Answer:
Easy search it on g o o g l e
A rocket powered sled accelerates a jet pilot in training straight forward from rest to 270 km/h in 12.1 seconds. Find:
a) The average acceleration of the sled
b) The time it takes to reach the speed limit on the highway, 100 km/h
c) The distance travelled when it reaches the final speed (270 km/h)
Answer:
6.198 m/s² 4.48 s 453.77 mExplanation:
a)The average acceleration of the sled will be 6.198 m/sec
b)The amount of time required to travel at the highway's 100 km/h speed limit will be 4.48 sec.
c)The distances covered when the vehicle hits its top speed of 270 km/h will be 453.77 m.
What is acceleration?The rate of velocity change concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
[tex]\rm a = \frac{v-u}{t} \\\\[/tex]
The given data in the problem is given by ;
u is the initial speed of the rocket= 0 km/h
v is the final speed of the rocket= 270 km/h
t is the time interval= 12.1 seconds
a is the average acceleration of the ball=? m/sec²
to is the time it takes to reach the speed of 100 km/h
s is the distance traveled when it reaches the final speed
a)
The average acceleration of the sled is found as;
a = (v-u)/t
a=(75-0)/12.1
a = 6.198 m/sec
b)
The amount of time required to travel at the highway's 100 km/h speed limit;
From Newton's second equation of motion;
v =u+at
27.7 = 0 + 6.198t
t = 27.7 / 6.198
t = 4.48 sec
c)
The distances covered when the vehicle hits its top speed of 270 km/h;
v²=u²+2as
75²=0+2(6.198)s
s=(75)²/2(6.198)
s=453.77 m
Hence the average acceleration of the sled, the amount of time required to travel at the highway's 100 km/h speed limit, and the amounts of time required to travel at the highway's 100 km/h speed limit will be 6.198 m/sec,4.48 sec and 453.77 m respectively.
To learn more about acceleration, refer to the link;
https://brainly.com/question/2437624
#SPJ2
True or false: The maximum tensile force a solid, cylindrical wire can withstand increases as the thickness of the wire increases.
True
False
Answer:
True
Explanation:
The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;
[tex]\sigma = \dfrac{F_t}{A_o}[/tex]
Where;
[tex]F_t[/tex] = The tensile force
[tex]A_o[/tex] = The original cross sectional area of the cylindrical wire = π·R²
R = The radius of the wire
Therefore;
[tex]F_t[/tex] = σ × [tex]A_o[/tex] = σ × π × R²
Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased
The correct option is; True.
¿Cuál de las siguientes no es un tipo de fuerza de roce
the resultant capacitance of four capacitorconnected in series is --------the smalest individual capacitance
Answer:
This question is misleading since
1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4
so it would have to be less than the smallest individual capacitance
Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iron
Give reasons for the following,
a. Pascal is a derived unit.
b. Mass is a fundamental quantity,
c. Unit of power is a derived unit,
d. Unit of length is a fundamental unit.
Answer:
a) Pascal is a derived unit because it is derived from the unit of force and area
b)Mass is a fundamental quantity because it doesn't depends upon others physical quantity and made up of only one unit
c) unit of power is a derived unit because they are dependent quantities
D) unit of length is a fundamental unit because it cannot be expressed in terms of another quantity.
An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image ,its nature and size?
Answer:
The position is 8.18cm from the mirror.
Nature is b=virtual
Size is 1.82cm
Explanation:
Note that for a convex mirror, the image distance and the focal length are negative;
Given
Object height H0 = 4cm
object distance u = 18cm
Radius of curvature R = 30cm
Since f = R/2
f = 30/2
f = -15cm
Recall that:
[tex]\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm[/tex]
Since the image distance is negative, this shows that the image is a virtual image.
To get the size:
[tex]\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm[/tex]
I’m steel, the solvent is And the solute is. .
The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N
Answer:
c
Explanation:
Drag each label to the correct location on the image. Identify the particles and characteristics on this model of an atom.
Positively charged
Electron
Proton
Neutron
Negatively charged
Answer:
cant see picture
Explanation:
Answer:
please add picture so i can help you
Explanation:
will mark brainliest. The speed of sound is 340 m/s where a tuning fork produces the second resonance position above a closed air column that is 49.8 cm in length. The frequency of the tuning fork is ___ Hz.
Answer:
Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)
Explanation:
Given:
Speed of sound = 340 m/s
Length of resonance position above a closed air column = 49.8 cm = 0.498 m
Find:
Frequency of the tuning fork
Computation:
Frequency of the tuning fork[second resonance] = 3v / 4l
Frequency of the tuning fork[second resonance] = 3(340) / 4(0.498)
Frequency of the tuning fork[second resonance] = 512.04
Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)
Answer:
The frequency is 512 Hz.
Explanation:
speed, v = 340 m/s
length, L = 49.8 cm = 0.498 m
let the frequency is f.
[tex]f =\frac{3 v}{4 L}\\\\f = \frac{3 \times 340 }{4\times 0.498}\\\\f = 512 Hz[/tex]
Calculate the maximum absolute uncertainty for R if:
R = B - A
A = 32 +/- 2 seconds
B = 11 +/- 3 seconds
43 seconds
1 second
21 seconds
5 seconds
6 seconds
Answer:
ΔR = 5 s
Explanation:
The absolute uncertainty or error in an expression is
ΔR = | [tex]\frac{dR}{dB}[/tex] | ΔB + | [tex]\frac{dR}{dA}[/tex] | ΔA
the absolute value guarantees to take the unfavorable case, that is, the maximum error.
We look for the derivatives
[tex]\frac{dR}{dB}[/tex] = 1
[tex]\frac{dR}{dA}[/tex] = -1
we substitute
ΔR = 1 ΔB + 1 ΔA
of the data
ΔB = 3 s
ΔA = 2 s
ΔR = 3 + 2
ΔR = 5 s
A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing
Answer:
Increasing
Explanation:
I Hope it Helps
Una pelota de béisbol de 142g de masa, luego de ser arrojada por el pitcher lleva una velocidad de 90mph. Luego de ser bateada se mueve en sentido contrario a 54 m/s.
a. Calcular el impulso del bate sobre la pelota.
b. Si la pelota permanece en contacto con el bate 0,008 s ¿cuál es el módulo de
la fuerza del golpe?
Answer:
a) I = 13.38 kg m / s, b) F = 1,373 10³ N
Explanation:
The impulse is given by the relation
I = ∫ F dt = Δp
I = p_f -p₀
I = m (v_f - v₀)
take the ball's exit direction as positive, whereby the ball velocities
v₀ = -90mph, the final velocity v_f = + 54 m / s
Let's reduce the units to
I = 0.142 [54- (-40.23) ]
the SI system
v₀ = - 90 mph (1609.34 m / 1 mile) (1h / 3600 s = -40.23 m / s
m = 142 g (1kg / 1000) = 0.142 kg
we calculate
I = 0.142 [54- (-40) ]
I = 13.38 kg m / s
b) let's use the definition of momentum
I = ∫ F .dt
I = F ∫ dt
F = I / t
F = 13.38 / 0.008
F = 1,373 10³ N
Example to measure the interval of time of a small stone dropped from 1m height.
Answer:
The time required is 0.45 s.
Explanation:
Height, h = 1 m
initial velocity, u = m/s
Let the time is t.
Use second equation of motion
[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]
the pages of a book are numbered 1 to 300. Each leaf is 0.1 mm thick . If each cover is 0.25 mm thick. what is the thickness of the book
Answer:
30.5mm
Explanation:
There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm
Your answer is 30.5mm.
Answer:
15.5mm
Explanation:
there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers
page's thickness is 0.1mm, cover's thickness is 0.25
so books thickness = 150*0.1+0.25*2 = 15.5mm
what will be the magnitude of work if a force of 25N pulls a stone through a distance of 5m in its direction?
Explanation:
125 is your answer........
What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V =
cm?
Explanation:
→ Volume of cone = πr² × h/3
Here,
Radius (r) = 13 cmHeight (h) = 27 cm→ Volume of cone = π(13)² × 27/3 cm³
→ Volume of cone = 169π × 9 cm³
→ Volume of cone = 1521π cm³
→ Volume of cone = 1521 × 22/7 cm³
→ Volume of cone = 33462/7 cm³
→ Volume of cone = 4780.28 cm³
Answer:
4,778.4 is correct
Explanation:
4. A body in motion is said to be in equilibrium when it is
A moving with uniform velocity.
B at rest.
C accelerated by a force.
D moving in an indefinite path.
Answer:
A. moving with uniform velocity.
Explanation:
Was this hepfull
Answer:
A
Explanation:
Equilibrium is a state in which opposing forces or influences are balanced hence A being correct
An electron travelling at 7.72 x 107 m/s [E] enters a force field that reduces its velocity to 2.46 x 107 m/s [E]. The acceleration is constant. The displacement during the acceleration is 0.478 m [E]. Determine (a) the electron’s acceleration (b) the time interval over which the acceleration occurs.
Answer:
Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].
Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].
Explanation:
Let [tex]u[/tex] denote the velocity of this electron before the change.Let [tex]v[/tex] denote the velocity of this electron after the change.Let [tex]x[/tex] denote the displacement.Let [tex]a[/tex] denote the acceleration.Let [tex]t[/tex] denote the time taken.Apply the SUVAT equation that does not involve time:
[tex]v^{2} - u^{2} = 2\, a \, x[/tex].
Equivalently:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].
By this equation, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].
The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].
The current in a light bulb is 2 A. How long does it take for a total charge of 4 C to pass a point in the wire
Answer:
2min
Explanation:
i think it will be clear from photo
Answer: The formula for current is charge/time
so here we have to change subject so we are asked to look for time
Explanation: so it would be T=Q/I
T=4/2
T=2s
hope this helpss
sinong personalidad ang bumuo ng pangkat militar na tinawag na black shirts na nagsagawa ng pagpupulong ng mga grupong sosyalista at komunista
Answer:
Answer to the following answer is as follows;
Explanation:
In the northwestern city of Milan, Mussolini formed his nationalist regime in 1919. He organised black-shirted street warriors into teams. His "Blackshirts" raped and expelled socialists and communists from municipal administrations.
The Blackshirts, originally known as the Squadrismo, were formed in 1919 by a group of dissatisfied former soldiers.
State two sources of EMF cell other than the chemical cell
Answers
Explanation:
A photodiode or solar cell may be considered as a source of emf, similar to a battery, resulting in an electrical voltage generated by charge separation driven by light rather than chemical reaction. Other devices that produce emf are fuel cells, thermocouples, and thermopiles.
What does the m stand for in the enthalpy equation?
Answer:
Use the formula ∆H = m x s x ∆T to solve.
Explanation:
Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.
A basketball is held over head at a height of 2.4 m. The ball is lobbed to a teammate at 8 m/s at an angle of 40'. If the ball is caught at the same height it was tossed at, how far away is the teammate?
Explanation:
since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.
We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.
range can be calculated by the formula :-
[tex] \boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }} [/tex]
u is the velocity during its take off and [tex]\theta[/tex] is the angle at which its thrown
Given that
u = 8m/ s [tex]\theta[/tex] = 40°calculating range using the above formula
[tex] = \frac{ {8}^{2} \sin2(40) }{10} [/tex]
[tex] = \frac{64 \times \sin(80) }{10} [/tex]
value of sin 80 = 0. 985
[tex] = \frac{64 \times 0.985}{10} [/tex]
[tex] = \frac{63.027}{10} [/tex]
[tex] = 6.3027[/tex]
Hence,
[tex] \mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } } [/tex]
prepare for the module exam,
Question 1
1 pts
If a 6 ohm wire is connected to a 10 volt battery, what will the current be?
O 6 amperes
O ,67 amperes
O 1.67 amperes
60 amperes
Answer:
1.67 amperes
Explanation:
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex] V = IR [/tex] ......equation 1
Where;
V represents voltage measured in voltage.I represents current measured in amperes.R represents resistance measured in ohms.Making I the subject of formula, we have;
[tex] I = \frac {V}{R} [/tex] .....equation 2
Given the following data;
Voltage = 10 VoltsResistance = 6 OhmsTo find the current flowing through the battery, we would use eqn 2;
[tex] I = \frac {10}{6} [/tex]
Current, I = 1.67 amperes
satellite does not need any energy to revolve around the earth why
Answer:
An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.
or maybe god:)))(
định luất bảo toàn động lực chỉ đúng trong trường hợp nào
Answer:
ᴀꜱ ᴡᴀʀᴍ ᴀꜱ ꜱᴜɴ
ᴀꜱ ꜱɪʟʟʏ ᴀꜱ ꜰᴜɴ
ᴀꜱ ᴄᴏʟᴅ ❄️ ᴀꜱ ᴀ ᴛʀᴇᴇ
ᴀꜱ ꜱᴄᴀʀʏ ᴀꜱ ꜱᴇᴀ
ᴀꜱ ʜᴏᴛ ᴀꜱ ꜰɪʀᴇ
ᴀꜱ ᴄᴏʟᴅ ᴀꜱ ɪᴄᴇ
ꜱᴡᴇᴇᴛ ᴀꜱ ꜱᴜɢᴀʀ
ᴀɴᴅ ᴇᴠᴇʀʏᴛʜɪɴɢ ɴɪᴄᴇ
ᴀꜱ ᴏʟᴅ ᴀꜱ ᴛɪᴍᴇ ⌛
ᴀꜱ ꜱᴛʀᴀɪɢʜᴛ ᴀꜱ ʟɪɴᴇ ➖
ᴀꜱ ʀᴏʏᴀʟ ᴀꜱ ᴀ ᴀɴɢᴇʟ☺️
ᴀꜱ ʙᴜᴢᴢᴇᴅ ᴀꜱ ʙᴇᴇ
ᴀꜱ ꜱᴛᴇᴀʟᴛʜ ᴀꜱ ᴛɪɢᴇʀ
ꜱᴍᴏᴏᴛʜ ᴀꜱ ɢʟɪᴅᴇʀ
ᴘᴜʀᴇ ᴀꜱ ʜᴇᴀʀᴛ ❤️
ᴘᴜʀᴇ ᴀꜱ ɪ ᴡᴀɴɴᴀ ʙᴇ
Why are simple everyday actions considered
thermodynamic reactions?
they transform energy
they destroy energy
they create energy
Answer:
They transform energy
Explanation:
thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy
C is not less than 0
