Answer: The answer is: D) as the moon revolves around earth, the different amounts of the sunlit side faces earth.
Explanation: I have my ways ;>
Have a great day!
-Sunny
How do you use the periodic table to recall the ionic charge of an alkali metal, an alkaline earth metal, or aluminum?
The positive charge is the group number.
The negative charge is the group number.
The positive charge is the period number.
The negative charge is the period number.
Answer:
the positive charge is the period number
Explanation:
I might be wrong
Answer:
The positive charge is the group number.
Explanation:
HELP, SCIENCE QUESTION I AM STUCK
6. Which of the following is NOT part of a circuit?
A. rim B. load C. power source D. conductor
Which type of wave causes particles of matter to vibrate in a direction
perpendicular to the direction of its motion?
O A. Sound
B. Transverse
C. Longitudinal
D. Compression
Answer:
C.) Longitudinal
Lamp is placed in the lamp holder. The switch is closed. The lamp glows brightly for a short time and then the lamp does not work. Explain these observations
Solution :
It is given that the lamp glows brightly for a shorter period of time when the switch is closed on it the switch is put on. But after the some time the lamp goes off and it stops working.
This is because as soon as we on the switch, the current start flowing to the lamp which makes the filament of the lamp to glow, but due to some issue, the current stop flowing even when the switch is on and this stops the lamp from glowing and hence the lamp does not work.
The force of friction acting on a sliding crate is 223 N.
How much force must be applied to main- tain a constant velocity?
Answer:
Friction Opposes Motion of an Object.
Now
To get the Net force that Moves an Object and causes acceleration....You subtract the Frictional force
Net force = Pushing Force - Frictional Force
Recall
Net Force; F=Ma
Ma = P - Fr
Now the question asked for How Much force Must be applied to Maintain a Constant velocity.
In a Constant Velocity Motion... Acceleration do not change... Its Zero
So Putting this into the formula above
M(0) = P - Fr
0=P - Fr
Fr = P.
This means
That The force needed to keep this object Moving at Constant Velocity Must be equal to its Frictional Force
Since Frictional Force; Fr =223N
The Applied Force(Pushing Force) Must be equal to 223N too.
When magma flows on the surface on the surface, it is already called lava
TRUE OR FALSE
Answer:
True
Explanation:
I guess you made a mistake on question.
but I understood what you wanted to say.
Hope this helps... :)
A -0.00125 C charge is placed 3.62 m from a +0.00333 C charge. What is the magnitude of the electric force between them?
Answer:
The magnitude of the force between the charges is approximately -2,858.77 N
Explanation:
The given details are;
The magnitude of the given charges;
q₁ = -0.00125 C, q₂ = +0.00333 C
The distance between the charges, r = 3.62 m
The magnitude of the electric force between the charges, 'F', between two charged particles or objects is given as follows;
[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]
Where;
k = Constant = 9 × 10⁹ N·m²/C²
q₁ = The magnitude of charge on the first charged object = -0.00125 C
q₂ = The magnitude of charge on the second charged object = +0.00333 C
r = The distance between the charges = 3.62 m
Plugging in the values, gives;
[tex]F = \dfrac{9 \times 10^9 \ \dfrac{N \cdot m^2}{C^2} \times (-0.00125 \, C) \times (+0.00333 \, C)}{\left( 3.62 \, m \right)^2} \approx -2,858.77 \, N[/tex]
The magnitude of the force between the charges, F ≈ -2,858.77 N
Use the universal law of gravitation to solve the following problem.
Hint: mass of the Earth is = 5.97 x 1024 kg
A scientific satellite of mass 1300 kg orbits Earth 200 km above its surface. If Earth has a radius of 6378 km, what is the force of gravity acting on the scientific satellite?
a. Write out the formula for this problem.
b. Plug in the values from this problem into the formula.
c. Solve the problem, writing out each step.
d. Correct answer
Answer:
a.
[tex]F=G\cdot\dfrac{M \cdot m}{r^{2}}[/tex]
b.
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}}[/tex]
c.
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}} \approx 1.144 \times 10^{13} \ N[/tex]
d. The force of gravity acting on the satellite is approximately 1.144 × 10¹³ N
Explanation:
a. The formula for finding the force of gravity, F, acting object on an object is given as follows;
[tex]F=G\cdot\dfrac{M \cdot m}{r^{2}}[/tex]
Where;
F = The force acting between the Earth and the object
G = The gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M = The mass of the Earth = 5.97 × 10²⁴ kg
m = The mass of the object
r = The distance between the center of the Earth and the object
b. Finding the gravitational force, 'F', between the Earth and the scientific satellite, we have;
The given mass of the satellite, m = 1,300 kg
The distance between the center of the Earth and the center of the satellite, r = The length of the radius of the Earth + The height of orbit of the satellite
The given height of orbit of the satellite, h = 200 km
∴ r = R + h = 6,378 km + 200 km = 6,578 m
Therefore, by plugging in the values, we get;
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}}[/tex]
c. Solving the above equation gives;
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}} \approx 1.144 \times 10^{13} \ N[/tex]
d. The force of gravity acting on the satellite, F ≈ 1.144 × 10¹³ Newton
In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
The force of the wall on the car and the car on the wall are equal
The force of the wall on the car is greatest
The force of the car on the wall is greatest
There is not enough information to tell
Answer:
A...................................
The force of the wall on the car and the car on the wall are equal is true about Newton’s Third Law. Option A is the correct answer.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that if the car hits the wall, there will be a force exerted by the car on the wall, and an equal and opposite force exerted by the wall on the car. Option A is the correct answer.
The forces involved in the interaction between the car and the wall are equal in magnitude but opposite in direction, as dictated by Newton's Third Law. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts a force of equal magnitude but in the opposite direction on the first object.
Learn more about Newton here:
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The complete question is, "In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
a. The force of the wall on the car and the car on the wall are equal
b. The force of the wall on the car is greatest
c. The force of the car on the wall is greatest
d. There is not enough information to tell"
help please just give the answers asap no explanation needed
Answer:
where is the question? I can only see the diagram
d) is an atom of Sodium and an atom of Chlorine.
e) is a molecule of water.
Rewrite the false statements correctly
1.If an object sinks in one liquid and floats on another liquid,it implies that the density of second liquid is less than the first liquid.
2.The immersed volume of body in a liquid depends on density of the liquid.
3.Relative density of a body is usually expressed in kgm^-3
Explanation:
1. if an object sjnks in one liquid and floats on another liquid it implies that the density of second liquid is greater than the density of first liquid
please help me..im begging you
Answer: The equations in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
Explanation:
(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.
So, PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant
T = temperature
Boyle's law: At constant temperature, the pressure of a gas is inversely proportional to volume.So, [tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Charles' law: At constant pressure, the volume of a gas is directly proportional to temperature. So,[tex]V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}[/tex]
Gay-Lussac's law: At constant volume, the pressure of a gas is directly proportional to temperature.So, [tex]P_{1}T_{2} = P_{2}T_{1}[/tex]
Avogadro's law: At same temperature and pressure, the volume of gas is directly proportional to moles of gas.So, [tex]V_{1}n_{2} = V_{2}n_{1}[/tex]
Combined gas law: When Boyle's law, Charles' law, and Gay-lussac's law are combined together then it is called combined gas law. So,[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex]
Graham's law of effusion: It states that the rate of effusion of a gas is inversely proportional to the square root of mass of its particles.[tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex]
Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
why trucks are made to have many tires?
Answer: Load carrying heavy vehicles have large number of wheels in order to reduce pressure on the contact patch on road. With large number of wheels, it becomes easy to distribute the entire pressure of loads in an even manner.
Explanation:
A truck travelling at 30m/s decelerates at 1.5m/s². How far does it travel during the 10th second after the brakes are applied?
Answer
225 meters.
Explanation:
x=x0+30t-(1/2)(1.5)t^2
x=0+30(10)-(1/2)(1.5)(10)^2
x=300-75
x=225
A ship anchored at sea is rocked by waves that have crests Lim apart the waves travel at 70m/S, at what frequency do the waves reach the ship?
Question: A ship anchored at sea is rocked by waves that have crests 100 m apart the waves travel at 70m/S, at what frequency do the waves reach the ship?
Answer:
0.7 Hz
Explanation:
Applying,
v = λf............... Equation 1
Where v = velocity of the wave, f = frequency fo the wave, λ = wavelength of the wave
make f the subject of the equation
f = v/λ................. Equation 2
From the question,
Given: v = 70 m/s, λ = 100 m ( distance between successive crest)
Substitute these values into equation 2
f = 70/100
f = 0.7 Hz
Hence the frequency at which the wave reach the ship is 0.7 Hz
You have 1 hour to answer this question or you will be logged out.
How much force (in Newtons) does a baseball pitcher have to exert on a 250g baseball to make it accelerate to 50 m/s the
Instant that it leaves his hand?
Answer:
Force = 12.5 Newton
Explanation:
Given the following data;
Mass = 250 g to kilograms = 250/1000 = 0.25 kg
Acceleration = 50 m/s²
To find the force;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
[tex] Acceleration = \frac {Net \; force}{mass} [/tex]
Making force the subject of formula, we have;
[tex] Force = mass * acceleration [/tex]
Substituting into the formula, we have
[tex] Force = 0.25 * 50 [/tex]
Force = 12.5 Newton
Una muestra de agua (líquida) de 1220 kg se encuentra a 0° C y baja se temperatura hasta -29°C mientras se congela en el proceso. ¿Cuánta energía es liberada al ambiente (Mega Joules) ?
Answer:
-148,6 MJ
Explanation:
Dado que la liberación de calor al medio ambiente es;
H = mcθ
Dónde;
m = masa de agua
c = capacidad calorífica específica del agua
θ = aumento de temperatura
H = 1220 kg × 4200 × [-29-0]
H = -148,6 MJ
In this graph, calculate the speed of
segment A in m/s?
Answer:
The answer is Speed=2m/s
Explanation:
S=D/T
S=10m/5s
S=2m/s
What is a cyclotron??
What is cyclotron frequency?
Answer:
A cyclotron is a type of particle accelerator.
Explanation:
Cyclotron frequency is the frequency of a charged particle moving perpendicular to the direction of a uniform magnetic field B, since that motion is always circular, the cyclotron frequency is given by equality of centripetal force and magnetic Lorentz force.
help me with this please
Answer:
Family
1. Definition of a family
A family is a group of people living together in a home related by blood, marriage or adoption.
2. Two function of the family are;
socialization for the children in the family.love and happiness should be in a family for it to be function.3. Two types of family are;
Single parent family- this family includes one parent and his or her child, we can say it's an incomplete family.nuclear family- this family includes the two parents and their children or child, this family is known as the complete family.4. Two roles and responsibilities of the parents and children in the home are;
both parents must and should protect their child or children from harm.the children must have respect for the family.Accident in the Home
1. Definition of accident in the home
accidents in the home are common to persons of all ages, therefore home accidents occurs in one's home that may cause an result an injury of a person
2. Two types of accident in the home
fallsminor cuts and wounds3. The two uses of cereals in cooking
Cereals in cooking are used as thickened agents.
4. complete table
1. minor cuts and wounds
Causes: these are caused by broken glasses, contact with sharp instruments such as knife, pins and needles.Prevention: this can be prevented by keeping the Sharp tools in safe places after used2. Poisoning
Causes: poisoning can caused by in a result from children taking tablets for sweets, which can lead to death.preventions: you can prevent this by avoiding poisoning from the from the home or you could put it at a safe place that you know the child cannot get it.Care labels
1. definition of care label
care labels can be defined as a permanent label or we can say a tag, which contains regular instructions that is attached at the back of a cloth.
3. two classification of carbohydrates
Monopolyid really appreciate it if you helped (I'll give you brainlist)
Explanation:
answer is in the picture above
At the local grocery store, you push a 14.5-kg shopping cart. You stop for a moment to add a bag of dog food to your cart. With a force of 12.0 N you now accelerate the cart from rest through a distance of 2.29 m in 3.00 s. What was the mass of the dog food?
Answer:
The mass of the dog food added is 9.03 kg
Explanation:
Given;
mass of the shopping cart, m₁ = 14.5 kg
let the mass of the bag added = m₂
the force applied, F = 12 N
initial velocity of the cart-bag system, u = 0
distance traveled by the system, d = 2.29 m
time of motion of the system, t = 3.0 s
The acceleration of the system is calculated as;
[tex]d = ut + \frac{1}{2} at^2\\\\2.29 = 0 + (\frac{1}{2} \times 3^2)a\\\\2.29 = 4.5 a\\\\a = \frac{2.29}{4.5} \\\\a = 0.51 \ m/s^2[/tex]
The total mass of the system (M) is calculated as follows;
F = Ma
M = F/a
M = (12)/(0.51)
M = 23.53 kg
The mass of the dog food added is calculated as;
m₂ = M - m₁
m₂ = 23.53 kg - 14.5 kg
m₂ = 9.03 kg
2. In a chemical reaction
a) The atoms of the reactants always stay together to form the products
b) The atoms of the reactants unbond, rearrange, and then rebond to form the products
c) New atoms are formed which combine to make the products
d) Some atoms disappear while others multiply to form the products
Answer:
what I think in my opinion is B
can someone please help me I will mark you as brilliant.
The current in a resistor is 5 A and the voltage between its terminals is 40 V. Calculate the resistance.
An iron wire has a resistance of 24 Ω. If the voltage across its ends is 12 V, calculate the current in the wire.
Answer:
1=8 ohms 2=0.5 Amps
Explanation:
The speed of light in a solid is 1.24 x 108 m/s.
Calculate the index of refraction
Answer:
125
Explanation:
According to the question, the refractive index of the solid is approximately 2.42.
What is meant by the Refractive index?The refractive index may be defined as the measure of the bending of a light ray when passing from one medium to another. It can also be defined as the ratio of the velocity of a light ray in an empty space to the velocity of light in a substance, n = c/v.
The Refractive index for a medium may be defined as the ratio of the speed of light in a vacuum to the speed of light in that particular medium. It is a pure ratio and hence it does not have a unit.
According to the question,
The speed of light in a solid = 1.24 × 10⁸ m/s.
The refractive index of the solid = ?
The formula for the Refractive index of a medium = (Speed of light in vacuum) / (Speed of light in the medium).
The Speed of light in vacuum = 3 × 10⁸ m/s
[(3 × 10⁸)m/s] ÷ [(1.24×10⁸)m/s]
= (3×10⁸)/(1.24×10⁸)
= 3/1.24
≈ 2.42
Therefore, the refractive index of the solid is approximately 2.42.
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What type of electromagnetic waves do heat lamps give off?
A. infrared
B. ultraviolet
C. microwaves
D. radio waves
What is the energy of a photon of red light with a wavelength of 6.47 x 10-7 m ?
Answer:
3.44×10-27 joules.
Explanation:
E = h * c / λ = h * f,
E is the energy of a photon
h is the Planck constant
c is the speed of light
λ is the wavelength
Which energy store is increased when an object is heated?
Answer:
Kinetic Energy
Explanation:
Explain how you would apply any five pricing techniques to attract customers
Answer:
Explanation:
1. DECOY PRICING
This occurs when customers make a purchase they must often choose between products with different prices and attributes.
This method of pricing is meant to influence the consumer's purchasing decision and maximise the sales of one particular product. The seller will offer at least three products; two of the products will have a similar or equal price. The two products with the similar prices should be the most expensive ones, and one of the two should be less attractive than the other.
2. LOSS LEADER
This is when a product is sold at a low price (often without profit) in order to stimulate other profitable sales or to attract new customers.
The main is that it will help the business to expand their market share as a whole. It's common practice when first entering a market as it introduces new customers to a service or product in the hope of building a customer base and securing future
3.ODD PRICING
This is a method of psychological pricing a product. Prices ending in 9, 95, 97, 99 are sometimes called “charm prices” and in this type of pricing, the seller fixes a price where the last digits are odd numbers. This is intended to give the buyer no room for manœuvering or for bargaining as the price appears to be less - a product priced at £9.99 will seems much cheaper than one priced at £10.00
4. PRICE DISCRIMINATION
The purpose of price discrimination is to capture the market's consumer surplus and generate the most revenue possible for a product. Identical goods or services are sold at different prices from the same provider to different segments of the market. Industries that commonly use price discrimination include the travel industry, pharmaceuticals and textbook publishers.
5. PRODUCT BUNDLE PRICING
Using this method, sellers will combine several products in the same package. It also serves to move old stock. Blu-ray and videogames are often sold using the bundle approach once they reach the end of their product life cycle. This technique is used at auctions where one attractive item may be included in a lot with a box of less interesting things. Buyers must bid for the entire lot. It’s a good way of moving slow selling products, and in a way is another form of promotional pricing.
A swimmer is capable of swimming at 1.4m/s in still water. a. How far downstream will he land if he swims directly across a 180m wide river? b. How long will it take him to reach the other side.
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
Answer:
Explanation:
From the given information:
a) the distance(D) showing how dar downstream he will land can be computed as follows:
Assuming the current of the river = 0.2 m/s
[tex]D = \dfrac{180 \ m \times 0.2 \ m/s}{1.4 \ m/s}[/tex]
D = 36 m ÷ 1.4
D = 25.71 m
The required time (t) to reach the other side is:
time (t) = 180 m/ 1.4 m/s
time (t) = 128.57 seconds
