

13x+19 = 16x -5

Subtract 13x from each side

13x-13x+19 = 16x-13x -5

19 = 3x-5

Add 5 to each side

19+5 = 3x-5+5

24 = 3x

Divide by 3

24/3 = 3x/3

8 = x

Answer:

x = 8

Step-by-step explanation:

The angles shown are vertical angles

Vertical angles are congruent

Hence, 13x + 19 = 16x - 5

We now solve for x using the equation we just created

13x + 19 = 16x - 5

Subtract 13 x from both sides

19 = 3x - 5

Add 5 to both sides

24 = 3x

Divide both sides by 3

x = 8

Answer:

perimeter=46.5 inches

Step-by-step explanation:

[tex]width=2\frac{3}{4}[/tex]

[tex]=\frac{5*4+3}{4}[/tex]

=[tex]=\frac{23}{4}[/tex]

[tex]length=3(\frac{23}{4} )[/tex]

[tex]=\frac{23*3}{4}[/tex]

=[tex]\frac{69}{4}[/tex]

perimeter of rectangle =2(l+b)

[tex]=2(\frac{69}{4} +\frac{24}{4} )[/tex]

[tex]=2(\frac{69+24}{4} )[/tex]   (since their denominator are same u can add their numerator)

[tex]=2(\frac{93}{4})[/tex]

[tex]=\frac{93*2}{4}[/tex]

[tex]=\frac{186}{4}[/tex]

[tex]=46.5[/tex]   inches

Answer:

x = -6

Step-by-step explanation:

All three angles are equal, so all three sides are equal, making this an equilateral triangle

5x+10 = 2x-8

Subtract 2x from each side

5x-2x +10 = 2x-8-2x

3x+10 = -8

Subtract 10 from each side

3x+10-10 = -8-10

3x = -18

Divide by 3

3x/3 = -18/-3

x = -6

Answer:

[tex]3 {}^{a - 4b} = 3 {}^{18} [/tex]

The value of the equation 3ᵃ / 81ᵇ = 3¹⁸

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

a - 4b = 18   be equation (1)

Now , the value of the equation 3ᵃ / 81ᵇ = A

On simplifying the equation , we get

81ᵇ = 3⁴ᵇ

And , 3ᵃ / 81ᵇ = 3ᵃ / 3⁴ᵇ

On further simplification , we get

3ᵃ / 3⁴ᵇ = 3ᵃ⁻⁴ᵇ

And , substituting the values from equation (1) , we get

3ᵃ⁻⁴ᵇ = 3¹⁸

Hence , the equation is 3ᵃ⁻⁴ᵇ = 3¹⁸

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Answer:

[tex] \rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)[/tex]

Step-by-step explanation:

we would like to factor the following:

[tex] \rm\displaystyle ( {a}^{2} + {b}^{2} {)}^{2} - 18( {a}^{2} + {b}^{2} ) - 88[/tex]

let a²+b²=x

thus substitute:

[tex] \rm\displaystyle x {}^{2} - 18x- 88[/tex]

rewrite the middle term as 4x-22x:

[tex] \rm\displaystyle x^{2} + 4x - 22x - 88[/tex]

factor out x:

[tex] \rm\displaystyle x( x^{} + 4)- 22x - 88[/tex]

factor out -22:

[tex] \rm\displaystyle x( x^{} + 4)- 22(x + 4)[/tex]

group:

[tex] \rm\displaystyle( x- 22)(x + 4)[/tex]

substitute back:

[tex] \rm\displaystyle( {a}^{2} + {b}^{2} - 22)( {a}^{2} + {b}^{2} + 4)[/tex]

and we are done!

Step-by-step explanation:

everything can be found in the picture

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj/ hyp

cos theta = 8/20

cos theta = 2/5

Taking the inverse cos of each side

cos^-1 (cos theta) = cos ^-1 ( 2/5)

theta =66.42182152

To the nearest degree

theta = 66 degrees

Answer:

x^2-2x+5

Step-by-step explanation:

5x^2 -4x +8 + -4x^2 +2x -3

Combine like terms

5x^2-4x^2-4x+2x+8-3

x^2-2x+5

No, The third line does not necessarily be a transversal.

What is Equation of line?

The equation of line with slope 'm' and y intercept at point 'b' is given as;

⇒ y = mx + b

Given that;

Two lines intersected by a third line.

Since, When two lines are parallel to each other and two lines intersected by a third line then, third lines are transversal.

So, Here it is not given two lines are parallel.

Thus, Third line is not necessarily a transversal.

Hence, The third line does not necessarily be a transversal.

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Answer:

Step-by-step explanation:

the sign must have a line underneath itself to show that it can be equal and unequal. 2/5 times a number (from my understanding) is 2/5 times a variable, plus 7.

Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.

The relationship between two non-equal values is defined by inequalities. Equal does not mean unequal, though. In most cases, the "not equal sign" is used.

Negative nine is greater than or equal to the sum of two-fifths times a number, and seven can be written as,

-9 ≥ (2/5x) + 7

Therefore, Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.

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Answer:

Step-by-step explanation:

3x - 14 = 46

   + 14   +14

3x = 60

3x/3 = 60/3

x = 20