Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-pentene (d) (Z)-3-Hexene (e) (E)-2-Pentene (f) 3,3,3-Tribromopropene (g) (Z,4R)-4-Methyl-2-hexene (h) (E,4S )-4-Chloro-2-pentene (i) (Z)-1-Cyclopropyl-1-pentene (j) 5-Cyclobutyl-1-pentene (k) (R)-4-Chloro-2-pentyne (l) (E)-4-Methylhex-4-en-1-yne

Answer: True

Explanation:

Answer: The changes are the mL of methanol ingestion (30mL) and the proof of the whiskey (40% ethanol; 80 proof), and the percentage of reduction (1%). I applied the formulas from the last post in reference to this question but am completely lost. The formulas used last time were: 2. Formulas Applied alpha=1 + ([etOH]/KetOH) (V[meOH]/V[etOH])= (Vmax*[meOH]/KmeOH+[meOH])/(Vmax*[meOH]/alpha*KmeOH+[meOH]) which reduces to (V[meOH]/V[etOH])=(alpha*KmeOH+[meOH])/(KmeOH+[meOH]) 3. My attempt Molarity of methanol: 30mL; which equates to 23.7g of methanol; in 40L that is equal to 0.5925 g/L Dividing the molecular weight by 32.04g/mol I get 0.0184925 which is approximately 0.02M; Km is 0.01M Since the molar mass of methanol and ethanol are two fold, I can multiply the g/l by 4. However, unlike the previous problem, I cannot multiply by 2 because I do not have 50% EtOH, so because 40 is less than 50 I assume to multiply by 2.5 yielding: (30mL)(4)(2.5)=300mL 300mL of EtOH to effectively reduce the Methanol to 1%.

Answer:

According to the law of conservation of energy, energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant. ... As the car coasts down the hill, it moves faster and so it's kinetic energy increases and it's potential energy decreases. hope this helps

Explanation:

Answer:

They cannot be destroyed or created however,

Explanation:

it can only be transformed or transferred from one form to another.

Answer:

P = protons

E = electrons

N = neutrons

remember protons and neutrons (protons are positive and neutrons are neutral as you can already tell by their names) are found at the centre of the nucleus (positive mass). Whilst the electrons (negative) orbit around the shells

Answer:·  44 g NaCl Explanation: The problem provides you with the molarity and volume of the target

Explanation:

Answer:

the number of electrons will end up changing

Answer:

temperature and rainfall

Explanation:

Answer:

Download Ptable, it will show all of the elements, and you can click on them, and it will show all the information you need about them!

Explanation:

I hope this helps!!!!!

Answer:

the first one

Explanation:

I looked it up:P

Only the 2nd answer is right, uncheck the 1st one

Explanation:

If we had a chemical formula like [tex]3(O_{2} )[/tex] the 3 means there are 3 molecules of [tex]O_{2}[/tex]. The 2 means there are two atoms of oxygen in each molecule.

Answer:

A

Explanation:

They help fight infection and other disease

Answer:

immunity is the answer for this question

Answer:

C. When melted rock solidifies.

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Answer:

ω-3 fatty acid and 19:4(Δ5,8,11,14)

Explanation:

From the image attached below:

We can see the structure of the delta nomenclature showing the numbers of carbons, numbers of double bonds, and the locations of the double bonds in the structure of the carboxylate salt.

Also, we can see the structure of the fatty acid where; the location of the first double bond from the methyl end is shown.

Hence, the designation which are accurate for these structures are:

ω-3 fatty acid and 19:4(Δ5,8,11,14)

Answer:

a

Explanation:

a

Answer:

Domain

Explanation:

This is because Linnaeus taxonomy is a system of classification which was invented by a swedish Botanist called Carl Linnaeus and it is refered to hierarchy of grouping organisms called taxa. It involve 7 system of classifications and they include Kingdom, Phylum, Class, Order, Family, Genus, and Species.

Answer: The total pressure is 7 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_A+p_B+p_C...[/tex]

Given : [tex]p_{total}[/tex] =total pressure of gases = ?

[tex]p_{O_2}[/tex] = partial pressure of oxygen = 2 atm

[tex]p_{N_2}[/tex] = partial pressure of nitrogen = 4 atm

[tex]p_{Ar}[/tex] = partial pressure of argon = 1 atm

putting in the values we get:

[tex]p_{total}=2atm+4atm+1atm[/tex]  

[tex]p_{total}=7atm[/tex]

Thus the total pressure is 7 atm

Answer:

CaO < BaO < KCl <KI

Explanation:

Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy.  If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.

However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.

KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.

One of the basic engine-diagnostic procedures that can be run is an engine compression test. All of the cylinders must have the same compression for the engine to run smoothly. There are just three possible ways for air to leak out of an engine and cause compression loss.

The engine should be warmed to its typical operating temperature before testing in order to achieve the best results. The following procedures should be followed for an accurate compression test:

Learn more about compression test here https://brainly.com/question/13274092

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Answer:

it's a double displacement Reaction.

Answer: d. Determining empirical formula

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Step 1: If percentage are given then we are taking total mass is 100 grams.  So, the mass of each element is equal to the percentage given.

Step 2 : convert given masses into moles

Step 3 : For the mole ratio, divide each value of moles by the smallest number of moles calculated

Step 4: The mole ratio gives the empirical formula of the compund.

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Answer: HSO4-

Explanation:

I hope this helped!

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Answer:

Hello your question is poorly written below is the well written question

Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of  approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5  billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth

Answer : 140 billion years

Explanation:

Given that :

U-238   h1/2 = 4.5 billion years

U-235   h1/2 = 700 million years

At the beginning both Isotopes where present in equal amount

Determine the T years before the amount of Uranium decays to Half

T =   ?    N'2 = N1 / 2

we know that N = No ( 1/2 )^h   where h = time / half-life time

attached below is the detailed solution of the given problem

Answer:

It depends. what hot spot are you looking for?

Answer:

A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.

Explanation:

Hope this is what you mean be hot spot!

I hope this helps you!  

In all living organisms, in substances like carbohydrate, starch, urea etc. To prove sugar contains carbon, take a little amount of sugar in spoon and heat it gently till it melts and turned into yellowish color. On further heating it changes into brown colored mass and then black, which is charcoal.

Answer: sugar treated with strong sulphur acid turns to black

Explanation: sulphur acid removes water from sugars and carbon is left in residue.

This should not to try at home. Water boils when high temperature is achieved.

Also smell of burned sugar occurs

i think it is

(b) 4

:) hope its correct :)

Answer: 2260 J/g is gained from the surrounding environment

When one gram of liquid water at its boiling point is changed into water vapor, 2260 J/g of energy is gained from the surrounding environment.

Heat of vaporization is the amount of heat that is required by any body during their transition process from liquid state to vapor state, at a particular temperature i.e. no change in temperature during whole process.

During the transition of one gram of liquid water into water vapor at its boiling point of 100°C, 2260 J/g energy is absorbed by the water for the formation of vapor.

Hence, option (3) is correct.

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Answer:

The percent composition of dichlorine heptoxide is 38.76% CI and 61.24% O

Answer:

38.76%cl and 61.24%o

Explanation:

the percent composition of dichlorine heptoxide is 38.76%Cl and 61.24%O