Answers
Answer:
Step-by-step explanation:
+ At time 0 (beginning), the volume is 5 (feet^3) of sand.
+ After 1 minute, it lefts: 90% of 5 = 0.9*5
+ After 2 minutes, it left 90% of (0.9*5) = 0.9*(0.9*5)
or
[tex]5.(0.9)^{2}[/tex]
+ After 3 minutes, it left 90% of [tex]5.(0.9)^{2}[/tex]
or
[tex]5.(0.9)^{3}[/tex]
.......
+ After x minutes, it left 90% of [tex]5.(0.9)^{x-1}[/tex]
or
[tex]5.(0.9)^{x}[/tex]
So the answer is [tex]5.(0.9)^{x}[/tex], that means C
Related Questions
Identify the graph of the equation... Then find q to the nearest degree.
16x^2+2xy+y^2-16=0
Answers
Answer:
ellipse ; 4 degrees
Step-by-step explanation:
edge’s possible answer 2020
Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. White. Gus, their boss, is tired of Mr. White’s negative attitude and is thinking about "firing" him and keeping only Jesse on the payroll. The problem, however, is that Mr. White seems to produce a higher quality sauce whenever he is in charge of production if compared to Jesse. Before making a final decision, Gus collected some data measuring the quality of different batches of sauce produced by Mr. White and Jesse. We assume the quality measurements for both of them are normally distributed with the common variance. The results, measured on a quality scale, are listed below:
Mr. White 97 1 7
Jesse 94 3 10
a. Based on this data, can we tell for sure (with 95% confidence) which one is the better chemist?
b. Gus wants to keep the mean quality score for the sauce above 90. In this case, can he can rid of Mr. White, i.e., is Jesse good enough to run the sauce production?
Answers
Answer:
Check the explanation
Step-by-step explanation:
Let [tex]\overline{x}[/tex] and [tex]\overline{y}[/tex] be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume [tex]\overline{x}[/tex] having with mean [tex]\mu_{1}[/tex] and [tex]\overline{y}[/tex] having mean [tex]\mu_{2}[/tex]
Also we have given the variance is constant
A)
We can test hypothesis as
[tex]H0: \mu_{1} = \mu_{2}H1: \mu_{1} > \mu_{2}[/tex]
For this problem
Test statistic is
[tex]T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}[/tex]
Where
[tex]s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}[/tex]
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
1. To measure the resting heart rate of an animal biologist use the function h(m) = 530m-C), where h
is resting heart rate in beats per minute, given the mass m in pounds.
Part A: What is a feasible domain for the function him?
Answers
Answer:
Step-by-step explanation:
In mathematics, the domain or set of departure of a function is the set into which all of the input of the function is constrained to fall. It is the set X in the notation f: X → Y. Since a function is defined on its entire domain, its domain coincides with its domain of definition, the subset of the domain for which the function associates an image. However this coincidence is no longer true for a partial function since the domain of definition of a partial function can be a proper subset of the domain.
Zoe says an equilateral triangle is always an acute triangle, but an acute triangle is never an equilateral triangle. Which statement explains whether Zoe is correct or not?
Zoe is not correct because equilateral triangles are acute triangles with three sides of equal length. Acute triangles can sometimes be equilateral triangles.
Zoe is not correct because equilateral triangles have three acute angles. Acute triangles have three acute angles, so acute triangles are always equilateral triangles.
Zoe is correct because equilateral triangles have three sides of equal length, and acute triangles have three sides of different lengths.
Zoe is correct because equilateral triangles have three acute angles. Acute triangles have one acute angle, so an acute triangle cannot be an equilateral triangle.
THE ANSWER IS NOT C
Answers
Answer:
Zoe is not correct because equilateral triangles are acute triangles with three sides of equal length. Acute triangles can sometimes be equilateral triangles.
Step-by-step explanation:
Logically, it makes no sense for Zoe to say, in effect, ...
"All E are A, but A are never E."
That is incorrect on its face. At least, it means that "sometimes A are E."
__
The appropriate choice is the first one:
Zoe is not correct because equilateral triangles are acute triangles with three sides of equal length. Acute triangles can sometimes be equilateral triangles.
Find the sum of the geometric series 1−0.99+0.99^2−0.99 ^3 +...−0.99
Answers
Answer:
0.28
Step-by-step explanation:
The sum of the geometric value progression is S = 0.28
What is Geometric Progression?A geometric progression is a sequence in which each term is derived by multiplying or dividing the preceding term by a fixed number called the common ratio.
The nth term of a GP is aₙ = arⁿ⁻¹
The general form of a GP is a, ar, ar2, ar3 and so on
Sum of first n terms of a GP is Sₙ = a(rⁿ-1) / ( r - 1 )
Given data ,
Let the sequence be A = { 1 - 0.99 + 0.99² - 0.99³... - 0.99⁷⁹ }
So , A = 1 - { 0.99 - 0.99² + 0.99³... + 0.99⁷⁹ }
Let the first term of the GP be a₁ = 0.99
Now , the common ratio of GP , r = 0.99
And , the number of terms in GP = 80
And , Sum of first n terms of a GP is Sₙ = a(rⁿ-1) / ( r - 1 )
On simplifying , we get
S₈₀ = 0.99 ( 1 - 0.99⁸⁰ ) ( 1 - 0.99 )
On further simplification , we get
S₈₀ = 0.7224
So , the sum of the GP is S = 1 - S₈₀ = 0.28
Hence , the sum of GP is 0.28
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Given the equation StartFraction 2 x + 2 Over y EndFraction = 4 w + 2 what is the value of x?
Answers
Question:
Given the equation (2x + 2)/y = 4w + 2.
What is the value of x?
Answer:
x = 2wy + y - 1
Step-by-step explanation:
Given
(2x + 2)/y = 4w + 2
Required
Find x
To find the value of x; the following steps will be used.
First, Multiply both sides by y
y * (2x + 2)/y = (4w + 2) * y
2x + 2 = 4wy + 2y
Subtract 2 from both sides
2x + 2 - 2 = 4wy + 2y - 2
2x = 4wy + 2y - 2
Multiply both sides by ½
½ * 2x = ½(4wy + 2y - 2)
x = ½(4wy + 2y - 2)
Open bracket
x = ½ * 4wy + ½ * 2y - ½ * 2
x = 2wy + y - 1
Hence, the value of x is 2wy + y - 1
Answer:
B
Step-by-step explanation:
I took the test
When you cough,the radius of your trachea (windpipe) decreases,affecting the speed S of the air in the trachea. If r0 is the normal radius of the trachea, the relationship between the speed S of the air and the radius r of the trachea during a cough is given by a function of the form
S(r) = (r0 - r) ar^2
where a is positive constant. Find the radius r for which the speed of the air is greatest.
Answers
Answer: 2r(0)/3.
Step-by-step explanation:
So, we are given one Important data or o or parameter in the question above and that is the function of the form which is given below(that is);
S(r) = (r0 - r) ar^2 -----------------------------(1).
We will now have to differentiate S(r) with respect to r, so, check below for the differentiation:
dS/dr = 2ar (r0 - r ) + ar^2 (-1 ) ---------;(2).
dS/dr = 2ar(r0) - 2ar^2 - ar^2.
dS/dr = - 3ar^2 + 2ar(r0) ------------------(3).
Note that dS/dr = 0.
Hence, - 3ar^2 + 2ar(r0) = 0.
Making ra the subject of the formula we have;
ra[ - 3r + 2r(0) ] = 0. -------------------------(4).
Hence, r = 0 and r = 2r(0) / 3.
If we take the second derivative of S(r) too, we will have;
d^2S/dr = -6ar + 2ar(0). -------------------(5).
+ 2ar(0) > 0 for r = 0; and r = 2r(0)/3 which is the greatest.
Answer:
[tex]r =\frac{2r_{0}}{3}[/tex]
Step-by-step explanation:
We need to take the derivative of S(r) and equal to zero to maximize the function. In this conditions we will find the radius r for which the speed of the air is greatest.
Let's take the derivative:
[tex]\frac{dS}{dr}=a(2r(r_{0}-r)+r^{2}(-1))[/tex]
[tex]\frac{dS}{dr}=a(2r*r_{0}-2r^{2}-r^{2})[/tex]
[tex]\frac{dS}{dr}=a(2r*r_{0}-3r^{2})[/tex]
[tex]\frac{dS}{dr}=ar(2r_{0}-3r)[/tex]
Let's equal it to zero, to maximize S.
[tex]0=ar(2r_{0}-3r)[/tex]
We will have two solutions:
[tex]r = 0[/tex]
[tex]r =\frac{2r_{0}}{3}[/tex]
Therefore the value of r for which the speed of the air is greatest is [tex]r =\frac{2r_{0}}{3}[/tex].
I hope it helps you!
On the first day of school, each student is given $0.50 to attend. On day two, each student earns $1.00. on day 3, $2.00, etc. How much do students earn on the 9th day
Answers
Answer:
255.50
Step-by-step explanation:
If each day the number is doubled, then all you must do is keep on doubling to the ninth day and then add it all together
day 2- $1.00
day 3- $2.00
this means every day the amount each student is given doubles from the day before.
day 4- $4.00
day 5- $8.00
day 6- $16.00
day 7- $32.00
day 8- $64.00
day 9- $128.00
so on the 9th day the students would earn $128.00
day 9- $128.00
PLEASE ANSWER AS QUICKLY AS POSSIBLE
Answers
Answer: D
Step-by-step explanation: Both the Equality property and the Identity property
If h = 85 cm and 1 = 36 cm, what is the length of g?
A. 77 cm
B.
92 cm
C
49 cm
D
75 cm
Answers
Answer:A
Step-by-step explanation:
h=85 f=36
Since it is a right angled triangle we can apply Pythagoras principle to get g
g=√(h^2 - f^2)
g=√(85^2 - 36^2)
g=√(85x85 - 36x36)
g=√(7225 - 1296)
g=√(5929)
g=77
what is (4 to the square root of 81)5?
Answers
Answer:
1310720
Step-by-step explanation:
Find out the frist part "4 to the square root of 81" 262144
then times it by 5
to get 1310720
Find the volume of a block of woods
Answers
Answer:volume=125 cm^3
Surface area=150 cm^2
Step-by-step explanation:
Part A:
volume=length x width x height
volume=5 x 5 x 5
Volume=125 cm^3
Part B:
Surface area=6x5x5
Surface area=150 cm^2
A 4-foot long steel pipe consists of two concentric cylinders, with the inner cylinder hollowed
out. The radius of the outside of the pipe is 6 inches and the radius of the inside of the pipe
is 5.75 inches.
HINT: The units of measure must be the same! Convert to inches and keep your answer in
terms of π.
A. Determine the volume of metal used to build the pipe.
B. If the pipe is to be powder-coated on the inside and outside surfaces, what is the total
surface area to be powder-coated?
Answers
Answer:
The pipe is formed by two concentric cylinders.The outside cylinder has 6 inches of radius.The inside cylinder has 5.75 inches of radius.To find the volume of the pipe, we need to subtract the inside cylinder volume from the outside cylinder volume.
Remember that the volume of a circular cylinder is
[tex]V=\pi r^{2} h[/tex]
Where [tex]r[/tex] is the radius and [tex]h[/tex] is the height.
Outside cylinder volume.[tex]V_{outside}=\pi r^{2}h= \pi (6in)^{2} (48in)=1,728 \pi in^{3}[/tex]
Inside cylinder volume.[tex]V_{inside}=\pi r^{2}h= \pi (5.75in)^{2} (48in)=1,587 \pi in^{3}[/tex]
Notice that we used the height 4 feet in inches units, that's why the height in the formulas is 48 inches, because each feet is equivalent to 12 inches.
Volume of the pipe.[tex]V_{pipe}=V_{outside} -V_{inside} =1,728 \pi in^{3}-1,587 \pi in^{3} =141 \pi in^{3}[/tex]
(A) Therefore, the volume of metal used to build the pipe is 141π cubic inches.
Now, to know the amount of powder-coat we must use, we need to find the surface area of the pipe, which is basically the sum of the surface area of both cylinders.
Surface area of outside cylinder.[tex]S_{outside}=2\pi r^{2}+2\pi rh=2 \pi (6in)^{2}+2 \pi (6in)(48in)= 72 \pi in^{2} +576 \pi in^{2} =648 \pi in^{2}[/tex]Surface area of the inside cylinder.[tex]S_{inside}=2\pi r^{2}+2\pi rh=2 \pi (5.75in)^{2}+ 2 \pi (5.75in) (48in)= 66.13 \pi in^{2} +552 \pi in^{2} =618.13 \pi in^{2}[/tex]
The total surface is[tex]S_{powder}=648 \pi in^{2} + 618.13 \pi in^{2} =1,266.13 \pi in^{2}[/tex]
(B) Therefore, we need 1,266.13π sqaure inches of powder to cover the whole pipe.
Answer:
A. volume of the metal used to build the pipe is 141[tex]\pi[/tex] cubic inches.
B. The total surface area to be powder coated is 1122.125 square inches.
Step-by-step explanation:
The length of the cylinder = 4 feet = 48 inches.
Radius of the outside of the pipe = 6 inches.
Radius of the inside of the pipe = 5.75 inches
A. volume of the metal used to build the pipe = volume of the outside pipe - volume of the inside pipe
volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
volume of the outside pipe = [tex]\pi[/tex][tex]r^{2}[/tex]h
= [tex]\pi[/tex] × [tex]6^{2}[/tex] × 48
= 1728[tex]\pi[/tex] cubic inches
volume of the inside pipe = [tex]\pi[/tex][tex]r^{2}[/tex]h
= [tex]\pi[/tex] × [tex]5.75^{2}[/tex] × 48
= 1587[tex]\pi[/tex] cubic inches
volume of the metal used to build the pipe = 1728[tex]\pi[/tex] - 1587[tex]\pi[/tex]
= 141[tex]\pi[/tex] cubic inches
B. Total surface area of a hollow cylinder = 2[tex]\pi[/tex] ( [tex]r_{1}[/tex] + [tex]r_{2}[/tex]) ( [tex]r_{2}[/tex] - [tex]r_{1}[/tex] + h)
where [tex]r_{1}[/tex] is the inner radius and [tex]r_{2}[/tex] is the outer radius.
= 2[tex]\pi[/tex] (6 + 5.75)(5.75 - 6 + 48)
= 2[tex]\pi[/tex] (11.75 × 47.75)
= 1122.125[tex]\pi[/tex] square inches
The total surface area to be powder coated is 1122.125 square inches.
A physical education class has 21 boys and 9 girls. Each day, the teacher randomly selects a team captain. Assume that no student is absent. What is the probability that the team captain is a girl two days in a row?
The probability of choosing a captain that is a girl two days in a row is
9
%.
Answers
Answer:9%
U already provided the answer. Anyways have a good day!!
The probability of choosing a captain that is a girl two days in a row is 9%
How to determine the probability?The given parameters are:
Boys = 21
Girls = 9
The total number of students is
Total = 21 + 9
Total = 30
This means that the probability of selecting a girl is:
P(Girl) = 9/30
For two days, the required probability is
P = 9/30 * 9/30
Evaluate
P = 9%
Hence, the probability of choosing a captain that is a girl two days in a row is 9%
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GIVING BRANLIEST Which prism has a greater surface area?
2 prisms. A rectangular prism has a length of 12 inches, height of 8 inches, and width of 6 inches. A triangular prism has a rectangular base with a length of 6 inches and height of 12 inches. 2 rectangular sides are 12 inches by 10 inches. The triangular sides have a base of 6 inches an height of 8 inches.
The rectangular prism has a greater surface area by 72 square inches.
The rectangular prism has a greater surface area by 88 square inches.
The triangular prism has a greater surface area by 72 square inches.
The triangular prism has a greater surface area by 88 square inches.
Answers
Answer:
Rectangular prism
Step-by-step explanation:
Calcula el 23 % de 175
Answers
Answer:40.25
Step-by-step explanation:
23% of 175
23/100 x 175
(23 x 175)/100
4025/100=40.25
x^2 = 8x - 15
.......................
Answers
Answer: x= 5
Step-by-step explanation: Lets solve by completing the square.
You first need to get -15 by itself.
x^2-8x=15 Now you need to complete the square my finding a perfect constant that will go with x^2-8x, then add it to the other side containing -15 to balance the equation out.
-8x/2= -4^2=16 This will be the perfect square.
x^2-8x+16 = -15 + 16
(x-4)^2 = 1 factor into a binomial, then use the square root on both sides.
√ x-4 ^ 2 = √ 1
x-4 = 1
x=5
The diameter of a circular placement is 42 centimeters what is the approximate area of the circular placement
Answers
Which equation represents a nonlinear function?
A) y=2(x-1)+5
B)y=5x(x-2)
C) y=5x-2
D)y=2x(5-1)
Answers
Answer:
B.)
Step-by-step explanation:
A linear equation, remember, is y = mx + b.
Identify.
A.) y = 2x + 3
B.) y = 5x^2 - 10x
C.) y = 5x - 2
D.) y = 8x
Eliminate.
Obviously, B.) is not correct because it doesn't follow the y = mx + b format because 5x is squared.
Hope that helped.
Find the prime factorization of the integer -32
Answers
Answer:-32=-2 x -2 x -2 x -2 x -2
Step-by-step explanation:
-32=-2 x -2 x -2 x -2 x -2
what is the equation of the line?
Answers
Answer:
y=a
Step-by-step explanation:
Given f(x) = -4x + 7 and g(x) = x, choose
the expression for (fºg)(x).
Answers
Answer:
-4x^2+7x
Step-by-step explanation:
Multiply -4x+7 and x.
You get -4x^2+7x.
In ΔKLM, the measure of ∠M=90°, KM = 48, LK = 73, and ML = 55. What ratio represents the cosine of ∠L?
Answers
Answer:
cos L = 55/73
Step-by-step explanation:
The triangle KLM is a right angle triangle. The ∠M = 90°. The side KM = 48, LK = 73, and ML = 55. The ratio that represents the cosine of ∠L can be solved below.
The right angle triangle formed has an hypotenuse , opposite and an adjacent side. Using the SOHCAHTOA principle one can find the ratio that represent the cosine of ∠L.
opposite side = 48
adjacent = 55
hypotenuse = 73
cos L = adjacent/hypotenuse
cos L = 55/73
Pls answer this I give brainliest thank you! Number 2
Answers
Answer:
D
Step by Step Explanation:
To find the volume of a cube, you need to cube the side length. In this case, since the side length is 8, the volume is 8^3=512 cubic inches, or answer choice D. Hope this helps!
i will rate you
brainliest PLZ HELP
You will get 25 points
Answers
Answer:
i can not see the picture can you describe it
Step-by-step explanation:
Find the area of the shaded region and choose the appropriate result?
Answers
Answer:
Option B
Step-by-step explanation:
The figures are made out of squares.
[tex]\text {Formula for area of a square: } A =s^2\\s-\text {Length of side.}[/tex]
Square 1 (the gray square):
The side measure is 4 cm.
[tex]A = 4^2 = 16cm^2[/tex]
Square 2 (white square):
The side measure is 2 cm.
[tex]A=2^2=4cm^2[/tex]
Subtract the area of the white square from the gray square to get the area of the shaded region:
[tex]16 - 4 =12[/tex]
The shaded region is [tex]12cm^2[/tex].
Option B should be the correct answer.
Brainilest Appreciated!
Which goes with which
Answers
A G.P has a common ratio of 2 find the value of 'n' for which the sum 2n terms is 33 times the sum of n?
Answers
n
= na.
(ii)When the numerical value of r is less than 1 (i.e., - 1 < r < 1), then the formula Sn
n
= a(1−rn)(1−r)
(
1
−
r
n
)
(
1
−
r
)
is used.
(iii) When the numerical value of r is greater than 1 (i.e., r > 1 or, r < -1) then the formula Sn
n
= a(rn−1)(r−1)
(
r
n
−
1
)
(
r
−
1
)
is used.
(iv) When r = 1, then Sn
n
= a + a + a + a + a + .................... to n terms = na.
(v) If l is the last term of the Geometric Progression, then l = arn−1
n
−
1
.
Therefore, Sn
n
= a(1−rn1−r
1
−
r
n
1
−
r
) = (a−arn1−r
a
−
a
r
n
1
−
r
) = a−(arn−1)r(1−r)
a
−
(
a
r
n
−
1
)
r
(
1
−
r
)
= a−lr1−r
a
−
l
r
1
−
r
Thus, Sn
n
= a−lr1−r
a
−
l
r
1
−
r
Or, Sn
n
= lr−ar−1
l
r
−
a
r
−
1
, r ≠ 1.
The diameter of a cylindrical water tank is 8 ft, and its height is 9 ft. What is the volume of the tank?
Use the value 3.14 for it, and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
Answers
Answer:
The volume of the tank is [tex]452\ \text{feet}^3[/tex].
Step-by-step explanation:
We have,
Diameter of a cylindrical water tank is 8 ft
Height of the water tank is 9 ft.
It is required to find the volume of the tank. The volume of a cylindrical shaped object is given by :
[tex]V=\pi r^2h[/tex]
r is radius of cylindrical tank, r = 4 ft
Plugging all the values in above formula,
[tex]V=3.14\times (4)^2\times 9\\\\V=452.16\ \text{feet}^3[/tex]
or
[tex]V=452\ \text{feet}^3[/tex]
So, the volume of the tank is [tex]452\ \text{feet}^3[/tex].
8 cm
Answer:
cm
Part B
Find circumference of the circle. Use
= 3.14.
A 25. 12 cm
B 50.24 cm
C 73.06 cm
D
200.96 cm
Answers
Answer:
D.200.96 cm
Step-by-step explanation:
Given radius (R) = 8
Diameter = 2R = 16
Circumference = 2πR
= 16π
= 50.265482457437
Area = πR2
= 64π
= 201.06192982975
