while riding an open freight elevator upwards at 5.1 m/s, a carpenter drops his hammer off the side. it hits the ground 2.4 s later. how far above the ground was the carpenter when he dropped the hammer?

When a soap bubble 100 nm thick and illuminated by white light incident perpendicular to its surface, then wavelength, λ is calculated =  5.32 *10^-7 m.

The ratio of the speed of light in a vacuum, c, to the speed of light in a medium, c' is called as index of refraction. One of the consequence of this difference in speed is that when light goes from one medium to another at an angle, then the propagation vector in the new medium has a different angle with respect to normal.

Given, t= 100nm= 100 * 10 ^-9  n= 1.33

ΔФ1 = λ/4

ΔФ2 = 2√2 t λ n/2 λ

=2 t n

=2 * 100 * 10 ^-9 * 1.33

= 2.66 *10^-7

2.66 *10^-7= λ/2

λ=  5.32 *10^-7 m.

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Two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide therefore what we can determine about the planets is that x is Earth while y is Venus.

This is referred to as the envelope of gases surrounding the earth or another planet and it makes life possible by providing different organisms with air to breathe

In the atmosphere of the planet Venus there is a high concentration of carbon dioxide as it is made up of  it is made of 96.5% of CO₂ and a 3% of nitrogen.

On the other hand in the atmosphere of the planet Earth, there is a high concentration of nitrogen which is about 78% and is therefore the reason why they were chosen as the correct choices.

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Newton's third law states that any action will have a(n) equal and opposite reaction.

If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.

How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

s = 1.925 meters

In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."

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The speed of the wave is determined as 18 m/s.

option D is the correct answer.

The speed of the wave is the rate of change of wave's displacement with time.

The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.

v = fλ

where;

The frequency of the wave is calculated as follows;

f = 1 / T

where;

The period of a wave is the time taken for the wave to complete one cycle.

In the picture given, 3 cycles of the wave = 0.5 s

1 cycle of the wave = ?

= 0.5 s / 3

= 0.16667 s

f = 1 / T

f = 1 / 0.16667

f = 6 Hz

The speed of the wave is calculated as follows;

v = fλ

v = 6 Hz  x  3 m

v = 18 m/s

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The work done by the dog is 0.81J.

Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.

It is said that no work is done if the object does not move.

The work done on an object is the amount of energy transferred to an object through work.

According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:

Force = mass × acceleration

Force = 0.75kg × 9.8m/s²

Force = 7.35N

Work done = 7.35N × 0.11m = 0.81J

Therefore, 0.81J is the work done by the dog.

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So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.

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The volume of the toy is 80 ml.

To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.

In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.

The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.

It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.

Answer:

Volume of the toy: [tex]80\; {\rm mL}[/tex].

Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)

Explanation:

The graduated cylinder initially measures the volume of water in this cylinder:

[tex]V(\text{water}) = 70\; {\rm mL}[/tex].

Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:

[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].

Rearrange to find the volume of the toy:

[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].

To find the average density of this toy, divide mass by volume:

[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].

Answer:

5 m

Explanation:

Displacement is the straight-line distance from the starting point to the end point.  Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).  

d² = 3² + 4² = 25

d = [tex]\sqrt{25}[/tex] = 5 m

Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)

Answer:

a=25/24 m/s^2

Explanation:

I’m going to assume you mean the final velocity is 25m/s.

v^2=u^2+2as

625=0+2a300

a=25/24 m/s^2 or 1.0416^_ (period 1) ^m

The force due to gravity will be 0.0272 Newtons.

The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.

Despite being weak and appealing, gravitational forces exist.

Given, mass of one object= 2300 kg

mass of another object= 4000 kg

distance between the two objects= 0.150 m

value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]

the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]

                       [tex]F=0.0272 N[/tex]

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The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m

To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:

s = ut

20 = 5 × t

Divide both sides by 5

t = 20 / 5

t = 4 s

Finally, we shall determine the height of the cliff. Details below:

h = ½gt²

h = ½ × 9.8 × 4²

h = 4.9 × 16

h = 78.4 m

Thus, the height of the cliff is 78.4 m

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The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]

[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]

for t in the above expression.

[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]

The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]

[tex]v=\frac{\lambda_3}{T_3}[/tex]

Here,

[tex]$$\lambda_3$$[/tex]

is the frequency of third harmonics and

[tex]$$T_3$$[/tex]

is the time-period of third harmonics.

Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for

[tex]$$\lambda_3$$[/tex]

and

[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]

[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]

The expression of the wave velocity is given by the following expression.

[tex]v=\sqrt{\frac{T}{m / L}}[/tex]

Rearrange the above expression for

[tex]$$m$$[/tex]

[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]

[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]

The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.

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The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg

We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.

We know that momentum =mass × velocity

So,initial momentum of car is =1.4 × 10³kg × 37km/hr

Similarly,,initial momentum of truck=2×10³kg × 35km/hr

Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg +  2×10³kg=3.4 ×10³kg

Assume final velocity of both vehicle is v

So,following the law of conservation,we get

=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v

=>51.8 ×10³ + 2×10³=3.4×10³ ×v

=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v

=>v = 53.8/3.4

=>v=15.82m/sec

Hence,final velocity of both vehicle after collision is 15.82m/sec.

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Answer:

C.) The United States would become less dependent on energies that emit greenhouse gases.

Explanation:

If nuclear energy increased, it would occupy a larger piece of the pie chart.  The prompt states that the usage of non-fossil fuel-based forms of energy would remain constant.  This condition means that nuclear energy would decrease the percentage of fossil fuel-based energy used.  Energy production through the use of fossil fuels necessarily produces greenhouse gases such as CO2.  An increase in nuclear energy would mean a corresponding decrease in dependence on greenhouse gas-producing fossil fuels.

Answer:

While on the earth, any object with a mass of 0.77 kg weighs 7.546 newtons (1.698 pounds).

On the moon, the same 0.77-kg object would weigh 1.232 newtons (0.277 pound)

Explanation:

Answer:

The total distance covered is 3 km and the displacement is 2.24 km.

Explanation:

For the total distance covered by Anthony, we just add all of the distances.

1 km (going east) + 1 km (going east again) + 1 km (going south) = 3 km

Hence, the his total distance covered when he went to the pizza place is 3 km.

Solving for the displacement is a different matter. We cannot just add all of the distances. From analysis of the problem, Anthony traveled and formed a right triangle. He traveled 1 km east twice, making it 2 km east in total, then he traveled 1 km south.

When dealing with a right triangle with 2 sides given (for this problem the two sides are the 2 km east and the 1 km south), we use the Pythagorean Theorem.

Solution:

c² = a² + b²  (Pythagorean Theorem)

c will be the longest side of the right triangle

a and b will be the other sides of the right triangle

c = √ (a² + b²)

c = √ (2² km + 1² km)

c = √5 km

c = 2.2361 km ≈ 2.24 km

Therefore, the displacement of Anthony is 2.24 km.

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Answer:

S = V1 t + 1/2 a t^2        distance traveled for linear acceleration

θ = ω1 t + 1/2 α t^2       equivalent angle for rotational acceleration

ω1 = 240 / min * 2 π * 240 / (60 s/min) = 8 π / s

ω2 = 360 rpm = 12 π / s

α = 4 π/ 6.5 s^2  = .62 π / s^2    angular acceleration

θ = 8 π / s  6.5 s + .62 π / 2 * 6.5^2

θ = 52 π + 13 π = 65 π = 65 * π / (2 π / rev) = 32.5 rev

1 rev = 2 * π * R = 2 * π * .4 m = 2.51 m / rev

S = 32.5 rev * 2.5 m/rev =  81 m

True. The Big Bang Theory is the current scientific explanation for the origin and evolution of the universe. According to this theory, the universe was initially in a state of extremely high density and temperature, and it has been expanding and cooling since its inception.

One reason we cannot directly observe the Big Bang is that the universe's density was so low at that time that there were no solid particles, such as atoms or molecules, that could have formed into stars or galaxies. Instead, the universe was filled with a hot, ionized plasma that was too diffuse to be observed by telescopes. Another reason is that the expansion of the universe has caused the light and other electromagnetic radiation that was emitted during the Big Bang to become redshifted, or stretched out in wavelength, over time. This means that the light from the earliest moments of the universe has shifted into the microwave and radio frequency ranges, which are not visible to the human eye. Therefore, while we can infer some details about the conditions of the early universe based on observations of the cosmic microwave background radiation and the large-scale structure of the universe, we cannot directly observe the Big Bang itself.

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All the tools of communication such as the drum, telegraph et cetra were used for emergency communication.

We know that communication has to do with the art of sending and receiving information between two people who may or may not be at the same place. We know that the dissemination of information is a very important aspect of life and we have always tried to invent means of communication especially at times when we have an emergency situation that needs a kind of an immediate remedy.

We can see that all the kinds of communication gadgets that have been show here are all from a period that is far behind the kind of civilization that we have to day and the kind of thge communication gadgets that are quite available to the people that are around today.

However, all the tools shown could be used to send information in times of emergency.

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The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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sheesh sheesh                                                    

Explanation:

Answer: Synthesis

Explanation: You are combining multiple Elements

You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.

Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.

The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.

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Refer to the photo taken.

The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is  147.2 N .

The Pascal's Law states that the relation between the pressure , force and area is given as :

Pressure = Force/Area ;

given that the diameter of the master cylinder is = 1.93 cm ;

so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;

the diameter of slave cylinder is = 24.9 cm ;

the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;

Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²

Area of the master cylinder (A₂) =  π(0.00965)² = 0.000292 m² ;

given mass of the car = 2500 Kg ,

the force exerted will be : F = m*a

F₁ = 2500*9.8 = 24500 N ;

F₁/A₁ = F₂/A₂

So , 24500/0.0486 = F₂/0.000292

F₂ = (24500/0.0486)×0.000292

F₂ = 147.2 N

Therefore , the force exerted on the master cylinder is 147.2 N  .

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We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.

acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.

An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.

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An average tendon can withstand 16000 per square inch of force (psi). The Achilles tendon may begin to fail at a force of F = 1280 pounds.

That meaning of the term "force" is obvious. At this point, it is quite acceptable to refer to a force as a push or possibly a pull. An item does not "have energy in it" or "encompass energy." A force is applied to one thing by another. A factor is anything that affects non-living things as well.

Inertia is what holds the cosmos together. Literally. That could prevent matter from having the electric forces necessary to produce its system layout. Vibrating particles generate heat and rotational motion, which operate to counteract inertia.

Area of tendon 0.4×0.2

=0.08 square inch.

0.08 square inch tendon =16000×0.08

F =1280 pound.

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The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.

The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.

Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.

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The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m

We'll begin by obtaining the acceleration of the box. Details below:

Net force = mass × acceleration

40 = 10 × acceleration

Divide both sides by 10

Acceleration = 40 / 10

Acceleration = 4 m/s²

Finally, we shall determine the distance. Details below

v² = u² + 2as

5² = 0² + (2 × 4 × s)

25 = 0 + 8s

25 = 8s

Divide both side by 8

s = 25 / 8

s = 3.125 m

Thus, we can conclude that the distance covered is 3.125 m

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