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Answer:

12 units

Step-by-step explanation:

Since all of the sides of a rhombus are congruent, JK = JM which means:

2x + 4 = 3x

-x = -4

x = 4 so 3x = 3 * 4 = 12

Answer:

d=55(t+0.5)

Step-by-step explanation:

d=55(t+0.5)

Answer:

27.5

Step-by-step explanation:

Answer: x=60°

Step-by-step explanation:

The sum of the angles of a triangle is 180°. With this, we can find x°.

33+87+x=180                         [combine like terms]

120+x=180                               [subtact both sides by 120]

x=60°

Answer:

60 degrees

Step-by-step explanation:

All the angles in a triangle add up to 180 degrees.

We know two angles, 33 degrees and 87 degrees.

Now we have to find the last one.

So we make an equation to solve this.

33 + 87 + x = 180

120 + x = 180

Subtracting 120 fr0m both sides get us,

120 - 120 + x = 180 -120

x = 60

60 degrees

We can check by adding all three angles by substituting 60 for x,

33 + 87 + 60 = 120 + 60 = 180 degrees

Answer:

Sample size n [tex]\simeq[/tex] 1269.15

Step-by-step explanation:

From the information given ,

At 99% of confidence interval,

the level of significance ∝ = 1 - 0.99

the level of significance ∝ =  0.01

the critical value for 99% of confidence interval is:

[tex]\mathtt{\dfrac{\alpha }{2} = \dfrac{0.01}{2}}[/tex]

= 0.005

[tex]\mathtt {z_{\alpha/2} = z_{0.005/2} }[/tex]

The value for z from the standard normal tables

= 2.58

The Margin of error E= 3% = 0.03

The formula to  determine the sample size n used can be expressed as follows:

[tex]\mathtt { n = (\dfrac{z_{\alpha/2}}{E})^2 \ \hat p (1 - \hat p) }[/tex]

where;

[tex]\mathtt{\hat p }[/tex] = 22% = 0.22

Then:

[tex]\mathtt { n = (\dfrac{2.58}{0.03})^2 \ \times 0.22 \times (1 - 0.22) }[/tex]

[tex]\mathtt { n = (86)^2 \ \times 0.22 \times (0.78) }[/tex]

[tex]\mathtt { n = 7396 \ \times 0.22 \times (0.78) }[/tex]

n = 1269.1536

Sample size n [tex]\simeq[/tex] 1269.15

Answer:

Section I test scores are more dispersed that that of section II.

Step-by-step explanation:

Consider the data collected from the arithmetic test given to two sections of a school.

Section I: Mean = 45, Standard  Deviation = 6.5

Section II: Mean = 45,  Standard deviation = 3.1

The mean of both the sections are same, i.e. 45.

So there is no comparison that can be made from the center of the distribution.

The standard  deviation for section I is 6.5 and the standard  deviation for section II is 3.1.

The standard deviation is a measure of dispersion, i.e. it tells us how dispersed the data is from the mean or how much variability is present in the data.

The standard  deviation for section I is higher than that of section II.

So, this implies that section I test scores are more dispersed that that of section II.

Answer:

149 degrees

Step-by-step explanation:

This shape is a cyclic, so opposite angles add up to 180 degrees.

180-31 = 149

Answer:

As in explanation.

Step-by-step explanation:

A) SSE means "Error Sum of Squares". The source of it is the sum of squared deviations within groups.

B) SSTR means "Treatment Sum of Squares". It's source is the weighted sum of squared deviations of group means from grand mean. It's the sum of squares between groups.

C) SST means "Total Sum of Squares''. It's source is total sum of squared deviations from the grand mean. It is a sum of SSE and SSTR.

A) SSE means "Error Sum of Squares". The source of it is the sum of squared deviations that lies within groups.

B) SSTR means "Treatment Sum of Squares". It's source that represents the weighted sum of squared deviations of group means from the grand mean. It's the sum of squares between groups.

C) SST means "Total Sum of Squares''. It's source that represents total sum of squared deviations from the grand mean. It is a sum of SSE and SSTR.

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Answer:

ans right down there

Step-by-step explanation:

Here,Part 1

if the circle has a radius r so,

15 = r theta

here, theta is in radian.

Part 2

[tex]theta = \frac{15}{6} = 2.5[/tex]

part 3

[tex]theta = \frac{2.5 \times 180}{\pi} [/tex]

or theta =

143.2394487827058021919953870352629258310136811664108038729006

In part (D), we found

[tex]2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)[/tex]

so the phase [tex]\phi[/tex] is [tex]\tan^{-1}\left(\frac52\right)\approx1.19\,\rm rad[/tex], which falls between 0 and [tex]\frac\pi2[/tex]. This means the weight is somewhere between the maximum positive position (where [tex]\phi[/tex] would be 0) and the equilibrium position (where [tex]\phi[/tex] would be [tex]\frac\pi2[/tex]), and would be traveling in the negative direction.

Answer:

34 grams

Step-by-step explanation:

If the remaining sample has 30.26 grams of radioactive substance, and 11% of it decayed, that means that 30.26 grams is 89% of the original. Let the original be x.

30.26=0.89x

Multiply both by one hundred

3026=89x

Divide both by 89

34=x

x=original, so the original was 34 grams.

Answer:

a

  [tex]df = 24.32[/tex]

b

 [tex]df = 30.10[/tex]

c

 [tex]df = 30.7[/tex]

d

[tex]df = 25.5[/tex]

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

          [tex]df = \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 } +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 } }[/tex]

Considering a

         a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

           [tex]df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 } }[/tex]

         [tex]df = 24.32[/tex]

Considering b

       (b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

          [tex]df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }[/tex]

        [tex]df = 30.10[/tex]

Considering c

      (c) m = 12, n = 21, s1 = 3.0, s2 = 6.0

           [tex]df = \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }[/tex]

           [tex]df = 30.7[/tex]

Considering c

        (d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

                [tex]df = \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 } +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 } }[/tex]

               [tex]df = 25.5[/tex]

Answer:

$935.76

Step-by-step explanation:

BOND VALUATION Asiana Fashion's bonds have 10 years remaining to maturity. Interest is paid annually; they have a $1,000 par value; the coupon interest rate is 8% and thebyield to maturity is 9%.What is the bond's current market price?​

Step 1

We find the Present value factor of sum

The formula =

(1 + i)^n

Where

i = maturity rate = 9% = 0.09

n = number of years = 10 years

Present Value = ( 1 + 0.09)^-10

= 0.4224

Step 2

We find the present value factor of annuity

The formula is given as:

1 - (1+i)^-n / i

i = maturity rate = 9% = 0.09

n = number of years = 10 years

= 1 - (1 + 0.09)^-10 /0.09

= 1 - 0.4224 /0.09

= 0.5775 /0.09

= 6.417

Step 3

The bond's current market price is calculated as:

= PV factor of Sum × Par Value + PV factor of annuity × coupon payment

Coupon payment is calculated as:

= Coupon interest × par value

= 8% × 1000

= 80

Hence,

= 0.4224 × 1,000 + 6.417 × 80

= 422.4 + 513.36

= 935.76

In this exercise we have to use the knowledge of finance to calculate the corrective value of the market place, in this way we find that:

[tex]\$935.76[/tex]

We find the Present value factor of sum, by the formula of:

[tex](1 + i)^n[/tex]

Where:

Substituting the values ​​in the formula as;

[tex]Present \ Value = ( 1 + 0.09)^{-10} = 0.4224[/tex]

We find the present value factor of annuity, by the formula as:

[tex]1 - (1+i)^{-n} / i[/tex]

Where:

Substituting the values ​​in the formula as;

[tex]= 1 - (1 + 0.09)^{-10} /0.09\\= 1 - 0.4224 /0.09\\= 0.5775 /0.09\\= 6.417[/tex]

The bond's current market price is calculated as:

[tex]= PV \ factor\ of\ Sum * Par\ Value + PV\ factor\ of\ annuity * coupon\ payment[/tex]

Coupon payment is calculated as:

[tex]= Coupon\ interest * par\ value\\= 8\% * 1000= 80[/tex]

So continue the calcule;

[tex]= 0.4224 *1,000 + 6.417 * 80\\= 422.4 + 513.36\\= 935.76[/tex]

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Answer:

{-2, -1, 1, 5, 6}

Step-by-step explanation:

The domain includes the five x-values (inputs):  {-2, -1, 1, 5, 6}

Answer:

The x-values -2, -1,1,5 and 6

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

So we already know that:

[tex]2^x=30[/tex]

And we want to find the value of:

[tex]2^{x+3}[/tex]

So, what you want to do here is to separate the exponents. Recall the properties of exponents, where:

[tex]x^2\cdot x^3=x^{2+3}=x^5[/tex]

We can do the reverse of this. In other words:

[tex]2^{x+3}=2^x\cdot 2^3[/tex]

If we multiply it back together, we can check that this statement is true.

Thus, go back to the original equation and multiply both sides by 2^3:

[tex]2^x(2^3)=30(2^3)\\[/tex]

Combine the left and multiply out the right. 2^3 is 8:

[tex]2^{x+3}=30(8)\\2^{x+3}=240[/tex]

The answer is C.

Answer:

the answer is c

Step-by-step explanation:

Answer:

$5

Step-by-step explanation:

Let the notebook cost x, then Mark spent:

Notebook costs $5

Answer:

D) 3/2(X-4)

Step-by-step explanation:

Invert and multiply to get:

3(x+4)/2(x²-16)

factor the bottom

3(x+4)/2(x+4)(x-4)

The (x+4)’s cancel out, and you’re left with

3/2(X-4)

[tex]\dfrac{{x+4\over2}}{{x^2-16\over3}}[/tex]

[tex]=\dfrac{3(x+4)}{2(x+4)(x-4)}=\frac{3}{2(x-4)} [/tex]

but in original fraction, denominator can't be zero so we have to exclude x=±4

do that answer is D

Answer:

Brainleist!

Step-by-step explanation:

0

there is no y=mX+b

there is no x no XXXX

that means the slope must be 0 (bc theres a y)

Sorry if my explanation is bad... let me know in comments if u need more help

Answer:

14 mi

Step-by-step explanation:

Cedarburg is 22 13/16 miles from Allenville and 8 13/16 miles from Lakeside.  You have to solve for the distance from Lakeside to Allenville.

8 13/16  +  x  =  22 13/16

(8 13/16  +  x)  -  8 13/16  =  22 13/16  -  8 13/16

x  =  14

The distance from Lakeside to Allenville is 14 miles.

Answer:

d. 60000000000

Step-by-step explanation:

Answer:

The answer is D. 60,000,000,000

Step-by-step explanation:

Answer:

The minimum sample size is [tex]n = 2123[/tex]

Step-by-step explanation:

From the question we are told that

    The margin of error is  [tex]E = 0.028[/tex]

Given that the confidence level is  99% then the level of significance is evaluated as

        [tex]\alpha = 100 - 99[/tex]

        [tex]\alpha = 1 \%[/tex]

        [tex]\alpha =0.01[/tex]

Next we obtain the critical value of  [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table

   The  value is  [tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]

Now let  assume that the sample proportion is  [tex]\r p = 0.5[/tex]

  hence  [tex]\r q = 1 - \r p[/tex]

=>            [tex]\r q = 0.50[/tex]

   Generally the sample size is mathematically represented as

                [tex]n =[ \frac{Z_{\frac{ \alpha }{2} }}{ E} ]^2 * \r p * \r q[/tex]

                [tex]n =[ \frac{2.58}{ 0.028} ]^2 * 0.5 * 0.5[/tex]

              [tex]n = 2123[/tex]

Answer:

x≥4

Step-by-step explanation:

The required solution for the inequality 5 - 2x ≤ -3 is x ≥ 4 or x ∈ [4, ∞).

Inequality shows relation between two expression which are not equal to each others.

The given inequality is,

5 - 2x ≤ -3.

Solve the inequality,

Add 3 to both the sides,

5 - 2x + 3 ≤ -3 + 3

8 - 2x ≤ 0

-2x  ≤ -8

Multiply -1 both the sides,

2x ≥ 8

x ≥ 4

The solution for the inequality is x ≥ 4 or x ∈ [4, ∞).

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Answer:

[tex]Slanted\ Roof = 20.77\ ft[/tex]

Step-by-step explanation:

The question has missing attachment (See attachment 1 for complete figure)

Given

Width, W = 20ft

Let the taller height be represented with H and the shorter height with h

H = 10ft

h = 8ft

Overhang = 8 inch

Required

Determine the length of the slanted roof

FIrst, we have to determine the distance between the tip of the roof and the shorter height;

Represent this with

This is calculated by

[tex]D = H - h[/tex]

Substitute 10 for H and 8 for h

[tex]D = 10 - 8[/tex]

[tex]D = 2ft[/tex]

Next, is to calculate the length of the slant height before the overhang;

See Attachment 2

Distance L can be calculated using Pythagoras theorem

[tex]L^2 = 2^2 + 20^2[/tex]

[tex]L^2 = 4 + 400[/tex]

[tex]L^2 = 404[/tex]

Take Square root of both sides

[tex]\sqrt{L^2} = \sqrt{404}[/tex]

[tex]L = \sqrt{404}[/tex]

[tex]L = 20.0997512422[/tex]

[tex]L = 20.10\ ft[/tex] -------Approximated

The full length of the slanted roof is the sum of L (calculated above) and the overhang

[tex]Slanted\ Roof = L + 8\ inch[/tex]

Substitute 20.10 ft for L

[tex]Slanted\ Roof = 20.10\ ft + 8\ inch[/tex]

Convert inch to feet to get the slanted roof in feet

[tex]Slanted\ Roof = 20.1\ ft + 8/12\ ft[/tex]

[tex]Slanted\ Roof = 20.10\ ft + 0.67\ ft[/tex]

[tex]Slanted\ Roof = 20.77\ ft[/tex]

Hence, the total length of the slanted roof in feet is approximately 20.77 feet

Answer:

7/36

Step-by-step explanation:

1 die has 6 faces

When two dice are rolled, the total number of outcomes

= 6 × 6 = 36

The Probability of having(5) =

(1 & 4), (2 & 3) , ( 3 & 2), (4 & 1)

= 4

The probability of having (10) =

(5 & 5), (4 & 6) , ( 6 & 4)

= 3

The probability that the score on the dice is either 5 or 10.

P(5) + P(10)

= 4/36 + 3/36

= 7/36

Answer: 7/36

Step-by-step explanation:

36 outcomes

4 chances of getting 5 (1+4, 2+3, 4+1, 3+2)

3 chances of getting 10 (4+6, 5+5, 6+4)

4+3=7

so 7/36 chance

Answer:

[tex]163 -y =-5\\Collect\:Like\:terms\\163+5 = y\\Simplify\\168 =y\\\\y = 168[/tex]

Hello There!

[tex]163-y=-5[/tex]

To solve your equation, you can just change the -5 to 5 and move it to where y is. After that, change the minus sign to addition.

[tex]163+5=y[/tex]

Now all you have to do is sum it up.

[tex]163+5=168[/tex]

So y = to 168

So your answer is

[tex]163-168=-5[/tex]

Hope this Helps!

Answer:

Answer is attached below :)

Answer:

x = 12

Step-by-step explanation:

3(x–6)=18

x-6 = 18:3

x-6 = 6

x = 6+6

x = 12

Answer:

x=12

Step-by-step explanation:

Answer:c

Step-by-step explanation:

Answer: The answer is C.

Hope this helps you!

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

[tex] BD = c*sin(A) [/tex]

[tex] BD = c*cos(B) [/tex]

[tex] BD = b*tan(A) [/tex]

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

[tex] sin(A) = \frac{x}{c} [/tex]

Make x the subject of formula.

[tex] c*sin(A) = x [/tex]

[tex] BD = x = c*sin(A) [/tex]

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

[tex] cos(B) = \frac{x}{c} [/tex]

Make x the subject of formula.

[tex] c*cos(B) = x [/tex]

[tex] BD = x = c*cos(B) [/tex]

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

[tex] tan(A) = \frac{x}{b} [/tex]

Make x the subject of formula.

[tex] b*tan(A) = x [/tex]

[tex] BD = x = b*tan(A) [/tex]

Answer:

g(x): 2(-5)+1= -10+1=-9

2(-1)+1= -2+1=-1

2(2)+1= 4+1=5

2(3)+1=6+1= 7

Hence, the range of [tex]g[/tex] using the set notation is [tex](-9,-1,5,7)[/tex].

What is the function?

Functions are often defined by a formula that describes a combination of arithmetic operations and previously defined functions; such a formula allows computing the value of the function from the value of any element of the domain.

Here given that,

The function g is defined as follows for the domain given.

[tex]g(x) = 2x+1,[/tex]  and domain [tex]= (-5, -1, 2, 3)[/tex]

So,

[tex]x=-5\\2(-5)+1\\= -10+1\\=-9\\\\x=-1\\2(-1)+1\\= -2+1\\=-1\\\\x=2\\2(2)+1\\= 4+1\\=5\\\\x=3\\2(3)+1\\=6+1\\= 7[/tex]

Hence, the range of [tex]g[/tex] using the set notation is [tex](-9,-1,5,7)[/tex].

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Answer:

[tex]\boxed{\frac{984}{1000}}[/tex]

Step-by-step explanation:

Hey there!

Well .984 is 984 over 1000 so .984 as a fraction is 984/1000.

We can check this by doing 984 / 1000 which is .984.

Hope this helps :)