will give brainyest (m^2/3 n^-1/3)^6

Answer:

where is the statement

Step-by-step explanation:

its incomplete po

Answer:

77.18%

Step-by-step explanation:

115:149*100 =

(115*100):149 =

11500:149 = 77.18

0.9.30 am to 4.30 p.m. is 7 hours.

If we minus 30 minutes from it then it is 6 hours 30 minutes.

Answer:

n(B) = 1350

Step-by-step explanation:

Using Venn sets, we have that:

[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]

Three values are given in the exercise.

The other is n(B), which we have to find. So

[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]

[tex]2290 = 1300 + n(B) - 360[/tex]

[tex]940 + n(B) = 2290[/tex]

[tex]n(B) = 2290 - 940 = 1350[/tex]

So

n(B) = 1350

Answer:

Ok... I hope this is correct

Step-by-step explanation:

Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16

Center:  ( 0 , 0 )

Vertices:  ( 4 , 0 ) , ( − 4 , 0 )

Foci:  ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )

Eccentricity:  √ 2

Focal Parameter:  2 √ 2

Asymptotes:  y = x ,  y = − x

Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.

Simplified

0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1

For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.

Vector:

csc ( x )  ,  x = π

cot ( 3 x )  ,  x = 2 π 3

cos ( x 2 )  ,  x = 2 π

Since  

( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 )  is constant with respect to  F , the derivative of  ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 )  with respect to  F  is  0 .

12. X= 6

14. B= -11

16. N= 15

Answer:

q12. [tex]x=6[/tex]

q14. [tex]b=-11[/tex]

q16. [tex]n=15[/tex]

Step-by-step explanation:

Q12.

[tex]-1=\frac{x}{-6}[/tex]

Flip the equation:

[tex]\frac{x}{-6} =-1[/tex]

Multiply both sides by 6/(-1)

[tex](\frac{6}{-1} )[/tex] × [tex](\frac{-1}{6}x )[/tex] = [tex](\frac{6}{-1} )[/tex] × [tex](-1)[/tex]

[tex]x=6[/tex]

Q14.

[tex]5b=-55[/tex]

[tex]b=\frac{-55}{5}[/tex]

[tex]b=-11[/tex]

Q16.

[tex]-3n=-45[/tex]

[tex]n=\frac{-45}{-3}[/tex]

[tex]n=15[/tex]

hope this helps.....

Answer:

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 24 - 1 = 23

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.5

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.

The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Answer:

1) 5.64

2) 17.321

1) [tex]\frac{21}{28}[/tex]

2) [tex]\frac{16}{34}[/tex]

3) [tex]\frac{28}{35}[/tex]

4) [tex]\frac{32}{24}[/tex]

Step-by-step explanation:

SOH - CAH - TOA

Sin = [tex]\frac{O}{H}[/tex]   Cos = [tex]\frac{A}{H}[/tex]  Tan = [tex]\frac{O}{A}[/tex]      

O = opposite, A = adjacent, H = hypotenuse

First two,  use Pythagorean Theorem

If you want to calculate the angle on the last 4, use inverse of function and put in the ratio.

For example :

1) Tan Z = [tex]\frac{21}{28}[/tex]

   [tex]Tan^{-1}[/tex] ( [tex]\frac{21}{28}[/tex])

Z = 36.9°

Answer:

Variables are used to represent an unknown quantity in a mathematical expression.

Step-by-step explanation:

Answer:

There are 8 penguins and 6 reindeers.

Step-by-step explanation:

Since Brian, the gorilla, was planning a party for his zoo friends, and he sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer, and Jamie said there were 40 legs and Nancy said there were 14 heads To determine how many penguins and reindeer were in the exhibit, the following calculation must be performed:

Penguins: 1 head and 2 legs

Reindeers: 1 head and 4 legs

40 - (14 x 2) = X

40 - 28 = X

12 = X

12/2 = 6

14 - 6 = 8

8 x 2 + 6 x 4 = X

16 + 24 = X

40 = X

Therefore, there are 8 penguins and 6 reindeers.

9514 1404 393

Answer:

  (c)  5x and 3x, and 4 and 1

Step-by-step explanation:

Like terms have the same variable(s) to the same power(s).

The terms of this expression are ...

The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

Subtracting the second equation from the third gives ...

  (2z +3x) -(2z -2x) = (-6) -(-6)

  5x = 0

  x = 0

Using this in the third equation, we have ...

  2z +0 = -6

  z = -3

And substituting these values into the first equation, we have ...

  5y -3(0) -4(-3) = 22

  5y = 10 . . . . . subtract 12

  y = 2

__

The solution to the system is (x, y, z) = (0, 2, -3).

Answer:

The number is 9.5

Step-by-step explanation:

Look at the picture above, it explains everything

Answer:

78.5 (I think 90% sure)

Step-by-step explanation:

sum of both scores

75+82 = 157

average for a third test

157÷2=78.5

Answer:

2.25 miles per hr

Answer:

2.25 miles per hour

Step-by-step explanation:

speed = distance / time

speed = [tex]\frac{3}{4} / \frac{1}{3}[/tex] (take the reciprocal of [tex]\frac{1}{3}[/tex])

= [tex]\frac{3}{4} * 3[/tex]

= [tex]\frac{9}{4}[/tex] = 2.25 miles per hour

Answer:

C: 44

Step-by-step explanation:

Answer:

The probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427

Step-by-step explanation:

We are given that

[tex]\mu_{\hat{p}}=p=4%=0.04[/tex]

n=662

We have to find the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%.

q=1-p=1-0.04=0.96

[tex]\sigma_{\hat{p}}=\sqrt{p(1-p)/n}[/tex]

[tex]\sigma_{\hat{p}}=\sqrt{\frac{0.04(1-0.04)}{662}}[/tex]

[tex]\sigma_{\hat{p}}=0.0076[/tex]

Now,

[tex]P(\hat{p}>0.06)=1-P(\hat{p}<0.06)[/tex]

[tex]=1-P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}<\frac{0.06-0.04}{0.0076})[/tex]

[tex]=1-P(Z<2.63)[/tex]

[tex]=1-0.99573[/tex]

[tex]P(\hat{p}>0.06)=0.00427[/tex]

Hence, the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427

Answer:

- 1 - 3(5m + 8) ≥ -85

-1 - 15m - 24 ≥ -85

-15m ≥ -85 + 1 + 24

-15m ≥ 25 - 85

-15m ≥ -60

(-1)(-15)m ≤ -60(-1)

15m ≤ 60

m ≤ 4

Decimals start at tenths, then hundredths, then thousandths, and so on. When we round, we look at the place value that is one smaller than the one we want to round to.

So, let's take a look at the thousandths place in 0.485. The value in the thousandths place is 5. When rounding, if the value is 5 or over we round up and if the value is 4 or lower we round down. Since the value in the thousandths place is 5, we will round the hundredths place up one.

0.485 rounded to the nearest hundredth is 0.49

Hope this helps!

Answer:

0.49

Step-by-step explanation:

[tex]0<x<5=[/tex] Round down

[tex]x\geq5=[/tex] Round up

In this case, it's a round up, so the answer would be...

0.49

Hope this helped! Please mark brainliest!

Answer:

[tex]y = 32 - \frac{1}{2}x[/tex]

Step-by-step explanation:

Given

[tex]Cups = 32[/tex] ---- not 52

[tex]Students = x[/tex]

[tex]Remainder = y[/tex]

[tex]Each = \frac{1}{2}[/tex] --- not z

Required

The equation for y

The remainder y is calculated as:

[tex]y = Cups - Students * Each\\[/tex]

[tex]y = 32 - \frac{1}{2}x[/tex]

Answer:

w= 103.5 inches

Step-by-step explanation:

384=w+3w-30

414=4w

w=414/4=103.5 inches

Answer:

first drop box 384

second drop box 3

third drop boc 30

384 = 3 [tex]w^{2}[/tex] – 30 w

Step-by-step explanation:

Correct answer on Plato/Edmentum test

Answer: 3x - 2

Step-by-step explanation:

First to solve this, we need to know some basic information such as:

1. (-) × (-) = +

2. (+) × (-) = -

3. (+) × (+) = +

Therefore, 6x-(3x+2)​

= 6x - 3x - 2

= 3x - 2

The answer to the question after removing the bracket will be 3x - 2.

Looking at Point A to A', the rectangle moves 5 places to the left which is the x value + 5 and it shifts 1 place down which would be the y value - 1

This gets written as:

(x+5, y-1)

Hello!

x² + 6x + 1 = 0 <=>

<=> x = -6±√6²-4×1×1/2×1 <=>

<=> x = -6±√36-4/2 <=>

<=> x = -6±√32/2 <=>

<=> x = -6±2²√2/2 <=>

<=> x = -6±4√2/2 <=>

<=> x = -6+4√2/2 <=>

and

<=> x = -6-4√2/2 <=>

<=> x = -3+2√2 <=>

and

<=> x = -3-2√2 <=>

x1 = -3-2√2 and x2 = -3+2√2

Good luck! :)

9514 1404 393

Answer:

  (b)  He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.

Step-by-step explanation:

Newton's Law of Cooling says the change in temperature is proportional to the temperature. This relation gives rise to an exponential function describing the temperature.

In this description, the temperature referred to is the difference between the temperature of the object and the temperature of the environment to/from which heat is being transferred.

Juan is only partially correct. The function is exponential, but the temperature that should be used in his equation is not the temperature of the tea, but the temperature difference between the tea and his desk.

__

The curve is not linear and not parabolic, excluding the other answer choices.

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]V=1000\text{mm}^3[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

I am assuming by the infomation given that the figure is a cube.

⸻⸻⸻⸻

[tex]\boxed{\text{Finding the volume of the cube...}}\\\\S = 10mm; V= s^3\\--------------\\\rightarrow V = 10^3\\\\\rightarrow V = 10 * 10 * 10\\\\\rightarrow \boxed{V=1000\text{mm}^3}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Hello,

[tex]if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\[/tex]

We suppose the property true for n:

1²+2²+...+n²=n(n+1)(2n+1) / 6

and we are going to demonstrate that the property is true for n+1:

1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6

[tex]1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\[/tex]

Answer:

[tex]-5 \to -24[/tex]

[tex]-1 \to -4[/tex]

[tex]2 \to 11[/tex]

[tex]3 \to 16[/tex]

[tex]4 \to 21[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 5x + 1[/tex]

Required

Complete the table (see attachment)

When x = -5

[tex]f(-5) = 5 * -5 + 1 = -24[/tex]

When x = -1

[tex]f(-1) = 5 * -1 + 1 = -4[/tex]

When x = 2

[tex]f(2) = 5 * 2 + 1 = 11[/tex]

When x = 3

[tex]f(3) = 5 * 3 + 1 = 16[/tex]

When x = 4

[tex]f(4) = 5 * 4 + 1 = 21[/tex]

So, the table is:

[tex]-5 \to -24[/tex]

[tex]-1 \to -4[/tex]

[tex]2 \to 11[/tex]

[tex]3 \to 16[/tex]

[tex]4 \to 21[/tex]