Write the formula for diphosphorous pentoxide

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume =  100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g

Answer:

2.652 g/h.

Explanation:

Burn rate (in mg/min) = 44.2 mg/min

Burn rate (in m/h) =?

We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:

1 mg/min = 0.001 g/min

Therefore,

44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min

44.2 mg/min = 0.0442 g/min

Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:

1 g/min = 60 g/h

Therefore,

0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min

0.0442 g/min = 2.652 g/h

Therefore, 44.2 mg/min is equivalent to 2.652 g/h.

Thus, the burn rate (in m/h) is 2.652 g/h.

The correct decay series :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

Decay's reaction :

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+x+y+z

From this decay reaction can be concluded

mass number decreased by 4

atomic number decreased by 1

Then the most suitable are:

Polonium-214 undergoes 1 alpha decay 1 beta decay and 1 gamma emission.

₈₄Po²¹⁴⇒₈₃Bi²¹⁰+₂He⁴+ ₋₁e⁰+ ₀γ⁰

So that the mass number and atomic number are the same both before and after decay

Answer:

a chromosome contains many genes

Explanation:

Answer:

Gibbs free energy equation

Explanation: