Write the quadratic in a verbal sentence. PLEASE HELP I’m super stuck!! If you can explain how to do this as well that would help so much!!

Answer:

C

Step-by-step explanation:

From the graph we can notice that the yo-yo crosses five positions: A,B,C,D and E.

The path created by the yo-yo has a parabolic form.

● In the area C, the yoyo crosses the vertex in wich the rate of change equals 0.

●In A the parabola decreases dramatically

● In B, the parabola is decreasing but slower than A.

● In D, the parabola is increasing in a fast way

● In E, the parabola is increasing faster than D.

● In the first half of C, the parabola is decreasing slower than B and A.

● At the vertex, the parabola has a null rate of change.

● In the second half of C, the parabola is increasing but slower than D and E.

So we deduce that C has the slowest rate of change.

Answer:

The answer is C i took the test

Step-by-step explanation:

Answer:

x-y=12

Step-by-step explanation:

Answer:

[tex]\boxed{v=300}[/tex]

Step-by-step explanation:

Hey there!

To find v we’ll set up the following,

v ÷ 5 = 60

To get v by itself we’ll do

5*60 = 300

v = 300

Hope this helps :)

Answer:

The numbers:

-43    and     58

Step-by-step explanation:

a + b = 15

a = b - 101

then:

(b-101) + b = 15

2b = 15+101

2b = 116

b = 116/2

b = 58

a = b - 101

a = 58 - 101

a = -43

Check:

a + b = 15

-43 + 58 = 15

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = [tex]59^{0}[/tex] + [tex]34^{0}[/tex]

                                           = [tex]93^{0}[/tex]

Thus,

<CAB = [tex]90^{0}[/tex] - [tex]59^{0}[/tex] = [tex]31^{0}[/tex]

<CBA = [tex]90^{0}[/tex] - [tex]34^{0}[/tex] = [tex]56^{0}[/tex]

Sine rule states;

[tex]\frac{a}{Sin A}[/tex] = [tex]\frac{b}{Sin B}[/tex] = [tex]\frac{c}{Sin C}[/tex]

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

[tex]\frac{b}{Sin B}[/tex] = [tex]\frac{c}{Sin C}[/tex]

[tex]\frac{b}{Sin 56^{0} }[/tex] = [tex]\frac{242}{Sin 93^{0} }[/tex]

[tex]\frac{b}{0.8290}[/tex] = [tex]\frac{242}{0.9986}[/tex]

cross multiply,

b = [tex]\frac{0.8290*242}{0.9986}[/tex]

  = 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

[tex]\frac{a}{Sin A}[/tex] = [tex]\frac{c}{Sin C}[/tex]

[tex]\frac{a}{Sin 31^{0} }[/tex] = [tex]\frac{242}{Sin 93^{0} }[/tex]

[tex]\frac{a}{0.5150}[/tex] = [tex]\frac{242}{0.9986}[/tex]

cross multiply,

a = [tex]\frac{0.5150*242}{0.9986}[/tex]

  = 124.8073

Sarge is about 125 feet away from the fire.

Answer:

That's your answer

x= 125

3x= 375

2x-1= 249

Answer:

x = 20°

Step-by-step explanation:

So when I learned it we called it the exterior angle theorem not the angle sum theorem but here goes.

Since exterior angle = 110 Degrees,

--> The Inner 2 angles's sum = 110 Degrees

so, 70 + 2x = 110

=> 2x = 40

x = 20

x = 20°

Hope this helps!

Answer:

7.00864

Step-by-step explanation:

The upper control limit for R -chart can be computed by using following formula

UCL=Rbar*D4.

We are given that average range R bar is

Rbar=3.76.

The value of D4 for n=8 is also given that is

D4=1.864.

Thus, the required computed upper control limit is

UCL=3.76*1.864=7.00864.

Answer:

hello your question has some missing parts attached below is a picture of the complete question

Answer : 3.59

Step-by-step explanation:

Calculating the standard deviation, mean and standard error of the hourly wages

Area 1 : mean = 12.75 , std = 4.9497 , std error = 1.75

Area 2 : mean = 18.25, std = 4.3671,  std error = 1.54399

Area 3 : mean = 16.25, std = 2.8660, std error = 1.01330

mean = sum of terms / number of terms

std = [tex]\sqrt{}[/tex] (X − μ)2 / n

std error = std / [tex]\sqrt{n}[/tex]

The value of the test statistic to test for a difference in the areas is

3.59 ( using anova table attached below )

Answer:

Hey there!

Using the foil method: (3x+2)(5x-7)

15x^2+10x-21x-14

15x^2-11x-14

Let me know if this helps :)

Answer:

see explanation

Step-by-step explanation:

If f(x) and [tex]f^{-1}[/tex] are inverse functions, then

f([tex]f^{-1}[/tex])(x) = x

Thus substitute x = [tex]f^{-1}[/tex] (x) into f(x)

f([tex]\frac{x+6}{5}[/tex] )

= 5 ([tex]\frac{x+6}{5}[/tex] ) - 6

= x + 6 - 6

= x

Thus f(x) and [tex]f^{-1}[/tex] (x) are inverse functions

Answer:

3.25

Step-by-step explanation:

Answer: approximately 10.8 centimeters

Step-by-step explanation:

We have a square, where each side measures approx. 4.25 in

Now we know that 1in ≈ 2.54 cm

Then, in 4.25 in, we have 4.25 times 1 inch, so we have 4.25 times the length of 2.54 cm

So the approximate measure of the sides in centimeters is:

4.25*(2.54)cm = 10.8 cm

So we have that each side measures approximately 10.8 centimeters

Answer:

[tex] \boxed{\sf Instantaneous \ velocity \ (v) = -3} [/tex]

Given:

Relation between position of an object at time t is given by:

s(t) = -9 - 3t

To Find:

Instantaneous velocity (v) at t = 8

Step-by-step explanation:

To find instantaneous velocity we will differentiate relation between position of an object at time t by t:

[tex] \sf \implies v = \frac{d}{dt} (s(t))[/tex]

[tex] \sf \implies v = \frac{d}{dt} ( - 9 - 3t)[/tex]

Differentiate the sum term by term and factor out constants:

[tex] \sf \implies v = \frac{d}{dt} ( - 9) - 3 (\frac{d}{dt} (t))[/tex]

The derivative of -9 is zero:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t)) + 0[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t))[/tex]

The derivative of t is 1:

[tex] \sf \implies v = - 3 \times 1[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3 [/tex]

(As, there is no variable after differentiating the relation between position of an object at time t by t so at time t = 8 is of no use.)

So,

Instantaneous velocity (v) at t = 8 is -3

Answer:

a) What is the cost of a chicken shawarma wrap?

$10.99

b) What is the cost of one order of spiced potatoes?

$4.99

c) If x denotes the cost of a chicken shawarma wrap and y denotes the cost of an order of spiced potatoes, what are the equations needed to solve this problem?

3x + 2y = $42.95 .............Equation 1

5x + 4y = $74.91 ................Equation 2

Step-by-step explanation:

Let x denotes the cost of a chicken shawarma wrap and y denotes the cost of an order of spiced potatoes,

Cost of a chicken sharwarma wrap = x

Cost of an order of spiced potatoes = y

Ms. Ironperson ordered 3 chicken shawarma wraps and 2 orders of spiced potatoes for a total bill of $42.95.

3x + 2y = $42.95 .............Equation 1

Mr. Thoro ordered 5 chicken shawarma wraps and 4 orders of spiced potatoes for a total bill of $74.91.

5x + 4y = $74.91 ................Equation 2

Hence, the Equations needed to solve the question is:

3x + 2y = $42.95 .............Equation 1

5x + 4y = $74.91 ................Equation 2

We use Elimination method to solve for this.

Multiply Equation 1 by coefficient of x in Equation 2

Equation 2 by coefficient of x in Equation 1

3x + 2y = $42.95 .............Equation 1 × 5

5x + 4y = $74.91 ................Equation 2 × 3

15x + 10y = 214.75..............Equation 3

15x + 12y = 224.73..............Equation 4

Subtract Equation 3 from Equation 4

2y = 9.98

y = 9.98/2

y = 4.99

Therefore, y = Cost of an order of spiced potatoes = $4.99

Subtitute 4.99 for y in Equation 1

3x + 2y = $42.95 .............Equation 1

3x +2(4.99) = 42.95

3x + 9.98 = 42.95

3x = 42.95 - 9.98

3x = 32.97

x = 32.97/3

x = 10.99

x = Cost of a chicken sharwarma wrap = $10.99

Therefore,

The cost of a chicken sharwarma wrap = $10.99

The cost of an order of spiced potatoes = $4.99

can u go to my page real quick and answer my question pls

Answer:

[tex]a_n = 8 + (n - 1) (-6)[/tex]

Step-by-step explanation:

Given

[tex]a_1 = 8[/tex]

Recursive: [tex]a_{n} = a_{n-1} - 6[/tex]

Required

Determine the formula

Substitute 2 for n to determine [tex]a_2[/tex]

[tex]a_{2} = a_{2-1} - 6[/tex]

[tex]a_{2} = a_{1} - 6[/tex]

Substitute [tex]a_1 = 8[/tex]

[tex]a_2 = 8 - 6[/tex]

[tex]a_2 = 2[/tex]

Next is to determine the common difference, d;

[tex]d = a_2 - a_1[/tex]

[tex]d = 2 - 8[/tex]

[tex]d = -6[/tex]

The nth term of an arithmetic sequence is calculated as

[tex]a_n = a_1 + (n - 1)d[/tex]

Substitute [tex]a_1 = 8[/tex] and [tex]d = -6[/tex]

[tex]a_n = a_1 + (n - 1)d[/tex]

[tex]a_n = 8 + (n - 1) (-6)[/tex]

Hence, the nth term of the sequence can be calculated using[tex]a_n = 8 + (n - 1) (-6)[/tex]

Answer:

Step-by-step explanation:

Given x = 5, y = 3/4 and z = -1/7, 2=we are to calculate [tex]\frac{xz}{y}[/tex]. Substituting the value of x, y and z into the expression will give;

[tex]= \frac{xz}{y}\\\\ \frac{5(-1/7)}{3/4} \\= \frac{-5/7}{3/4}\\\\= \frac{-5}{7} * \frac{4}{3}\\ \\ = \dfrac{-20}{21}\\[/tex]

Hence the value of the expression is -20/21

Answer:

$856

Step-by-step explanation:

Find 7% of $800 and then add it to $800

Answer:

[tex]\text{Critical Region} = z<-1.96\ \text{or}\ z>1.96[/tex]

Step-by-step explanation:

A test for the difference between two population means is to be performed.

As the population variances are known, the z-test will be used.

The hypothesis can be defined as follows:

H₀: μ₁ = μ₂ vs. Hₐ: μ₁ ≠ μ₂

Assume that the significance level of the test is, α = 0.05.

The critical region can be defined as follows:

The critical value of z for α = 0.05 is:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025} =-1.96\\\\z_{1-\alpha/2}=z_{1-0.05/2}=z_{0.975} =1.96[/tex]

Use a z-table.

[tex]\text{Critical Region} = z<-1.96\ \text{or}\ z>1.96[/tex]

Answer:

11.7 pounds

Step-by-step explanation:

Multiply the weight of one bag of oranges by 9 bags.

Answer:

[tex]\boxed{\sf C. \ 10}[/tex]

Step-by-step explanation:

[tex]\sf The \ intersecting \ chord \ theorem \ states \ that \ the \ products[/tex]

[tex]\sf of \ the \ lengths \ of \ the \ line \ segments \ on \ each \ chord \ are \ equal.[/tex]

[tex]NH \times HT = MH \times HY[/tex]

[tex](x+20) \times 8=12 \times 20[/tex]

[tex]\sf Expand \ brackets \ and \ multiply.[/tex]

[tex]8x+160=240[/tex]

[tex]\sf Subtract \ 160 \ from \ both \ sides.[/tex]

[tex]8x+160-160=240-160[/tex]

[tex]8x=80[/tex]

[tex]\sf Divide \ both \ sides \ by \ 8.[/tex]

[tex]\displaystyle \frac{8x}{8} =\frac{80}{8}[/tex]

[tex]x=10[/tex]

The value of x is 10.

We have a circle and inside it two chords MY and NT intersect at point H.

We have to find the value of x in the figure.

According to the intersecting chord theorem, when two chords say AB and CD intersect at point O, then

AO x OB = CO x OD

Applying the chord intersecting theorem to the figure in the question, we get -

MH x HY = NH x HT

12 x 20 = (x+20) x 8

240 = 8x + 160

8x = 80

x = 10

Hence the value of x is 10.

To solve more questions on Circles and chords, visit the link below -

https://brainly.com/question/15568573

#SPJ5

Answer:

3

Step-by-step explanation:

[tex] \sqrt[4] {27} \cdot \sqrt[4] {3} = [/tex]

[tex] = \sqrt[4] {27 \cdot 3} [/tex]

[tex] = \sqrt[4] {3^3 \cdot 3^1} [/tex]

[tex] = \sqrt[4] {3^4} [/tex]

[tex] = 3 [/tex]

Answer:

positively skewed to the right

Step-by-step explanation:

The measure of the central tendency is a profound way to describe the mean, median and mode. The measure of central tendency indicates where the center of distribution tends to be. The measure of central tendency provide a validity and answers whether the scores are high or generally low.

In this measure,The mean is usually pulled to the tail. The skewed is determined by where the tail goes, to the right side , it is positively skewed  and to the left side , it is known as negatively skewed distribution.

Given that:

In a frequency of distribution of 290 scores,

the mean  = 99

the median = 86

One would expect this distribution to be; positively skewed to the right  since the mean value is greater than the median value.

Answer:

.22

Step-by-step explanation:

The number of times a 3 was rolled is 44 out of 200

The experimental probability is  44/200 = .22

The frequency of rolling a 3 was 44.

So... 44/200

After dividing we get 0.22

Therefore, the answer is A

Best of Luck!

Answer: 0.129

Step-by-step explanation:

Let [tex]\overline{X}[/tex] denotes a random variable that represents the mean weight of babies born.

Population mean : [tex]\mu= \text{3316 grams,}[/tex]

Standard deviation: [tex]\text{324 grams}[/tex]

Sample size = 83

Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :

[tex]P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}<\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}<\dfrac{-54}{\dfrac{324}{\sqrt{83}}})\\\\=1-[P(-1.518<Z<1.518)\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-[P(Z<1.518)-P(z<-1.518)]\\\\=1-[P(Z<1.518)-(1-P(z<1.518))]\\\\=1-[2P(Z<1.518)-1]=2-2P(Z<1.518)\\\\=2-2(0.9355)\ [\text{By z-table}]\\\\=0.129[/tex]

hence, the required probability =  0.129

Answer:

so first convert to fraction so

9 3/4 = 39/4

so it was spread among 3

so this is division so you do 39/4 divided by 3

so you keep switch flip

which is  39/4 *1/3

answer is 13/4

Answer:

Step-by-step explanation:

[tex]9\frac{3}{4}= \frac{(4 \times 9)+3}{4}= \frac{39}{4} \\\\\frac{39}{4} = 3 \:vegetable \: beds\\x \:\:\:= 1 \: vegetable \:bed\\\\3x = \frac{39}{4} \\\\\frac{3x}{3} = \frac{\frac{39}{4} }{3} \\\\x = \frac{13}{4} \\\\x = 3\frac{1}{4}[/tex]

Answer:

20.8 hours

Step-by-step explanation:

Given that hours (h) varies inversely with age (a) then the equation relating them is

h = [tex]\frac{k}{a}[/tex] ← k is the constant of variation

To find k use the condition h = 52 when a = 20, thus

52 = [tex]\frac{k}{20}[/tex] ( multiply both sides by 20 )

1040 = k

h = [tex]\frac{1040}{a}[/tex] ← equation of variation

When a = 50, then

h = [tex]\frac{1040}{50}[/tex] = 20.8 hours

It's a variable that deals with various labels, rather than the usual type of numeric variable you may be used to.

One example of a categorical variable is color. You could have red, green, blue, yellow, and orange as the five choices for your categorical variable. Each color is a label or category.

This is an example of a qualitative variable. We don't have any numeric data attached to color. They're simply names or labels. In contrast, a quantitative variable is something like a person's height since a number is attached here (more specifically its a continuous quantitative variable).

Answer:

21

Step-by-step explanation:

√1500 = 38.7

Round to nearest whole number

≈39

39²-1500

= 1521 - 1500

= 21