Write a method named numUnique that accepts a sorted array of integers as a parameter and that returns the number of unique values in the array. The array is guaranteed to be in sorted order, which means that duplicates will be grouped together. For example, if a variable called list stores the following values: int[] list

Answer:

The method in Java is as follows:

public static int numUnique(int list[]) {  

int unique = 1;  

for (int i = 1; i < list.length; i++) {  

 int j = 0;  

 for (j = 0; j < i; j++) {

  if (list[i] == list[j])  

   break;  

 }

 if (i == j)  

  unique++;  

}  

return unique;  

}  

Explanation:

This line defines the numUnique method

public static int numUnique(int list[]) {

This initializes the number of unique elements to 1

int unique = 1;  

This iterates through the list

for (int i = 1; i < list.length; i++) {

The following iteration checks for unique items

 int j = 0;  

 for (j = 0; j < i; j++) {

  if (list[i] == list[j]) If current element is unique, break the iteration

   break;  

 }

 if (i == j)  

  unique++;  

}

This returns the number of unique items in the list

return unique;  

}  

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Write a program that reads an integer between o and 1000 and adds all the digits in the integer. For example, if an integer is 932, the sum of all the digits is 14. Hint: Use the % operator to extract digits, and use the / operator to remove the extracted digit. For instance, 932 % 10=2 and 932/10 =93. Here is a sample run:
Enter a number between 0 and 1000 : 999
The sum of digits is 27.