Write a function int checkBalance(char exp[]); that can take an expression as input and check whether the parenthesis used in that expression are valid or invalid. It returns 1 if it is valid, and returns 0 if it is not valid.For example, the following expressions are valid: [ A * {B (C D)}] and [{()()}]The following expressions are invalid: [ A * {B (C D})], [ { ( ] ) ( ) }

Answers

Answer 1

Answer:

Explanation:

The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.

import java.util.ArrayList;

class Brainly {

   public static void main(String[] args) {

       char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};

       char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};

       System.out.println(checkBalance(exp));

       System.out.println(checkBalance(exp2));

   }

   public static boolean checkBalance(char exp[]) {

       ArrayList<Character> symbols = new ArrayList<>();

       for (char x: exp) {

           if ((x =='[') || (x == '{') || (x == '(')) {

               symbols.add(x);

           }

           if (x ==']') {

               if (symbols.get(symbols.size()-1) == '[') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x =='}') {

               if (symbols.get(symbols.size()-1) == '{') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

           if (x ==')') {

               if (symbols.get(symbols.size()-1) == '(') {

                   symbols.remove(symbols.size()-1);

               } else {

                   return false;

               }

           }

       }

       return true;

   }

}

Write A Function Int CheckBalance(char Exp[]); That Can Take An Expression As Input And Check Whether

Related Questions

write a loop that reads positive integers from stands input and that terinated when it reads an interger that is not positive after the loop termpinates

Answers

Loop takes only positive numbers and terminates once it encounters a negative numbers.

Answer and Explanation:

Using javascript:

Var positiveInt= window.prompt("insert positive integer");

While(positiveInt>=0){

Alert("a positive integer");

Var positiveInt= window.prompt("insert positive integer");

}

Or we use the do...while loop

Var positiveInt= window.prompt("insert positive integer");

do{

Var positiveInt= window.prompt("insert positive integer");

}

While (positiveInt>=0);

The above program in javascript checks to see if the input number is negative or positive using the while loop condition and keeps executing with each input until it gets a negative input

Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline and decare/use loop variable. Example output for numCycles = 2:
1: Lather and rinse.
2: Lather and rinse.
Done.
import java.util.Scanner; 3 public class ShampooBottle 4 5 Your solution goes here / 7 public static void main (String [] args) ShampooBottle trialSize - new ShampooBottle); trialsize.printShampooInstructions (2) 10 Run View your last submission Your solution goes here / public void printShampooInstructions (int numCycles) f if (numCycles 1) System.out.printin("Too few.") else if (numCycles4) System.out.printin("Too many.") else System.out.println("Done."); for (int i = 1; i (z numCycles ; ++i){ System.out . printin (? + ": Lather and rinse.");

Answers

Answer:

if (numCycles < 1){

        System.out.println("Too few.");

     }

     else if (numCycles > 4){

        System.out.println("Too many.");

        }    

  else{

     for(int i = 1; i <= numCycles; i++)

  {

     System.out.println(i + ": Lather and rinse.");

  }

     System.out.println("Done.");

  }

 

Explanation:

Assign courseStudent's name with Smith, age with 20, and ID with 9999. Use the print member function and a separate cout statement to output courseStudents's data. End with a newline. Sample output from the given program:
#include
#include
using namespace std;
class PersonData {
public:
void SetName(string userName) {
lastName = userName;
};
void SetAge(int numYears) {
ageYears = numYears;
};
// Other parts omitted
void PrintAll() {
cout << "Name: " << lastName;
cout << ", Age: " << ageYears;
};
private:
int ageYears;
string lastName;
};
class StudentData: public PersonData {
public:
void SetID(int studentId) {
idNum = studentId;
};
int GetID() {
return idNum;
};
private:
int idNum;
};
int main() {
StudentData courseStudent;
/* Your solution goes here */
return 0;
}

Answers

Answer:

Replace /* Your solution goes here */

with the following:

courseStudent.SetName("Smith");

courseStudent.SetAge(20);

courseStudent.SetID(9999);

courseStudent.PrintAll();

cout <<courseStudent.GetID();

Explanation:

From the given code segment, we have the following methods defined under the StudentData class;

SetName -> It receives name from the main

SetAge -> It receives age from the main

SetID --> It receives ID from the main and passes it to GetID method

printID --> Prints all the required output.

So, we have:

Pass name to setName

courseStudent.SetName("Smith");

Pass age to setAge

courseStudent.SetAge(20);

Pass ID to setID

courseStudent.SetID(9999);

Print all necessary outputs

courseStudent.PrintAll();

Manually print the student ID

cout <<courseStudent.GetID();

Cardinality ratios often dictate the detailed design of a database. The cardinality ratio depends on the real-world meaning of the entity types involved and is defined by the specific application. For the binary relationships below, suggest cardinality ratios based on the common-sense meaning of the entity types. Clearly state any assumptions you make.
Entity 1 Cardinality Ratio Entity 2
1. Student SocialSecurityCard
2. Student Teacher
3. ClassRoom Wall
4. Country CurrentPresident
5. Course TextBook
6. Item (that can
be found in an
order) Order
7. Student Class
8. Class Instructor
9. Instructor Office
10. E-bay Auction item E-bay bid

Answers

Solution :

ENTITY 1               CARDINALITY RATIO                                     ENTITY 2

1. Student                        1 to many                                     Social security card

                      A student may have more than one          

                     social security card (legally with the

                      same unique social security number),

                     and every social security number belongs

                   to a unique.

2. Student                   Many to Many                                    Teacher

                    Generally students are taught by many

                    teachers and a teacher teaches many students.

3.ClassRoom               Many to Many                                   Wall

                      Do not forget that the wall is usually

                      shared by adjacent rooms.

4. Country                 1 to 1                                             Current President

                       Assuming a normal country under normal

                       circumstances having one president at a

                      time.

5. Course               Many to Many                               TextBook

                        A course may have many textbooks and

                       text book may be prescribed for different

                      courses.

6. Item                             Many to Many                           Order

                        Assuming the same item can appear

                         in different orders.

7. Student                       Many to Many                          Class

                        One student may take several classes.

                        Every class usually has several students.

8. Class                                 Many to 1                             Instructor

                       Assuming that every class has a unique

                        instructor. In case instructors were allowed

                        to team teach, this will be many-many.

9. Instructor                  1 to 1                                             Office

                       Assuming every instructor has only one

                      office and it is not shared. In case of offices

                     shared by 2 instructors, the relationship

                    will be 2-1. Conversely, if any instructor has a joint

                    appointment and offices in both departments,

                    then the relationship will be 1-2. In a very general

                  case, it may be many-many.

10. E-bay Auction item             1-Many                           E-bay bid

                        1 item has many bids and a bid is unique

                        to an item.

While configuring a wireless access point device, a technician is presented with several security mode options. Which of the following options will provide the most secure access?

Answers

Answer:

Bro this is my area the answer is WPA2 and AES  

Explanation:

its because AES is a more secure encryption protocol introduced with WPA2. AES isn't some creaky standard developed specifically for Wi-Fi networks, either. It's a serious worldwide encryption standard that's even been adopted by the US government.

There are many possible variations in wireless network design depending on the surroundings.

What is wireless network?

Even in a complicated single site, different wireless networks running on the same hardware as part of the broader wireless LAN environment can have different network configuration fundamentals needed for a successful deployment.

At the same time, a number of essential network configuration activities are part of any successful wireless project's typical chores. Let's look at the broad and specific procedures that wireless experts should take while setting up enterprise-grade Wi-Fi networks.

Therefore, There are many possible variations in wireless network design depending on the surroundings.

To learn more about wifi, refer to the link:

https://brainly.com/question/6145118

#SPJ5

Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from the LinkedList by removing the second and subsequent elements. If there is only one copy of an element, it is not removed. The list size should shrink accordingly based on the number of duplicates removed.

Answers

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

     

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

               

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       

       //make ptr1 equals to head.

       ptr1 = head;

       

       

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

               

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-

Create and configure databases in oracle database management system operation administration

Answers

Answer:

You typically create a database during Oracle Database software installation. However, you can also create a database after installation.

Reasons to create a database after installation are as follows:

You used Oracle Universal Installer (OUI) to install software only, and did not create a database. You want to create another database (and database instance) on the same host computer as an existing Oracle database. In this case, this chapter assumes that the new database uses the same Oracle home as the existing database. You can also create the database in a new Oracle home by running OUI again. You want to make a copy of (clone) a database.

How does OOP keep both code and data safe from outside interference and
incuse?

Answers

Answer:

it is the process that binds together the data and code into a single unit and keeps both from being safe from outside interference and misuse. In this process, the data is hidden from other classes and can be accessed only through the current class's methods

Write a program in Cto define a structure Patient that has the following members

Answers

Answer:

Explanation:

The answer should be 1.16 or 61.1

In C language
In a main function declare an array of 1000 ints. Fill up the array with random numbers that represent the rolls of a die.
That means values from 1 to 6. Write a loop that will count how many times each of the values appears in the array of 1000 die rolls.
Use an array of 6 elements to keep track of the counts, as opposed to 6 individual variables.
Print out how many times each value appears in the array. 1 occurs XXX times 2 occurs XXX times
Hint: If you find yourself repeating the same line of code you need to use a loop. If you declare several variables that are almost the same, maybe you need to use an array. count1, count2, count3, count4, … is wrong. Make an array and use the elements of the array as counters. Output the results using a loop with one printf statement. This gets more important when we are rolling 2 dice.

Answers

Answer:

The program in C is as follows:

#include <stdio.h>

#include <stdlib.h>

#include <time.h>

int main(){

   int dice [1000];

   int count [6]={0};

   srand(time(0));

   for (int i = 0; i < 1000; i++) {

       dice[i] = (rand() %(6)) + 1;

       count[dice[i]-1]++;

   }

   for (int i = 0; i < 6; i++) {

       printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");

       printf("\n");

   }

   return 0;

}

Explanation:

This declares an array that hold each outcome

   int dice [1000];

This declares an array that holds the count of each outcome

   int count [6]={0};

This lets the program generate different random numbers

   srand(time(0));

This loop is repeated 1000 times

   for (int i = 0; i < 1000; i++) {

This generates an outcome between 1 and 6 (inclusive)

       dice[i] = (rand() %(6)) + 1;

This counts the occurrence of each outcome

       count[dice[i]-1]++;    }

The following prints the occurrence of each outcome

   for (int i = 0; i < 6; i++) {

       printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");

       printf("\n");    }

Briefly explain what an array is. As part of your answer make use of a labelled example to show the declaration and components of an array

Answers

Answer:

Explanation:

In programming an array is simply a grouping of various pieces of data. Various data elements are grouped together into a single set and saved into a variable. This variable can be called which would return the entire set which includes all of the elements. The variable can also be used to access individual elements within the set. In Java an example would be the following...

int[] myArray = {33, 64, 73, 11, 13};

In Java, int[] indicates that the variable will hold an array of integers. myArray is the name of the variable which can be called to access the array elements. The elements themselves (various pieces of data) are located within the brackets {}

Register the countChars event handler to handle the keydown event for the textarea tag. Note: The function counts the number of characters in the textarea.
Do not enter anything in the HTML file, put your code in the JavaScript section where it says "Your solution goes here"
1 klabel for-"userName">user name: 2
3

Answers

Answer:

Explanation:

The following Javascript code is added in the Javascript section where it says "Your solution goes here" and counts the current number of characters in the text within the textArea tag. A preview can be seen in the attached image below. The code grabs the pre-created variable textareaElement and attached the onkeypress event to it. Once a key is pressed it saves the number of characters in a variable and then returns it to the user.

var textareaElement = document.getElementById("userName");

function textChanged(event) {

   document.getElementById("stringLength").innerHTML = event.target.value.length;

}

// Your solution goes here

textareaElement.onkeypress = function() {

   let numOfCharacters = textareaElement.value.length;

   return numOfCharacters;

};

You have a shared folder named Reports. Members of the Managers group have been given Write access to the shared folder. Mark Mangum is a member of the Managers group. He needs access to the files in the Reports folder, but he should not have any access to the Confidential.xls file. What should you do

Answers

Answer:

Following are the solution to the given question:

Explanation:

The common folder called Report has also been shared. Writing access to a shared folder was given to management group members. Mark is a member of a group of managers. We can access the files within your reporting directory, but you really should not access the Confidential.xls file. We want to add Mark Mangum to our ACL files using Deny permissions on Confidential.xls.

Indicate whether the following actions are the actions of a person who will be a victim, or will not be a victim, of phishing attacks.

Replying to an e-mail requesting your user ID and password Phishing victim Not a phishing victim

Answers

Answer:

Phishing Victim

Explanation:

Replying to this email could make you a victim of a phishing scam. Phishing attacks are common challenges on security that internet users are faced with. It could lead to others getting hold of sensitive information like your password or bank details. email is one way the hackers used to get this information. replying to such an email could lead one to an unsecure website where information could be extracted

(Count the occurrences of words in a text file) Rewrite Listing 21.9 to read the text from a text file. The text file is passed as a command-line argument. Words are delimited by whitespace characters, punctuation marks (, ; . : ?), quotation marks (' "), and parentheses. Count the words in a case-sensitive fashion (e.g., consider Good and good to be the same word). The words must start with a letter. Display the output of words in alphabetical order, with each word preceded by the number of times it occurs.
I ran my version of the program solution on its own Java source file to produce the following sample output:
C:\Users\......\Desktop>java CountOccurrenceOfWords CountOccurrenceOfWords.java
Display words and their count in ascending order of the words
1 a
1 alphabetical
1 an
2 and
3 args
2 as
1 ascending
1 catch
1 class
4 count
2 countoccurrenceofwords
1 create
1 display
1 else
3 entry
3 entryset
2 ex
1 exception
1 exit
1 file
2 filename
3 for
1 fullfilename
3 get
1 getkey
1 getvalue
1 hasnext
1 hold
5 i
3 if
2 import
2 in
3 input
2 int
1 io
3 java
6 key
3 length
2 line
1 main
3 map
1 matches
3 new
1 nextline
1 null
1 of
2 order
3 out
3 println
1 printstacktrace
2 public
2 put
2 scanner
1 set
1 split
1 static
5 string
4 system
2 the
1 their
1 to
1 tolowercase
2 tree
6 treemap
2 trim
1 try
1 util
1 value
1 void
1 while
9 words
C:\Users\......\Desktop>

Answers

Answer:

Explanation:

The following is written in Java. It uses File input, to get the file and read every line in the file. It adds all the lines into a variable called fullString. Then it uses regex to split the string into separate words. Finally, it maps the words into an array that counts all the words and how many times they appear. A test case has been created and the output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.

Large computer programs, such as operating systems, achieve zero defects prior to release. Group of answer choices True False PreviousNext

Answers

Answer:

The answer is "False"

Explanation:

It is put to use Six Sigma had 3.4 defects per million opportunities (DPMO) from the start, allowing for a 1.5-sigma process shift. However, the definition of zero faults is a little hazy. Perhaps the area beyond 3.4 DPMO is referred to by the term "zero faults.", that's why Before being released, large computer programs, such as operating systems, must have no faults the wrong choice.

CPT (Current Procedural Terminology) codes consist of 3-4 numbers representing a unique service. True False

Answers

this is in fact false to my knowledge

In the forward chaining technique, used by the inference engine component of an expert system, the _____ condition is evaluated first.

Answers

Answer:

"if" is the right response.

Explanation:

Forward chaining is being utilized just to split the logical sequential order down as well as operate throughout every component once the preceding one is accomplished, from start to finish.Its whole algorithm begins with proven information that activates all the rules, which are fulfilled as well as makes established realities even more complete.

Given an array of n distinct integers sorted in ascending order, write a function that returns a Fixed Point in the array, if there is any Fixed Point present in array, else returns -1. Fixed Point in an array is an index i such that arr[i] is equal to i. Note that integers in array can be negative. Examples: #include using namespace std; void removeDivByFive(int *arr,int& size) { int index=0; for(int i=0;i

Answers

Answer:

The function is as follows:

int returnsFixed(int arr [],int n){

   int retVal = -1;

   for(int i = 0; i<n;i++){

       if(i == arr[i]){

           retVal = i;

           break;

       }

   }

   return retVal;

}

Explanation:

This defines the functionl it receives the array and the length of the array

int returnsFixed(int arr [],int n){

This initializes the return value to -1

   int retVal = -1;

This iterates through the array

   for(int i = 0; i<n;i++){

This checks if i equals arr[i]

       if(i == arr[i]){

If yes, the return value (i.e. the fixed point) is set to i

           retVal = i;

And the code is exited

           break;

       } This ends the if condition

   } This ends the iteration

This returns the calculated fixed point

   return retVal;

}

A blogger writes that the new "U-Phone" is superior to any other on the market. Before buying the U-Phone based on this review, a savvy consumer should (5 points)

consider if the blogger has been paid by U-Phone
assume the blogger probably knows a lot about U-Phones
examine multiple U-Phone advertisements
speak to a U-Phone representative for an unbiased opinion

Answers

Answer:

Speak to a U-Phone representative.

Explanation:

A representative will tell you the necessary details about the U-phone without any biases whatsoever, as they´re the closest to the company when it comes to detail about their products.

Tu teléfono es muy bueno no sé mucho de que se trata porque no se inglés y el celular está en inglés.

Coding 5 - Classes The Item class is defined for you. See the bottom of the file to see how we will run the code. Define a class ShoppingCart which supports the following functions: add_item(), get_total_price(), and print_summary(). Write code only where the three TODO's are. Below is the expected output: Added 2 Pizza(s) to Cart, at $13.12 each. Added 1 Soap(s) to Cart, at $2.25 each. Added 5 Cookie(s) to Cart, at $3.77 each.

Answers

Answer:

Explanation:

The following is written in Java. It creates the ShoppingCart class as requested and implements the requested methods. A test class has been added to the main method and the output is highlighted in red down below.

import java.util.ArrayList;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       ShoppingCart newCart = new ShoppingCart();

       newCart.add_item();

       newCart.add_item();

       newCart.add_item();

       newCart.print_summary();

   }

}

class ShoppingCart {

   Scanner in = new Scanner(System.in);

   ArrayList<String> items = new ArrayList<>();

   ArrayList<Integer> amount = new ArrayList<>();

   ArrayList<Double> cost = new ArrayList<>();

   public ShoppingCart() {

   }

   public void add_item() {

       System.out.println("Enter Item:");

       this.items.add(this.in.next());

       System.out.println("Enter Item Amount:");

       this.amount.add(this.in.nextInt());

       System.out.println("Enter Cost Per Item:");

       this.cost.add(this.in.nextDouble());

   }

   public void get_total_price() {

       double total = 0;

       for (double price: cost) {

           total += price;

       }

       System.out.println("Total Cost: $" + total);

   }

   public void print_summary() {

       for (int i = 0; i < items.size(); i++) {

           System.out.println(amount.get(i) + " " + items.get(i) + " at " + cost.get(i) + " each.");

       }

       get_total_price();

   }

}

_________________________ are the countable products resulting from a program, while ________________________ are the changes in clients that are achieved as a result of program participation.

Answers

Answer: Outputs; Outcomes.

Explanation:

Program refers to the collection of instructions which the computer can execute in order to perform a certain task.

Outputs are are the countable products resulting from a program, while on the other hand, outcomes are the changes in clients that are achieved as a result of program participation.

Given main(), complete the Car class (in file Car.java) with methods to set and get the purchase price of a car (setPurchasePrice(), getPurchasePrice()), and to output the car's information (printInfo()).
Ex: If the input is:
2011
18000
2018
where 2011 is the car's model year, 18000 is the purchase price, and 2018 is the current year, the output is:
Car's information:
Model year: 2011
Purchase price: 18000
Current value: 5770
Note: printInfo() should use three spaces for indentation.

Answers

Answer and Explanation:

public class Main {

int Carmodel;

int Purchaseprice;

int Currentyear;

Public void setPurchasePrice(int Purchaseprice){

this.Purchaseprice=Purchaseprice;

}

Public void getPurchasePrice(){

return Purchaseprice;

}

static void printInfo(int Carmodel int Currentyear ){

this.Carmodel=Carmodel;

this.Currentyear=Currentyear;

System.out.println(getPurchasePrice() Carmodel Currentyear);

}

}

The above java program defines a class that has three methods, a get method that returns purchase price of the object, a set method that sets purchase price of the object, and a print method that print out the information about the car object(model, year, price). The print method also takes arguments and assigns values of the arguments/parameters to the object, then prints all.

Define a class named Point with two data fields x and y to represent a point's x- and y-coordinates. Implement the Comparable interface for the comparing the points on x-coordinates. If two points have the same x-coordinates, compare their y-coordinates. Define a class named CompareY that implements Comparator. Implement the compare method to compare two points on their y-coordinates. If two points have the same y-coordinates, compare their x-coordinates. Randomly create 100 points and apply the Arrays.sort method to display the points in increasing order of their x-coordinates, and increasing order of their y-coordinates, respectively.

Answers

Answer:

Here the code is given in java as follows,

Batter boards (if properly offset) will allow for the end user to continually re-string the layout to double check accuracy without having to continually set up an instrument True False

Answers

Answer:

The given statement is "True".

Explanation:

Batter panels seem to be platform frames that are used to temporarily suspend foundations plan threads. These same batter board members look like barriers once built.Its positioning is important for creating a foundation precisely as the plans state since some components of their development would have to be accurate. Placed correctly batter panels guarantee that the boundaries seem to be at the appropriate temperatures as well as positions.

The next few questions will be based on interpretations of a topographic map from East Brownsville, TX. To answer these questions you will have to access the topographic map of East Brownsville attached below:
What stage of fluvial landscape development is shown across the region displayed here?
a. Youthful
b. Mature
c. Old age

Answers

Answer:

a. Youthful

Explanation:

The river gets its water from youth stage fluvial water. The river meanders from side to side. East Brownsville will be less stable in international boundary in terms of physical position on the landscape because its base level drops.

Modeling and simulation can enhance the Systems Engineering process by:__________.
a. Helping IPT members to understand the interrelationship of components without physically changing the system.
b. Providing designs that will consistently exceed functional capabilities.
c. Quickly providing physical solutions to meet functional capabilities.
d. Eliminating technical risk before production begins.

Answers

C the Quiclyprovideinf

Which information can you apply to every page of your document with the page layout options?
header
conclusion
body
footer
introduction

Answers

Answer:

Header and footer

Explanation:

The page layout tab usually found in document programs such as Microsoft Word hold options used to configure several page options which is to be applied to a document. The page layout option gives users options to set page margins, orientation, page numbering, indentation and the other page layout options which is primarily how we would like our document to look like when printed. The page layout option also allows the insertion of a header and footer which is a note which can be written at the topmost and bottomost part of the document. Once, a header and footer option is selected, it is applied to every page of the document being worked on at the moment.

Which attack form either exploits a software flaw or floods a system with traffic in order to prevent legitimate activities or transactions from occurring?

Answers

Answer:

Denial of service attack.

Explanation:

In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.

This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.

Data theft can be defined as a cyber attack which typically involves an unauthorized access to a user's data with the sole intention to use for fraudulent purposes or illegal operations. There are several methods used by cyber criminals or hackers to obtain user data and these includes DDOS attack, SQL injection, man in the middle, phishing, sniffing, DOS attack, etc.

A denial of service (DOS) attack is a form of cyber attack that involves either the exploitation of a software flaw or overwhelmingly floods a computer system in a network with traffic in order to prevent authorized users from performing legitimate activities or transactions.

Some of the ways to prevent vulnerability or cyber attacks in a network are;

1. Ensure you use a very strong password with complexity through the use of alphanumerics.

2. You should use a two-way authentication service.

3. You should use encrypting software applications or services.

what is an RTF file?

Answers

Answer:

The Rich Text Format is a proprietary document file format with published specification developed by Microsoft Corporation from 1987 until 2008 for cross-platform document interchange with Microsoft products.

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