Answer:
It is
[tex]{ \underline{ \sf{y = - \frac{3}{2}x - 3 }}}[/tex]
Step-by-step explanation:
General equation:
[tex]{ \sf{y = mx + c}}[/tex]
m is the slope
c is the y-intercept
[tex]y = - \frac{ 3}{2} x - 3[/tex]
What is the value of the expression 4x^3 – 3x when x = 6?
Can someone help me with this question? please
Answer:
6 cm3
Step-by-step explanation:
3 x 2 x 1 = 6
Find the supremum and infimum of each of the following sets of real numbers
S = {3x 2 − 10x + 3 < 0}
Answer:
[tex]\sup(S) = 3[/tex].
[tex]\displaystyle \inf(S) = \frac{1}{3}[/tex].
Step-by-step explanation:
When factored, [tex]3\,x^{2} - 10\, x + 3[/tex] is equivalent to [tex](3\, x - 1)\, (x - 3)[/tex].
[tex]3\, x^{2} - 10\, x + 3 < 0[/tex] whenever [tex]\displaystyle x \in \left(\frac{1}{3},\, 3\right)[/tex].
Typically, the supremum and infimum of open intervals are the two endpoints. In this question, [tex]\sup(S) = 3[/tex] whereas [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex].
Below is a proof of the claim that [tex]\sup(S) = 3[/tex]. The proof for [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex] is similar.
In simple words, the supremum of a set is the smallest upper bound of that set. (An upper bound of a set is greater than any element of the set.)
It is easy to see that [tex]3[/tex] is an upper bound of [tex]S[/tex]:
For any [tex]x > 3[/tex], [tex]3\,x^{2} - 10\, x + 3 > 0[/tex]. Hence, any number that's greater than [tex]3\![/tex] could not be a member [tex]S[/tex]. Conversely, [tex]3[/tex] would be greater than all elements of [tex]S\![/tex] and would thus be an upper bound of this set.To see that [tex]3[/tex] is the smallest upper bound of [tex]S[/tex], assume by contradiction that there exists some [tex]\epsilon > 0[/tex] for which [tex](3 - \epsilon)[/tex] (which is smaller than [tex]3\![/tex]) is also an upper bound of [tex]S\![/tex].
The next step is to show that [tex](3 - \epsilon)[/tex] could not be a lower bound of [tex]S[/tex].
There are two situations to consider:
The value of [tex]\epsilon[/tex] might be very large, such that [tex](3 - \epsilon)[/tex] is smaller than all elements of [tex]S[/tex].Otherwise, the value of [tex]\epsilon[/tex] ensures that [tex](3 - \epsilon) \in S[/tex].Either way, it would be necessary to find (or construct) an element [tex]z[/tex] of [tex]S[/tex] such that [tex]z > 3 - \epsilon[/tex].
For the first situation, it would be necessary that [tex]\displaystyle 3 - \epsilon \le \frac{1}{3}[/tex], such that [tex]\displaystyle \epsilon \ge \frac{8}{3}[/tex]. Let [tex]z := 1[/tex] (or any other number between [tex](1/3)[/tex] and [tex]3[/tex].)
Apparently [tex]\displaystyle 1 > \frac{1}{3} \ge (3 - \epsilon)[/tex]. At the same time, [tex]1 \in S[/tex]. Hence, [tex](3 - \epsilon)[/tex] would not be an upper bound of [tex]S[/tex] when [tex]\displaystyle \epsilon \ge \frac{8}{3}[/tex].With the first situation [tex]\displaystyle \epsilon \ge \frac{8}{3}[/tex] accounted for, the second situation may assume that [tex]\displaystyle 0 < \epsilon < \frac{8}{3}[/tex].
Claim that [tex]\displaystyle z:= \left(3 - \frac{\epsilon}{2}\right)[/tex] (which is strictly greater than [tex](3 - \epsilon)[/tex]) is also an element of [tex]S[/tex].
To verify that [tex]z \in S[/tex], set [tex]x := z[/tex] and evaluate the expression: [tex]\begin{aligned} & 3\, z^{2} - 10\, z + 3 \\ =\; & 3\, \left(3 - \frac{\epsilon}{2}\right)^{2} - 10\, \left(3 - \frac{\epsilon}{2}\right) + 3 \\ = \; &3\, \left(9 - 3\, \epsilon - \frac{\epsilon^{2}}{4}\right) - 30 + 5\, \epsilon + 3 \\ =\; & 27 - 9\, \epsilon - \frac{3\, \epsilon^{2}}{4} - 30 + 5\, \epsilon + 3 \\ =\; & \frac{3}{4}\, \left(\epsilon\left(\frac{16}{3} - \epsilon\right)\right)\end{aligned}[/tex].This expression is smaller than [tex]0[/tex] whenever [tex]\displaystyle 0 < \epsilon < \frac{16}{3}[/tex]. The assumption for this situation [tex]\displaystyle 0 < \epsilon < \frac{8}{3}[/tex] ensures that [tex]\displaystyle 0 < \epsilon < \frac{16}{3}\![/tex] is indeed satisfied. Hence, [tex]\displaystyle 3\, z^{2} - 10\, z + 3 < 0[/tex], such that [tex]z \in S[/tex].At the same time, [tex]z > (3 - \epsilon)[/tex]. Hence, [tex](3 - \epsilon)[/tex] would not be an upper bound of [tex]S[/tex].Either way, [tex](3 - \epsilon)[/tex] would not be an upper bound of [tex]S[/tex]. Contradiction.
Hence, [tex]3[/tex] is indeed the smallest upper bound of [tex]S[/tex]. By definition, [tex]\sup(S) = 3[/tex].
The proof for [tex]\displaystyle \inf(S) = \frac{1}{3}[/tex] is similar and is omitted because of the character limit.
A display case of glitter stickers are marked 15 for $2. If Cathy wants to buy 30 glitter stickers, how much will Cathy spend?
Answer:
$4, 15 x 2=30
2 x 2=4
Answer:
4 dollars
Step-by-step explanation:
We can write a ratio to solve
15 stickers 30 stickers
----------------- = -------------
2 dollars x stickers
Using cross products
15x = 2*30
15x = 60
Divide by 15
15x/15 = 60/15
x = 4
How can you rewrite simple rational expressions in different forms using long division?
(50 POINTS)PLEASE!!!!!
please help me. thank you so much
Answer:
D. On sale at 60% of the original price
Step-by-step explanation:
That just means they are taking off 40% off the original price.
I hope this helps!
pls ❤ and mark brainliest pls!
please help meeee out
Answer:
between 15.5 and 16
Step-by-step explanation:
which std
I need some help with the homework problem. I have a list of formulas, but can't seem to get it done.
[tex]\int\frac{9}{\sqrt{1+e^{2x}}} \, dx[/tex]
I started by taking the constant out and setting u = [tex]\sqrt{1+e^{2x\\}}[/tex]
After this I can't seem to progress.
After setting [tex]u=\sqrt{1+e^{2x}}[/tex], partially solving for x in terms of u gives
[tex]u = sqrt{1+e^{2x}} \implies u^2 = 1 + e^{2x} \implies e^{2x} = u^2 - 1[/tex]
Then taking differentials, you get
[tex]2 e^{2x} \,\mathrm dx = 2u \, \mathrm du \implies \mathrm dx = \dfrac{u}{u^2-1}\,\mathrm du[/tex]
Replacing everything in the original integral then gives
[tex]\displaystyle \int \frac9{\sqrt{1+e^{2x}}}\,\mathrm dx = \int \frac9u \times \frac u{u^2-1}\,\mathrm du = 9 \int \frac{\mathrm du}{u^2-1}[/tex]
Split up the integrand into partial fractions:
[tex]\dfrac1{u^2-1} = \dfrac a{u-1} + \dfrac b{u+1} \\\\ 1 = a(u+1) + b(u-1) = (a+b)u + a-b \\\\ \implies \begin{cases}a+b=0\\a-b=1\end{cases} \implies a=\dfrac12,b=-\dfrac12[/tex]
so that
[tex]\displaystyle 9 \int \frac{\mathrm du}{u^2-1} = \frac92 \int \left(\frac1{u-1} - \frac1{u+1}\right) \,\mathrm du \\\\ = \frac92 \left(\ln|u-1| - \ln|u+1|\right) + C \\\\ = \frac92 \ln\left|\frac{u-1}{u+1}\right| + C \\\\ = \frac92 \ln\left(\frac{\sqrt{1+e^{2x}}-1}{\sqrt{1+e^{2x}}+1}\right) + C[/tex]
Gh bisects cf =2y-2 and cd =3y-11 find cd
Answer:CD is 4
Step-by-step explanation: ham
Y= - 1/2x + 5/2 what are the table solutions
Answer:
[tex]y = - \frac{1}{2} x + \frac{5}{2 } \\ y = \: x ( - \frac{1}{2}) + \frac{5}{2} \\ y = - \frac{6}{2} x \\ y = - 3x \\ \frac{y}{3} = x[/tex]
i need help answering the question in the picture provided
answer:
(a).
Equation of circle is x² + y² - 25 = 0
(b).
(-5, 0) » yes
(√7, 1) » no
(-3, √21) » no
(0, 7) » no
Step-by-step explanation:
(a).
If centred at origin, centre is (0, 0)
General equation of circle:
[tex]{ \boxed{ \bf{ {x}^{2} + {y}^{2} + 2gx + 2fy + c = 0}}}[/tex]
but g and f are 0:
[tex] {x}^{2} + {y}^{2} + c = 0 \\ but : \\ c = {g}^{2} + {f}^{2} - {r}^{2} \\ c = { - 25} [/tex]
Calculate the distance between the points -8,2 and 3,2 on a coordinate plane
[tex]\\ \rm\Rrightarrow \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{(3+8)^2+(2-2)^2}[/tex]
[tex]\\ \rm\Rrightarrow \sqrt{11^2}[/tex]
[tex]\\ \rm\Rrightarrow 11[/tex]
round off 1,246,193 to the nearest thousands
Answer:
1,246,193 rounded to the nearest thousands is 1,246,000
Because the digit next to the thousands place (The hundreds place) is less that 5, it is 1 therefore you keep the digit the same in the thousands place and make the rest a 0.
Answer:
1,246,000
Step-by-step explanation:
1,246,193
The 6 is in the thousands place
We look at the hundreds place
1 is in the hundreds place, Since it is 4 or less, we leave the thousands place alone.
1,246,000
pls help with this problem
====================================================
Explanation:
Refer to the diagram below. The rectangle MATH has the diagonal MT that cuts the rectangle into two identical right triangles.
We then use the pythagorean theorem to find the length of the hypotenuse MT.
a^2 + b^2 = c^2
10^2 + 24^2 = c^2
100 + 576 = c^2
676 = c^2
c^2 = 676
c = sqrt(676)
c = 26
Segment MT is 26 cm long.
This applies to the other diagonal AH as well.
The picture above is what I’m stuck on Algebra
Answer:
Inequality
2x > 14
Solution
x > 7
Step-by-step explanation:
Twice of a number = 2x or 2 * x
Is more than 14 = > 14
Put these 2 descriptions together
2x > 14
Then divide each side by the coefficient
2x / 2 = x > 14 / 2 = x > 7
Answer:
2x > 14
Any number above 7.
Step-by-step explanation:
"Twice a number (x) is more than 14." can be written as 2x > 14.
Breakdown:
2x > 14 for Twice a number (x) is more than 14.
2x > 14 for Twice a number (x) is more than 14.
2x > 14 for Twice a number (x) is more than 14.
The solution to the inequality is any number above 7.
. Evaluate the expression below for x = 4. 6(x+8) (please
Answer:
D
Step-by-step explanation:
6(x + 8) = Plug in x with 4
6(4 + 8) =
6(12) =
72
Whats the answer to it i can't figure it out
Answer:
-0.1
...............................
Match the terms to their definition.
1. union
2. intersection
3. compound inequality
Hurry plz
Step-by-step explanation:
compound inequality: a statement formed by two.......
intersection: elements that are in both set A and B
union: elements that are in either set A or B
5.
A bag contains three types of candy (gumdrops, jelly beans, and jawbreakers). If
chosen at random, the probability of getting a gumdrop is 1/6 and the probability
of getting a jellybean is 1/3 What is the probability of getting a jawbreaker?
Answer:
P) = 1/2 jawbreaker
simplified P) 3/6 = 1/2 jawbreaker
Which both mean the same, so show simplified if asked and either answer if not asked would be marked high.
as 2/6 + 1/3 = 3/6
1 - 3/6 = 3/6
= 1/2 are the workings.
Step-by-step explanation:
Jelly bean = 1/3 = 2/6
Gumdrop = 1/6
2/6 + 1/6 = 3/6 = the difference of 1
1-3/6 = 3/6
Therefore; P) = 3/6 jawbreaker
Find the exact sum or difference. (1 point)
$5.03-$3.30=
A. $1.67
B. $1.63
C. $1.73
D. $1.83
Answer:
C. $1.73
Step-by-step explanation:
$5.03
$3.30
---------
$1.73
jane bought two new skirts for school. one cost 15 less than twice the cost of the total cost for both skirts was 75, what was the cost of each skirt?
A property sells for $140,000 two years after it was purchased. If the annual appreciation rate is 6%, how much did the original buyer pay for it?
Answer:
$123,200
Step-by-step explanation:
0.06 x 2 = 0.12
140,000 x 0.12 = 16,800
140,000 - 16,800 = 123,200
The original buyer paid the amount of $123,200 for the property.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
The property appreciated by 6% per year, so in two years it would have appreciated by 6% × 2 years = 12%.
Once we know the total appreciation, we can subtract that value from 100% to find the original purchase price as a percentage of the final sale price.
If the property appreciated by 12%, then the original purchase price must have been 100% - 12% = 88% of the final sale price.
Now, multiply the final sale price by the original purchase price as a percentage to find the original purchase price.
So, the original buyer paid the amount = 88% × $140,000 = $123,200
Therefore, the original purchase price was $123,200.
Learn more about the percentages here:
brainly.com/question/24159063
#SPJ2
√400=x² what is x? Thanks
Answer:
x=4.47213
I hope it's helps you
Find x- and y- intercepts given the following representation
Step-by-step explanation:
x intercept is 1
y intercept is 2
Hope it helps
If you were to take a longitudinal section from a long cylinder, what shape would you get? Question 23 options: A circle A parallelogram A square A rectangle
Answer:
A Rectangle
Step-by-step explanation:
A longitudinal section means that the plane slicing the cylinder is vertical, just as a latitudinal section means that the slice is horizontal.
When you think about it, a flat slice of a cylinder in the vertical direction is a rectangle.
If the cylinder is sliced along the length of the cylinder then the shape we get is a rectangle. Then the correct option is B.
What is a cylinder?A cylinder is a closed solid that has two parallel circular bases connected by a curved surface.
If you were to take a longitudinal section from a long cylinder.
Then the shape we get will be
If the cylinder is sliced along the length of the cylinder then the shape we get is a rectangle.
More about the cylinder link is given below.
https://brainly.com/question/3692256
What is the area of a square whose
diagonal is 14cm
Answer:
98 [tex]cm^{2}[/tex]
Step-by-step explanation:
The formula for the area of a square when given the diagonal is:
A = [tex]\frac{1}{2}[/tex] [tex]d^{2}[/tex] Where d is the value of the diagonal so it becomes:
0.5 × 14 × 14
This is equal to 98 [tex]cm^{2}[/tex].
HOPE THIS HELPED
Name the two input device
Answer:
keyboard and mouse are two examples of input device
Answer:
keyboard and mouse
Step-by-step explanation:
If you like my answer than please mark me brainliest
15
Determine whether the ordered pairs (1,0) and 4,
(4:15)
are solutions of the following equation.
- 5x + 7y= -5
BRE
Is (1,0) a solution of - 5x + 7y = - 5?
O Yes
Ο Νο
(ANSWER QUICKLY)
Answer:
yes
Step-by-step explanation:
x = 1, y = 0
so,
-5×1 + 7×0 = -5
-5 + 0 = -5
-5 = -5
true, therefore (1, 0) is a solution (a point on the graph) of the equation.
I am not sure what the other pair should be.
Select the correct answer.
Which statement best describes the zeros of the function () = (x-6)(X + 8x + 16)?
ОА.
The function has two distinct real zeros.
ОВ.
The function has three distinct real zeros.
OC. The function has one real zero and two complex zeros.
OD
The function has three complex zeros.
Answer:
So for the sequence to work, the 5,3=18 would have to be changed to 5,3=23 in which it now fits and works to solve for x which is 4. There was a pattern of the numbers 4 and 5 that surfaced as the difference between each pairings sum total. The difference between each sum was alternating between the numbers 4 and 5, which equal 9 when added together. Which also helped me to form a chart of sorts that makes sense. My answer is typed above, that is the most stable conclusion that I could come to to make sense of the pairings that were listed.
Answer: A (if i have well corrected)
Step-by-step explanation:
[tex]f(x)=(x-6)(x^2+8x+16)\ i\ suppose)\\\\f(x)=(x-6)(x+4)^2\\Sol=\{6;-4\}\\Answer \ A[/tex]
In the coordinate plane, plot AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ given by the points A(−4, 5), B(−4, 8), C(2, −3), D(2, 0)
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The x-coordinate is the same in each pair of points, so the line segment will be a vertical line segment 3 units long.
