Answer:
[tex]\boxed{\sf QS = 98}[/tex]
Step-by-step explanation:
QP = PS [Diagonals are bisected(Divided into two equal parts) by the other diagonal of parallelogram]
So,
3x - 11 = 2x + 9
3x - 2x = 9 + 11
x = 20
Now,
QS = QP + PS
QS = 3x-11+2x+9
QS = 3(20)-11+2(20)+9
QS = 60 - 11 + 40 + 9
QS = 49 + 49
QS = 98
Answer: QS=98
Step-by-step explanation: diagonals are bisected by the other diagonal parallelogram
Angles θ and φ are angles in standard position such that:
sinθ = -5/13 and θ terminates in Quadrant III
tanφ = -8/15 and φ terminates in Quadrant II
Find sin(θ + φ).
When [tex]\theta[/tex] terminates in quadrant III, both [tex]\cos\theta[/tex] and [tex]\sin\theta[/tex] are negative, and
[tex]\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{12}{13}[/tex]
When [tex]\varphi[/tex] terminates in quadrant II, [tex]\cos\varphi[/tex] is negative and [tex]\sin\varphi[/tex] is positive, so
[tex]1+\tan^2\varphi=\sec^2\varphi\implies\sec\varphi=-\dfrac{17}{15}[/tex]
which gives
[tex]\cos\varphi=\dfrac1{-\frac{17}{15}}=-\dfrac{15}{17}[/tex]
[tex]\tan\varphi=\dfrac{\sin\varphi}{\cos\varphi}=-\dfrac8{15}\implies\sin\varphi=\dfrac8{17}[/tex]
Now,
[tex]\sin(\theta+\varphi)=\sin\theta\cos\varphi+\cos\theta\sin\varphi=-\dfrac{21}{221}[/tex]
What are the zeros of this function?
A. X= 2 and x = -6
B. x= 0 and x = -6
C. X= 0 and x = 5
D. X = 0 and x= -5
Answer:
I think its C because if I remember correctly zero of the function is just the x intercept
Sondra receives an allowance of $10 per week, plus an additional $5 for each chore she completes. Which graph represents Sondra's earnings?
Answer: I know this is a bit late but for anyone looking the answer to this question, i got it right here :D.
Step-by-step explanation: I guessed and got it correct.
The graph representing Sondra's weekly earnings is plotted and attached.
What is a expression? What is a mathematical equation? What is Equation modelling ?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
Given is Sondra receives an allowance of $10 per week, plus an additional $5 for each chore she completes.
Assume that her weekly earnings is $y. Assume she does [x] extra chores in a week. Then, we can model her earnings by the equation -
y = 5x + 10.
Refer to the graph attached.
Therefore, the graph representing Sondra's weekly earnings is plotted and attached.
To solve more questions on Equations, Equation Modelling and Expressions visit the link below -
brainly.com/question/14441381
#SPJ2
Joshua remembered he had a coupon in his pocket that would take and additional 30%off the price of the shirts. Calculate the new total cost of the shirts including a sales tax of 6.5%
Answer:
New cost of the shirt=$39.028416
Step-by-step explanation:
Target is having a Back to School sale where all polo shirts are discounted by 20%. Joshua wants to buy five shirts: two cost $10.98 each, one costs $11.50, and two others cost $15.99 each. Joshua remembered he had a coupon in his pocket that would take an additional 30% of the shirts. Which choice represents the new total cost of the shirts including the sales tax of 6.5%
Solution
Two shirts cost=$10.98 each
One shirt cost=$11.50
Two shirts cost=$15.99 each
Total cost of shirts=(2*$10.98 + $11.50 + 2*$15.99)
=$21.96 + $11.50 + $31.98
=$65.44
All polo shirts are discounted by 20%
It means he would pay 100%-20% of the total cost
100%-20%=80%
Discounted price=$65.44 * 80%
=$65.44 * 0.8
=$52.352
He has a coupon of 30% off the shirt
100% -30%=70%
=$52.352*70%
=$52.352 * 0.7
=$36.6464
Plus Sales tax of 6.5%
6.5% of $36.6464
=0.065* $36.6464
=$2.382016
New cost of the shirt=$36.6464 + $2.382016
=$39.028416
what is -7 + 11 - 14 + 3 + 12
Answer:
5
Step-by-step explanation:
Answer:
5 (Follow PEMDAS left—>right)
Varadha bought two bags of rice of weights 45 kg and 63 kg. Find the maximum weight required, to measure the weight of rice exact number of times. options : 1.6 kg 2.35 kg 3.3 kg 4.9 kg
Answer:
3 kg
Step-by-step explanation:
given data
weights bag1 = 45 kg
weights bag2 = 63 kg
solution
we will take here first HCF of 75 and 69
factor of 75 = 3 × 5 × 5
factor of 69 = 3 × 23
so here HCF of 75 and 69 = 3
so that here maximum weight required, to measure the weight of rice exact 3 times
so correct option is 3. 3 kg
Answer:
4. 9 kg
Step-by-step explanation:
The greatest common factor of 45 kg and 63 kg is 9 kg.
45 = 9×5
63 = 9×7
A 9 kg weight could be used to weigh these amounts exactly.
_____
Comment on the problem statement
Appropriate formatting is helpful. It is difficult to tell that your answer choices are not 1.6, 2.35, 3.3, and 4.9. None of those makes any sense. With minimal formatting effort, you could list them as ...
1. 6 kg
2. 35 kg
3. 3 kg
4. 9 kg
Even better, the choices could be identified using letters and/or a separator other than a decimal point: A) 6 kg, B) 35 kg, and so on. The idea is to make it very clear what the numbers of the choices are. Less confusion is better.
the product of 5 and z
Answer:
5z
Step-by-step explanation:
As product = multiplication =>
5 x z --> 5(z)
[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]
Two trains leave New York at the same time heading in opposite directions. Train A travels at 4 5 the speed of train one. After seven hours they are 693 miles apart. What was the speed of train A?
Answer:
Speed of train A is 44 miles/hr.
Step-by-step explanation:
Let the speed of train A = [tex]u\ miles/hr[/tex]
Let the speed of train one = [tex]v\ miles/hr[/tex]
Train A travels at [tex]\frac{4}{5}^{th}[/tex] the speed of train one.
i.e.
[tex]u = \dfrac{4}{5}v \\\Rightarrow v =\dfrac{5}{4}u.... (1)[/tex]
Distance traveled = 693 miles
Time taken = 7 hours
They are travelling in opposite directions so the resultant speed will appear to be faster.
Relative speed = [tex]u+v\ miles/hr[/tex]
The trains are 693 miles apart in 7 hours that means they have traveled a total distance of 693 miles in 7 hours with a speed of ([tex]u+v[/tex]) miles/hr.
Using the formula:
[tex]Speed = \dfrac{Distance}{Time}[/tex]
[tex]u+v = \dfrac{693}{7}\\\Rightarrow u+v=99 ...... (2)[/tex]
Putting the value of v using equation (1):
[tex]\dfrac{5}4u+u=99\\\Rightarrow 5u+4u = 99 \times 4\\\Rightarrow 9 u = 99 \times 4\\\Rightarrow u = 11 \times 4 = \bold{44\ miles/hr}[/tex]
Speed of train A is 44 miles/hr.
Simplify to create an equivalent expression. -3(2+4k)+7(2k-)
Answer:
[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]
Step-by-step explanation:
The question seem incomplete; however, the given parameter is assumed as
[tex]-3(2 + 4k) + 7(2k)[/tex]
Required
Simplify
[tex]-3(2 + 4k) + 7(2k)[/tex]
Start by opening the brackets
[tex]-3*2 -3* 4k + 7*2k[/tex]
[tex]-6 -12k +14k[/tex]
Collect Like Terms
[tex]-6 -12k +14k[/tex]
[tex]-6 + 2k[/tex]
Reorder the above expression
[tex]2k - 6[/tex]
The answer can be further simplified as
[tex]2(k - 3)[/tex]
Hence;
[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]
help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help ill give brainly ;))
Answer:
a) 22:25 is the earliest time
b)15 min
Step-by-step explanation:
Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....
10:10(standard) = 22:10 (military)
22:10 -> 15min-> 22:25
Answer:
a) 22:25 is the earliest time
b)15 min
Because
Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....
Solve the equation
(If possible please show work)
I need help will rate brainliest please
Answer:
the stone fell in the air for 7 sec and fell in the water for 5 sec
Answer:
Let time taken in air be 'a'
And the time taken in water be 'b'
a+b=12
Distance covered in air = 16a
′′′′′ ′′″″ water= 3b
16a + 3b = 127
Solve the two equations simultaneously
a= 7 secs
b= 5 secs
How many cubes with side lengths of \dfrac12 \text{ cm} 2 1 cmstart fraction, 1, divided by, 2, end fraction, start text, space, c, m, end text does it take to fill the prism? Cubes
Answer:
24
Step-by-step explanation:
Answer
24!
Step-by-step explanation:
Person above me is correct :)
25 point please help I would really appreciate it :)))
Answer:
(a) 40
(b) 15% per week, to the nearest percent.
Step-by-step explanation:
Given:
old production,
P(w) = 230(1.1^w)
(a) At week 0, w=0, so
P(0) = 230(1.1^0) = 230
Difference (old - new) = 230-190 = 40
(b) about 15% per week
(c) from the 4th week on
approximate growth rate of new factory
N(w) = 190(R^w)
we know
w=0, N(0) = 190
w=7, N(7) = 505
so R=(505/190)^(1/7) = 1.1499 = 1.15 approx.
(c)
The old production tabulated:
w P(w) New
0 230 190
1 253 220
2 278 252
3 306 290
4 337 337
5 370 380
6 407 440
7 448 505
So we see that at the end of the 4th week, the two productions match, and new factory begins to exceed old production.
Angie has 18 oatmeal cookies.She splits them evenly among b bags.Choose the expression that shows how many cookies are in each bag. 1.B-18 2.18/b 3.18 4.B
Answer:
2, 18/b
Step-by-step explanation:
if you divide by the number of bags you will get the number of cookies in each bag.
Answer:2,18/b
Step-by-step explanation:If you multiply the cookies in a bag by b, you will get 18
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
Answer:
a) From A ∩ A' = ∅, we have;
A ∩ (A' ∪ B) = A ∩ B
b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;
A ∩ (A ∪ B)' = ∅
Step-by-step explanation:
a) By distributive law of sets, we have;
A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
From the complementary law of sets, we have;
A ∩ A' = ∅
Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have
A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)
A ∩ A' = ∅ (complementary law of sets)
Therefore;
(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)
∴ A ∩ (A' ∪ B) = A ∩ B
b) By De Morgan's law
(A ∪ B)' = A' ∩ B'
Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')
By associative law of sets, we have;
A ∩ (A' ∩ B') = (A ∩ A') ∩ B'
A ∩ A' = ∅ (complementary law of sets)
Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅
Which gives;
A ∩ (A ∪ B)' = ∅.
Someone pls help . Will be marking someone brainliest !
Answer:
27.89 hours.
Step-by-step explanation:
I hope this helps! If you would like an explanation, let me know!
Answer:
First question, 28 hours
Second question, 20 minutes
Step-by-step explanation:
$9.50 for each hour + $75 for showing up on time
Let's say the employee showed up on time
(340 - 75) ÷ 9.5 = 28 hours approximately
120 ÷ 6 = 20 minutes
A box contain 12 balls in which 4 are white 3blue and 5 are red.3 balls are drawn at random from the box. Find the chance that all three balls are of different colour
Answer:
white: 1/3, blue: 1/4, red: 5/12
Step-by-step explanation:
Take the amount of balls each color has and divide by 12.
White:
4/12 = 1/3
Blue:
3/12 = 1/4
Red:
5/12 (can't simplify)
Answer:
3/44 or 0.068
Step-by-step explanation:
(3/12 × 2/11 × 1/10)+(5/12 × 4/11 × 3/10)+(4/12 × 3/11 × 2/10)
=3/44
PLEASE HELP ME REALLY QUICK!
Answer:
90 degrees
Step-by-step explanation:
Add them together. 58+32=90
90 degrees
add them togather
what is the value of this expression when g= -3.5?
8-|2g-5|
a. 20
b. 10
c. 6
d. -4
Answer:
d. -4
Step-by-step explanation:
Let's plug in g
8 - |2(-3.5) - 5|
8 - |-7-5|
8 - |-12|
The absolute value is always positive of any number,
8 - 12
= -4
Answer:
D. -4
Step-by-step explanation:
We are given this expression:
[tex]8-|2g-5|[/tex]
and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.
[tex]8-|2(-3.5)-5|[/tex]
First, multiply 2 and -3.5
2 * -3.5 = -7
[tex]8-|-7-5|[/tex]
Next, subtract 5 from -7.
-7-5= -12
[tex]8-|-12|[/tex]
Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.
[tex]8-12[/tex]
Subtract 12 from 8.
[tex]-4[/tex]
The value of the expression is -4 and D is the correct answer.
Please answer. I need this to be done, Thanks. Will give brainliest
Answer:
The answer is s^26/pq59
Step-by-step explanation:
Answer:
p^ -1 q ^ -59 s ^26
or without negative exponents
s^ 26 /(p q^ 59)
Step-by-step explanation:
When multiplying , we can add the exponents when the bases are the same
p^0 q ^ -60 r^-1 s^25 * p^-1 qrs
When there is no exponent written, there is an implied 1
p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)
p^ -1 q ^ -59 r ^0 s ^26
r^0 = 1
p^ -1 q ^ -59 s ^26
If you need the negative exponents written as positive
a^-b = 1/ a^b
s^ 26 /(p q^ 59)
41 =12d-7 d= Math is not my strong suit. I love to read and write but I can not do math without a little bit of help.
Answer:
[tex]\huge\boxed{d = 4 }[/tex]
Step-by-step explanation:
41 = 12d - 7
Adding 7 to both sides
41+7 = 12d
48 = 12 d
Dividing both sides by 12
4 = d
OR
d = 4
Answer:
[tex]\large \boxed{{d=4}}[/tex]
Step-by-step explanation:
[tex]41 =12d-7[/tex]
Add 7 on both sides.
[tex]41 +7=12d-7+7[/tex]
[tex]48=12d[/tex]
Divide both sides by 12.
[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]
[tex]4=d[/tex]
Nijah has 45 stickers.
She gives 2/5 to her sister.
She gives 1/3 of her remaining stickers to Brett.
How many stickers does Nijah have left?
Answer:
Nijah has 6 stickers left.
Step-by-step explanation:
Starting stickers:
45
2/5 are given away:
[tex]\frac{2}{5}[/tex] * 45
[tex]\frac{2}{5}[/tex] * [tex]\frac{45}{1}[/tex]
[tex]\frac{90}{5}[/tex]
18
1/3 of the remaining are given away:
[tex]\frac{1}{3}[/tex] * 18
[tex]\frac{1}{3}[/tex] * [tex]\frac{18}{1}[/tex]
[tex]\frac{18}{3}[/tex]
6
Nijah has 6 stickers left.
Answer:
18
Step-by-step explanation:
Find the part she gave to her sister
45 *2/5 = 18
The part remaining is
45 - 18 = 27
She gives 1/3 to Brett
27 * 1/3 = 9
She has 27 - 9 = 18
She has 18 remaining
A pet store is offering a $5 in-store coupon for every person who buys a flea control product. If the flea control products range from $29.53 to $56.15, which compound inequality represents this situation?
Question 19 options:
29.53 ≤ x + 5 ≤ 56.15
29.53 ≤ x/5x ≤ 56.15
29.53 ≤x5≤ 56.15
29.53 ≤ 5 x – 5 ≤ 56.15
Answer:
29.53 ≤ x + 5 ≤ 56.15
Step-by-step explanation:
A $5 in-store coupon for every person who buys a flea control product which ranges between $29.53 to $56.15. This means that if you bought a flea control product you would be given an additional $5 that means that for buying a flea product, $5 is given to you. If you have $x, and you bought a flea product you would have x + 5. The inequality that represents this situation is given as:
29.53 ≤ x + 5 ≤ 56.15
m∠QPSm, is a straight angle m∠RPS=6x+11 m∠QPR=7x+143 ;Find RPS
Answer:
23
Step-by-step explanation:
6x + 11 + 7x + 143 = 180
13x + 154 = 180
13x = 26
x = 2
m<RPS = 6(2) + 11 = 23
Two of the lights at the local stadium are flickering. They both just flickered at the same time.
One of the lights flickers every 7 seconds and the other light flickers every 8 seconds.
How many seconds until both lights will flicker at the same time again?
seconds
Answer:
56
Step-by-step explanation:
you have to find the LCM of 7 AND 8.
which is 56
Answer:
The answer is 56
Step-by-step explanation:
Using the conversion 1 mile equals 1.6093 km to convert 4.9 kilometers to miles, round o the nearest tenth of a mile
Answer:
3.0 miles
Step-by-step explanation:
Using the conversion 1 mile equals 1.6093 km to convert 4.9 kilometers to miles, round to the nearest tenth of a mile.
1 mile = 1.6093 km
Convert 4.9km to mile
We can use cross multiplication :
Let the number of miles = m
1 mile = 1.6093 km
'm' miles = 4.9 km
Cross multiply :
m × 1.6093 = 4.9 × 1
m = 4.9 / 1.6093
m = 3.0448020 miles
Rounding 3.0448020 to the nearest tenth :
3.0 miles
The Cube root of 66 is between which two integers?
Answer:
4 and 5
Step-by-step explanation:
cube root of 66 is 4.041240021
Write and solve an equation to answer the question. How many people must attend the third show so that the average attendance per show is 3000?
Answer:
3250
Step-by-step explanation:
so for the first and 2nd show, the attendance is 2580 and 2920.
The average of both these numbers is 2750
the if the third show had 3000 people, the average attendance would only be 2875.
We need the average number to be 3000.
2750 is 250 less than 3000, so the other number must be 250 more.
3250 is how many people should go to the last show.
=====================================
Explanation:
We have 2580 people attend the first show and 2920 attend the second. So far, that's 2580+2920 = 5500 people. Add on another x people to get 5500+x, which represents the sum of all three days attendance figures. Divide this sum by 3 to get the average attendance
average attendance = (sum of individual attendance values)/(number of days)
average attendance = (5500+x)/3
So that's why (5500+x)/3 goes in the first box. The parenthesis are important to ensure that you divide all of "5500+x" over 3. If you just wrote 5500+x/3, then the computer would think you just want to divide x only over 3.
----------------
We set (5500+x)/3 equal to 3000 as we want the average of the three days to be 3000
(5500+x)/3 = 3000
5500+x = 3*3000
5500+x = 9000
x = 9000-5500
x = 3500
We need 3500 people to show up on day 3 so that the average of all three days is 3000.
3500 goes in the second box.
----------------
Check:
The figures for the three days are 2580, 2920, and 3500
They add to 2580+2920+3500 = 9000
Which divides to 9000/3 = 3000, which is the average we're after. So the answer is confirmed.
QUESTION 2
Solve for X.
3x + 4 + 2 = 15
Answer:
x=3
Step-by-step explanation:
3x+6 =15
x=3
Answer:
3
Step-by-step explanation:
3x + 6 = 15
3x = 15 - 6 = 9
x = 9/3 = 3