Work out 7/9×18/63 Give your answer in its simplest form.

Answer:

No solution is possible from the information provided

Step-by-step explanation:

Answer:

The campsites can be chosen in 5,765,760 different ways.

Step-by-step explanation:

Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:

16 x 15 x 14 x 13 x 12 x 11 = X

240 x 182 x 132 = X

240 x 24,024 = X

5,765,760 = X

Therefore, the campsites can be chosen in 5,765,760 different ways.

Answer:

30.00×.06=1.8+30.00=31.8

Step-by-step explanation:

Tập nghiệm của [tex]2^x=-1[/tex] là tập rỗng nha bạn. Vì 2 là số dương nên mũ mấy cũng dương hết.

Answer:

Step-by-step explanation:

let the coordinates of P be (x,y)

[tex]x=\frac{mx2+nx1}{m+n} \\y=\frac{my2+ny1}{m+n} \\x=\frac{2(5)+3(-3)}{2+3} \\x=\frac{10-9}{5} =\frac{1}{5} =0.2\\y=\frac{2(0)+3(-4)}{2+3} \\y=\frac{0-12}{5} =\frac{-12}{5} =-2.4\\[/tex]

so coordinates of P are (0.2,-2.4)

Answer:

43.82 mph

266.67 feet

Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

l = Length of skid mark

If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

80 = √30*0.8*l

80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

Answer:

cant see it

Step-by-step explanation:

just type it out

A quadratic function's graph being wide or narrow is determined or depended on a-term:

[tex] \large{y = a {x}^{2} + bx + c}[/tex]

If |a| has a lot of value, for example a = 2 or a = 100. The graph will get narrower if increasing the value of |a|. On the other hand, If |a| has small value, for example a = 1/2 or a = 1/10000. The graph would be wide.

Also it does not matter if a-term is negative or not since a-term being positive or negative determines if a parabola is upward or downward. Only |a| determines how narrow/wide the graph is.

From the question, it is clear that the parabola y = 2x^2 is the narrowest graph since it has the highest |a| value out of all choices.

Answer

Answer:

27 xy^2

Step-by-step explanation:

(3xy) (9y)

Multiply

3*9 =27

xy*y = xy^2

Combine

27 xy^2

Answer:

[tex]{ \tt{graph \: y \:and \:graph\: z}}[/tex]

Part (a)

1 meter = 100 cm

25 meters = 2500 cm .... multiply both sides by 25

Divide the 2500 cm over the 53 cm to get 2500/53 = 47.1698

Ignore the stuff after the decimal point. This means we can cut exactly 47 smaller bits of string, each 53 cm long

====================================================

Part (b)

We found that we can cut exactly 47 smaller bits of string, each 53 cm long. That takes up 47*53 = 2491 cm overall

The leftovers would be 2500 - 2491 = 9 cm which isn't longer than 53 cm

Convert 9 cm to mm by multiplying by 10 (because 1 cm = 10 mm).

9 cm = 90 mm

Your Answer is in the above image.

Answer:

33 squares of chocolate need

Answer:

33 Biscuits

Step-by-step explanation:

Uni method

How much biscuits do we need for 1 square of chocolate?

22/16 = 1.3

For 1 square of chocolate she needs 1.3 Biscuits.

So for 24 biscuits,

24 * 1.3

=33 biscuits

Answer:

The radius is approximately 14 cm

Step-by-step explanation:

The circumference

C = 2 * pi *r

88 = 2 * pi *r

Divide by 2

44 = 3.14 *r

Divide by 3.14

44/3.14 = r

14.01273885=r

Answer:

A = 41.4°

Step-by-step explanation:

Reference angle = A

Length of Adjacent side = 6

Length of Hypotenuse = 8

Apply the trigonometric function, CAH.

Cos A = Adj/Hyp

Substitute

[tex] Cos(A) = \frac{6}{8} [/tex]

[tex] A = Cos^{-1}(\frac{6}{8}) [/tex]

A = 41.4° (approximated to the nearest tenth)

Answer:

1/8

Step-by-step explanation:

Hope this helps you! <33

Answer:

1/8

Step-by-step explanation:

We all know 1/2 is 0.5, right?

If you split that in half again, you get 0.25 as 1/4.

If you divide that again by two, you get 1/8 as 0.125

I dont think I can be answered with just the given info... is some of the q missing still?

Closest we can do with above is dress cost = 120+ c

Answer:

The non-negative zero of the function f(x) is x = 2.

Step-by-step explanation:

For a given function f(x), the "zeros" of the function are the values of x such that:

f(x) = 0

In this case, we have the function:

f(x) = 6*x^2 - 9*x - 6

If we want to find the zeros of this function, we need to solve:

f(x) = 0 =  6*x^2 - 9*x - 6

To solve this, we can use the Bhaskara's formula, which says that for a general quadratic equation:

0 = a*x^2 + b*x + c

The zeros are:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]

In this case our equation is:

0 =  6*x^2 - 9*x - 6

then, in the above notation, we have:

a = 6

b = -9

c = -6

Replacing these in our general formula, we get:

[tex]x = \frac{-(-9) \pm \sqrt{(-9)^2 - 4*6*(-6)} }{2*6} = \frac{9 \pm 15 }{12}[/tex]

Then we have two zeros:

x = (9 + 15)/12 = 24/12 = 2

x = (9 - 15)/12 = -6/12 = -1/2

But we want only the non-negative, so we can discard the second one.

Concluding, the non-negative zero of the function f(x) is x = 2.

Answer:

A

Step-by-step explanation:

Answer:

7 hours

Step-by-step explanation:

9 : 30 to 17:00 = 7 hours 30 minutes

Minus 30 minutes = 7 hours

Answer:

Apr 16, 2018 — p>Which exponential function is represented by the graph?</p><span>f(x) = 2(1/​2)^x </span><span>f(x) = 1/2(2)^x </span><span>f(x) = 1/2

Step-by-step explanation:

Answer:

2h

Step-by-step explanation:

f(3 + h) = 2(3 + h)^2 + 1

= 2(3^2 + h^2) + 1

= 2(9) + 2h^2 + 1

= 18 + 2h^2 + 1

= 2h^2 + 19

f(3) = 2(3)^2 + 1

= 2(9) + 1

= 18 + 1

= 19

2h^2 + 19 - 19 / h

2h^2 / h

2h

Answer:

c I think that's the right answer

Answer:

The committee of 8 members can be selected in 990,675 different ways.

Step-by-step explanation:

The order in which the teachers and the students are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

4 teachers from a set of 6.

4 students from a set of 37.

Then

[tex]T = C_{6,4}C_{37,4} = \frac{6!}{4!2!} \times \frac{37!}{4!33!} = 990675[/tex]

The committee of 8 members can be selected in 990,675 different ways.

Answer:

V = 64 in^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 4^3

V = 64 in^3

Answer:

64

Step-by-step explanation:

volume of a cube formula: V = a^3

a is just one of the edges

[tex]4^{3}[/tex] = 64 = V

:)

[tex]\sf \bf {\boxed {\mathbb {GIVEN:}}}[/tex]

Radius of the circle "[tex]r[/tex]" = 5.5 yd

[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]

The area of the given figure.

[tex]\sf \bf {\boxed {\mathbb {SOLUTION :}}}[/tex]

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {b. \:47.5\:sq\:yd.}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]

We know that,

[tex]\sf\pink{Area\:of\:a\:semi-circle}[/tex] = [tex]\frac{\pi \: {r}^{2} }{2} [/tex]

Using 3.14 for π, we have

[tex] = \frac{3.14 \times ( {5.5 \: yd})^{2} }{2} \\[/tex]

[tex] = \frac{3.14 \times 5.5 \times 5.5 \: {yd}^{2} }{2}\\ [/tex]

[tex] = \frac{94.985 \: {yd}^{2} }{2} \\[/tex]

[tex] = 47.5 \: {yd}^{2} \\[/tex]

Using [tex]\frac{22}{7} [/tex] for π,

[tex] = \frac{22 \times 5.5 \times 5.5 \: {yd}^{2} }{7 \times 2} \\[/tex]

[tex] = \frac{665.5 \: {yd}^{2} }{14}\\ [/tex]

[tex] = 47.5 \: {yd}^{2} \\[/tex]

Therefore, the area of the semi-circle is [tex]47.5\: yd²[/tex].

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}[/tex]

Step-by-step explanation:

a rectangle which has a length which was three times the width could be

3 x 9 - this would give a total of just 27 feet.....so we know its bigger than this.....but essentially this starting place puts us in the right ballpark

following on from this....

if we do.....3.11 x 9.33 - this gives us 29.0163

and we have a rectangle which meets the criteria