Write a function int checkBalance(char exp[]); that can take an expression as input and check whether the parenthesis used in that expression are valid or invalid. It returns 1 if it is valid, and returns 0 if it is not valid.For example, the following expressions are valid: [ A * {B (C D)}] and [{()()}]The following expressions are invalid: [ A * {B (C D})], [ { ( ] ) ( ) }

Answer:

The OSI Model (Open Systems Interconnection Model) is a conceptual framework used to describe the functions of a networking system. The OSI model characterizes computing functions into a universal set of rules and requirements in order to support interoperability between different products and software.

Answer:

Now, it has been a while since I have written any sort of pseudocode. So please take this answer with a grain of salt. Essentially pseudocode is a methodology used by programmers to represent the implementation of an algorithm.

create a variable(userInput) that stores the input value.

create a variable(celsius) that takes userInput and applies the Fahrenheit to Celsius formula to it

Fahrenheit to Celsius algorithm is (userInput - 32) * (5/9)

Actual python code:

def main():

   userInput = int(input("Fahrenheit to Celsius: "))

   celsius = (userInput - 32) * (5/9)

   print(str(celsius))

main()

Explanation:

I hope this helped :) If it didn't tell me what went wrong so I can make sure not to make that mistake again on any question.    

Answer:

1.

190.190.190.190

Class B

Number of octets in the network part of the address: 2

Number of octets in the host part of the address: 2

Network number: 190.190.0.0/16

Network broadcast address: 190.190.255.255

2.

200.1.1.1

Class C

Number of octets in the network part of the address: 3

Number of octets in the host part of the address: 1

Network number: 200.1.1.0/24

Network broadcast address: 200.1.1.255

Explanation:

Answer:

A computer is an electronic device that accept raw data and instructions and process it to give meaningful results.

Answer:

import pandas as pd

def load_data():

df = pd.read_csv("airline-safety.csv')

num_rows = df.shape[0]

num_cols = df.shape[1]

return df, num_rows, num_cols

Explanation:

Using the pandas python package.

We import the package using the import keyword as pd and we call the pandas methods using the dot(.) notation

pd.read_csv reads the csv data into df variable.

To access the shape of the data which is returned as an array in the format[number of rows, number of columns]

That is ; a data frame with a shape value of [10, 10] has 10 rows and 10 columns.

To access the value of arrays we use square brackets. With values starting with an index of 0 and so on.

The row value is assigned to the variable num_rows and column value assigned to num_cols

Answer:

Code:

import java.util.*;  

public class Greetings  

{  

   public static void main(String[] args)  

   {        

       Scanner s = new Scanner(System.in);  

       System.out.println(getGreetings(s));  

   }  

   private static String getGreetings(Scanner console)  

   {          

   System.out.print("Please enter your first name: ");  

   String firstName=console.next();    

   char firstChar=firstName.toUpperCase().charAt(0);  

   System.out.print("Please enter your last name: ");  

   String lastName=console.next();    

   lastName=lastName.toUpperCase().charAt(0)+lastName.substring(1, lastName.length());  

   System.out.print("Please enter your year of birth: ");  

   int year=console.nextInt();  

   int age=getCurrentYear()-year;  

   return "Greetings, "+firstChar+". "+lastName+"! You are about "+age+" years old.";  

   }  

   private static int getCurrentYear()  

   {  

       return Calendar.getInstance().get(Calendar.YEAR);  

   }  

}

Output:-

Answer:

thanks for your question

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837

Answer:

Explanation:

A computer that is easy to operate is called User Friendly

Answer:

answer would be D. I do customer service and would never give information over the phone always give a solution

In order to resolve this problem correctly, you should: D. reset the password and have her check her email account to verify she has the information.

Cybersecurity can be defined as a group of preventive practice that are adopted for the protection of computers, software applications (programs), servers, networks, and data from unauthorized access, attack, potential theft, or damage, through the use of the following;

For web assistance, the security standard and policy which must be adopted to enhance data integrity, secure (protect) data and mitigate any unauthorized access or usage of a user's sensitive information such as username and password, by a hacker, is to ensure the information is shared discreetly with the user but not over the phone (call).

In this context, the most appropriate thing to do would be resetting the password and have the customer check her email account to verify she has the information.

Read more: https://brainly.com/question/24112967

This is true for most modern computers

Answer:

Gantt charts

Explanation:

Gantt charts control all aspects of your project plan from scheduling to assigning tasks and even monitoring progress. A Gantt chart shows your tasks across a timeline and puts them in phases for better organization.

Answer and Explanation:

In C programming language:

char fun(int*a, int*b){

printf("enter two integers: ");

scanf("%d%d",a,b);

int e;

printf("please enter a character: ");

e=getchar();

return e;

}

int main(int argc, char *argv[]) {

int d;

int f;

int g;

fun();

printf("%d%d%d", d, f, g);

}

We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.

Answer:

The statement is:

For number = 0 to 5

Explanation:

Given

The incomplete pseudocode

Required

The loop statement to complete the pseudocode

To loop from 0 to 5, we make use of:

For number = 0 to 5

Where:

number is the integer variable declared on line 1

So, the complete pseudocode is:

Declare Integer number

For number = 0 to 5

Display number

End For

Answer:

Error reports

Explanation:

Answer:

no sé jejejejeje

lslsl

lonsinet

ko

If I'm understanding the question correctly, you are looking for an integer b (b ≠ 0, b ≠ 1) such that

[tex]34_b = 22_{10}[/tex]

In other words, you're solving for b such that

3×b ¹ + 4×b ⁰ = 22

or

3b + 4 = 22

Solving this is trivial:

3b + 4 = 22

3b = 18

b = 6

So we have

34₆ = 22₁₀

Answer:

CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator.

Explanation:

There are six basic components of a microcomputer which includes CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator. CPU is the central processing unit which is considered as the brain of the computer. It is the part of a computer that executes instructions. Data memory is the place where data is stored that is present in the CPU.

D. digital

Explanation:

I hope it helps you

Answer:

false

Explanation:

My teacher quized me on this

a computer works on input processing output device true

Answer:

a computer works on input processing output device. True

Explanation:

God bless you.

Answer:

Managed devices

Explanation:

hope it helps u

Answer:

Direct memory access (DMA) is a process that allows an input/output (I/O) device to send or receive data directly to or from the main memory, bypassing the CPU to speed up memory operations and this process is managed by a chip known as a DMA controller (DMAC).

Explanation:

A defined portion of memory is used to send data directly from a peripheral to the motherboard without involving the microprocessor, so that the process does not interfere with overall computer operation.

In older computers, four DMA channels were numbered 0, 1, 2 and 3. When the 16-bit industry standard architecture (ISA) expansion bus was introduced, channels 5, 6 and 7 were added.

ISA was a computer bus standard for IBM-compatible computers, allowing a device to initiate transactions (bus mastering) at a quicker speed. The ISA DMA controller has 8 DMA channels, each one of which associated with a 16-bit address and count registers.

ISA has since been replaced by accelerated graphics port (AGP) and peripheral component interconnect (PCI) expansion cards, which are much faster. Each DMA transfers approximately 2 MB of data per second.

A computer's system resource tools are used for communication between hardware and software. The four types of system resources are:

DMA channels are used to communicate data between the peripheral device and the system memory. All four system resources rely on certain lines on a bus. Some lines on the bus are used for IRQs, some for addresses (the I/O addresses and the memory address) and some for DMA channels.

A DMA channel enables a device to transfer data without exposing the CPU to a work overload. Without the DMA channels, the CPU copies every piece of data using a peripheral bus from the I/O device. Using a peripheral bus occupies the CPU during the read/write process and does not allow other work to be performed until the operation is completed.

With DMA, the CPU can process other tasks while data transfer is being performed. The transfer of data is first initiated by the CPU. The data block can be transferred to and from memory by the DMAC in three ways.

In burst mode, the system bus is released only after the data transfer is completed. In cycle stealing mode, during the transfer of data between the DMA channel and I/O device, the system bus is relinquished for a few clock cycles so that the CPU can perform other tasks. When the data transfer is complete, the CPU receives an interrupt request from the DMA controller. In transparent mode, the DMAC can take charge of the system bus only when it is not required by the processor.

However, using a DMA controller might cause cache coherency problems. The data stored in RAM accessed by the DMA controller may not be updated with the correct cache data if the CPU is using external memory.

Solutions include flushing cache lines before starting outgoing DMA transfers, or performing a cache invalidation on incoming DMA transfers when external writes are signaled to the cache controller.

Answer:

See explanation

Explanation:

DMA [tex]\to[/tex] Direct Memory Access.

The peripherals of a computer system are always in need to communicate with the main memory; it is the duty of the DMA to allow these peripherals to transfer data to and from the memory.

The first step is that the processor starts the DMA controller, then the peripheral is prepared to send or receive the data; lastly, the DMA sends signal when the peripheral is ready to carry out its operation.

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

Answer:

A

Explanation:

Answer:

Testing that super user (SYSADMIN) access is limited to only appropriate personnel.

Explanation:

A test for logical access at an organization being audited would include testing that super user (SYSADMIN) access is limited to only appropriate personnel.

Clarissa should modify the file /root/.profile.

Runtime environment variables

Therefore, in the context, Clarissa wishes to modify the run time environment variable which can be used for all the new logins and also for the new instances for the BASH shell. So for this, Clarissa should modify the /root/.profile file command.

Learn More :

https://brainly.in/question/10061342

Following are the description of the wrong choice:

Therefore, the "/root/.profile" file should be changed by Clarissa.

Learn More :  

https://brainly.in/question/6708999

Answer:

vxxgxfufjdfhgffghgfghgffh

Answer

Medical Training

From operating MRI equipment to performing complex surgeries, AR tech holds the potential to boost the depth and effectiveness of medical training in many areas. Students at the Cleveland Clinic at Case Western Reserve University, for example, will now learn anatomy utilizing an AR headset allowing them to delve into the human body in an interactive 3D format.

it is also use in retail ,. Repair & Maintenance,Design & Modeling,Business Logistics etc

Answer:

Hence the correct option is 2nd option. all integer exceptions.

Explanation:

A catch block that expects an integer argument will catch all integer exceptions.