Answer:
PR= 8
ST=5
Step-by-step explanation:
PQ and PR are congruent so
2x=8
x=4
2*4=8
PR=8
ST and TU are congruent so
5z=2z+3
3z=3
z=1
5*1=5
ST=5
Answer:
PR=8
ST=5
Step-by-step explanation:
PR
QS=SR (marked)
a²=b²+c² (TRIANGLE PQS)
PQ²=PS²+QS²
8²=PS²+SR² (PQ=8, QS=SR)
64=PS²+SR²
a²=b²+c² (TRIANGLE PRS)
PR²=PS²+SR²
(2x)²=64
2x=8
x=4
PR=2x=2(4)=8
ST
a²=b²+c² (TRIANGLE VUT)
VT²=TU²+UV²
VT²=(2z+3)²+UV²
VT²=4z²+12z+9+UV²
a²=b²+c² (TRIANGLE VST)
VT²=VS²+ST²
VT²=VS²+25z²
4z²+12z+9+UV²=VS²+25z²
21z²-12z-9=0
7z²-4-3=0
(7z+3)(z-1)=0
z=-3/7 or z=1
cant be neg, z=1
ST=5(1)=5
PLS HELP !!! I need this question done quick
Answer:
a. 17 b. 51
Step-by-step explanation:
Follow Order of Operations (PEMDAS):
Parentheses, Exponents, Multiplication/Division, Addition/Subtraction
a. 9 + 4² - (4-2) • 4
9 + 4² - (4-2) • 4 –––Start with (4-2) = 2 (parentheses)
9 + 4² - 2 • 4 ––– 4² (exponents)
9 + 16 - 2 • 4 ––– 2 • 4 (multiplication)
9 + 16 - 8 ––– 9 + 16 (addition)
25 - 8 ––– 25 - 8 (subtraction)
17
b. 15 - 4 + 2(7-3) • 5
15 - 4 + 2(7-3) • 5 ––– Start with 2(7-3)
~ Note: this can be done using distributive property (2•7 - 2•3) OR solving the parentheses first and then multiplying 2(4). Both get 8 and same end result.
15 - 4 + 8 • 5 ––– 8 • 5 (multiplication)
15 - 4 + 40 ––– 15 - 4 (subtraction) *Note: Subtraction and addition are interchangeable in the order because you do it left to right*
11 + 40 ––– 11 + 40 (addition)
51
Answer:
(a. 7) (b. 51)
Step-by-step explanation:
A.
[tex]9 + 4^{2} - (4-2) * 4\\\\9 + 4^{2} - (2) * 4\\9 + 16 - 2 * 4\\9 + 16 - 8\\25 - 8\\17 \\[/tex]
B.
[tex]15 - 4 + 2 (7 - 3) * 5\\15 - 4 + 2 (4) * 5\\15-4+(2*4*5 )\\15-4+40\\11 + 40\\51[/tex]
(I don't know the numerical values)