Write the function in the form f(x) = (x − k)q(x) + r for the given value of k. F(x) = x3 − x2 − 18x + 19, k = 4 f(x) = Demonstrate that f(k) = r. F(4) =

Answers

Answer 1

Solution :

Given :

[tex]$f(x)=x^3-x^2-18x+19$[/tex]

By using the remainder theorem, if f(x) is divided by (x-k) and the remainder is 'r', then

[tex]$f(x)=(x-k)q(x)+r$[/tex]

Here, k = 4

Therefore, divide the f(x) with (x - 4) to find the q(x) and r.

           __________________

[tex]$x-4$[/tex]    |    [tex]$x^3-x^2-18x+19$[/tex]         |      [tex]$x^2+3x-6$[/tex]

            [tex]$x^3-4x^2$[/tex]

         ------------------------------------

                    [tex]$3x^2-18x$[/tex]

                    [tex]$3x^2-12x$[/tex]

          -------------------------------------

                          [tex]$-6x+19$[/tex]

                          [tex]$-6x+24$[/tex]

          -------------------------------------

                                  [tex]$-5$[/tex]

Therefore,

q(x) =  [tex]$x^2+3x-6$[/tex]

  r = -5

[tex]$f(x)=(x-4)(x^2+3x-6)-5$[/tex]

[tex]$f(4)=(4-4)(4^2+3 \times 4-6)-5$[/tex]

       [tex]$=-5$[/tex]


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