Will mark brainliest!!!Solve for each variable

Answer:

x>3

Step-by-step explanation:

3x+2>x+8

   -2      -2

3x>x+6

-x    -x

2x>6

/2   /2

x>3

The solution of the inequality 3x+2>x+8 will be x>3. The correct option is A.

When two expressions are connected by a sign like "not equal to," "greater than," or "less than," it is said to be inequitable. The inequality shows the greater than and less than relationship between variables and the numbers.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that inequality is  3x+2>x+8. The inequality will be solved as below,

3x+2>x+8

3x>x+6

2x>6

x>3

Hence, the solution is x>3.

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Answer:

pure out 8 gallons

Step-by-step explanation:

Im big brain.

Step-by-step explanation:

removing 8 gallons of water from a fish tank

Answer:

i think it is 20

Step-by-step explanation:

i hope it help

Answer:

1 is false

2 is blueprints

Step-by-step explanation:

Answer:

[tex]g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}[/tex]

Step-by-step explanation:

The inverse of a function has [tex]x[/tex] and [tex]y[/tex] values switched from the original function. Therefore, simply switch [tex]x[/tex] and [tex]y[/tex] and isolate [tex]y[/tex] to get your inverse function:

Original function: [tex]g(x)=41x^3+a[/tex]

Switching [tex]x[/tex] and [tex]y[/tex], then isolating [tex]y[/tex]:

[tex]x=41y^3+a,\\x-a=41y^3,\\\frac{x-a}{41}=y^3,\\y=\sqrt[3]{\frac{x-a}{41}}[/tex].

Therefore, the inverse of the [tex]g(x)=41x^3+a[/tex] is:

[tex]\fbox{$g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}$}[/tex].

Answer: c. R OR E

e. R′

f. E

Step-by-step explanation:

Outcomes for Red card ={1,2,3,4,5,6} = 6

Outcomes of Blue card = {1,2,3} =3

R = event of drawing a red card, B = event of drawing a blue card, E=event of drawing an even numbered card, and O = event of drawing an odd card.

Then, R= {1R,2R,3R,4R,5R,6R} , B= {1B,2B,3B}

E={2R, 4R, 6R , 2B}

O = {1R, 3R, 5R, 3B}

R or O = { 1R,2R,3R,4R,5R,6R ,3B}   [all elements of R and O]

B and O = {3B}             [all elements common in B and O]

R or E = {1R,2R,3R,4R,5R,6R,2B }

R and O = {1R, 3R, 5R}  [all elements common in R and O]

R' = B= {1B,2B,3B}     [all elements except R]

Blue 2 = 2B belongs to B, R or E, R' and E.

Correct options are c. e. f.

Answer:

Blue 3

E'

B AND O

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

The graph has a normal distribution, mean at 3.6, and a standard deviation of 0.6

Answer:

the Correct Answer Is c

Step-by-step explanation:

PLZ PLZ PLZ MARK AS BRAINLIEST LOL PLZ

Answer:

B

Step-by-step explanation:

Answer:

b incorrect sentences

Step-by-step explanation:

got it right on my test

Answer: For 25% put the smallest one and for 60% put the one with blue shaded over six lines not included 0 line the small lines bye

Step-by-step explanation:

no no no no no

Answer:

I hope this helps.

Step-by-step explanation:

h(t) = -16t2 + 108t + 28

(a)

Maximum height occurs at the vertex of the height-vs.-time parabola, which is at

t = -108/[2(-16)] sec = ? sec

Evaluate h(t) at this value of t to get hmax.

(b)

Set h(t) = 0 and solve the quadratic equation for t.  You will get a positive and a negative solution.  Discard the negative solution, since time starts at t = 0.

The quadratic function, h = -16t + 136t + 72, gives us:

a) The maximum height of the ball is 360 feet.

b) The time taken by the ball to hit the ground is 9 seconds.

A quadratic function is a function over a quadratic expression, that is, over an expression having degree 2.

In the question, we are informed that a person standing close to the edge of a 72-foot building throws a ball vertically upward. The quadratic function h = -16t² + 136t + 72 models the ball's height above the ground, h in feet, t seconds after it was thrown.

We solve the following:-

a) What is the maximum height of the ball?

The maximum height of the ball can be obtained by differentiating the given quadratic function, h = -16t² + 136t + 72.

Differentiating both sides. we get:

[tex]\frac{\delta h}{\delta t} = -32t + 136[/tex] .

To get point of inflection, we equate this to 0, to get:

[tex]\frac{\delta h}{\delta t} = -32t + 136 = 0[/tex],

or, -32t + 136 = 0,

or, t = 136/32 = 4.5.

To check whether the value of h is maximum/minimum at t = 4.5, we differentiate [tex]\frac{\delta h}{\delta t} = -32t + 136[/tex] again, to get:

[tex]\frac{\delta^{2} h}{\delta t^{2} } = -32[/tex] , which is < 0, which that implies, h is maximum at t = 4.5.

Now, we calculate the maximum height, by putting in t = 4.5, in the equation, to get:

h = -16(4.5)² + 136(4.5) + 72,

or, h = -16(20.25) + 612 + 72,

or, h = -324 + 684 = 360.

Therefore, The maximum height of the ball is 360 feet.

b) How many seconds does it take until the ball hits the ground?

The time taken can be calculated by putting the value of h = 0, and solving the quadratic function h = -16t² + 136t + 72, as the height of the ball at the ground is 0.

Therefore, it can be written as:

0 = -16t² + 136t + 72.

or, 16t² - 136t - 72 = 0.

Solving this using the quadratic equation, we get:

[tex]t = \frac{-(-136)\pm \sqrt{(-136)^{2} - 4(16)(-72)}}{2(16)}[/tex] ,

or, [tex]t = \frac{136\pm \sqrt{18496 + 4608}}{32}[/tex] ,

or, [tex]t = \frac{136\pm \sqrt{23104}}{32}[/tex] ,

or, [tex]t = \frac{136\pm 52}{32}[/tex]

Therefore, either t = (136+152)/32 = 9,

or, t  (136 - 152)/32 = -0.5.

Since t represents time, we won't take the negative value, and hence t = 9.

Therefore, The time taken by the ball to hit the ground is 9 seconds.

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Answer:

A 4040 bag sample 25.0425.0 grams. A level of significance of 0.020.02

the decision rule. Assume the standard deviation is known to be 11.011.0.

Step-by-step explanation:

Answer: D

Step-by-step explanation:

Answer:

1. 29.67°

2. 68.96°

3. 89.85°

Step-by-step explanation:

1. Reference angle = x

Opposite = 45 cm

Adjacent = 79 cm

Therefore:

[tex] tan(x) = \frac{45}{79} [/tex]

[tex] tan(x) = 0.569620253 [/tex]

[tex] x = tan^{-1}(0.569620253) [/tex]

[tex] x = 29.67 [/tex] (nearest hundredth)

2. Reference angle = B

Opposite = 14

Hypotenuse = 15

Therefore:

[tex] sin(B) = \frac{14}{15} [/tex]

[tex] sin(B) = 0.93333 [/tex]

[tex] B = sin^{-1}(0.93333) [/tex]

[tex] B = 68.96 [/tex] (nearest hundredth)

3. Reference angle = x

Adjacent = 238,900 mi

Hypotenuse = 92,955,807 mi

Therefore:

[tex] cos(x) = \frac{238,900}{92,955,807} [/tex]

[tex] x = cos^{-1}(\frac{238,900}{92,955,807}) [/tex]

[tex] x = 89.85 [/tex] (nearest hundredth)

If Angle A is 71°, E is 355°.

Answer:

Angle E: 289

Step-by-step explanation:

If there are only 2 angles, and they would add up to be 360, then it is 289.

Just subtract 360-71 to get 289

Answer at the bottom

Step 1: Simplify both sides of the equation.

4x−7x=34−55

4x+−7x=34+−55

(4x+−7x)=(34+−55)(Combine Like Terms)

−3x=−21

−3x=−21

Step 2: Divide both sides by -3.

−3x

−3

=

−21

−3

x=7

Answer:

x=7

Answer:

The answer is 0.

Step-by-step explanation:

solve 9+5=14

14/7=2

2-2=0

solve the pther side

25-20=5

4*5=20

0*20=0

Answer:

m < 1 = 52

m < 3 = 52

Step-by-step explanation:

m < 8 = 128 therefore m < 4 = 128

1.) we know that m < 4 + m < 1 must equal 180

128 + m < 1 = 180

180 - 128 = m < 1

52 = m < 1

due to the position of m < 1 and m < 3, they are the exact same

Answer:

110.835389 ft3

Step-by-step explanation:

Answer:

The house is 18.75 feet tall

Step-by-step explanation:

The triangles are similar by the AA postulate.  

We are given the length of the bottom sides of the triangles, 4 and 15 respectively.  

Thus, the ratio is 4:15

We are also given the height of Annie's eyes, which is 5 feet. The height of the side that corresponds to the house is 5, so we can set up a proportion.

[tex]\frac{4}{15} = \frac{5}{x} \\4x = (5*15) = 75\\x = \frac{74}{4} \\x = 18.75[/tex]

Thus, the house is 18.75 feet tall.

Answer:

[tex]\mathbf{4 \lim \limits _{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n(n+4i)}{2n^3 +(n+4i)^3} \Big )}[/tex]

Step-by-step explanation:

Given integral:

[tex]\int ^5_1 \dfrac{x}{2+x^3} \ dx[/tex]

[tex]\mathbf{Using \ Riemann \ sums; \ we \ have: }[/tex]

[tex]\int ^b_a \ f(x) \ dx = \lim_{n \to \infty} \sum \limits ^n_{i =1} \ f( a + i \Delta x) \Delta x[/tex]

[tex]here; \ \Delta x = \dfrac{b-a}{n}[/tex]

∴

[tex]\int ^5_1 \dfrac{x}{2+x^3} \ dx = f(x) = \dfrac{x}{2+x^3}[/tex]

[tex]\implies \Delta x = \dfrac{5-1}{n} =\dfrac{4}{n}[/tex]

[tex]f(a + i \Delta x ) = f ( 1 + \dfrac{4i}{n})[/tex]

[tex]f( 1 + \dfrac{4i}{n}) = \dfrac{n^2 ( n+4i)}{2n^3 + (n + 4i)^3}[/tex]

[tex]\lim_{n \to \infty} \sum \limits ^n_{i=1} \ f(a + i \Delta x) \Delta x = \lim_{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n^2(n+4i)}{2n^3 +(n+4i)^3} \Big )\dfrac{4}{n}[/tex]

[tex]\mathbf{= 4 \lim \limits _{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n(n+4i)}{2n^3 +(n+4i)^3} \Big )}[/tex]

Answer: continuous random variable.

Step-by-step explanation:

A discrete random variable is defined as a random variable which consists of countable number. Examples include numbers of shoes, number of sales etc.

A continuous random variable is a random variable whereby the data can take several values. It is a random variable that takes time into consideration.

Therefore, the amount of time six randomly selected volleyball players play during a game will be a continuous random variable since time so involved.

Answer:

1. 90

2. 61

3. 29

4. 61

Step-by-step explanation:

1 is a 90 degree angle. Triangles = 180 degrees